I have a symfony project and I have one model, which for this example I will name Boat. From the Boat's showSuccess page, I would like to make a link to another model's form page. For this example we will call it Ticket. When they click on the link, I would like for the Boat object to be passed to the Ticket form because I have to display some of that specific Boat's fields (title, price, etc) on the Ticket form page (newSuccess.php).
I guess my question is, how do I pass an object (as a variable) to another model's "new" form page. I have looked everywhere and I can't seem to find an answer that works for me. Thank you!
UPDATE:
Here is some of the code I've tried:
Routing.yml
ticket_new_car:
url: /ticket/:category/:iditem
class: sfDoctrineRoute
options: { model: car, type: object }
param: { module: ticket, action: new }
requirements:
id: \d+
sf_method: [get]
Link on Car page
<a href="<?php echo url_for('ticket_new_car', $car)?>" > Test </a>
actions.class.php
public function executeNew(sfWebRequest $request)
{
$this->item = $this->getRoute()->getObject();
$this->forward404Unless($this->item);
$this->form = new TicketForm();
}
_form.php
<?php echo $item->getTitle() ?>
I'm getting "Undefined variable: item". I did everything in the tutorial except for the "slug" part because I'm not slugging my URLs. What could I be doing wrong?
Look at this page
http://www.symfony-project.org/jobeet/1_4/Doctrine/en/05#chapter_05_object_route_class
And scroll down to Object Route Class
Related
I want to create a page detail of product containing the following information such as name, ID, type, status, quantity, description etc by AEM 6.1. But it seems difficult to me.
Assuming there is a table of product list. Once clicking the Read One link in a row, the detail page of the item will absolutely be rendered.
Do you have any ideas ?
I think this really depends on how your product details (ID, type, status, quantity, description, etc) are stored.
A good solution would be to create a new page component that reads an ID http parameter passed when clicking on the READ ONE button as an argument into the rendering of the new (PRODUCT DETAIL) page.
so the all the buttons would look like this: www.mywebsite/products/productdetails?ID=x where x is the ID of the product in the given row when clicked.
Your new page component would have to have a code snippet similar to this:
<div id="product-detail-component" data-sly-use.product="com.mypackage.models.ProductModel">
<ul>
<li>${product.ID} </li>
<li>${product.description}</li>
</ul>
</div>
And then you would need a new Sling Model class that can handle a http parameter
#Model({adaptables= Resource.class,SlingHttpServletRequest.class}) public class Product Model {
#PostConstruct
public void init()
{
/*
1.retrieve HTTP parameter which is ID
2.access resourceResolver/resource to locate node containing product properties relative to resource location
*/
}
}
This is a very basic and not functional example, but I think it may give you a better direction.
On user-registration confirmation I want to show a simple popup. For the moment, in order to simplify I'm happy to show an "Hello World".
This is the template file, views/templates/hook/registrationConfirm.tpl
<div id="idname" class="block">
<h1 class="title_block">HelloWorld</h1>
</div>
In my custom module I have this hook (which I know is being triggered doing debug):
public function hookActionCustomerAccountAdd($params) {
return $this->display(__FILE__, 'registrationConfirm.tpl');
}
It doesn't show anything (I also tried inspect the source code of the rendered page, but I dind't find the "HelloWorld")
Hooks starting by "Action" react to an action but do not display anything, but those starting with "Display" do.
You should also react to the hook displayCustomerAccount
public function hookActionCustomerAccountAdd() {
$this->is_new_account = true;
}
public function hookDisplayCustomerAccount()
{
if ($this->is_new_account) {
return $this->display(__FILE__, 'registrationConfirm.tpl');
}
}
I tried the solution posted by #shagshag but for some reason it doesn't work for me. So I share my solution (it's not pretty, nor efficient I think, but it seem to work for me): in the hookActionCustomerAccountAdd I save on a custom table (newCustomersTmp) email and customer id, because these are the data I need after, in the display Hook. Then in the hookDisplayCustomerAccount I check if an user with the current email ($this->context->customer->email) already exists in my table: if so I retrieve the data, do the actions I need with them and delete the row in the table.
I want to show some customized content in the left panel which usually contains the treeview.
As the stuff in this panel will be an editable Gridfield wich should be related to the EditForm, I tried to built a new EditFormTools panel in this way:
I copied the CMSMain_Content.ss in mysite/templates/Includes and changed $Tools into $EditFormTools
I created the file CMSMain_EditFormTools.ss in the same directory with this code:
<div class="cms-content-tools west cms-panel" data-expandOnClick="true" data-layout-type="border" id="cms-content-tools-CMSMain">
<div class="cms-panel-content west">
<% include Test %>
</div>
</div>
I created a Test.php with:
class Test extends CMSMain{
public $var = 'test';
public function testfunction(){
$variable = 'hakuna matata';
return $variable;
}
}
Then I created a Test.ss with this code:
some Text
$var
$testfunction
$variable
The Panel appears in my CMS now but it only contains "some Text". So the include of Test.ss works perfectly fine but passing variables from Test.php to Test.ss doesn't.
Can anybody help?
Greetings
It may not directly answer your question but may give you direction.
You need to extend a controller class.
Then you can use a called functions to tell controller which template file it should use using renderWith().
for example,
public function index(){
return $this->renderWith("Test");
}
Then your function references in Test.ss will call functions in Test.php given it is the controller.
If Test class is not the controller rendering the template, the template doesnt know where your variable returning function is.
By the way, you can pass variables from layout to include template.
I have a simple search form I want to reuse across multiple pages in my codeigniter application. For example, right now I have a search form in the sidebar and I'm planning on displaying that sidebar on the index, about, and other pages.
I want to have the form validation display errors on the same page the users submits the form from.
For example:
User is on About page.
User submits form with invalid data
User sees error in the sidebar on the About page
and
User is on Index page.
User submits form with invalid data
User sees error in the sidebar on the Index page
But I'd like to reuse that form validation logic. I just want it to display the error on whichever page the user posted from.
Any ideas how to do that? Sorry for the noob question, I'm pretty new to CI.
Here you have to think globally.
Step.1 : Make one view file : display.php
which contains :
<div id = "main">
<div id = "header">
[load header file here]
</div>
<?php
if(validation_errors() != '') {
?>
<div id = "error">
<?=validation_errors()?>
</div>
<?php
}
?>
<div id = "content">
<?=$page?>
</div>
<div id = "footer">
[load footer file here]
</div>
</div>
Step.2 : About us Page.(controlller)
.... Your data ....
at end of controller function
$data['page'] = 'aboutus';
$this->load->view('display',$data);
With regards to your comment on the above question you could use Flash data
With the assumption that you have the session library loaded, here is a helper function.
function last_page($page = null){
$ci = get_instance();
if($page === null)
return $ci->session->flashdata('last_page');
$ci->session->set_flashdata('last_page', $page);
}
then you can call last_page('about'); at the top of the about page, and then when you want to find out what the last page you were on was you can just call last_page(); with no params.
In the User Guide, there's different ways to configure sets/groups of rules. Then you can simply have something like:
if ($this->form_validation->run('signup') == FALSE)
{
$this->load->view('myform');
}
else
{
$this->load->view('formsuccess');
}
Which will run your "signup" group of validations. To me, this is the cleanest way to achieve reusable validation rules.
This is a perfectly valid question.
I'm not a PHP expert, nor a CI expert, but the fact is sometimes you want to post to a controller that didn't create the view from which you're posting. Which means posting back to itself is not going to work.
I came across this post on the Ellislab forum:
http://ellislab.com/forums/viewthread/217176/
On this page, There are 2 methods of going about it. Both of which use flashdata and both of which are totally valid, IMHO.
The first: create a helper function
http://ellislab.com/forums/viewreply/1003010/
The second: extend the CI_Form_Validation Class.
http://ellislab.com/forums/viewreply/1047536/
The second is the way I went as it seems cleanest although some may argue whether the form validation class should know anything about flash data.
I am using an application (a blog) written using the CodeIgniter framework and would like to search my blog from my browsers location bar by adding a string to the end of my blogs url like this:
http://mysite.com/blog/index.php/search...
As you can see in the example above I am not really sure how to format the rest of the url after the search part so I am hoping someone here might be able to point me in the right direction.
This is what the form looks like for the search box if that helps at all.
form class="searchform" action="http://mysite.com/blog/index.php/search" method="post">
<input id="searchtext" class="search_input" type="text" value="" name="searchtext">
<input type="submit" value="Search" name="Search">
</form>
Thx,
Mark
Since your form is posting to http://mysite.com/blog/index.php/search, I'm assuming this 'search' controller's default function is the one your are attempting to submit your data to. I think that the easiest way to do this would be to just grab the post data inside of the controller method you're posting to. Example:
function search()
{
$search_params = $this->input->post('search_text');
}
Then you would have whatever the user input stored as $search_params, and you can take actions from there. Am I misunderstanding what you're asking?
It seems like you're kind of discussing two different approaches. If you wanted to make a request to
mysite.com/blog/index.php/search&q=what_I_am_looking_for
This is going to call the search controllers default method (which is index by default). If you wanted to use the URL to pass parameters like that you would go to your function in the search controller and do:
print_r($this->input->get('q'));
This will print out "what_am_I_looking_for".
An easier approach in my opinion would be to:
1. Create a view called "search_view" with the HTML content you pasted above, and have the form "action" http://www.mysite.com/blog/index.php/test/search
Create a controller called "Test" that looks like the following:
class Test extends CI_Controller {
function search()
{
$search = $this->input->post('searchtext');
print_r($search);
}
public function display_search()
{
$this->load->view('search_view');
}
}
Visit http://www.mysite.com/blog/index.php/test/display_search in your browser. This should present you with the form you placed in search_view.php. Once the form is submitted, you should be sent to the search function and print out the variable $search, which will have whatever text you submitted on that form.
If this isn't what you were looking for then I am afraid I do not understand your question.