So I have a text layer in aftereffects with text source expression:
D = new Date(Date(0));
D.getDate() + "/" + (D.getMonth()+1)
which gives me result like this 29/12 and I need to add 3 days to it.
I tried:
D = new Date(Date(0));
(D.getDate()+3) + "/" + (D.getMonth()+1)
But that results to 32/12 .. How do I make it so the result would be (in this particular case) 1/1? In Java people suggest to use calendar class. But I'm not sure if After Effects has such thing.
Try this:
D = new Date(Date(0));
D = new Date(D.getTime()+3*24*60*60*1000);
D.getDate() + "/" + (D.getMonth()+1)
you can use things like this:
DateTime.Now.AddDays(12);
DateTime.Now.AddYears(2);
in javascript you can set with the help of setDate() function
var d = new Date();
d.setDate(35); // this will give you 4 jan 2013
d.setDate(25); // this will give you 25 Dec 2012
Related
I'm using the Foundation 5 framework and trying to use the accordion.
If I use the sample code all ok: http://foundation.zurb.com/docs/components/accordion.html
If I try to use div tags and / or sectin in place of tag dl and dd does not work
Why?
Because the accordion code is with hardcoded tag names :) ... and you can't even configure them.
This is part of the accordion code:
........
.on('click.fndtn.accordion', '[' + this.attr_name() + '] dd > a', function (e) {
var accordion = S(this).closest('[' + self.attr_name() + ']'),
target = S('#' + this.href.split('#')[1]),
siblings = S('dd > .content', accordion),
aunts = $('> dd', accordion),
settings = accordion.data(self.attr_name(true) + '-init'),
active_content = S('dd > .content.' + settings.active_class, accordion),
active_parent = S('dd.' + settings.active_class, accordion);
........
You can see the dd and dl tag names inside :) ... but - of course - you can make them configurable :) ...
I am using a datepicker in a modal window in my Bootstrap application. I am using the original Datepicker from Stefan Petre. I built it where it works in a desktop and mobile using a mouse and it works fine.
Recently I had a user request to allow it to also work with a keyboard. I removed the readonly property to allow the user to enter a date in the input field. The date-format is set to 'mm/dd/yyyy'.
When I enter a date like today for example like this "12/11/13" then it will default to 1913. This isn't a huge deal as I could just train the users to use 4 digits, but I would rather just have it default to this century.
Note: This only seems to happen for the date-format with a 4 digit year. This also seems to happen in the same manner in the newer forks of Stefan's code.
Note: I am using Bootstrap 2.0.4. I am testing with Firefox.
Here is what it looks like:
In JavaScript, set the datepicker's assumeNearbyYear attribute to true, like this:
$("#dp").datepicker({
assumeNearbyYear: true
});
This happens because the Bootstrap datepicker is using JavaScript Date objects. When you create a new Date object and pass in a two digit year it will output 1900+year (see Why does Javascript evaluate a 2-digit year of 00 as 1900 instead of 2000?)
You could try to tweak the datepicker source code, but that might be too complicated.
From what I can see on http://www.eyecon.ro/bootstrap-datepicker/ there is no option to set a range for the selectable dates, but you could change the format to use two digit years.
On your screenshot I can see, that you are using the datepicker for "Arrival Date" which I assume is in the future. On the website there is an example on how to disable dates in the past.
I hope that helps.
UPDATE
I have written an event handler for your problem which should do the trick.
Javascript on http://jsfiddle.net/pCYbd/1/
$("#dp").datepicker();
$("#dp").on("keyup", function(e) {
var date, day, month, newYear, value, year;
value = e.target.value;
if (value.search(/(.*)\/(.*)\/(.*)/) !== -1) {
date = e.target.value.split("/");
month = date[0];
day = date[1];
year = date[2];
if (year === "") {
year = "0";
}
if (year.length < 4) {
newYear = String(2000 + parseInt(year));
$(this).datepicker("setValue", "" + month + "/" + day + "/" + newYear);
if (year === "0") {
year = "";
}
return $(this).val("" + month + "/" + day + "/" + year);
}
}
});
CoffeeScript on http://jsfiddle.net/pCYbd/2/
$("#dp").datepicker()
$("#dp").on "keyup", (e) ->
value = e.target.value
if value.search(/(.*)\/(.*)\/(.*)/) != -1
date = value.split("/")
month = date[0]
day = date[1]
year = date[2]
year = "0" if year == ""
if year.length < 4
newYear = String(2000 + parseInt(year))
$(#).datepicker("setValue", "#{month}/#{day}/#{newYear}")
year = "" if year == "0"
$(#).val("#{month}/#{day}/#{year}")
My JavaScript skills are not the best, but this should work.
Updating bootstrap-datepicker.js as shown in this post solved it for me https://github.com/eternicode/bootstrap-datepicker/pull/1461/commits/2ea16adad27cbc4d4dfa20b924addfb480e5b036
yyyy: function(d,v){
if (format.parts.indexOf('yyyy') > -1 && v < 1000) v = 2000+v; // this line ***
return d.setUTCFullYear(v);
},
I'm using bootstrap-datepicker v1.5.1 and if you look around line 1741 where it does the year mapping, you will notice this:
yyyy: function (d, v) {
return d.setUTCFullYear(v);
},
yy: function (d, v) {
return d.setUTCFullYear(2000 + v);
},
When you specify that the control uses a four year date "yyyy", it will only do the return d.setUTCFullYear(v);, which will get you the previous century that JavaScript gives you. When you specify that it use the two year date "yy", it will do the correct 2000+ that you need for the current century.
So if you want the correct two year date to be 2016, 2017, etc., you need to set your datepicker to use the "yy" like so:
$('#tbPurchaseDate').datepicker({
format: 'mm/dd/yy',
autoclose: true,
todayBtn: 'linked',
todayHighlight: true,
orientation: 'bottom auto'
});
Or you can change the "yyyy" setting in the bootstrap-datepicker.js to match the "yy" version, but then you'd have to remember to do that every time you update the datepicker js file via nuget. It's much easier to just change your format setting.
Of course, if you want the full 4 digit year to display in the control, then you might want to try one of the elaborate fixes listed here or just set the "yyyy" to what the "yy" is in the js file.
Or just update your code to the latest version (1.6.4 right now) and "yyyy" and "yy" are the same and you use assumeNearbyYear: true as noted in another answer here.
For me, the best solution was to customize parseDate function in bootstrap-datepicker.js file directly. Inside a function, there is variable setters_map with yyyy property which I modified a bit. Here is my solution:
yyyy: function(d,v) {
if (v.toString().length == 2 && v <= 30) {
v = 2000 + parseInt(v);
}
return d.setUTCFullYear(v);
},
In my case it was needed to convert only years that are less or equals 30.
In the update function of bootstrap-datepicker.js I added this block of code:
var str = this.element.prop('value');
var defaulted = false;
if (str.lastIndexOf("/") >= 0 && (str.match(/\//g) || []).length == 2)
{
var yr = str.substring(str.lastIndexOf("/") + 1);
if (yr.length <= 2)
defaulted = true;
}
if (this.date.getFullYear() < 2000 && defaulted) {
this.date.setFullYear(this.date.getFullYear() + 100);
}
right before the viewdate is set on this line:
this.viewDate = new Date(this.date.getFullYear(), this.date.getMonth(), 1, 0, 0, 0, 0);
It will work 100% if you update below two line in UTCDate() of bootstrap-datepicker.js core file:
function UTCDate(){
/* Date defaulted date from 2000 if entered date year less than 4 degit*/
if(arguments!=null && arguments[0].toString().length<4)
arguments[0] = 2000 + arguments[0];
return new Date(Date.UTC.apply(Date, arguments));
}
What I am trying to do here is this - I want to give index to only the workdays in each week.
So, if in a week, Monday and Wednesday are holidays, then Tuesday should get 1, Thursday should get 2, Friday should get the index 3. Otherwise, in a normal week without any holidays, Monday should get 1, Tuesday 2, Wednesday 3, and so on ...
Here is the code I have written (I haven't coded in years now, so please pardon the crude approach)
Sheet 'Holidays' contains a list of holidays in the column B starting from row 2
Variable date is the date for which I want to find out the index for
Variable dayOfTheWeek is the number of day of 'date' counted from last Sunday, so if date is a Monday, dayOfTheWeek is 1; if date is Tuesday, dayOfTheWeek is 2, and so on ...
function indexOfWorkdayOfTheWeek (date, dayOfTheWeek, lastSundayDate)
{
var activeSheet = SpreadsheetApp.getActiveSpreadsheet();
var activeCell = activeSheet.getActiveRange();
var activeRow = activeCell.getRowIndex();
var activeColumn = activeCell.getColumn();
var count = 1;
for (var j = 1; j < dayOfTheWeek; j++)
{
var date2 = lastSundayDate.valueOf() + j*86400;
Logger.log('Date ' + j + ' is:' + date2);
Logger.log('Last Sunday is:' + lastSundayDate);
if (holidayOrNot(date2) == true)
{
}
else
{
count = count + 1;
}
}
return count;
}
function holidayOrNot(date2)
{
var holidaysSheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Holidays');
var listOfHolidays = holidaysSheet.getSheetValues(2, 2, 95, 1);
var isDateMatch = false;
for (var k = 0; k < 90; k++)
{
if (date2 == listOfHolidays[k].valueOf())
{
isDateMatch = true;
break;
}
else
{
continue;
}
}
return isDateMatch;
}
I think the problem is two-fold here:
The date2 calculation isn't working for some reason (var date2 = lastSundayDate.valueOf() + j*86400;)
The function holidayOrNot is returning false, no matter what, even if it encounters a holiday ... the condition date2 == listOfHolidays[k] isn't working for some reason...
Help would be appreciated!
maybe this method below could help you in your calculations, it returns an integer corresponding to the day of the year so if you apply this to your holidays days and compare to the days of interest it could be a good way to find matches.
here it is, just add these lines outside of any function in your script (so you can use it anywhere) then use it like this :
var d = new Date().getDOY();
Logger.log(d)
Here the method :
Date.prototype.getDOY = function() {
var onejan = new Date(this.getFullYear(),0,1);
return Math.ceil((this - onejan) / 86400000);
}
Assuming that lastSundayDate is being passed around correctly, I see a glaring problem:
lastSundayDate.valueOf().
valueOf() on Date objects returns the primitive value... it looks like you're going for adding a day to the date (86400 seconds * j)? I can't tell what the logic is supposed to be here. But the valueOf() date2 is definitely giving you an integer something like: 1384628769399 (see here).
What you really want to accomplish is something like Date.getDay(), or something similar so that you can add hours, days, etc. to the original Date. This is likely the source of all your problems.
What you can do is read the Mozilla Developer Network documentation on Date objects to see all of the functions on Dates and their uses. You can greatly simplify what you're trying to do by using these functions, instead of doing abstract operations like j * 86400.
It should also be noted that you can do simple operations such as the following, to add 4 hours to the current Date (time):
var myDate = new Date();
Logger.log(myDate); // ~ console.write
var laterDate = new Date(myDate.setHours(myDate.getHours() + 4));
Logger.log(laterDate); // ~ console.write
which gives the following:
[13-11-16 14:13:38:947 EST] Sat Nov 16 14:13:38 GMT-05:00 2013
[13-11-16 14:13:38:954 EST] Sat Nov 16 18:13:38 GMT-05:00 2013
Working with dates can be tricky - but it's always best to use the simplest methods that are available, which are built into the Date objects themselves. There are also numerous other libraries that provide extended functionality for Dates such as Date js.
If you're still running into your problem after attempting to try using methods I displayed above, please run your script and post both the Execution Transcript and the content of the Logger so that I can help you narrow down the issue :)
I am using a mailing list program which inserts a date into a web link that is "encoded" so it can't be changed or edited by users.
The format is described as follows:
An eight character string, AABBCCDD,where:
Year = 1980 + HexToInt(BB) / 3
Month = HexToInt(CC) / 7 - 21
Day = HexToInt(DD) / 7 - 5
There is also a checksum included to avoid casual modification:
AA = IntToHex(Year + Month + Day mod 200)
For example 2660BDAF would refer to 20 June, 2012.
Can you help me convert the following to Classic ASP:
CodedDateStr = Request.querystring("Exp")
AYear = 1980 + HexToInt(CodedDateStr[3] + CodedDateStr[4]) / 3
AMonth = HexToInt(CodedDateStr[5] + CodedDateStr[6]) / 7 - 21
ADay = HexToInt(CodedDateStr[7] + CodedDateStr[8]) / 7 - 5
ACheckSum = AYear + AMonth + ADay mod 200
if ACheckSum <> HexToInt(CodedDateStr[1] + CodedDateStr[2]) then
ValidDate = 0
else
ValidDate = 1
end if
AExpiryDate = EncodeDate(ADay, AMonth, AYear)
if Date() > AExpiryDate then
ExpiredOffer = 1
else
ExpiredOffer = 0
end if
....
It looks like the HexToInt equivalent is clng("&h" & hexnumber)
I'm not sure about EncodeDate, i hope it is not something cludgy like CDate(AMonth + "/" + ADay + "/" + AYear)
CLng("&h" & hexnumber) looks like a good method for HexToInt.
For EncodeDate, look at the DateSerial function, which takes a year, month, and day, and returns a Date value.
I need to convert a datenumber to its closest end-of-month date. I found an online link but it is very inefficient for a large matrix (at http://www.mathworks.com/matlabcentral/fileexchange/26374-round-off-dates-and-times). Does Matlab (Financial Toolbox) has an inbuilt function for this? I couldn't find it.
date_in = 734421 ;
somefunction(date_in) --> Sept 2010
Thanks!
Basically, it sounds like you are asking for whether a given date is closer to the preceding or following month. You can greatly simplify the logic involved if you use the functions EOMDAY to find the date for the end of the month and ADDTODATE to shift the current month up or down by one. Here's an example function that takes a date number as input:
function closestString = closest_month(dateNumber)
dateVector = datevec(dateNumber);
daysInMonth = eomday(dateVector(1),dateVector(2));
if dateVector(3) > daysInMonth/2
dateNumber = addtodate(dateNumber,1,'month');
else
dateNumber = addtodate(dateNumber,-1,'month');
end
closestString = datestr(dateNumber,'mmm yyyy');
end
I had some errors in my previous version. Here's the logic incorporated into a function. It also checks for the month and updates accordingly.
function out = roundMonth(dateNumber)
dateVector = datevec(dateNumber);
day = dateVector(3);
month = dateVector(2);
year = dateVector(1);
month = month + sign(day - 15 + double(~(month-2)))...
+ double(~(day-15 + double(~(month-2))));
dateVector(1) = year + double((month-12)==1) - double((1-month)==1);
dateVector(2) = mod(month,12) + 12*double(~mod(month,12));
out = datestr(dateVector,'mmm yyyy');
EXAMPLES:
1.
roundMonth(datenum('10-Oct-2010'))
ans =
Sep 2010
2.
roundMonth(datenum('20-Oct-2010'))
ans =
Nov 2010
3.
roundMonth(datenum('20-Dec-2010'))
ans =
Jan 2011
4.
roundMonth(datenum('10-Jan-2010'))
ans =
Dec 2009