Set up a NSMutableArray of objects to match a string value - iphone

Question

I'm using the value of two sliders as the first search criteria.
Now I want a second criteria. I have a
NSMutableArray *suitsArray;
which is containing up to 10 words, or it could be empty (0 words). Example of array:
2012-08-12 03:13:14.825 App[4595:f803] The content of array is(
mushroom,
grill,
pizza
)
What I want is this:
If suitsArray is like above, containing words mushroom, grill and pizza
and the "Suits" value in a dictionary is: "This wine suits mushroom dishes, grilled food, pizza and chicken."
This dictionary is added to searchResultsArray, same with all other dictionaries where "Suits" value containing words mushroom, grill and pizza.
But if suitsArray is empty of objects, skip this critera.
But I'm not sure how to write the code for it. Can you help me on it?
-(IBAction)searchButtonPressed:(id)sender{
resultObjectsArray = [NSMutableArray array];
for(NSDictionary *object in allObjectsArray)
{
NSString *objectPrice = [object objectForKey:#"75 cl price"];
NSString *suitsString = // the words in suitsArray
NSString *objectSuits = [object objectForKey:#"Suits"];
BOOL priceConditionGood = YES;
if (minPrisSlider.value <= maxPrisSlider.value && (winePrice.floatValue < minPrisSlider.value || winePrice.floatValue > maxPrisSlider.value))
priceConditionGood = NO;
if (priceConditionGood)
[resultObjectsArray addObject:object];
}
ResultsTableViewController *nextController = [[self storyboard] instantiateViewControllerWithIdentifier:#"ResultsController"];
nextController.objectsArray = [[NSMutableArray alloc]initWithArray:resultObjectsArray];
[self.navigationController pushViewController:nextController animated:YES];
}

Answer 1

It would be better to see if suitsArray contains the string objectSuits, rather than using rangeOfString.
if ([suitsArray containsObject:objectSuits]);
[resultObjectsArray addObject:object];
After edit: I think I understand now. This method looks at each word in suitsArray, and if it finds any of them in objectSuits, then object is added to the resultObjectArray.
for (NSString *aWord in suitsArray) {
if ([objectSuits rangeOfString:aWord].length == aWord.length) {
[resultObjectArray addObject:objectSuits];
break;
}
}
Second Edit: After further thought, the above code has a flaw in the logic that may or may not be important -- because it uses rangeOfString it will find words inside other words. So, if objectSuits was "This wine goes well with cheesecake" and suitsArray contained the word cheese, it would find a match (I can't imagine a wine that would be good with cheese would be good with cheesecake). So, here is a better solution, I think, that breaks objectSuit up into individual words and puts them into a set. suitsArray is also converted to a set, so that we can use intersectsSet: to find if there are any common words.
NSCharacterSet *sepSet = [NSCharacterSet characterSetWithCharactersInString:#" ,.;"];
NSArray *words = [objectSuits componentsSeparatedByCharactersInSet:sepSet];
NSSet *objectSuitsWords = [NSSet setWithArray:words];
NSSet *suitsSet = [NSSet setWithArray:suitsArray];
BOOL ans = [suitsSet intersectsSet:objectSuitsWords];
So, if ans is 1, then that object should be added to the results array. Notice that sepSet starts with a space and includes a comma, period, and semicolon. There might be other things you might want to include, but I think this should work in most cases.