Is there a Matlab conditional IF operator that can be placed INLINE like VBA's IIF - matlab

Question

In VBA I can do the following:
A = B + IIF(C>0, C, 0)
so that if C>0 I get A=B+C and C<=0 I get A=B
Is there an operator or function that will let me do these conditionals inline in MATLAB code?

Answer 1

How about simply using the fact that MATLAB automatically converts variable types when required by the operation? E.g., logical to double.
If your variables are scalar double, your code, I believe, can be replaced by
a = b + (c > 0) * c;
In this case, the operator (c > 0) values 1 (logical type) whenever c > 0 and values to 0 otherwise.

Answer 2

There is no ternary operator in Matlab. You can, of course, write a function that would do it. For example, the following function works as iif with n-d input for the condition, and with numbers and cells for the outcomes a and b:
function out = iif(cond,a,b)
%IIF implements a ternary operator
% pre-assign out
out = repmat(b,size(cond));
out(cond) = a;
For a more advanced solution, there's a way to create an inline function that can even do elseif, as outlined in this blog post about anonymous function shenanigans:
iif = #(varargin) varargin{2*find([varargin{1:2:end}], 1, 'first')}();
You use this function as
iif(condition_1,value_1,...,true,value_final)
where you replace the dots with any number of additional condition/value pairs.
The way this works is that it picks among the values the first one whose condition is true. 2*find(),1,'first') provides the index into the value arguments.

Answer 3

There is no built-in solution for this, but you can write an IIF yourself.
function result=iif(cond, t, f)
%IIF - Conditional function that returns T or F, depending of condition COND
%
% Detailed
% Conditional matrix or scalar double function that returns a matrix
% of same size than COND, with T or F depending of COND boolean evaluation
% if T or/and F has the same dimensions than COND, it uses the corresponding
% element in the assignment
% if COND is scalar, returns T or F in according with COND evaluation,
% even if T or F is matrices like char array.
%
% Syntax
% Result = iif(COND, T, F)
% COND - Matrix or scalar condition
% T - expression if COND is true
% F - expression if COND is false
% Result - Matrix or scalar of same dimensions than COND, containing
% T if COND element is true or F if COND element is false.
%
if isscalar(cond)
if cond
result = t;
else
result = f;
end
else
result = (cond).*t + (~cond).*f;
end
end

Answer 4

Others have said already that there is no ternary ?: operator in Matlab. As a solution I suggest this function, which takes three functions instead of values. Therefore the amount of unnecessary calculations is minimized and you can check conditions before starting calculations, e.g. if a value is really numeric, or finite, or nonzero:
function [ out ] = iif( condition, thenF, elseF, in, out)
%iif Implements the ternary ?: operator
% out = iif (#condition, #thenF, #elseF, in[, out])
%
% The result is equivalent to:
% condition(x) ? thenF(x) : elseF(x)
%
% The optional argument out serves as a template, if the output type is
% different from the input type, e.g. for mapping arrays to cells and
% vice versa.
%
% This code is in the public domain.
mask = condition(in);
if nargin <= 4
out = in;
end
if sum(mask)
out(mask) = thenF(in(mask));
end
if sum(~mask)
out(~mask) = elseF(in(~mask));
end
end
Use it like this:
f = #(y)(iif(#(x)(x > 3), #(x)(x.^2), #(x)(x/2), y))
f(linspace(0,6,10))

Answer 5

Inspired by Jonas' answer the function below also works for mixed type input and chars, for which his function isn't stable.
function out = iif(cond, a, b)
%IIF implements a ternary operator
% Use cell output for either char or mixed type input
if ischar(a) || ischar(b) || ~strcmp(class(a), class(b))
out = cell(size(cond));
[out{cond}] = deal(a);
[out{~cond}] = deal(b);
else
% Use array output and logical indexing
out = repmat(b, size(cond));
out(cond) = a;
end
end
Edit: weeded out the extra conditional options in the cell branch, which were apparently remnants of a previous mistake, this is probably faster, and definitely cleaner.

Answer 6

What you refer to is a ternary operator, in C-like notation, ?:. The expression
tern = bool ? T : F
returns T if bool evaluates to true, F otherwise. MATLAB has no ternary operator, however it can be implemented in different ways as an inline expression.
Arrays
% cell array version (any type)
tern = {F,T}{bool+1} % only Octave
tern = subsref({F,T}, struct('type', '{}', 'subs', {{bool+1}}))
% vector array version (numeric types only)
tern = [F,T](bool+1) % only Octave
tern = subsref([F,T], struct('type', '()', 'subs', {{bool+1}}))
Note that T and F have been swapped, and that different brackets are used. The vector array version is a specialization for numeric types. MATLAB does not allow direct indexation of fresh arrays, hence the use of subsref.
Pros: Works for any type and any value. Can be used inline.
Cons: Before returning the result to tern, both T and F
are evaluated.
Logical operators and eval
( bool && eval('tern=T') ) || eval('tern=F')
Note that the logical operators are short-circuited.
Pros: Works for any type and any value. Only one, T or F, is evaluated.
Cons: Works only in Octave. Can't be used inline, but through the variable tern. eval is not efficient but required.
Basic arithmetic
tern = bool*T + !bool*F
Pros: Can be used inline.
Cons: Works only for numeric types, and might fail when T or F are NaN or Inf. Both, T and F, are evaluated.
Maximum
tern = max(T,F) % bool = T>F
Note that this solution fits the particular requirements of the initial question with max(C,0).
Pros: Can be used inline.
Cons: Works only for numeric types, and might fail when T or F are NaN. Both, T and F, are evaluated. Use is strongly limited.

Answer 7

There is now a tern function on the MathWorks file exchange:
http://www.mathworks.com/matlabcentral/fileexchange/39735-functional-programming-constructs/content/tern.m
The code is reproduced here:
function varargout = tern(condition, true_action, false_action)
% out = tern(condition, true_action, false_action)
%
% Ternary operator. If the first input is true, it returns the second
% input. Otherwise, it returns the third input. This is useful for writing
% compact functions and especially anonymous functions. Note that, like
% many other languages, if the condition is true, not only is the false
% condition not returned, it isn't even executed. Likewise, if the
% condition is false, the true action is never executed. The second and
% third arguments can therefore be function handles or values.
%
% Example:
%
% >> tern(rand < 0.5, #() fprintf('hi\n'), pi)
% ans =
% 3.1416
% >> tern(rand < 0.5, #() fprintf('hi\n'), pi)
% hi
%
% It works with multiple outputs as well.
%
% >> [min_or_max, index] = tern(rand < 0.5, ...
% #() min([4 3 5]), ...
% #() max([4 3 5]))
% min_or_max =
% 5
% index =
% 3
%
% Tucker McClure
% Copyright 2013 The MathWorks, Inc.
if condition() % Works for either a value or function handle.
[varargout{1:nargout}] = true_action();
else
[varargout{1:nargout}] = false_action();
end
end

Answer 8

This is more of an addenum to Alex's answer.
Alex's method doesn't work when you want to return inf
In these cases you often end up getting a 0*inf figure, which MATLAB will evaluate to NaN. Problematic... We can avoid this multiplication using a lookup instead.
As an example, a useful barrier function in convex optimization is something that behaves like log everywhere positive, and -inf elsewhere. Here is how you might create such a function using a lookup:
INF_CONDITION = [0, inf];
fn_logbr = #(x) (x>0)*log(x) - INF_CONDITION( 1+(x<=0) )
Inline conditionals are a hack, and you lose lazy evaluation. You have to be careful. However, having semantic code is really nice, and its easier to share your code when you can't guarantee everyone's environments are the same.

Answer 9

If you're looking for an option that doesn't force you to build a function and can take care fairly simple expressions, you can take advantage of anonymous functions. The anonymous function returns a logical, which can be a numeral 1 or 0. Because of this, they can be used to multiply with other numbers to determine if they still hold a value after the expression, or lose their value.
For your case (including if A, B, and C are vectors or not): A = B .+ (#() C>0)()

Answer 10

Using:
eval('input;', 'input = 1;');
is very helpful where 'input' might not exist in the first place.