How to replace the following correctly?
NSString *stringURL = [NSString stringWithFormat:#"http://192.168.1.183:8001/GetDocument.aspx?id=%# & user=admin_document",self.index];
NSURL *targetURL = [NSURL URLWithString:stringURL];
I want to replace %# with self.index.
Your problem is more likely the whitespace. Try removing it:
NSString *stringURL = [NSString stringWithFormat:#"http://192.168.1.183:8001/GetDocument.aspx?id=%#&user=admin_document", self.index];
NSLog(#"URL:%#", stringURL); //You can print out to check
NSURL *targetURL = [NSURL URLWithString:stringURL];
Remove the whitespaces in the link.
If self.index is not an NSString object, then the %# format specifier will not work. I suspect with a name like index it is probably an NSInteger or similar, in which case you want to use %d instead.
Have a look at this Apple documentation for all the possible format specifiers and the types they correspond to. The compiler should pick you up on this though and suggest the correct specifier.
just parse and use it if it is integer then you use like this
int a=10;
NSString *stringURL = [NSString stringWithFormat:#"this is my number %d",a];
and if you want to use string then you did like this
NSString stringName=#"john";
NSString *stringURL = [NSString stringWithFormat:#"this is my name %#",stringName];
Related
I am trying to remove just the last part of the url, Its a FTP URL.
Suppose, I have a URL like: > ftp://ftp.abc.com/public_html/somefolder/. After removing the last portion I should have it as: ftp://ftp.abc.com/public_html/.
I have tried using stringByDeletingLastPathComponenet and URLByDeletingLastPathComponent, but they dont remove the last portion correctly. They change the entire looks of the url.
for instance, after using the above said methods, here is the URL format i get ftp:/ftp.abc.com/public_html/. It removes one "/" in "ftp://", which is crashing my program.
How is it possible to removve just the last part without disturbing the rest of the URL ?
UPDATE:
NSURL * stringUrl = [NSURL URLWithString:string];
NSURL * urlByRemovingLastComponent = [stringUrl URLByDeletingLastPathComponent];
NSLog(#"%#", urlByRemovingLastComponent);
Using above code, I get the output as :- ftp:/ftp.abc.com/public_html/
Hmm. URLByDeletingLastPathComponent works perfectly given the above input.
NSURL *url = [NSURL URLWithString:#"ftp://ftp.abc.com/public_html/somefolder/"];
NSLog(#"%#", [url URLByDeletingLastPathComponent]);
returns
ftp://ftp.abc.com/public_html/
Do you have some sample code that is yielding improper results?
Max
Now try
NSString* filePath = #"ftp://ftp.abc.com/public_html/somefolder/.";
NSArray* pathComponents = [filePath pathComponents];
NSLog(#"\n\npath=%#",pathComponents);
if ([pathComponents count] > 2) {
NSArray* lastTwoArray = [pathComponents subarrayWithRange:NSMakeRange([pathComponents count]-2,2)];
NSString* lastTwoPath = [NSString pathWithComponents:lastTwoArray];
NSLog(#"\n\nlastTwoArray=%#",lastTwoPath);
NSArray *listItems = [filePath componentsSeparatedByString:lastTwoPath];
NSLog(#"\n\nlist item 0=%#",[listItems objectAtIndex:0]);
}
output
path=(
"ftp:",
"ftp.abc.com",
"public_html",
somefolder,
"."
)
lastTwoArray =somefolder/.
list item 0 =ftp://ftp.abc.com/public_html/
An example of how to extract the last part of NSURL. In this case the location of the file. Sqlite core data
NSURL *storeURL = [[self applicationDocumentsDirectory] URLByAppendingPathComponent:#"CoreAPI.sqlite"];
NSString *localPath = [storeURL absoluteString];
NSArray* pathComponents = [localPath pathComponents];
NSLog(#"%#",[pathComponents objectAtIndex:6]);
NSString * nombre = [NSString stringWithFormat:#"%#", [pathComponents objectAtIndex:6]];
This code returns me the name of the file CoreAPI.sqlite
for(int i= 0 ;i<[urlsArrray count]; i++)
{
NSString *urlString = [urlsArrray objectAtIndex:i];
NSString *escapedUrlString = [urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [NSURL URLWithString:escapedUrlString];
NSString *urlstring1 = [url absoluteString];
NSArray *parts = [urlstring1 componentsSeparatedByString:#"/"];
NSString *fileName = [parts objectAtIndex:[parts count]-1];
NSMutableString *tempString = [NSMutableString stringWithString:fileName];
// [tempString replaceCharactersInRange:[tempString rangeOfString:#"%20"] withString:#" "];
NSLog(#"file name in temp string: %# word name: %#", tempString, wordNameDB);
NSRange match = [tempString rangeOfString:wordNameDB];
if(match.location != NSNotFound)
{
NSLog(#"match found at %u", match.location);
isAvailable = YES;
break;
}
Hi friends, now my problem is i am getting file name from server..., if file name is having any spaces then it replace '%20' ( i.e ex: "hello world" is actual name but i am getting file name like: "hello%20world") .
1. I am not sure all file names having spaces.
2. And also i am not sure a file may have only one space
so first i have to check the file is having spaces or not, if have then i want to replace all "%20" with #" " string. Please give me any suggestions or code snippets.
OR " THERE IA ANY OTHER WAY TO READ FILE NAMES WITHOUT GETTING '%20' IN THE PLACE OF SPACE(#" ")..... thank you
If you have your file name stored in fileName param, you can use the following:
fileName = [fileName stringByReplacingOccurrencesOfString:#"%20" withString:#" "];
The above code will replace all "%20" with " ". If there are no "%20" in the fileName, you will get back the same string.
Correction:
I was confused with stringByAddingPercentEscapesUsingEncoding mentioned in code and thought you have already used stringByReplacingPercentEscapesUsingEncoding. If you are not using stringByReplacingPercentEscapesUsingEncoding method, you should use that in this case. The above code is useful, only if that is not able to remove any particular string which you want to replace.
What you need is replacing the escape charcters, according to the encoding.
Use this and all your spaces and other URL encoded characters will be converted to what you need.
[#"yourString" stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
THERE IA ANY OTHER WAY TO READ FILE NAMES WITHOUT GETTING '%20' IN THE PLACE OF SPACE(#" ")
Yes, use this:
NSString *newString = [yourstring stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
Use this to remove spaces ..
urlString = [urlString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
You seem to already have a valid NSURL object representing the file. Getting the filename from a URL is easy:
...
NSURL *url = [NSURL URLWithString:escapedUrlString];
NSString *path = [url path];
NSString *filename = [path lastPathComponent];
No fiddling with unescaping percent escapes, URL parsing, and other error prone stuff.
I got some URL's heading to certain mp3's like:
(1) localhost://blablabla/song1.mp3
(2) localhost://blablabla/songwithmorechars.mp3
and so on.
How can I crop the URL's to:
(1) song1.mp3
(2) songwithmorechars.mp3
Need to display the current song my AVAudioPlayer is playing in a UILabel.
Thanks
SOLUTION:
Here's the deal:
titleLabel.text = [[[self.audioPlayer.url absoluteString] lastPathComponent] stringByReplacingOccurrencesOfString:#".mp3" withString:#""];
Take the substring with the last / (there's a method in ObjC for that!)
NSString *sub = [url lastPathComponent];
Here's the info for that method:
NSString lastPathComponent Apple Doc
Just use [url lastPathComponent], you don't need to convert it to a string first.
use
NSString *lastString = [yourStringName lastPathComponent];
NSURL *firstURL = [NSURL URLWithString:#"localhost://blablabla/song1.mp3"];
NSString *firstString = [firstURL absoluteString];
NSLog(#"Name:%#",[firstString lastPathComponent]);
From docs:
NSURL Class Reference
NSString Class Reference
I have a text with http:// in NSString. I want to get that http link from the NSString. How can i get the link/url from the string? Eg: 'Stack over flow is very useful link for the beginners https://stackoverflow.com/'. I want to get the 'https://stackoverflow.com/' from the text. How can i do this? Thanks in advance.
I am not sure what you exactly mean by link but if you want to convert your NSString to NSURL than you can do the following:
NSString *urlString = #"http://somepage.com";
NSURL *url = [NSURL URLWithString:urlString];
EDIT
This is how to get all URLs in a given NSString:
NSString *str = #"This is a grate website http://xxx.xxx/xxx you must check it out";
NSArray *arrString = [str componentsSeparatedByString:#" "];
for(int i=0; i<arrString.count;i++){
if([[arrString objectAtIndex:i] rangeOfString:#"http://"].location != NSNotFound)
NSLog(#"%#", [arrString objectAtIndex:i]);
}
Rather than splitting the string into an array and messing about that way, you can just search for the substring beginning with #"http://":
NSString *str = #"Stack over flow is very useful link for the beginners http://stackoverflow.com/";
// get the range of the substring starting with #"http://"
NSRange rng = [str rangeOfString:#"http://" options:NSCaseInsensitiveSearch];
// Set up the NSURL variable to hold the created URL
NSURL *newURL = nil;
// Make sure that we actually have found the substring
if (rng.location == NSNotFound) {
NSLog(#"URL not found");
// newURL is initialised to nil already so nothing more to do.
} else {
// Get the substring from the start of the found substring to the end.
NSString *urlString = [str substringFromIndex:rng.location];
// Turn the string into an URL and put it into the declared variable
newURL = [NSURL URLWithString:urlString];
}
try this :
nsstring *str = #"Stack over flow is very useful link for the beginners http://stackoverflow.com/";
nsstring *http = #"http";
nsarray *arrURL = [str componentsSeparatedByString:#"http"];
this will give two objects in the nsarray. 1st object will be having:Stack over flow is very useful link for the beginners and 2nd will be : ://stackoverflow.com/ (i guess)
then you can do like:
NSString *u = [arrURL lastObject];
then do like:
nsstring *http = [http stringByAppendingFormat:#"%#",u];
Quite a lengthy,but i think that would work for you. Hope that helps you.
How can I combine "stringURL" and "stringSearch" together?
- (IBAction)search:(id)sender;{
stringURL = #"http://www.websitehere.com/index.php?s=";
stringSearch = search.text;
/* Something such as:
stringURL_ = stringURL + stringSearch */
[web loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:stringURL_]]];
}
Philippe gave a good example.
You can also use plain stringWithFormat: method.
NSString *combined = [NSString stringWithFormat:#"%#%#", stringURL, stringSearch];
This way you can manipulate string even more by putting somethig inbetween the strings like:
NSString *combined = [NSString stringWithFormat:#"%#/someMethod.php?%#", stringURL, stringSearch];
NSString* combinedString = [stringUrl stringByAppendingString: search.text];
NSString * combined = [stringURL stringByAppendingString:stringSearch];
Instead of stringByAppendingString:, you could also use
NSString *combined = [NSString stringWithFormat: #"%#%#",
stringURL, stringSearch];
This is especially interesting/convenient if you have more than one string to append. Otherwise, the stringbyAppendingString: method is probably the better choice.
You can use stringByAppendingString:
stringURL = [#"http://www.websitehere.com/index.php?s="
stringByAppendingString:search.text];
If you want to have some control about the format of the parameter you should assemble
your URL string with
[NSString stringWithFormat:#"http://www.websitehere.com/index.php?s=%#", search.text]
This solution is charming because you can append almost anything which can be inserted into a printf-style format.
I would not have given the answer of such general question.
There are many answers of same type question have already given. First find the answer of your question from existing question.
NSString* myURLString = [NSString stringWithFormat:#"http://www.websitehere.com/index.php?s=%#", search.text];