I'm trying to find out how to get JSON object results of selected rows, and not to show duplicated rows.
My current query:
SELECT DISTINCT ON (vp.id) jsonb_agg(jsonb_build_object('affiliate',a.*)) as affiliates, jsonb_agg(jsonb_build_object('vendor',vp.*)) as vendors FROM
affiliates a
INNER JOIN related_affiliates ra ON a.id = ra.affiliate_id
INNER JOIN related_vendors rv ON ra.product_id = rv.product_id
INNER JOIN vendor_partners vp ON rv.vendor_partner_id = vp.id
WHERE ra.product_id = 79 AND a.is_active = true
GROUP BY vp.id
The results that I receive from this is:
[
affiliates: {
affiliate: affiliate1
affiliate: affiliate2
},
vendors: {
vendor: vendor1,
vendor: vendor1,
}
As you can see in the second record, vendor is still vendor1 because there are no more results, so I'd like to also know if there's a way to remove duplicates.
Thanks.
First point : the result you display here above doesn't conform the json type : the keys are not double-quoted, the string values are not double-quoted, having dupplicated keys in the same json object ('{"affiliate": "affiliate1", "affiliate": "affiliate2"}' :: json) is not be accepted with the jsonb type (but it is with the json type).
Second point : you can try to add the DISTINCT key word directly in the jsonb_agg function :
jsonb_agg(DISTINCT jsonb_build_object('vendor',vp.*))
and remove the DISTINCT ON (vp.id) clause.
You can also add an ORDER BY clause directly in any aggregate function. For more information, see the manual.
You could aggregate first, then join on the results of the aggregates:
SELECT a.affiliates, v.vendors
FROM (
select af.id, jsonb_agg(jsonb_build_object('affiliate',af.*)) as affiliates
from affiliates af
group by af.id
) a
JOIN related_affiliates ra ON a.id = ra.affiliate_id
JOIN related_vendors rv ON ra.product_id = rv.product_id
JOIN (
select vp.id, jsonb_agg(jsonb_build_object('vendor',vp.*)) as vendors
from vendor_partners vp
group by vp.id
) v ON rv.vendor_partner_id = v.id
WHERE ra.product_id = 79
AND a.is_active = true
Related
I need to insert createdate column twice with two different datatypes one with the datatype defined in the table itself and another in char datatype.
I can insert it by changing the alias name of createdate column but can't insert with same alias name which i need.
so help me out to get correct way of doing it.
My query:
SELECT DISTINCT TE.id, T.debatchqueuelink, TE.transactionlink,
EC.errorclassification, TE.errorvalue,
EC.errorparameter, TE.classificationlink, TE.description,
TE.createdate AS createdate, TO_CHAR(TE.createdate, 'MM/dd/yyyy') AS createdate,
TE.status, TE.rebutt, TE.rebuttedstatus, BQ.appbatchnumber,
BQ.scanbatchnumber, BQ.clientlink, BQ.locationlink, T.patientid,
(DEUD.firstname|| ' ' ||DEUD.lastname) AS deusername, DEUD.email AS deuseremail,
(QCUD.firstname|| ' ' ||QCUD.lastname) AS qcusername, TE.inactive,
TE.decomment
INTO table373
FROM qctransactionerror TE
INNER JOIN errorclassification EC ON EC.id = TE.classificationlink
INNER JOIN qctransaction T ON T.id = TE.transactionlink
INNER JOIN batchqueue BQ ON T.debatchqueuelink = BQ.id
INNER JOIN batchqueue QCBQ ON T.qcbatchqueuelink = QCBQ.id
INNER JOIN userdetail QCUD ON QCBQ.assignedto = QCUD.id
INNER JOIN userdetail DEUD ON BQ.assignedto = DEUD.id
WHERE TE.inactive='t'
AND TE.status IN ('ERROR','QCCORRECTED')
LIMIT 0
The actual error message I am getting is:
Duplicate column:column "createdate" specified more than once
I need to implement the following T-SQL clause ....
SELECT
CONCAT( RANK() OVER (ORDER BY [Order].codOrder, [PackedOrder].codPackedProduct ), '/2') as Item,
[Order].codOrder as [OF],
[PackedOrder].codLine as [Ligne],
[PackedOrder].codPackedProduct as [Material], ----------------------
[Product].lblPProduct as [Product],
[PackedProduct].lblPackedProduct as [MaterialDescription],
[PackedOrder].codPackedBatch as [Lot],
[Product].codCustomerColor as [ReferenceClient],
[PackedOrder].nbrPackedQuantity as [Quantity],
[PackedOrder].nbrLabelToPrint as [DejaImprime]
FROM [Order] INNER JOIN PackedOrder
ON [Order].codOrder = PackedOrder.codOrder INNER JOIN Product
ON [Order].codProduct = Product.codProduct INNER JOIN PackedProduct
ON PackedOrder.codPackedProduct = PackedProduct.codPackedProduct
Where [Order].codOrder = 708243075
So Far, I'm able to do:
var result =
from order1 in Orders
join packedorder1 in PackedOrders on order1.codOrder equals packedorder1.codOrder
join product1 in Products on order1.codProduct equals product1.codProduct
join packedproduct1 in PackedProducts on packedorder1.codPackedProduct equals packedproduct1.codPackedProduct
where order1.codOrder == _order.codOrder
select new FinishedProductPrintingM
{
OF = order1.codOrder,
Ligne = packedorder1.codLine,
Material = packedorder1.codPackedProduct,
Produit = product1.codProductType,
MaterialDescription = packedproduct1.lblPackedProduct,
Lot = packedorder1.codPackedBatch,
RéférenceClient = product1.codCustomerColor,
Quantité = packedorder1.nbrPackedQuantity,
Déjàimprimé = packedorder1.nbrLabelPrinted
};
Please let me know if its possible or not. I need to display the Items in such a way.Please feel free to add your valuable comments.
I am not aware how to use concat and Rank over function in LINQ.
Can anyone help me to convert my SQL query into LINQ?
First of all, I would like to know if it is possible to do?
Below is my query and I am trying to build using criteria.
SELECT CONCAT('record-', rl.record_id) AS tempId,
'sloka' AS type,
rl.record_id AS recordId,
rl.title AS title,
rl.locale as locale,
rl.intro AS intro,
rl.title AS localetitle,
NULL AS audioUrl,
lp.name AS byName,
lp.person_id AS byId,
lp.name AS onName,
lp.person_id AS onId
FROM record_locale rl
LEFT JOIN record r ON rl.record_id = r.record_id
LEFT JOIN locale_person lp ON r.written_on = lp.person_id
WHERE rl.title LIKE :title
AND rl.locale = :locale
AND lp.locale = :locale
UNION
SELECT CONCAT('lyric-', s.song_id) AS tempId,
'bhajan' AS type,
s.song_id AS recordId,
s.title,
l.locale as locale,
NULL AS intro,
l.title AS localetitle,
s.audio_url AS audioUrl,
lpb.name AS byName,
lpb.person_id AS byId,
lpo.name AS onName,
lpo.person_id AS onId
FROM song s
LEFT JOIN locale_person lpb
ON (s.written_by = lpb.person_id AND lpb.locale = :locale)
LEFT JOIN locale_person lpo
ON (s.written_on = lpo.person_id AND lpo.locale = lpb.locale)
INNER JOIN lyric l
ON (l.locale = lpb.locale AND l.song_id = s.song_id)
WHERE s.title LIKE :title AND s.approved_by IS NOT NULL
ORDER BY localeTitle ASC
// END
Based on few conditions, I might need to have union of both queries or just individual query without union.
Converting the SQL to JPQL is usually a good first step, as we can't quite tell what these tables map to, or what you are expecting to get back. If it is possible to do in JPQL, it should be possible with a criteria query. Except in this case: JPA/JPQL does not have the union operator so it won't work in straight JPA, but some providers such as EclipseLink have support. See:
UNION to JPA Query
and
http://www.eclipse.org/eclipselink/documentation/2.5/jpa/extensions/j_union.htm
Suppose I have an activity table and a subscription table. Each activity has an array of generic references to some other object, and each subscription has a single generic reference to some other object in the same set.
CREATE TABLE activity (
id serial primary key,
ob_refs UUID[] not null
);
CREATE TABLE subscription (
id UUID primary key,
ob_ref UUID,
subscribed boolean not null
);
I want to join with the set-returning function unnest so I can find the "deepest" matching subscription, something like this:
SELECT id
FROM (
SELECT DISTINCT ON (activity.id)
activity.id,
x.ob_ref, x.ob_depth,
subscription.subscribed IS NULL OR subscription.subscribed = TRUE
AS subscribed,
FROM activity
LEFT JOIN subscription
ON activity.ob_refs #> array[subscription.ob_ref]
LEFT JOIN unnest(activity.ob_refs)
WITH ORDINALITY AS x(ob_ref, ob_depth)
ON subscription.ob_ref = x.ob_ref
ORDER BY x.ob_depth DESC
) sub
WHERE subscribed = TRUE;
But I can't figure out how to do that second join and get access to the columns. I've tried creating a FromClause like this:
act_ref_t = (sa.select(
[sa.column('unnest', UUID).label('ob_ref'),
sa.column('ordinality', sa.Integer).label('ob_depth')],
from_obj=sa.func.unnest(Activity.ob_refs))
.suffix_with('WITH ORDINALITY')
.alias('act_ref_t'))
...
query = (query
.outerjoin(
act_ref_t,
Subscription.ob_ref == act_ref_t.c.ob_ref))
.order_by(activity.id, act_ref_t.ob_depth)
But that results in this SQL with another subquery:
LEFT OUTER JOIN (
SELECT unnest AS ob_ref, ordinality AS ref_i
FROM unnest(activity.ob_refs) WITH ORDINALITY
) AS act_ref_t
ON subscription.ob_refs #> ARRAY[act_ref_t.ob_ref]
... which fails because of the missing and unsupported LATERAL keyword:
There is an entry for table "activity", but it cannot be referenced from this part of the query.
So, how can I create a JOIN clause for this SRF without using a subquery? Or is there something else I'm missing?
Edit 1 Using sa.text with TextClause.columns instead of sa.select gets me a lot closer:
act_ref_t = (sa.sql.text(
"unnest(activity.ob_refs) WITH ORDINALITY")
.columns(sa.column('unnest', UUID),
sa.column('ordinality', sa.Integer))
.alias('act_ref'))
But the resulting SQL fails because it wraps the clause in parentheses:
LEFT OUTER JOIN (unnest(activity.ob_refs) WITH ORDINALITY)
AS act_ref ON subscription.ob_ref = act_ref.unnest
The error is syntax error at or near ")". Can I get TextAsFrom to not be wrapped in parentheses?
It turns out this is not directly supported by SA, but the correct behaviour can be achieved with a ColumnClause and a FunctionElement. First import this recipe as described by zzzeek in this SA issue. Then create a special unnest function that includes the WITH ORDINALITY modifier:
class unnest_func(ColumnFunction):
name = 'unnest'
column_names = ['unnest', 'ordinality']
#compiles(unnest_func)
def _compile_unnest_func(element, compiler, **kw):
return compiler.visit_function(element, **kw) + " WITH ORDINALITY"
You can then use it in joins, ordering, etc. like this:
act_ref = unnest_func(Activity.ob_refs)
query = (query
.add_columns(act_ref.c.unnest, act_ref.c.ordinality)
.outerjoin(act_ref, sa.true())
.outerjoin(Subscription, Subscription.ob_ref == act_ref.c.unnest)
.order_by(act_ref.c.ordinality.desc()))
When I run the selects below, I do not get Field3 in the result set, why?
Select
a.Field1,
a.Field2,
a.Field3,
sum(IsNull(a.Field4, 0)) AS SomeAlias1,
a.SomeField5,
a.SomeField6,
a.SomeField7
From SomeTable a
INNER JOIN SomeView1 v on v.au = a.au
inner join (select Username, House from Users userBuildings where UserName = #UserName) as userHouses on userHouses.au = a.au
WHERE
(((where claus logic here....
Group BY a.Field1,
a.Field2,
a.SomeAlias1,
a.Field3,
a.Field4,
a.Field5,
a.Field6,
a.Fielf7
)
Select
transBudget.Field1,
transBudget.Field2,
transDiscount.Field4,
... some other fields...
IsNull(transDiscount.Actual, 0) - IsNull(transBudget.Actual, 0) AS Variance
from (Select * from Transactdions Where TransDesc = 'Budget') AS transBudget
FULL OUTER JOIN
(Select * from Transactions Where TransDesc = 'Discount') AS transDiscount
ON transBudget.Market = transDiscount.Market AND transBudget.SubMarket = transDiscount.SubMarket
I see every field except Field3 for some reason and it's beyond me how the heck this can happen.
In the second part of your query, you are missing field 3.
Select
transBudget.Field1,
transBudget.Field2,
transDiscount.Field4,
... some other fields...
IsNull(transDiscount.Actual, 0)
You appear to have two separate SQL queries there. The first one contains Field3, but the second one does not.