I was wondering if it's possible to make a regular expression to find all of the text that is in between the following two strings:
mutablePath = CGPathCreateMutable();
...
CGPathAddPath(skinMutablePath, NULL, mutablePath);
Basically, the first and last lines will always be the same, and there will be a whole bunch of random stuff in between. I'm using the find feature in xCode and would like to count the number of lines that appear between all instances of the first and last line from above.
Is this even possible?
Xcode does not support multi-line regex matching. You'll have to search for your first and last line and count the lines in between by yourself.
Looks like you can use the DOTALL modifier,
I was able to find a block of code like yours with this regex:
(?s)mutablePath = CGPathCreateMutable\(\);.+CGPathAddPath\(skinMutablePath, NULL, mutablePath\);
More info in the ICU regex documentation here
Related
i have a file u01/appl/wandl/import/AT/file.csv. i need to get the AT part only and store it in a variable using regex.it is always a 2 digit code but it could be BE UK etc etc.
\/([A-Z]{2})\/
That regex find exactly two big letters with / / around so it finds things like /AT/ or /UK/ or /BE/
As you can see parentheses are around 2 digit code so only code will be captures by grouping
I'm coming across a strange situation where I cannot search on string tags that end with a special character. So far I've tried ) and ].
For example, given a Fruit index with a record with a tag apple (red), if you query (using the JS library) with tagFilters: "apple (red)", no results will be returned even if there are records with this tag.
However, if you change the tag to apple (red (not ending with a special character), results will be returned.
Is this a known issue? Is there a way to get around this?
EDIT
I saw this FAQ on special characters. However, it seems as though even if I set () as separator characters to index that only effects the direct attriubtes that are searchable, not the tag. is this correct? can I change the separator characters to index on tags?
You should try using the array syntax for your tags:
tagFilters: ["apple (red)"]
The reason it is currently failing is because of the syntax of tagFilters. When you pass a string, it tries to parse it using a special syntax, documented here, where commas mean "AND" and parentheses delimit an "OR" group.
By the way, tagFilters is now deprecated for a much clearer syntax available with the filters parameter. For your specific example, you'd use it this way:
filters: '_tags:"apple (red)"'
I want to search a file for a specific string and then place a comment at the beginning of that string. But I need an answer that avoids regex, global changes, and all the other fancy stuff.
I wrote this line:
sed -i.bak '/PermitRootLogin no/# PermitRootLogin no/' ./sshd_config
but I get an error:
sed: -e expression #1, char 21: comments don't accept any addresses
I assume the issue is that I need to escape the # character, but I'm not finding any resources on how to do that, or even mentioning it. I've tried various combinations of putting ^ or \ or \^ in front of the # but I'm jut not getting it right.
Please note I am intentionally repeating the text to be replaced. I would like the most simple possible solution to this question: how to replace "XYX" with "# XYZ" in the most obvious possible way.
As indicated in the comments by #mlt , you could try adding an s at the beginning your sed command. Straight from his comment:
s/PermitRootLogin....
I see that you said you're intentionally repeating the test to be replaced. If by that you mean, you want it to be the same, maybe consider grouping your matched text. I understand you may have meant that you just want it hand typed. Anyway, here is how to match the grouped text and add the comment character:
s/(PermitRootLogin)/# \1/
The parens indicated that the matched text should be consider a group, the \1 indicates that you want to put that matched group there.
I hope this was helpful. Happy coding! Leave a comment if you have any questions.
I have an NSArray of lines (objective-c iphone), and I'm trying to find the line which starts with a number, followed by a dot and a space, but can have any number of spaces (including none) before it, and have any text following it eg:
1. random text
2. text random
3.
what regular expression would I use to get this? (I'm trying to learn it, and I needed the above expression anyway, so I thought I'd use it as an example)
With C#:
#"^ *[0-9]+\. "
It doesn't check for the presence of something after the ., so this is legal:
1.(space)
If you delete the # and escape the \ it should work with other languages (it is pretty "down-to-earth" as RegExpes go)
I may suggest (Perl-compatible regexp):
^\s*\d+\.\s
At the beginning of a line:
Any number (0-n) of spaces
One or more digits
A dot
A space
Something like
^\s*\d+\.
But it depends on the language.
/^\s*[0-9]+\.\s+/
would be my guess providing you don't have any space before the number
I'm using regular expression lib icucore via RegKit on the iPhone to
replace a pattern in a large string.
The Pattern i'm looking for looks some thing like this
| hello world (P1)|
I'm matching this pattern with the following regular expression
\|((\w*|.| )+)\((\w\d+)\)\|
This transforms the input string into 3 groups when a match is found, of which group 1(string) and group 3(string in parentheses) are of interest to me.
I'm converting these formated strings into html links so the above would be transformed into
Hello world
My problem is the trailing space in the third group. Which when the link is highlighted and underlined, results with the line extending beyond the printed characters.
While i know i could extract all the matches and process them manually, using the search and replace feature of the icu lib is a much cleaner solution, and i would rather not do that as a result.
Many thanks as always
Would the following work as an alternate regular expression?
\|((\w*|.| )+)\s+\((\w\d+)\)\| Where inserting the extra \s+ pulls the space outside the 1st grouping.
Though, given your example & regex, I'm not sure why you don't just do:
\|(.+)\s+\((\w\d+)\)\|
Which will have the same effect. However, both your original regex and my simpler one would both fail, however on:
| hello world (P1)| and on the same line | howdy world (P1)|
where it would roll it up into 1 match.
\|\s*([\w ,.-]+)\s+\((\w\d+)\)\|
will put the trailing space(s) outside the capturing group. This will of course only work if there always is a space. Can you guarantee that?
If not, use
\|\s*([\w ,.-]+(?<!\s))\s*\((\w\d+)\)\|
This uses a lookbehind assertion to make sure the capturing group ends in a non-space character.