Something strange is going on. When I reassign an NSString to my subString variable near the bottom of my code. It seems that the value of subString is empty in the output. I don't know if objectAtIndex is returning something weird or it's a memory problem. If I create a new variable instead of reassigning the value of subString, I can print see the correct value in the output console. If anyone could help me figure this out. It'd be greatly appreciated.
NSString *subString = #"";
if ([text length] > 0)
{
UITextRange *selectedRange = [_textView selectedTextRange];
UITextPosition *cursorPosition = [_textView positionFromPosition:selectedRange.start offset:0];
UITextRange *subTextRange = [_textView textRangeFromPosition:_textView.beginningOfDocument toPosition:cursorPosition];
subString = [textView textInRange:subTextRange];
}
NSLog(subString);
NSLog(#" %s", [subString hasSuffix:#" "] ? "TRUE" : "FALSE");
BOOL hasSpaceSuffix = [subString hasSuffix:#" "];
NSLog(#" %s", _taggingInProgress ? "TRUE" : "FALSE");
NSArray *substringArray = [[subString componentsSeparatedByString:#" "] retain];
if ([substringArray count] > 1) {
int index = [substringArray count];
if ([[substringArray objectAtIndex:index-1] isEqualToString:#" "])
{
NSLog(#"1st");
subString = [substringArray objectAtIndex:index-2];
NSLog(subString);
}
else
{
NSLog(#"2nd");
subString = [substringArray objectAtIndex:index-1];
NSLog(subString);
}
NSLog(#"AFTER");
NSLog(subString);
}
I think you need to use:
subString = [NSString stringWithString:[substringArray objectAtIndex:index]];
...fixed...
Related
Code Snippet:
NSString *tempStr = self.consumerNumber.text;
if ([tempStr hasPrefix:#"0"] && [tempStr length] > 1) {
tempStr = [tempStr substringFromIndex:1];
[self.consumerNumbers addObject:tempStr];>
}
I tried those things and removing only one zero. how to remove more then one zero
Output :001600240321
Expected result :1600240321
Any help really appreciated
Thanks in advance !!!!!
Try to use this one
NSString *stringWithZeroes = #"001600240321";
NSString *cleanedString = [stringWithZeroes stringByReplacingOccurrencesOfString:#"^0+" withString:#"" options:NSRegularExpressionSearch range:NSMakeRange(0, stringWithZeroes.length)];
NSLog(#"Clean String %#",cleanedString);
Clean String 1600240321
convert string to int value and re-assign that value to string,
NSString *cleanString = [NSString stringWithFormat:#"%d", [string intValue]];
o/p:-1600240321
You can add a recursive function that is called until the string begin by something else than a 0 :
-(NSString*)removeZerosFromString:(NSString *)anyString
{
if ([anyString hasPrefix:#"0"] && [anyString length] > 1)
{
return [self removeZerosFromString:[anyString substringFromIndex:1]];
}
else
return anyString;
}
so you just call in your case :
NSString *tempStr = [self removeZerosFromString:#"000903123981000"];
NSString *str = #"001600240321";
NSString *newStr = [#([str integerValue]) stringValue];
If the NSString contains numbers only.
Other wise use this:
-(NSString *)stringByRemovingStartingZeros:(NSString *)string
{
NSString *newString = string;
NSInteger count = 0;
for(int i=0; i<[string length]; i++)
{
if([[NSString stringWithFormat:#"%c",[string characterAtIndex:i]] isEqualToString:#"0"])
{
newString = [newString stringByReplacingCharactersInRange:NSMakeRange(i-count, 1) withString:#""];
count++;
}
else
{
break;
}
}
return newString;
}
Simply call this method:-
NSString *stringWithZeroes = #"0000000016909tthghfghf";
NSLog(#"%#", [self stringByRemovingStartingZeros:stringWithZeroes]);
OutPut: 16909tthghfghf
Try the `stringByReplacingOccurrencesOfString´ methode like this:
NSString *new = [old stringByReplacingOccurrencesOfString: #"0" withString:#""];
SORRY: This doesn't help you due to more "0" in the middle part of your string!
I need to remove all emoijs from a NSString.
So far i am using this NSString extension ...
- (NSString*)noEmoticon {
static NSMutableCharacterSet *emoij = NULL;
if (emoij == NULL) {
emoij = [[NSMutableCharacterSet alloc] init];
// unicode range of old emoijs
[emoij removeCharactersInRange:NSMakeRange(0xE000, 0xE537 - 0xE000)];
}
NSRange range = [self rangeOfCharacterFromSet:emoij];
if (range.length == 0) {
return self;
}
NSMutableString *cleanedString = [self mutableCopy];
while (range.length > 0) {
[cleanedString deleteCharactersInRange:range];
range = [cleanedString rangeOfCharacterFromSet:emoij];
}
return cleanedString;
}
... but that does not work at all. The range.length is always 0.
So the general question is : How can i remove a range of unicode characters from a NSString?
Thanks a lot.
It seems to me that in the above code the emoij variable is eventually an empty set. Didn't you mean to addCharactersInRange: rather than to removeCharactersInRange:?
I am using RegexKitLite, i want to validate that my uitextfield has + prefixed and contains numeric length of 13 or only 13 numeric values.
Please let me know
Below is the code i tried
textview.text = #"123458kdkmfmdfmsdf"
NSString *regEx = #"{3}-[0-9]{3}-[0-9]{4}";
NSString *match = [textView.text stringByMatching:regEx];
if ([match isEqual:#""] == NO)
{ NSLog(#"Phone number is %#", match); }
else { NSLog(#"Not found."); }
the ouput i want is belo
ouput 1 = "1234567891012"
or output 2 can be like "+1234567891012
try this :
NSString * forAlphaNumeric = #"^([+]{1})(a-zA-Z0-9{13})$";
BOOL isMatch = [yourString isMatchedByRegex:forAlphaNumeric];
NSString * forNumeric = #"^([+]{1})(0-9{13})$";
BOOL isMatch = [yourString isMatchedByRegex:forNumeric];
I got a headache trying to count returns (\n) in my UITextView. As you'll soon realise, I'm a bloody beginner and here is my theory of what I've come up with, but there are many gaps...
- (IBAction)countReturns:(id)sender {
int returns;
while ((textView = getchar()) != endOfString [if there is such a thing?])
{
if (textView = getchar()) == '\n') {
returns++;
}
}
NSString *newText = [[NSString alloc] initWithFormat:#"Number of returns: %d", returns];
numberReturns.text = newText;
[newText release];
}
I checked other questions on here, but people are usually (in my eyes) lost in some details which I don't understand. Any help would be very much appreciated! Thanks for your patience.
You can simply
UITextView *theview; //remove this line, and change future theview to your veiw
NSString *thestring; //for storing a string from your view
int returnint = 0;
thestring = [NSString stringWithFormat:#"%#",[theview text]];
for (int temp = 0; temp < [thestring length]; temp++){ //run through the string
if ([thestring characterAtIndex: temp] == '\n')
returnint++;
}
NSArray *newlines = [textView.text componentsSeparatedByString:#"\n"];
int returns = ([newlines count]-1)
Should work. Keep in mind this isn't such a great idea if you have a gia-normous string, but it's quick, dirty and easy to implement.
there are a lot of ways to do that. Here is one:
NSString *str = #"FooBar\n\nBaz...\n\nABC\n";
NSString *tmpStr = [str stringByReplacingOccurrencesOfString:#"\n" withString:#""];
NSInteger count = [str length] - [tmpStr length];
NSLog(#"Count: %d", count);
i'm trying to build a function that will tell me the range of a string at an occurrence.
For example if I had the string "hello, hello, hello", I want to know the range of hello at it's, lets say, third occurrence.
I've tried building this simple function, but it doesn't work.
Note - the top functions were constructed at an earlier date and work fine.
Any help appreciated.
- (NSString *)stringByTrimmingString:(NSString *)stringToTrim toChar:(NSUInteger)toCharacterIndex {
if (toCharacterIndex > [stringToTrim length]) return #"";
NSString *devString = [[[NSString alloc] init] autorelease];
for (int i = 0; i <= toCharacterIndex; i++) {
devString = [NSString stringWithFormat:#"%#%#", devString, [NSString stringWithFormat:#"%c", [stringToTrim characterAtIndex:(i-1)]]];
}
return devString;
[devString release];
}
- (NSString *)stringByTrimmingString:(NSString *)stringToTrim fromChar:(NSUInteger)fromCharacterIndex {
if (fromCharacterIndex > [stringToTrim length]) return #"";
NSString *devString = [[[NSString alloc] init] autorelease];
for (int i = (fromCharacterIndex+1); i <= [stringToTrim length]; i++) {
devString = [NSString stringWithFormat:#"%#%#", devString, [NSString stringWithFormat:#"%c", [stringToTrim characterAtIndex:(i-1)]]];
}
return devString;
[devString release];
}
- (NSRange)rangeOfString:(NSString *)substring inString:(NSString *)string atOccurence:(int)occurence {
NSString *trimmedString = [inString copy]; //We start with the whole string.
NSUInteger len, loc, oldLength;
len = 0;
loc = 0;
NSRange tempRange = [string rangeOfString:substring];
len = tempRange.length;
loc = tempRange.location;
for (int i = 0; i != occurence; i++) {
NSUInteger endOfWord = len+loc;
trimmedString = [self stringByTrimmingString:trimmedString fromChar:endOfWord];
oldLength += [[self stringByTrimmingString:trimmedString toChar:endOfWord] length];
NSRange tmp = [trimmedString rangeOfString:substring];
len = tmp.length;
loc = tmp.location + oldLength;
}
NSRange returnRange = NSMakeRange(loc, len);
return returnRange;
}
Instead of trimming the string a bunch of times (slow), just use rangeOfString:options:range:, which searches only within the range passed as its third argument. See Apple's documentation.
So try:
- (NSRange)rangeOfString:(NSString *)substring
inString:(NSString *)string
atOccurence:(int)occurence
{
int currentOccurence = 0;
NSRange rangeToSearchWithin = NSMakeRange(0, string.length);
while (YES)
{
currentOccurence++;
NSRange searchResult = [string rangeOfString: substring
options: NULL
range: rangeToSearchWithin];
if (searchResult.location == NSNotFound)
{
return searchResult;
}
if (currentOccurence == occurence)
{
return searchResult;
}
int newLocationToStartAt = searchResult.location + searchResult.length;
rangeToSearchWithin = NSMakeRange(newLocationToStartAt, string.length - newLocationToStartAt);
}
}
You need to rework the whole code. While it may seem to work, it's poor coding and plain wrong, like permanently reassigning the same variable, initializing but reassigning one line later, releasing after returning (which will never work).
For your question: Just use rangeOfString:options:range:, and do this the appropriate number of times while just incrementing the starting point.