I have following string, how can I extract the text that lies between the two delimiters:
some text to be extracted :
text text text text
= = = = = = = = = = = = =
some text to be extracted
= = = = = = = = = = = = =
text text text text
I want also the two delimiters to be returned with the text.
how can this be done with Objective-C ?
Here's a way to do it.
You have to find all the ranges where your delimiter strings are.
Then you take ranges 2 by 2 to extract your string between them :
NSString *str = #"text text text text --- some text to be extracted... --- text text text text";
NSString *myDelimiterString = #"---";
NSMutableArray *arrayOfRangeForOccurrences = [[NSMutableArray alloc] init];
NSUInteger length = [str length];
NSRange range = NSMakeRange(0, length);
while(range.location != NSNotFound)
{
range = [str rangeOfString:myDelimiterString options:0 range:range];
if(range.location != NSNotFound)
{
[arrayOfRangeForOccurrences addObject:[NSValue valueWithRange:range]];
range = NSMakeRange(range.location + range.length, length - (range.location + range.length));
}
}
//at least 2 delimiters have been found, we can extract a string
if (arrayOfRangeForOccurrences.count >= 2) {
//Extracting first text :
NSRange firstRangeForDelimiter = [[arrayOfRangeForOccurrences objectAtIndex:0] rangeValue];
NSRange secondRangeForDelimiter = [[arrayOfRangeForOccurrences objectAtIndex:1]rangeValue];
NSRange rSub = NSMakeRange(firstRangeForDelimiter.location + firstRangeForDelimiter.length, secondRangeForDelimiter.location - firstRangeForDelimiter.location - firstRangeForDelimiter.length);
NSString *myExtractedText = [str substringWithRange:rSub];
NSLog(#"myExtractedText is : %#", myExtractedText);
} else {
NSLog(#"No pair of delimiter found");
}
you can use something like below line of code,
NSArray *arrChars = [#"Your,String,for,test" componentsSeparatedByString:#","];
So you will get parts of string separated by ,.
Hope this may help you for what you want.
Related
I am using RegexKitLite, i want to validate that my uitextfield has + prefixed and contains numeric length of 13 or only 13 numeric values.
Please let me know
Below is the code i tried
textview.text = #"123458kdkmfmdfmsdf"
NSString *regEx = #"{3}-[0-9]{3}-[0-9]{4}";
NSString *match = [textView.text stringByMatching:regEx];
if ([match isEqual:#""] == NO)
{ NSLog(#"Phone number is %#", match); }
else { NSLog(#"Not found."); }
the ouput i want is belo
ouput 1 = "1234567891012"
or output 2 can be like "+1234567891012
try this :
NSString * forAlphaNumeric = #"^([+]{1})(a-zA-Z0-9{13})$";
BOOL isMatch = [yourString isMatchedByRegex:forAlphaNumeric];
NSString * forNumeric = #"^([+]{1})(0-9{13})$";
BOOL isMatch = [yourString isMatchedByRegex:forNumeric];
In objective c how to Remove text after a string occurrence.
for example i have to remove a text after occurrence of text 'good'
'iphone is good but..' here i have to remove the but text in the end so the text will be now 'iphone is good'
Try with below code
NSString *str_good = #"iphone is good but...";
NSRange range = [str_good rangeOfString:#"good"];
str_good = [str_good substringToIndex:range.location+range.length];
NSString * a = #"iphone is good but..";
NSRange match = [a rangeOfString:#"good"];
NSString * b = [a substringToIndex:match.location+match.length];
If you want to remove rest of the string after a particular occurrence of "but", you can get the range of "but" and trim the original string down
NSString * test = [NSString stringWithString:#"iphone is good but rest of string"];
NSRange range = [test rangeOfString:#"but"];
if (range.length > 0) {
NSString *adjusted = [test substringToIndex:range.location];
NSLog(#"result %#", adjusted);
}
EDIT
We can assume that the search does not want to cut of "butter is yellow", and can change the range to include " but"
NSRange range = [test rangeOfString:#" but"];
Try this:-
NSArray *array = [string componentsSeperatedBy:#"good"];
NSString *requiredString = [array objectAtIndex:0];
NSArray *array = [string componentsSeparatedByString:stringToSearch];
NSString *requiredString;
if ([array count] > 0) {
requiredString = [[array objectAtIndex:0] stringByAppendingString:stringToSearch];
}
There is a substring that occurs in a string several times. I use rangeOfString, but it seems that it can only find the first location. How can I find all the locations of the substring?
NSString *subString1 = #"</content>";
NSString *subString2 = #"--\n";
NSRange range1 = [newresults rangeOfString:subString1];
NSRange range2 = [newresults rangeOfString:subString2];
int location1 = range1.location;
int location2 = range2.location;
NSLog(#"%i",location1);
NSLog(#"%i",location2);
You can use rangeOfString:options:range: and set the third argument to be beyond the range of the first occurrence. For example, you can do something like this:
NSRange searchRange = NSMakeRange(0,string.length);
NSRange foundRange;
while (searchRange.location < string.length) {
searchRange.length = string.length-searchRange.location;
foundRange = [string rangeOfString:substring options:0 range:searchRange];
if (foundRange.location != NSNotFound) {
// found an occurrence of the substring! do stuff here
searchRange.location = foundRange.location+foundRange.length;
} else {
// no more substring to find
break;
}
}
Swift 3.0
Find all locations of substring i
let text = "This is the text and i want to replace something"
let mutableAttributedString = NSMutableAttributedString(string: text)
var searchRange = NSRange(location: 0, length: text.characters.count)
var foundRange = NSRange()
while searchRange.location < text.characters.count {
searchRange.length = text.characters.count - searchRange.location
foundRange = (text as NSString).range(of: "i", options: NSString.CompareOptions.caseInsensitive, range: searchRange)
if foundRange.location != NSNotFound {
// found an occurrence of the substring! do stuff here
searchRange.location = foundRange.location + foundRange.length
mutableAttributedString.addAttribute(NSForegroundColorAttributeName, value: UIColor.red, range: foundRange)
}
else {
// no more substring to find
break
}
}
//Apply
textLabel.attributedText = mutableAttributedString;
And this output-
This is my solution. Basically, the algorithm traverses the string looking for substring matches and returns those matches in an array.
Since an NSRange is a struct it cannot be added to the array directly. By using NSValue, I can encode the match first and then add it to the array. To retrieve the range, I then decode the NSValue object to an NSRange.
#import <Foundation/Foundation.h>
NSRange makeRangeFromIndex(NSUInteger index, NSUInteger length) {
return NSMakeRange(index, length - index);
}
NSArray<NSValue *> * allLocationsOfStringMatchingSubstring(NSString *text, NSString *pattern) {
NSMutableArray *matchingRanges = [NSMutableArray new];
NSUInteger textLength = text.length;
NSRange match = makeRangeFromIndex(0, textLength);
while(match.location != NSNotFound) {
match = [text rangeOfString:pattern options:0L range:match];
if (match.location != NSNotFound) {
NSValue *value = [NSValue value:&match withObjCType:#encode(NSRange)];
[matchingRanges addObject:value];
match = makeRangeFromIndex(match.location + 1, textLength);
}
}
return [matchingRanges copy];
}
int main(int argc, const char * argv[]) {
#autoreleasepool {
NSString *text = #"TATACCATGGGCCATCATCATCATCATCATCATCATCATCATCACAG";
NSString *pattern = #"CAT";
NSArray<NSValue *> *matches = allLocationsOfStringMatchingSubstring(text, pattern);
NSLog(#"Text: %#", text);
NSLog(#"Pattern: %#", pattern);
NSLog(#"Number of matches found: %li", matches.count);
[matches enumerateObjectsUsingBlock:^(NSValue *obj, NSUInteger idx, BOOL *stop) {
NSRange match;
[obj getValue:&match];
NSLog(#" Match found at index: %li", match.location);
}];
}
return 0;
}
Passing nil to [string rangeOfString:substring options:nil range:searchRange]; shows a warning.
To get rid of the warning, put in an enum from this group
enum {
NSCaseInsensitiveSearch = 1,
NSLiteralSearch = 2,
NSBackwardsSearch = 4,
NSAnchoredSearch = 8,
NSNumericSearch = 64,
NSDiacriticInsensitiveSearch = 128,
NSWidthInsensitiveSearch = 256,
NSForcedOrderingSearch = 512,
NSRegularExpressionSearch = 1024
};
https://developer.apple.com/library/ios/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/index.html#//apple_ref/doc/constant_group/Search_and_Comparison_Options
Here is a version in Swift 2.2 of PengOne's answer with input from kevinlawler and Gibtang
Note: string and substring are of type NSString
let fullStringLength = (string as String).characters.count
var searchRange = NSMakeRange(0, fullStringLength)
while searchRange.location < fullStringLength {
searchRange.length = fullStringLength - searchRange.location
let foundRange = string.rangeOfString(substring as String, options: .CaseInsensitiveSearch, range: searchRange)
if foundRange.location != NSNotFound {
// found an occurrence of the substring! do stuff here
searchRange.location = foundRange.location + 1
} else {
// no more strings to find
break
}
}
I suggest using regular expression because it's a more declarative way and has fewer lines of code to write.
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"%#" options:nil error:nil];
NSString *toSearchStr = #"12312 %# Text %# asdsa %#";
__block int occurs = 0;
[regex enumerateMatchesInString:toSearchStr options:0 range:NSMakeRange(0, toSearchStr.length) usingBlock:^(NSTextCheckingResult * _Nullable result, NSMatchingFlags flags, BOOL * _Nonnull stop) {
occurs++;
}];
// occurs == 3
I know NSString has methods that determine the frame size for it, using NSString UIKit Additions, sizeWithFont......
How about the other way around? I mean if I have a fixed frame size, how do I know how many characters or words for a NSString that can fit into it?
If I know this, I can cut off the NSString easily.
thanks
It might not be the most elegant solution, but you could do something like this:
- (NSString *)string:(NSString *)sourceString reducedToWidth:(CGFloat)width withFont:(UIFont *)font {
if ([sourceString sizeWithFont:font].width <= width)
return sourceString;
NSMutableString *string = [NSMutableString string];
for (NSInteger i = 0; i < [sourceString length]; i++) {
[string appendString:[sourceString substringWithRange:NSMakeRange(i, 1)]];
if ([string sizeWithFont:font].width > width) {
if ([string length] == 1)
return nil;
[string deleteCharactersInRange:NSMakeRange(i, 1)];
break;
}
}
return string;
}
Then call it like this:
NSString *test = #"Hello, World!";
CGFloat width = 40.0;
UIFont *font = [UIFont systemFontOfSize:[UIFont labelFontSize]];
NSString *reducedString = [self string:test reducedToWidth:width withFont:font];
NSLog(#"%#", reducedString);
You cannot know/determine the number of characters that fits in a UILabel with fixed width because some characters are smaler than others, eg l and m.
There are two options:
Use Mono-Space-Fonts (each character has also a fixed width). Then determine the width for one char in your font with your font-size and calculate the number of chars
Allow any number of characters and check on insert if the inserted characters fit.
You have to know what behaviour you want to have. What should happen if there is text that does not fit. If you only want to truncate (like the solution of mortenfast does) then just use UILineBreakModeTailTruncation for the lineBreakMode-property of your UILabel (there are more options, like TruncateHead, Clip, Word Wrap)
Or you just just use the lineBreak property and set it to NSLineBreakByCharWrapping and move on with your life. https://stackoverflow.com/a/29088337/951349
Thanks #Morten. I've updated the sample code to handle word separation. It also eliminates extra spaces in between words. It has not been tested in the field, but my tests have, thus far, proven OK. Please update at your leisure if you find improvements or bug/glitch fixes.
-(NSString*)string:(NSString*)sourceString reducedToWidth:(CGFloat)width withFont:(UIFont*)font {
// if full string is within bounds, simply return the full string
if( [sourceString sizeWithFont:font].width <= width ) return sourceString;
// break up string into words. if <= 1 word, return original string
NSArray* words = [sourceString componentsSeparatedByString:#" "];
NSInteger numWords = [words count];
if( numWords <= 1 ) return sourceString;
// our return var. we populate as we go
NSMutableString* str = [NSMutableString string];
// temp var to test with before adding to return string
NSMutableString* strTemp = [NSMutableString string];
// string to hold word LESS spaces
NSString* strWordTemp = nil;
// the word we're currently on
NSInteger numWord = 0;
// whether we need to add a space (when not last word)
Boolean addSpace = NO;
// loop through our words....
for( NSString* strWord in words ) {
// which word we're on
numWord++;
// eliminate white space
strWordTemp = [strWord stringByReplacingOccurrencesOfString:#" " withString:#""];
// if this word is empty or was a space(s), skip it
if( [strWordTemp isEqualToString:#""] ) continue;
// append to temp string
[strTemp appendString:strWordTemp];
// if we're still within the bounds...
if( [strTemp sizeWithFont:font].width <= width ) {
// default = no extra space
addSpace = NO;
// if we're not the last word, add a space & check for length
if( numWord < numWords ) {
[strTemp appendString:#" "];
// if adding space made it too long, then just don't add it!
if( [strTemp sizeWithFont:font].width > width ) {
// it was too long with space, so we'll just add word
[str appendString:strWordTemp];
break;
}
// otherwise, it's OK to add the space
else addSpace = YES;
}
// append to return string and continue
[str appendFormat:#"%#%#", strWordTemp, ( addSpace ? #" " : #"" )];
}
// otherwise, we're done
else break;
}
// return our result
return str;
}
i'm trying to build a function that will tell me the range of a string at an occurrence.
For example if I had the string "hello, hello, hello", I want to know the range of hello at it's, lets say, third occurrence.
I've tried building this simple function, but it doesn't work.
Note - the top functions were constructed at an earlier date and work fine.
Any help appreciated.
- (NSString *)stringByTrimmingString:(NSString *)stringToTrim toChar:(NSUInteger)toCharacterIndex {
if (toCharacterIndex > [stringToTrim length]) return #"";
NSString *devString = [[[NSString alloc] init] autorelease];
for (int i = 0; i <= toCharacterIndex; i++) {
devString = [NSString stringWithFormat:#"%#%#", devString, [NSString stringWithFormat:#"%c", [stringToTrim characterAtIndex:(i-1)]]];
}
return devString;
[devString release];
}
- (NSString *)stringByTrimmingString:(NSString *)stringToTrim fromChar:(NSUInteger)fromCharacterIndex {
if (fromCharacterIndex > [stringToTrim length]) return #"";
NSString *devString = [[[NSString alloc] init] autorelease];
for (int i = (fromCharacterIndex+1); i <= [stringToTrim length]; i++) {
devString = [NSString stringWithFormat:#"%#%#", devString, [NSString stringWithFormat:#"%c", [stringToTrim characterAtIndex:(i-1)]]];
}
return devString;
[devString release];
}
- (NSRange)rangeOfString:(NSString *)substring inString:(NSString *)string atOccurence:(int)occurence {
NSString *trimmedString = [inString copy]; //We start with the whole string.
NSUInteger len, loc, oldLength;
len = 0;
loc = 0;
NSRange tempRange = [string rangeOfString:substring];
len = tempRange.length;
loc = tempRange.location;
for (int i = 0; i != occurence; i++) {
NSUInteger endOfWord = len+loc;
trimmedString = [self stringByTrimmingString:trimmedString fromChar:endOfWord];
oldLength += [[self stringByTrimmingString:trimmedString toChar:endOfWord] length];
NSRange tmp = [trimmedString rangeOfString:substring];
len = tmp.length;
loc = tmp.location + oldLength;
}
NSRange returnRange = NSMakeRange(loc, len);
return returnRange;
}
Instead of trimming the string a bunch of times (slow), just use rangeOfString:options:range:, which searches only within the range passed as its third argument. See Apple's documentation.
So try:
- (NSRange)rangeOfString:(NSString *)substring
inString:(NSString *)string
atOccurence:(int)occurence
{
int currentOccurence = 0;
NSRange rangeToSearchWithin = NSMakeRange(0, string.length);
while (YES)
{
currentOccurence++;
NSRange searchResult = [string rangeOfString: substring
options: NULL
range: rangeToSearchWithin];
if (searchResult.location == NSNotFound)
{
return searchResult;
}
if (currentOccurence == occurence)
{
return searchResult;
}
int newLocationToStartAt = searchResult.location + searchResult.length;
rangeToSearchWithin = NSMakeRange(newLocationToStartAt, string.length - newLocationToStartAt);
}
}
You need to rework the whole code. While it may seem to work, it's poor coding and plain wrong, like permanently reassigning the same variable, initializing but reassigning one line later, releasing after returning (which will never work).
For your question: Just use rangeOfString:options:range:, and do this the appropriate number of times while just incrementing the starting point.