I'd like to do something like this:
How to achieve a row index column in Emacs Org Mode using a Calc column rule
but I'd like the rows to be numbered in reverse order. I suspect this should be very easy, and should have something to do with #>, but e.g. $1=#>-## doesn't work.
You can try this example
| row | data |
|-----+------|
| 8 | |
| 7 | |
|-----+------|
| 6 | |
| 5 | |
| 4 | |
| 3 | 5123 |
| 2 | |
| 1 | 4234 |
#+TBLFM: $1='(- (length org-table-dlines) ##)
Related
I have a table like the following one:
+---------+-------+-------+-------------+--+
| Section | Group | Level | Fulfillment | |
+---------+-------+-------+-------------+--+
| A | Y | 1 | 82.2 | |
| A | Y | 2 | 23.2 | |
| A | M | 1 | 81.1 | |
| A | M | 2 | 28.2 | |
| B | Y | 1 | 89.1 | |
| B | Y | 2 | 58.2 | |
| B | M | 1 | 32.5 | |
| B | M | 2 | 21.4 | |
+---------+-------+-------+-------------+--+
And this would be my desired output:
+---------+-------+--------------------+--------------------+
| Section | Group | Level1_Fulfillment | Level2_Fulfillment |
+---------+-------+--------------------+--------------------+
| A | Y | 82.2 | 23.2 |
| A | M | 81.1 | 28.2 |
| B | Y | 89.1 | 58.2 |
| B | M | 32.5 | 21.4 |
+---------+-------+--------------------+--------------------+
Thus, for each section and group I'd like to obtain their percents of fulfillment for level 1 and level 2. To achieve this, I've tried crosstab(), but using this function returns me an error ("The provided SQL must return 3 columns: rowid, category, and values.") because I'm using more than three columns (I need to maintain section and group as identifiers for each row). Is possible to use crosstab in this case?
Regards.
I find crosstab() unnecessary complicated to use and prefer conditional aggregation:
select section,
"group",
max(fulfillment) filter (where level = 1) as level_1,
max(fulfillment) filter (where level = 2) as level_2
from the_table
group by section, "group"
order by section;
Online example
I have one table:
| id | head1| head2 | head3|
| 1 | fv1 | fw1,fw2,fw3| fv3 |
| 2 | sv2 | sw1,sw2,sw3| sv4 |
And would like to have the following:
| id | head2 |
| 1 | fw1 |
| 1 | fw2 |
| 1 | fw3 |
| 2 | sw1 |
| 2 | sw2 |
| 2 | sw3 |
So I would like to split a comma-delimited content of some columns and then copy it over into the different table as rows for search purposes.
Which Talend component should I use to achieve this? Is that possible?
tNormalize should help you with this problem.
Just select "," as field separator, and head2 as the column to normalize.
I have the following table that I have loaded in Tableau (It has only one column CreatedOnDate)
+-----------------+
| CreatedOnDate |
+-----------------+
| 1/1/2016 |
| 1/2/2016 |
| 1/3/2016 |
| 1/4/2016 |
| 1/5/2016 |
| 1/6/2016 |
| 1/7/2016 |
| 1/8/2016 |
| 1/9/2016 |
| 1/10/2016 |
| 1/11/2016 |
| 1/12/2016 |
| 1/13/2016 |
| 1/14/2016 |
+-----------------+
I want to be able to find the maximum date in the table, compare it with every date in the table and get the difference in days. For the above table, the maximum date in table is 1/14/2016. Every date is compared to 1/14/2016 to find the difference.
Expected Output
+-----------------+------------+
| CreatedOnDate | Difference |
+-----------------+------------+
| 1/1/2016 | 13 |
| 1/2/2016 | 12 |
| 1/3/2016 | 11 |
| 1/4/2016 | 10 |
| 1/5/2016 | 9 |
| 1/6/2016 | 8 |
| 1/7/2016 | 7 |
| 1/8/2016 | 6 |
| 1/9/2016 | 5 |
| 1/10/2016 | 4 |
| 1/11/2016 | 3 |
| 1/12/2016 | 2 |
| 1/13/2016 | 1 |
| 1/14/2016 | 0 |
+-----------------+------------+
My goal is to create this Difference calculated field. I am struggling to find a way to do this using DATEDIFF.
And help would be appreciated!!
woodhead92, this approach would work, but means you have to use table calculations. Much more flexible approach (available since v8) is Level of Details expressions:
First, define a MAX date for the whole dataset with this calculated field called MaxDate LOD:
{FIXED : MAX(CreatedOnDate) }
This will always calculate the maximum date on table (will overwrite filters as well, if you need to reflect them, make sure you add them to context.
Then you can use pretty much the same calculated field, but no need for ATTR or Table Calculations:
DATEDIFF('day', [CreatedOnDate], [MaxDate LOD])
Hope this helps!
I am looking at a org-mode spreadsheet formula to get the number of non-empty lines in a cell. Example :
| col1 | col2 |
|------+------|
| a | 3 |
| b | |
| c | |
| | |
|------+------|
| a | 1 |
| | |
|------+------|
| a | 2 |
| b | |
| | |
|------+------|
I have "col1" as input, and would like to fill "col2" automatically (the values can be anything, not just a b c).
Note that what you call "cell" is actually a group of cells delimited by horizontal separators (hlines).
The following example uses calc's vlen function to get the size of the vector of cells on column 1, and rows between the previous (#-I) and next (#+I) hlines.
| col1 | col2 |
|------+------|
| a | 3 |
| b | |
| c | |
| | |
|------+------|
#+TBLFM: #2$2=vlen(#-I$1..#+I$1)
You have to apply this same formula for all row groups.
gave this table:
| a | b | c |
|---+---+----+
| 3 | 4 | |
| 1 | 2 | |
| 1 | 3 | |
| 2 | 2 | |
I want to get the dot product of two column a and b ,the result should be equel to (3*4)+(1*2)+(1*3)+(2*2) which is 21.
I don't want use the clumsy formula (B1*B2+C1*C2+D1*D2+E1*E2) because actually I have a large table waiting to calculate.
I know emacs's Calc tool has a "vprod" function which can do those sort of things ,but I dont' know how to turn the full column to a vector.
Can anybody tell me how to achieve this task,appreciate it!
In emacs-calc, the simple product of 2 vectors calculates the dot product.
This works (I put the result in #6$3; also the parenthesis can be omitted):
| a | b | c |
|---+---+----|
| 3 | 4 | |
| 1 | 2 | |
| 1 | 3 | |
| 2 | 2 | |
|---+---+----|
| | | 21 |
#+TBLFM: #6$3=(#I$1..#II$1)*(#I$2..#II$2)
#I and #II span from the 1st hline to the second.
This can be solved using babel and R in org-mode:
#+name: mytable
| a | b | c |
|---+---+----+
| 3 | 4 | |
| 1 | 2 | |
| 1 | 3 | |
| 3 | 2 | |
#+begin_src R :var mytable=mytable
sum(mytable$a * mytable$b)
#+end_src
#+RESULTS:
: 23