So I am trying to link to a Facebook page on iOS6 from my app using
NSString* urlString = #"https://www.facebook.com/vioside";
[[UIApplication sharedApplication] openURL:[NSURL URLWithString: urlString]];
This opens up the Facebook app successfully but it doesn't go on my page. Anyone has an idea on how to link properly on iOS6?
The problem is that you may not use the short name. It has to be the 'id' for it to work currently.
iOS6 and facbook URLs not opening correctly in facebook app
I fixed this myself by removing the 'www' from the url. It's funny but with the 'www' is only opens the Facebook app, after removing it, safari is opened instead and views the proper page. Maybe it's an iOS6 bug but this worked for me
Replace "www.facebook.com" with "m.facebook.com":
NSString* urlString = #"https://m.facebook.com/vioside";
[[UIApplication sharedApplication] openURL:[NSURL URLWithString: urlString]];
it's working fine i tested it as like:-
- (void)viewDidLoad
{
[super viewDidLoad];
NSString* urlString = #"https://www.facebook.com/vioside";
[[UIApplication sharedApplication] openURL:[NSURL URLWithString: urlString]];
}
Related
I am working on a map application in my iPhone app.
I have a button go.
When the user clicks this button in this method I want to check if user has installed the waze application on his iphone. If yes then navigate to waze application otherwise open iPhone's default map app.
Try to do this way :
NSString *wazeAppURL = #"waze://";
NSString *mapsAppURL = #"maps://";
BOOL canOpenURL = [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:wazeAppURL]];
NSString *url = canOpenURL ? wazeAppURL : mapsAppURL;
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:url]];
Here, canOpenURL allows you to test if the Waze app is installed on your iPhone. if iPhone can open the url waze:// it means you already have the app and it will launch it. Otherwise it will launch the default Maps app. Safari won't be called.
To open an app you need to call
BOOL canOpenURL = [[UIApplication sharedApplication]
canOpenURL:[NSURL URLWithString:#"app://"]];
if ( canOpenUrl ) [[UIApplication sharedApplication]
openURL:[NSURL URLWithString:url]];
To find all the url, go to this page: http://handleopenurl.com/
For waze in particular, http://handleopenurl.com/scheme/waze
hope this helps.
Note that on iOS you can also navigate to Google Maps -- and pass along the query string or geopoint. Here's one example of navigating to a specific geopoint:
if (self.mapView.userLocation.location) {
NSString *urlAsString = [NSString stringWithFormat:#"comgooglemaps://?q=%f,%f", self.mapView.userLocation.location.coordinate.latitude, self.mapView.userLocation.location.coordinate.longitude];
if ([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:urlAsString]]) {
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlAsString]];
}
}
Just a suggestion to enhance the user experience.
I am making an app for a charity and Apple's review guidelines state that all donations must be made outside of the app in Safari, except for SMS donations, which we're not doing anyway. How do I make a button, that when tapped, goes to a specific URL in Safari? Thanks for your help!
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"your.website.here"]];
And put it in an IBAction for your button.
There might be a problem connecting to your site try this:
NSURL *url = [NSURLWithString:#"your.website.here"];
if (![[UIApplication sharedApplication] openURL:url])
NSLog(#"%#%#",#"Failed to open url:",[url description]);
They actually have a post on it here:
How can I launch Safari from an iPhone app?
You can use this code in button click event
[[UIApplication sharedApplication] openURL:[NSURL URLWithString: #"your url"]];
it automatically opens in safari
I am able to call from my iphone application by using below code:
NSString *phoneNumber = #"tel://1234567890";
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];
Now, i want to know how to return to my application back when the call ends ?
UIWebView *phoneCallWebview = [[UIWebView alloc] init];
// [self.view addSubview:phoneCallWebview];
NSURL *callURL = [NSURL URLWithString:[NSString stringWithFormat:#"tel:%#", 9238928399]];
[phoneCallWebview loadRequest:[NSURLRequest requestWithURL:callURL ]];
As far as I'm aware, such interaction is impossible since your application has been demoted to background, and all UI interaction has been delegated to the Phone app, and the user.
I found this SO question
End call, don't return to app automatic in iphone 3.1 version
Which pointed to an article on apple dev forums
https://devforums.apple.com/message/128046 (dev account required)
Which says it was a change in iOS 3.1 but a "workaround" is
use UIWebView to open the tel: url, after the call, your app will relaunch, but you get the annoying do you want to make this call alert.
I have't verified this works as described, just thought I'd point it out
From iOS 5, use below...
NSString *phoneNumber = [#"telprompt://" stringByAppendingString:#"12345678"];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];
Just use telprompt:// instead of tel://
telprompt will prompt the user first, and when call ends,it will go back to your application.
NSString *myNumber = [#"telprompt://" stringByAppendingString:txtMobileNo.titleLabel.text];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:myNumber]];
I have read a lot of topics, but i don't find when i want
I want to launch google map api from my application with that:
[[UIApplication sharedApplication] openURL:[NSURL URLWithString: #"http://maps.google.com/maps?saddr=41.029598,28.972985&daddr=41.033586,28.984546"]]
But it's open safari with Google maps page. I want open Google map API with my route. There is a maps:// or other things?
Thanks for help !!!
Try this
UIApplication *app = [UIApplication sharedApplication];
NSURL *url = [[NSURL alloc] initWithString: #"http://maps.google.com/maps?saddr=41.029598,28.972985&daddr=41.033586,28.984546"];
[app openURL:url];
[url release];
have a look at the Apple URL Scheme Reference for MapLinks
Edit: your URL looks correct. Looks like you are testing on Simulator! GoogleMaps app is only available on device!
Try this
NSString *urlstring=[NSString stringWithFormat:#"http://maps.google.com/?&saddr=%# &daddr=%#",sourceaddress,destinationaddress];
[[UIApplication sharedApplication]openURL:[NSURL URLWithString:urlstring]];
I am in this situation where I have to display a button which says "Open myApp" (if myApp is installed on the device) or it says "Download myApp" (if myApp is not installed on the device) in an iphone app. To do this, I need to detect whether an app (with a known custom URL) has been installed on the device. How can I do this? Thanks in advance.
UPDATED 8th January 2014 - 3 things you can do
I actually had to do this for a client again. They wanted users to be able to open their second app from the main app if it had been installed.
This is my finding. Use the canOpenURL method to check if an app is installed or/and then use the openURL method to
Open the application installed on the iOS device
Take the user to the app store directly pointing them to the app/your list of developer apps
Take them to a website instead
All code samples available for each scenario
//Find out if the application has been installed on the iOS device
- (BOOL)isMyAppInstalled {
return [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:#"nameOfMyApp:"]];
}
- (IBAction)openOrDownloadApp {
//This will return true if the app is installed on the iOS device
if ([self myAppIsInstalled]){
//Opens the application
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"nameOfMyApp:"]];
}
else { //App is not installed so do one of following:
//1. Take the user to the apple store so they can download the app
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"itms://itunes.com/apps/nameOfMyApp"]];
//OR
//2. Take the user to a list of applications from a developer
//or company exclude all punctuation and space characters.
//for example 'Pavan's Apps'
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"itms://itunes.com/apps/PavansApps"]];
//OR
//3. Take your users to a website instead, with maybe instructions/information
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"http://www.pavan.com/WhyTheHellDidTheAppNotOpen_what_now.html"]];
}
}
Choose one option, I've just spoiled you with choice. Choose one that fits your requirements.
In my case I had to use all three options in different areas of the program.
If the URL scheme for your app is "myapp:", then
BOOL myAppInstalled = [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:#"myapp:"]];
(Requires iOS 3.0.)
To check app is install in device or not
1) In info.plist add LSApplicationQueriesSchemes as below example
2) and in URL Types
3) Now to check app is install or not
- (IBAction)openAppPressed:(UIButton *)sender {
NSString *urlString = #"XYZAPP://";
NSURL *url = [NSURL URLWithString:urlString];
if ([[UIApplication sharedApplication] canOpenURL:url]) {
[[UIApplication sharedApplication] openURL:url];
}
else {
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"itunes link for download app"]];
}
}
You can add a simple meta tag in the head of any page that needs this app-sniffing.
For more info, go here:
http://developer.apple.com/library/ios/#documentation/AppleApplications/Reference/SafariWebContent/PromotingAppswithAppBanners/PromotingAppswithAppBanners.html
For those using canOpenURL it is always safe to migrate from this to openURL:options:completionHandler:
NSString *urlString = #"XYZAPP://";
NSURL *url = [NSURL URLWithString:urlString];
[[UIApplication sharedApplication] openURL:url options:#{} completionHandler:^(BOOL success) {
if (!success) {
[[UIApplication sharedApplication] openURL:appStoreUrl options:#{} completionHandler:nil];
}
}];
because that doesn't require you to declare the scheme ahead of time.
canOpenURL which is deprecated already has some odd limitations because Twitter used it to detect hundreds of apps long ago.