I have a list of date ranges for the past 8 quarters given by the below function
q) findLastYQuarters:{reverse("d"$(-3*til y)+m),'-1+"d"$(-3*-1+til y)+m:3 bar"m"$x}[currentDate;8]
q) findLastYQuarters
2020.01.01 2020.03.31
2020.04.01 2020.06.30
2020.07.01 2020.09.30
2020.10.01 2020.12.31
2021.01.01 2021.03.31
2021.04.01 2021.06.30
2021.07.01 2021.09.30
2021.10.01 2021.12.31
I need to produce a separate list that labels each item in this list by a specific format; the second list would need to be
1Q20,2Q20,3Q20,4Q20,1Q21,2Q21,3Q21,4Q21
This code needs to be able to run on it's own, so how can I take the first list as an input and produce the second list? I thought about casting the latter date in the range as a month and dividing it by 3 to get the quarter and extracting the year, but I couldn't figure out how to actually implement that. Any advice would be much appreciated!
I'm sure there are many ways to solve this, a function like f defined below would do the trick:
q)f:{`$string[1+mod[`month$d;12]%3],'"Q",/:string[`year$d:x[;0]][;2 3]}
q)lyq
2020.01.01 2020.03.31
2020.04.01 2020.06.30
2020.07.01 2020.09.30
2020.10.01 2020.12.31
2021.01.01 2021.03.31
2021.04.01 2021.06.30
2021.07.01 2021.09.30
2021.10.01 2021.12.31
q)f lyq
`1Q20`2Q20`3Q20`4Q20`1Q21`2Q21`3Q21`4Q21
Figured it out.
crop:findLastYQuarters;
crop[0]:crop[0][1];
crop[1]:crop[1][1];
crop[2]:crop[2][1];
crop[3]:crop[3][1];
crop[4]:crop[4][1];
crop[5]:crop[5][1];
crop[6]:crop[6][1];
crop[7]:crop[7][1];
labels:()
labelingFunc:{[r] temp:("." vs string["m"$r]); labels,((string(("J"$temp[1])%3)),"Q",(temp[0][2,3])};
leblingFunc each crop;
labels
Related
I want to get the number of days between two dates based on specific condition, here is the image illustration of what I am talking about:
I need to devise a formula to calculate number of days from dates (column C) it takes ID = 1 to reach from L1 to L2 , so ideally the output for ID = 1 should be:
L1 : 0
L2 : 2022-07-14 - 2022-07-06 = 8
Same for other ids (2,3). I am just a beginner trying to learn, so I apologize for my ordinary question. Thank you
DAYS will give you the day count between dates. try:
=DAYS(SINGLE(FILTER(C:C; B:B="L2"; A:A=1));
SINGLE(FILTER(C:C; B:B="L1"; A:A=1)))
=DAYS(SINGLE(FILTER(C:C; B:B="L2"; A:A=2));
SINGLE(FILTER(C:C; B:B="L1"; A:A=2)))
=DAYS(SINGLE(FILTER(C:C; B:B="L2"; A:A=3));
SINGLE(FILTER(C:C; B:B="L1"; A:A=3)))
I have two timetables, each of them have 4 columns, where the first 2 columns are of my particular interest. The first column is a date and the second is an hour.
How can I know which observations (by date an hour) are in the timetable 1 but not in the timetable 2 and, therefore, drop those observations from my timetable 1?
So for example, just by looking I realized that timetable1 included the day 25/05/2015 with hours 1 and 2, but the timetable 2 did not include them, therefore I would like to drop those observations from timetable 1.
I tried using the command groups_timetable1 = findgroups(timetable1.Date,timetable1.Hour);but unfortunately this command does not tell you a lot how to distinguish between observations.
Thank you!
call ismember to find one set of data in another.
to find multiple records as a group in another composite records, you call ismember(..., 'rows').
for example
baseline=[
100, 2.1
200, 7.5
120, 11.0
];
isin=ismember(baseline,[200, 7.5],'rows');
pos=find(isin)
if you have time date strings or datetime objects, please convert those to numerical values, such as by calling datenum or posixtime first.
You can use the timetable method innerjoin to do this. Like so:
% Fabricate some data
dates1 = datetime(2015, 5, ones(10,1));
hours1 = (1:10)';
timetable1 = timetable(dates1(:), hours1, rand(10,1), rand(10,1), ...
'VariableNames', {'Hour', 'Price', 'Volume'});
% Subselect a few rows for timetable2
timetable2 = timetable1([1:3, 6:10],:);
% Use innerjoin to pick rows where Time & Hour intersect:
innerjoin(timetable1, timetable2, 'Keys', {'Time', 'Hour'})
By default, the result of innerjoin contains the table variables from both input tables - that may or may not be what you want.
I have a bunch of daily change % data. I would like to calculate cumulative change, which should just be (1+change)*previous day in a chart in Tableau.
Seems simple enough right? I can do it in a few seconds in Excel, but I've tried for hours to get it to work in Tableau and cannot do it.
My thought was that I can create a column that is (1+daily change%), then try to do a compound product. However, I can't seem to get it to work.
I can't attach any files here so I pasted the data, along with a column that is "cum change", which is what I would like the calculation to be.
Thank you much in advance!
Date Daily Change Cum Change
4/1/2015 0.47% 1
4/2/2015 0.56% 1.0056
4/3/2015 -0.72% 0.99835968
4/6/2015 -0.56% 0.992768866
4/7/2015 -0.80% 0.984826715
4/8/2015 0.44% 0.989159952
4/9/2015 -0.66% 0.982631497
4/10/2015 0.99% 0.992359549
4/13/2015 0.92% 1.001489256
4/14/2015 0.73% 1.008800128
4/15/2015 0.95% 1.018383729
4/16/2015 0.42% 1.022660941
4/17/2015 0.52% 1.027978778
4/20/2015 0.02% 1.028184373
4/21/2015 0.56% 1.033942206
4/22/2015 0.35% 1.037561004
4/23/2015 -0.34% 1.034033296
4/24/2015 0.18% 1.035894556
4/27/2015 0.61% 1.042213513
4/28/2015 0.46% 1.047007695
4/29/2015 0.94% 1.056849568
Create a calculated field:
IF INDEX() = 1
THEN 1
ELSE
(1 + AVG([Daily Change])) * PREVIOUS_VALUE(1)
END
The condition checking to see if it's the first row of the partition (INDEX() = 1) is necessary to ensure that the first value of the field is a 1. After that, you can just use the self-referential PREVIOUS_VALUE() to get the previous value of this same calculation.
I'm looking for a function or solution to the following:
For the chart in SQL Reporting i need to multiply values from a Column A. For summation i would use =SUM(COLUMN_A) for the chart. But what can i use for multiplication - i was not able to find a solution so far?
Currently i am calculating the value of the stacked column as following:
=ROUND(SUM(Fields!Value_Is.Value)/SUM(Fields!StartValue.Value),3)
Instead of SUM i need something to multiply the values.
Something like that:
=ROUND(MULTIPLY(Fields!Value_Is.Value)/MULTIPLY(Fields!StartValue.Value),3)
EDIT #1
Okay tried to get this thing running.
The expression for the chart looks like this:
=Exp(Sum(Log(IIf(Fields!Menge_Ist.Value = 0, 10^-306, Fields!Menge_Ist.Value)))) / Exp(Sum(Log(IIf(Fields!Startmenge.Value = 0, 10^-306, Fields!Startmenge.Value))))
If i calculate my 'needs' manually i have to get the following result:
In my SQL Report i get the following result:
To make it easier, these are the raw values:
and you have the possibility to group the chart by CW, CQ or CY
(The values from the first pictures are aggregated Sum values from the raw values by FertStufe)
EDIT #2
Tried your expression, which results in this:
Just to make it clear:
The values in the column
=Value_IS / Start_Value
in the first picture are multiplied against each other
0,9947 x 1,0000 x 0,59401 = 0,58573
Diffusion Calenderweek 44 Sums
Startvalue: 1900,00 Value Is: 1890,00 == yield:0,99474
Waffer unbestrahlt Calenderweek 44 Sums
Startvalue: 620,00 Value Is: 620,00 == yield 1,0000
Pellet Calenderweek 44 Sums
Startvalue: 271,00 Value Is: 160,00 == yield 0,59041
yield Diffusion x yield Wafer x yield Pellet = needed Value in chart = 0,58730
EDIT #3
The raw values look like this:
The chart ist grouped - like in the image - on these fields
CY (Calendar year), CM (Calendar month), CW (Calendar week)
You can download the data as xls here:
https://www.dropbox.com/s/g0yrzo3330adgem/2013-01-17_data.xls
The expression i use (copy / past from the edit window)
=Exp(Sum(Log(Fields!Menge_Ist.Value / Fields!Startmenge.Value)))
I've exported the whole report result to excel, you can get it here:
https://www.dropbox.com/s/uogdh9ac2onuqh6/2013-01-17_report.xls
it's actually a workaround. But I am pretty sure is the only solution for this infamous problem :D
This is how I did:
Exp(∑(Log(X))), so what you should do is:
Exp(Sum(Log(Fields!YourField.Value)))
Who said math was worth nothing? =D
EDIT:
Corrected the formula.
By the way, it's tested.
Addressing Ian's concern:
Exp(Sum(Log(IIf(Fields!YourField.Value = 0, 10^-306, Fields!YourField.Value))))
The idea is change 0 with a very small number. Just an idea.
EDIT:
Based on your updated question this is what you should do:
Exp(Sum(Log(Fields!Value_IS.Value / Fields!Start_Value.Value)))
I just tested the above code and got the result you hoped for.
I simply want to generate a series of dates 1 year apart from today.
I tried this
CurveLength=30;
t=zeros(CurveLength);
t(1)=datestr(today);
x=2:CurveLength-1;
t=addtodate(t(1),x,'year');
I am getting two errors so far?
??? In an assignment A(I) = B, the number of elements in B and
Which I am guessing is related to the fact that the date is a string, but when I modified the string to be the same length as the date dd-mmm-yyyy i.e. 11 letters I still get the same error.
Lsstly I get the error
??? Error using ==> addtodate at 45
Quantity must be a numeric scalar.
Which seems to suggest that the function can't be vectorised? If this is true is there anyway to tell in advance which functions can be vectorised and which can not?
To add n years to a date x, you do this:
y = addtodate(x, n, 'year');
However, addtodate requires the following:
x must be a scalar number, not a string.
n must be a scalar number, not a vector.
Hence the errors you get.
I suggest you use a loop to do this:
CurveLength = 30;
t = zeros(CurveLength, 1);
t(1) = today; % # Whatever today equals to...
for ii = 2:CurveLength
t(ii) = addtodate(t(1), ii - 1, 'year');
end
Now that you have all your date values, you can convert it to strings with:
datestr(t);
And here's a neat one-liner using arrayfun;
datestr(arrayfun(#(n)addtodate(today, n, 'year'), 0:CurveLength))
If you're sequence has a constant known start, you can use datenum in the following way:
t = datenum( startYear:endYear, 1, 1)
This works fine also with months, days, hours etc. as long as the sequence doesn't run into negative numbers (like 1:-1:-10). Then months and days behave in a non-standard way.
Here a solution without a loop (possibly faster):
CurveLength=30;
t=datevec(repmat(now(),CurveLength,1));
x=[0:CurveLength-1]';
t(:,1)=t(:,1)+x;
t=datestr(t)
datevec splits the date into six columns [year, month, day, hour, min, sec]. So if you want to change e.g. the year you can just add or subtract from it.
If you want to change the month just add to t(:,2). You can even add numbers > 12 to the month and it will increase the year and month correctly if you transfer it back to a datenum or datestr.