How to launch another app from an iPhone app - iphone

I am working on a map application in my iPhone app.
I have a button go.
When the user clicks this button in this method I want to check if user has installed the waze application on his iphone. If yes then navigate to waze application otherwise open iPhone's default map app.

Try to do this way :
NSString *wazeAppURL = #"waze://";
NSString *mapsAppURL = #"maps://";
BOOL canOpenURL = [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:wazeAppURL]];
NSString *url = canOpenURL ? wazeAppURL : mapsAppURL;
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:url]];
Here, canOpenURL allows you to test if the Waze app is installed on your iPhone. if iPhone can open the url waze:// it means you already have the app and it will launch it. Otherwise it will launch the default Maps app. Safari won't be called.

To open an app you need to call
BOOL canOpenURL = [[UIApplication sharedApplication]
canOpenURL:[NSURL URLWithString:#"app://"]];
if ( canOpenUrl ) [[UIApplication sharedApplication]
openURL:[NSURL URLWithString:url]];
To find all the url, go to this page: http://handleopenurl.com/
For waze in particular, http://handleopenurl.com/scheme/waze
hope this helps.

Note that on iOS you can also navigate to Google Maps -- and pass along the query string or geopoint. Here's one example of navigating to a specific geopoint:
if (self.mapView.userLocation.location) {
NSString *urlAsString = [NSString stringWithFormat:#"comgooglemaps://?q=%f,%f", self.mapView.userLocation.location.coordinate.latitude, self.mapView.userLocation.location.coordinate.longitude];
if ([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:urlAsString]]) {
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlAsString]];
}
}
Just a suggestion to enhance the user experience.

Related

Opening an Native ios App inside an Another App?

i have this idiotic Question .
Is there any way open an another ios Application inside a view controller of a app.
I know we can open a another Ios app if we have url schema and the calling application goes to background and called application goes to background.
Is there any way ?? i just got a dream ,so am asking can we do it??
It is not possible to do it with the iPhone SDK. You can do this though by using Private APIs.
You can make it work on jailbroken devices.
But if you want to call native social apps like facebook or twitter you should use this code.
It works and apple approves it.
NSURL *fbNativeAppURL = [NSURL URLWithString:#"fb://"];
if ( [[UIApplication sharedApplication] canOpenURL:fbNativeAppURL])
{
[[UIApplication sharedApplication] openURL:fbNativeAppURL];
}
or
NSURL *twNativeAppURL = [NSURL URLWithString:#"twitter://"];
if ( [[UIApplication sharedApplication] canOpenURL:twNativeAppURL])
{
[[UIApplication sharedApplication] openURL:twNativeAppURL];
}

Integrating native map app first direct to safari

In my app, I have integrated native map app for showing directions between two points on button action. I am using the following code.
- (IBAction)showRoute
{
NSString *urlString = [NSString stringWithFormat:#"http://maps.apple.com/maps? daddr=%#,%#&saddr=%f,%f",d_latitude,d_longitude, s_latitude, s_longitude];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];
}
But the problem is when click the button it first redirects to safari and then maps app - is there any way to miss out the safari step ?
In which iOS have you tried.? I tried on iOS 6 simulator works fine, opens the map app directly. In iOS simulator it opened safari has it doesn't have map app on simulator.
I have tried the below code on button action, its similar the one you used.
NSString* url = [NSString stringWithFormat:#"http://maps.apple.com/maps?daddr=%f,%f&saddr=Current%%20Location", 40.7142, 74.0064];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:url]];

How to move the user to a URL in Safari

I am making an app for a charity and Apple's review guidelines state that all donations must be made outside of the app in Safari, except for SMS donations, which we're not doing anyway. How do I make a button, that when tapped, goes to a specific URL in Safari? Thanks for your help!
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"your.website.here"]];
And put it in an IBAction for your button.
There might be a problem connecting to your site try this:
NSURL *url = [NSURLWithString:#"your.website.here"];
if (![[UIApplication sharedApplication] openURL:url])
NSLog(#"%#%#",#"Failed to open url:",[url description]);
They actually have a post on it here:
How can I launch Safari from an iPhone app?
You can use this code in button click event
[[UIApplication sharedApplication] openURL:[NSURL URLWithString: #"your url"]];
it automatically opens in safari

How to return to my iphone application after call ends?

I am able to call from my iphone application by using below code:
NSString *phoneNumber = #"tel://1234567890";
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];
Now, i want to know how to return to my application back when the call ends ?
UIWebView *phoneCallWebview = [[UIWebView alloc] init];
// [self.view addSubview:phoneCallWebview];
NSURL *callURL = [NSURL URLWithString:[NSString stringWithFormat:#"tel:%#", 9238928399]];
[phoneCallWebview loadRequest:[NSURLRequest requestWithURL:callURL ]];
As far as I'm aware, such interaction is impossible since your application has been demoted to background, and all UI interaction has been delegated to the Phone app, and the user.
I found this SO question
End call, don't return to app automatic in iphone 3.1 version
Which pointed to an article on apple dev forums
https://devforums.apple.com/message/128046 (dev account required)
Which says it was a change in iOS 3.1 but a "workaround" is
use UIWebView to open the tel: url, after the call, your app will relaunch, but you get the annoying do you want to make this call alert.
I have't verified this works as described, just thought I'd point it out
From iOS 5, use below...
NSString *phoneNumber = [#"telprompt://" stringByAppendingString:#"12345678"];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];
Just use telprompt:// instead of tel://
telprompt will prompt the user first, and when call ends,it will go back to your application.
NSString *myNumber = [#"telprompt://" stringByAppendingString:txtMobileNo.titleLabel.text];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:myNumber]];

Detecting programmatically whether an app is installed on iPhone

I am in this situation where I have to display a button which says "Open myApp" (if myApp is installed on the device) or it says "Download myApp" (if myApp is not installed on the device) in an iphone app. To do this, I need to detect whether an app (with a known custom URL) has been installed on the device. How can I do this? Thanks in advance.
UPDATED 8th January 2014 - 3 things you can do
I actually had to do this for a client again. They wanted users to be able to open their second app from the main app if it had been installed.
This is my finding. Use the canOpenURL method to check if an app is installed or/and then use the openURL method to
Open the application installed on the iOS device
Take the user to the app store directly pointing them to the app/your list of developer apps
Take them to a website instead
All code samples available for each scenario
//Find out if the application has been installed on the iOS device
- (BOOL)isMyAppInstalled {
return [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:#"nameOfMyApp:"]];
}
- (IBAction)openOrDownloadApp {
//This will return true if the app is installed on the iOS device
if ([self myAppIsInstalled]){
//Opens the application
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"nameOfMyApp:"]];
}
else { //App is not installed so do one of following:
//1. Take the user to the apple store so they can download the app
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"itms://itunes.com/apps/nameOfMyApp"]];
//OR
//2. Take the user to a list of applications from a developer
//or company exclude all punctuation and space characters.
//for example 'Pavan's Apps'
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"itms://itunes.com/apps/PavansApps"]];
//OR
//3. Take your users to a website instead, with maybe instructions/information
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"http://www.pavan.com/WhyTheHellDidTheAppNotOpen_what_now.html"]];
}
}
Choose one option, I've just spoiled you with choice. Choose one that fits your requirements.
In my case I had to use all three options in different areas of the program.
If the URL scheme for your app is "myapp:", then
BOOL myAppInstalled = [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:#"myapp:"]];
(Requires iOS 3.0.)
To check app is install in device or not
1) In info.plist add LSApplicationQueriesSchemes as below example
2) and in URL Types
3) Now to check app is install or not
- (IBAction)openAppPressed:(UIButton *)sender {
NSString *urlString = #"XYZAPP://";
NSURL *url = [NSURL URLWithString:urlString];
if ([[UIApplication sharedApplication] canOpenURL:url]) {
[[UIApplication sharedApplication] openURL:url];
}
else {
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"itunes link for download app"]];
}
}
You can add a simple meta tag in the head of any page that needs this app-sniffing.
For more info, go here:
http://developer.apple.com/library/ios/#documentation/AppleApplications/Reference/SafariWebContent/PromotingAppswithAppBanners/PromotingAppswithAppBanners.html
For those using canOpenURL it is always safe to migrate from this to openURL:options:completionHandler:
NSString *urlString = #"XYZAPP://";
NSURL *url = [NSURL URLWithString:urlString];
[[UIApplication sharedApplication] openURL:url options:#{} completionHandler:^(BOOL success) {
if (!success) {
[[UIApplication sharedApplication] openURL:appStoreUrl options:#{} completionHandler:nil];
}
}];
because that doesn't require you to declare the scheme ahead of time.
canOpenURL which is deprecated already has some odd limitations because Twitter used it to detect hundreds of apps long ago.