I want to define a variable /Test123 in perl .I am trying something like this but i am getting error
my $uriReference="Test123";
##Here is where i am trying to create /Test123
my $routingUrl = "\"/".$uriReference."\"";
I think i am doing some mistake here Need help?
You can use qq() instead to emulate double quote interpolation:
my $url = qq("/$uriReference");
Although I do not see anything technically wrong with your assignment, it should assign "/Test123" to your variable. So perhaps the error is about something else. We would know if you had included your error message in your question. There is no reason you should ever not include error messages in questions.
You should also know that you do not need to break up your quotes, you can do this:
my $url = "\"/$uriReference\"";
Related
I have $stringF. Contained within $stringF is the following (the string is all one line, not word-wrapped as below):
http://news.google.com/news/url?sa=t&fd=R&ct2=us&usg=
AFQjCNHWQk0M4bZi9xYO4OY4ZiDqYVt2SA&clid=
c3a7d30bb8a4878e06b80cf16b898331&cid=52779892300270&ei=
H4IAW6CbK5WGhQH7s5SQAg&url=https://abcnews.
go.com/Lifestyle/wireStory/latest-royal-wedding-thousands-streets-windsor-55280649
I want to locate that string and make it look like this:
https://abcnews.go.com/Lifestyle/wireStory/latest-royal-
wedding-thousands-streets-windsor-55280649
Basically I need to use preg_replace to find the following string:
http://news.google.com/news/url?sa= ***SOME UNKNOWN CONTENT*** &url=http
and replace it with the following string:
http
I'm a little rusty with my php, and even rustier with regular expressions, so I'm struggling to figure this one out. My code looks like this:
$stringG = preg_replace('http://news.google.com/news/url?sa=*&url=http','http',$stringH);
except I know I can't use wildcards and I know I need to specially deal with the special characters (colon, forward slash, question mark, and sign, etc). Hoping someone can help me out here.
Also of note is that my $stringF contains multiple instances of such strings, so I need the preg_replace to be not greedy - otherwise it will replace a huge chunk of my string unnecessarily.
PHP has tools for that, no need to use a regex. parse_url to get the components of an url (scheme, host, path, anchor, query, ...) and parse_str to get the keys/values of the query part.
$url = 'http://news.google.com/news/url?sa=t&fd=R&ct2=us&usg=AFQjCNHWQk0M4bZi9xYO4OY4ZiDqYVt2SA&clid=c3a7d30bb8a4878e06b80cf16b898331&ci=52779892300270&ei=H4IAW6CbK5WGhQH7s5SQAg&url=https://abcnews.go.com/Lifestyle/wireStory/latest-royal-wedding-thousands-streets-windsor-55280649';
parse_str(parse_url($url, PHP_URL_QUERY), $arr);
echo $arr['url'];
Why I cannot use str_replace() to replace content between the ""? While I replace links within a file they get skipped since they are within quotes.
Example.
href="/path/to/file/is/here"
should be
href="/New/Path/To/File/Goes/Here"
If the paths/urls were not in quotes, str_replace() would work.
I'm assuming this is PHP. So, from the examples here:
http://php.net/manual/en/function.str-replace.php
You can see that you should not intercalate the same type of quotes.
So try changing the quotes in your code to single quotes or, change, the double quotes in your html to single quotes.
If that's not it, I hope at least that doc reference helps you.
This might help I usually code in java but php is pretty similar. Next time input part of your code so that the community can see your logic.
In your if statement on line 67 the 3rd variable $stringToSearch should be regex not the string your assigning it to. The purpose of regex as you know is to replace characters you don't want in your code as you already know
What you had that was not working:
// replacing string from files
//$stringToSearch = str_replace('"', "!!", $stringToSearch);
$stringToSearch = str_replace($toBeReplaced, $toBeReplacedWith, $stringToSearch);
//$stringToSearch = str_replace("!!", '"', $stringToSearch);
What I am thinking it should be:
$stringToRegex = str_replace('"', "!!", $stringToSearch);
$stringToSearch = str_replace($toBeReplaced, $toBeReplacedWith, $stringToRegex );
If anyone else has any suggestion it would be appreciated as i don't code in php.
I'm using RRDs::Simple function and it needs bunch of parameters.
I have placed these parameters in a special variable (parsing, sorting and calculating data from a file) with all quotes, commas and other stuff.
Of course
RRDs::create ($variable);
doesn't work.
I've glanced through all perl special variables and have found nothing.
How to substitute name of variable for the data that contained in that variable?
At least could you tell me with what kind of tools(maybe another special variables) it can be done?
Assuming I'm understanding what you're asking:
You've build the 'create' data in $variable, and are now trying to use RRDs::create to actually do it?
First step is:
print $variable,"\n"; - to see what is actually there. You should be able to use this from the command line, with rrdtool create. (Which needs a filename, timestep, and some valid DS and RRA parameters)
usually, I'll use an array to pass into RRDs::create:
RRDs::create ( "test.rrd", "-s 300",
"DS:name:GAUGE:600:U:U", )
etc.
If $variable contains this information already, then that should be ok. The way to tell what went wrong is:
if ( RRDs::error ) { print RRDs::error,"\n"; }
It's possible that creating the file is the problem, or that your RRD definitions are invalid for some reason. rrdtool create on command line will tell you, as will RRDs::error;
I have an array that have some symbols that I want to remove and even thought I find a solution, I will like to know if this is the right way because I'm afraid if I use it with array will remove the character that I might need on future arrays.
Here is an example item on my array:
$string1='22 | logging monitor informational';
so I try the following:
$string1=~ s/\s{6}\|(?=\s{6})//;
So my output is:
22 logging monitor informational
Is the other way that best match "|". I just want to remove the pipe character.
Thanks in advance
"I want to remove just the pipe character."
OK, then do this:
$string1 =~ s/\|//;
This will remove the first pipe character in the string. (You said in another comment that you don't want to remove any additional pipe characters.) If that's not what you want, then I'd suggest telling us exactly what you do want. We can't read minds, you know.
In the mean time, I'd also strongly recommend reading the Perl regular expressions tutorial.
Quick question... I'm trying the following:
set changedir "cd $JSDIR/"
eval $changedir
..Where $JSDIR is defined already. Running this script gives the error: "set: Variable name must begin with a letter."
What's the fix?
Thanks.
That's not an error message generated by Tcl, because Tcl's variables most definitely do not need to begin with a letter. OK, it tends to be convenient to keep them alphanumeric because the $var shorthand syntax is more restrictive than the general space of variable names, but the set var form can handle virtually anything.
I'm guessing that script is being evaluated by something that isn't Tcl, perhaps bash?
Try to set changedir cd ${JSDIR/} instead
This message can appear when in fact the variable name is entirely correct, and the real problem is that the variable value needs to be quoted. Try instead of: set changedir "cd $JSDIR//"