I have this select statement, I want to export them to json array with an another nested json agregate function but postgres says that "aggregate function calls cannot be nested", I can not figure aout how i can do this.
select json_agg(json_build_object(
'plan_number', plan.id,
'plan_carrier_code', carrier_plan.carrier_code,
'plan_name', plan.plan_name,
'plan_mac', mac.mac_name,
'plan_termination_date', plan.termination_date,
'plan_mod_start_date', plan.mod_start_date,
'plan_mod_user', plan.mod_user,
'plan_opt_brandcode_g_on_mn_as_generic_copay', plan.opt_brandcode_g_on_mn_as_generic_copay,
'plan_opt_exclude_daw2_from_ded_calculations', plan.opt_exclude_daw2_from_ded_calculations,
'plan_opt_exclude_daw2_from_oop_calculations', plan.opt_exclude_daw2_from_oop_calculations,
'plan_opt_limit_patient_pay_to_pay', plan.opt_limit_patient_pay_to_pay,
'plan_opt_only_pay_primary_claims', plan.opt_only_pay_primary_claims,
'plan_opt_allow_discontinued_drugs', plan.opt_allow_discontinued_drugs,
'plan_opt_allow_negative_payments_to_pharmacy', plan.opt_allow_negative_payments_to_pharmacy,
'plan_opt_process_y_drugs_as_preferred', plan.opt_process_y_drugs_as_preferred,
'plan_opt_reject_otc', plan.opt_reject_otc,
'plan_opt_reject_repackaged_drugs', plan.opt_reject_repackaged_drugs,
'plan_opt_test_only', plan.opt_test_only,
'plan_opt_cost_effective_pricing', plan.opt_cost_effective_pricing,
'plan_opt_original_mony_for_copay', plan.opt_original_mony_for_copay,
'plan_daw_differential', json_agg(json_build_object(
'plan_daw_differential_daw_code', plan_daw_differential.daw_code,
'plan_daw_differential_claim_type', plan_daw_differential.claim_type,
'plan_daw_differential_updated_at', plan_daw_differential.updated_at,
'plan_daw_differential_updated_by', plan_daw_differential.updated_by
))
)) as plan
from splan.groups_plan_list gpl
left join splan.plan plan on plan.id = gpl.plan_id
left join splan.carrier carrier_plan on carrier_plan.id = plan.carrier_id
left join splan.plan_daw_differential plan_daw_differential on plan_daw_differential.parent_id = plan.id
left join sdrug.mac mac on mac.id = plan.mac_id
where gpl.parent_id = 69;
but it throws me an error that said "aggregate function calls cannot be nested"
the expected result can be:
[
{
"plan_number":1,
"plan_carrier_code":"lltest",
"plan_daw_differential":[
{
"plan_daw_differential_daw_code":"0505",
"plan_daw_differential_claim_type":"02"
},
{
"plan_daw_differential_daw_code":"0505",
"plan_daw_differential_claim_type":"02"
}
]
}
]
Options:
use subquery (or join lateral) to evaluate plan_daw_differential element for every plan element.
using GROUP BY plan... gpl... carrier_plan... mac...
Because the solutions differ in execution plan you will have to pick one that fits your requirements the most.
I would go with first option in most cases. It is more compact easier to write and maintain. The only reason to pick the second would be requirement to filter the plan using data from plan_daw_differential table.
Examples:
Subquery:
select json_agg(json_build_object(
'plan_number', plan.id,
'plan_carrier_code', carrier_plan.carrier_code,
'plan_name', plan.plan_name,
'plan_mac', mac.mac_name,
'plan_termination_date', plan.termination_date,
'plan_mod_start_date', plan.mod_start_date,
'plan_mod_user', plan.mod_user,
'plan_opt_brandcode_g_on_mn_as_generic_copay', plan.opt_brandcode_g_on_mn_as_generic_copay,
'plan_opt_exclude_daw2_from_ded_calculations', plan.opt_exclude_daw2_from_ded_calculations,
'plan_opt_exclude_daw2_from_oop_calculations', plan.opt_exclude_daw2_from_oop_calculations,
'plan_opt_limit_patient_pay_to_pay', plan.opt_limit_patient_pay_to_pay,
'plan_opt_only_pay_primary_claims', plan.opt_only_pay_primary_claims,
'plan_opt_allow_discontinued_drugs', plan.opt_allow_discontinued_drugs,
'plan_opt_allow_negative_payments_to_pharmacy', plan.opt_allow_negative_payments_to_pharmacy,
'plan_opt_process_y_drugs_as_preferred', plan.opt_process_y_drugs_as_preferred,
'plan_opt_reject_otc', plan.opt_reject_otc,
'plan_opt_reject_repackaged_drugs', plan.opt_reject_repackaged_drugs,
'plan_opt_test_only', plan.opt_test_only,
'plan_opt_cost_effective_pricing', plan.opt_cost_effective_pricing,
'plan_opt_original_mony_for_copay', plan.opt_original_mony_for_copay,
'plan_daw_differential', (
SELECT
json_agg(json_build_object(
'plan_daw_differential_daw_code', plan_daw_differential.daw_code,
'plan_daw_differential_claim_type', plan_daw_differential.claim_type,
'plan_daw_differential_updated_at', plan_daw_differential.updated_at,
'plan_daw_differential_updated_by', plan_daw_differential.updated_by
))
FROM
splan.plan_daw_differential plan_daw_differential
WHERE
plan_daw_differential.parent_id = plan.id )
)) as plan
from
splan.groups_plan_list gpl
left join splan.plan plan on plan.id = gpl.plan_id
left join splan.carrier carrier_plan on carrier_plan.id = plan.carrier_id
left join sdrug.mac mac on mac.id = plan.mac_id
where
gpl.parent_id = 69;
Grouping:
select json_agg(json_build_object(
'plan_number', plan_number,
'plan_carrier_code', plan_carrier_code,
'plan_name', plan_name,
'plan_mac', plan_mac,
'plan_termination_date', plan_termination_date,
'plan_mod_start_date', plan_mod_start_date,
'plan_mod_user', plan_mod_user,
'plan_opt_brandcode_g_on_mn_as_generic_copay', plan_opt_brandcode_g_on_mn_as_generic_copay,
'plan_opt_exclude_daw2_from_ded_calculations', plan_opt_exclude_daw2_from_ded_calculations,
'plan_opt_exclude_daw2_from_oop_calculations', plan_opt_exclude_daw2_from_oop_calculations,
'plan_opt_limit_patient_pay_to_pay', plan_opt_limit_patient_pay_to_pay,
'plan_opt_only_pay_primary_claims', plan_opt_only_pay_primary_claims,
'plan_opt_allow_discontinued_drugs', plan_opt_allow_discontinued_drugs,
'plan_opt_allow_negative_payments_to_pharmacy', plan_opt_allow_negative_payments_to_pharmacy,
'plan_opt_process_y_drugs_as_preferred', plan_opt_process_y_drugs_as_preferred,
'plan_opt_reject_otc', plan_opt_reject_otc,
'plan_opt_reject_repackaged_drugs', plan_opt_reject_repackaged_drugs,
'plan_opt_test_only', plan_opt_test_only,
'plan_opt_cost_effective_pricing', plan_opt_cost_effective_pricing,
'plan_opt_original_mony_for_copay', plan_opt_original_mony_for_copay,
'plan_daw_differential', draw_differential_arr
)) as plan
FROM (
SELECT
plan.id AS plan_number,
carrier_plan.carrier_code AS plan_carrier_code,
plan.plan_name AS plan_name,
mac.mac_name AS plan_mac,
plan.termination_date AS plan_termination_date,
plan.mod_start_date AS plan_mod_start_date,
plan.mod_user AS plan_mod_user,
plan.opt_brandcode_g_on_mn_as_generic_copay AS plan_opt_brandcode_g_on_mn_as_generic_copay,
plan.opt_exclude_daw2_from_ded_calculations AS plan_opt_exclude_daw2_from_ded_calculations,
plan.opt_exclude_daw2_from_oop_calculations AS plan_opt_exclude_daw2_from_oop_calculations,
plan.opt_limit_patient_pay_to_pay AS plan_opt_limit_patient_pay_to_pay,
plan.opt_only_pay_primary_claims AS plan_opt_only_pay_primary_claims,
plan.opt_allow_discontinued_drugs AS plan_opt_allow_discontinued_drugs,
plan.opt_allow_negative_payments_to_pharmacy AS plan_opt_allow_negative_payments_to_pharmacy,
plan.opt_process_y_drugs_as_preferred AS plan_opt_process_y_drugs_as_preferred,
plan.opt_reject_otc AS plan_opt_reject_otc,
plan.opt_reject_repackaged_drugs AS plan_opt_reject_repackaged_drugs,
plan.opt_test_only AS plan_opt_test_only,
plan.opt_cost_effective_pricing AS plan_opt_cost_effective_pricing,
plan.opt_original_mony_for_copay AS plan_opt_original_mony_for_copay,
json_agg(json_build_object(
'plan_daw_differential_daw_code', plan_daw_differential.daw_code,
'plan_daw_differential_claim_type', plan_daw_differential.claim_type,
'plan_daw_differential_updated_at', plan_daw_differential.updated_at,
'plan_daw_differential_updated_by', plan_daw_differential.updated_by
)) as draw_differential_arr
FROM
splan.groups_plan_list gpl
left join splan.plan plan on plan.id = gpl.plan_id
left join splan.carrier carrier_plan on carrier_plan.id = plan.carrier_id
left join splan.plan_daw_differential plan_daw_differential on plan_daw_differential.parent_id = plan.id
left join sdrug.mac mac on mac.id = plan.mac_id
WHERE
gpl.parent_id = 69
GROUP BY
plan.id,
carrier_plan.carrier_code,
plan.plan_name,
mac.mac_name,
plan.termination_date,
plan.mod_start_date,
plan.mod_user,
plan.opt_brandcode_g_on_mn_as_generic_copay,
plan.opt_exclude_daw2_from_ded_calculations,
plan.opt_exclude_daw2_from_oop_calculations,
plan.opt_limit_patient_pay_to_pay,
plan.opt_only_pay_primary_claims,
plan.opt_allow_discontinued_drugs,
plan.opt_allow_negative_payments_to_pharmacy,
plan.opt_process_y_drugs_as_preferred,
plan.opt_reject_otc,
plan.opt_reject_repackaged_drugs,
plan.opt_test_only,
plan.opt_cost_effective_pricing,
plan.opt_original_mony_for_copay
) AS plan_row
I'm trying to find out how to get JSON object results of selected rows, and not to show duplicated rows.
My current query:
SELECT DISTINCT ON (vp.id) jsonb_agg(jsonb_build_object('affiliate',a.*)) as affiliates, jsonb_agg(jsonb_build_object('vendor',vp.*)) as vendors FROM
affiliates a
INNER JOIN related_affiliates ra ON a.id = ra.affiliate_id
INNER JOIN related_vendors rv ON ra.product_id = rv.product_id
INNER JOIN vendor_partners vp ON rv.vendor_partner_id = vp.id
WHERE ra.product_id = 79 AND a.is_active = true
GROUP BY vp.id
The results that I receive from this is:
[
affiliates: {
affiliate: affiliate1
affiliate: affiliate2
},
vendors: {
vendor: vendor1,
vendor: vendor1,
}
As you can see in the second record, vendor is still vendor1 because there are no more results, so I'd like to also know if there's a way to remove duplicates.
Thanks.
First point : the result you display here above doesn't conform the json type : the keys are not double-quoted, the string values are not double-quoted, having dupplicated keys in the same json object ('{"affiliate": "affiliate1", "affiliate": "affiliate2"}' :: json) is not be accepted with the jsonb type (but it is with the json type).
Second point : you can try to add the DISTINCT key word directly in the jsonb_agg function :
jsonb_agg(DISTINCT jsonb_build_object('vendor',vp.*))
and remove the DISTINCT ON (vp.id) clause.
You can also add an ORDER BY clause directly in any aggregate function. For more information, see the manual.
You could aggregate first, then join on the results of the aggregates:
SELECT a.affiliates, v.vendors
FROM (
select af.id, jsonb_agg(jsonb_build_object('affiliate',af.*)) as affiliates
from affiliates af
group by af.id
) a
JOIN related_affiliates ra ON a.id = ra.affiliate_id
JOIN related_vendors rv ON ra.product_id = rv.product_id
JOIN (
select vp.id, jsonb_agg(jsonb_build_object('vendor',vp.*)) as vendors
from vendor_partners vp
group by vp.id
) v ON rv.vendor_partner_id = v.id
WHERE ra.product_id = 79
AND a.is_active = true
I would like to ask if it is possible to select again from a result set if a column contains a specific value?
For example, from the below query I want to select it as subquery and check if that subquery's first column contains both 2 and 3 result. Otherwise, no values should be return.
select e.evaluator_id, ROUND(avg(cast(e.rating_score as int))::numeric,1)::varchar, c.q_category_name
from tms.t_evaluation e
inner join tms.m_q_category c
on e.nendo=c.nendo
and e.q_category_id = c.q_category_id
and c.delete_flg = '0'
inner join tms.m_q_subcategory qs
on e.q_category_id = qs.q_category_id
and e.q_subcategory_id = qs.q_subcategory_id
and c.nendo = qs.nendo
and qs.delete_flg = '0'
where e.nendo = '2018'
and e.empl_id = 'empl05'
and e.delete_flg = '0'
and e.evaluator_id in ('2' , '3')
group by e.empl_id, e.nendo, e.q_category_id,
c.q_category_name, e.evaluator_id, e.history_no
Result contains both 2 and 3 in first column. Is this possible?
select e.evaluator_id, ROUND(avg(cast(e.rating_score as int))::numeric,1)::varchar, c.q_category_name
from tms.t_evaluation e
inner join tms.m_q_category c
on e.nendo=c.nendo
and e.q_category_id = c.q_category_id
and c.delete_flg = '0'
inner join tms.m_q_subcategory qs
on e.q_category_id = qs.q_category_id
and e.q_subcategory_id = qs.q_subcategory_id
and c.nendo = qs.nendo
and qs.delete_flg = '0'
where e.nendo = '2018'
and e.empl_id = 'empl05'
and e.delete_flg = '0'
and e.evaluator_id in (select case when evaluator_id=2 or evaluator_id=3 then evaluator_id else null from t_evaluation order by evaluator_id asc)
group by e.empl_id, e.nendo, e.q_category_id,
c.q_category_name, e.evaluator_id, e.history_no
SELECT
nzy.NZPYYD
,nzy.NZZSYG
,nzy.NZJRYG
,acn.ANITCD
FROM
ACNTRA acn
LEFT OUTER JOIN NZYTFL nzy
ON (
nzy.NZCNO1 = acn.ANCNO1
AND nzy.NZCNO2 = acn.ANCNO2
AND nzy.NZCNO3 = acn.ANCNO3
AND nzy.NZCNO4 = acn.ANCNO4
AND nzy.NZCNO5 = acn.ANCNO5
AND nzy.NZSLKI = acn.ANSLKI
AND nzy.NZDLTM = ''
)
WHERE
acn.ANDLTM = ''
AND acn.ANTKCD = '1029'
AND nzy.NZTXKB = 1
The problem here is it gives 2 rows result.I want to get one unique row from the result of left outer join .Any help?
If both rows are identical, try
SELECT DISTINCT
nzy.NZPYYD
,nzy.NZZSYG
,nzy.NZJRYG
,acn.ANITCD
If not, you can try to SUM(), CONCAT(), MAX() or whatever the column with different values.
Difficult to be more precise without a sample output.