format of read file in fortran - fortran90

What should be the read format of the of following dataset in fortran. there are 6 spaces between column 1 and 2 with no space of column 1 from margin.
1911.01.01 2.42873702403226
1911.01.02 3.5057043827303
1911.01.03 2.73602527398387
1911.01.04 6.07213767208333
1911.01.05 6.94818901068145
1911.01.06 3.66986589769583
1911.01.07 1.94565994542339
1911.01.08 2.39384275272177
1911.01.09 3.05526130775417
1911.01.10 2.69990836499194
1911.01.11 6.08406263835833
1911.01.12 7.34200241064516
1911.01.13 2.42873702403226
1911.01.14 3.5057043827303
1911.01.15 2.73602527398387
1911.01.16 6.07213767208333
1911.01.17 6.94818901068145
1911.01.18 3.66986589769583
1911.01.19 1.94565994542339
1911.01.20 2.39384275272177
1911.01.21 3.05526130775417
1911.01.22 2.69990836499194
1911.01.23 6.08406263835833
1911.01.24 7.34200241064516
1911.01.25 2.42873702403226
1911.01.26 3.5057043827303
1911.01.27 2.73602527398387
1911.01.28 6.07213767208333
1911.01.29 6.94818901068145
1911.01.30 3.66986589769583
1911.01.31 1.94565994542339
I tried.....
format (i4,i2,i2,6x,d9.14)
but it didnt work
thanks in advance
elisa

So try
(i4,a1,i2,a1,i2,6x,d16.14)
I think you've made two mistakes:
Not accounting for the . characters in the dates, I don't think that they will automatically be treated as field separators (as , or spaces would be). Obviously you'll want to ignore them.
In your d edit descriptor the number of decimal digits, that is the number after the . ought to be no greater than the total field width, ie the number before the ..

Related

Make a list with the quarter and year based on a date range of quarters KDB+/Q

I have a list of date ranges for the past 8 quarters given by the below function
q) findLastYQuarters:{reverse("d"$(-3*til y)+m),'-1+"d"$(-3*-1+til y)+m:3 bar"m"$x}[currentDate;8]
q) findLastYQuarters
2020.01.01 2020.03.31
2020.04.01 2020.06.30
2020.07.01 2020.09.30
2020.10.01 2020.12.31
2021.01.01 2021.03.31
2021.04.01 2021.06.30
2021.07.01 2021.09.30
2021.10.01 2021.12.31
I need to produce a separate list that labels each item in this list by a specific format; the second list would need to be
1Q20,2Q20,3Q20,4Q20,1Q21,2Q21,3Q21,4Q21
This code needs to be able to run on it's own, so how can I take the first list as an input and produce the second list? I thought about casting the latter date in the range as a month and dividing it by 3 to get the quarter and extracting the year, but I couldn't figure out how to actually implement that. Any advice would be much appreciated!
I'm sure there are many ways to solve this, a function like f defined below would do the trick:
q)f:{`$string[1+mod[`month$d;12]%3],'"Q",/:string[`year$d:x[;0]][;2 3]}
q)lyq
2020.01.01 2020.03.31
2020.04.01 2020.06.30
2020.07.01 2020.09.30
2020.10.01 2020.12.31
2021.01.01 2021.03.31
2021.04.01 2021.06.30
2021.07.01 2021.09.30
2021.10.01 2021.12.31
q)f lyq
`1Q20`2Q20`3Q20`4Q20`1Q21`2Q21`3Q21`4Q21
Figured it out.
crop:findLastYQuarters;
crop[0]:crop[0][1];
crop[1]:crop[1][1];
crop[2]:crop[2][1];
crop[3]:crop[3][1];
crop[4]:crop[4][1];
crop[5]:crop[5][1];
crop[6]:crop[6][1];
crop[7]:crop[7][1];
labels:()
labelingFunc:{[r] temp:("." vs string["m"$r]); labels,((string(("J"$temp[1])%3)),"Q",(temp[0][2,3])};
leblingFunc each crop;
labels

Numeric (not integer or double precision) picture token Clarion+Postgresql

i need numeric mask like this:
100
101.1
102.123
Take maksimum given decimal places but if last digit is 0 trim it.
Something like:
#n-12_`2 but trim right 0 and .
Ex:
x = 102.1230057::double precision
select rtrim(rtrim(round(x::numeric, 2)::text, '0'), '.')::numeric
If you don't need right aligned numbers, you can use #S10 (or the length you want).
#P<#.##P style pictures might help.

Remove according to the pattern matching

The current raw data :
1-2-05.11
1-15-05.20
how can I remove after .. The expected result is 1-2-05. I test using split_part and also substring, but the result is not fit the requirement.
Any suggestion ?
Try this,I assume that your expected output is 1-2-05.(with .)
Using split_part().
SELECT SPLIT_PART('1-2-05.11','.',1)||'.';
Using substring().
SELECT SUBSTRING('1-15-05.20', 1, LENGTH('1-15-05.20') - 2)
1 is the starting position(from left) of the string(1-15-05.20) in which substring action to be taken
LENGTH('1-15-05.20') - 2, is to define the number of character to be extracted from the given string.The string is 1-15-05.20 the length() of it is 10, you need to remove last two characters from this 10 chars so 10 - 2 ie LENGTH('1-15-05.20') - 2

How to pad a number with zeros to a specific length in tcl?

I need to pad a number with a specific length (say 8) where the input number could be of any length.
Example: If the input number is 123456, I want to pad it as 12345600
If I knew that all input numbers would be of the same length (say 6), I would have done something like
[format "$input_num%02d" 0]
But since the input number can be of varied length, how do I achieve this?
Obviously the below didn't work:
set cur_length [expr[llength[split $input_num ""]]
set padding [expr 8 - $cur_length]
set padded_num [format "$input_num%${padding}d" 0]
Any help is appreciated.
Thanks.
It's really simple, actually:
format %-08s $input_num
A number is also a string, so it can be left-justified like a string.
Documentation: format

Applescript: return specific index positions from a date string

I have already used the text delimiters and item numbers to extract a date from a file name, so I'm clear about how to use these. Unfortunately the date on these particular files are formatted as "yyyyMMdd" and I need to covert the date into format "yyyy-MM-dd". I have been trying to use the offset function to get particular index positions, and I have found several examples of how you would return the offset of particular digits in the string, example:
set theposition to offset of 10 in theString -- this works
(which could return 5 or 7) but I have not found examples of how to call the digits at a specific index:
set _day to offset 7 of file_date_raw -- error
"Finder got an error: Some parameter is missing for offset." number -1701
How would you do this, or is there a totally better way I'm unaware of?
To "call the digits at a specific index", you use:
text 1 thru 4 of myString
If you know that each string has 8 characters in the yyyymmdd format, then you don't need to use 'offset' or any parsing, just add in the -'s, using text x thru y to dissect the string.
set d to "20011018"
set newString to (text 1 thru 4 of d) & "-" & (text 5 thru 6 of d) & "-" & (text 7 thru 8 of d)