I've got a huge table for R which should not be exported. So I added a #TAGS: noexport above the table, but that doesn't seem to have any effect. So how do I tag a table?
You cannot add tags to a table, only to a header.
Also, the #+TAGS directive is used to declare a group of tags specific to the whole document, not for tagging a table.
If you surround the table within a comment block, it will not be exported. For example:
#+begin_comment
#+tblname: very_long_table
| col1 | col2 |
|------+------|
| 1 | 22 |
| 2 | 23 |
| 3 | 24 |
| 4 | 25 |
| 5 | 26 |
#+end_comment
#+begin_src sh :var tbl=very_long_table :exports both
echo $tbl
#+end_src
#+RESULTS:
: 1 22 2 23 3 24 4 25 5 26
Related
I am trying to sort my mongodb query according to the occurence of a string in one of its fields (an array). So given this example dataset:
id | hits | categories
------------------------------
1 | 18 | ['sports']
2 | 12 | ['sports', 'news']
3 | 22 | []
4 | 20 | ['news']
I would like to make a query like this one ($includes is obviously a made-up keyword):
Records.find({}, {sort: {$includes: {categories: 'news'}, hits: -1});
Which would give me the resulting output:
id | hits | categories
------------------------------
4 | 20 | ['news']
2 | 12 | ['sports', 'news']
3 | 22 | []
1 | 18 | ['sports']
Is there a simple way to do that?
gave this table:
| a | b | c |
|---+---+----+
| 3 | 4 | |
| 1 | 2 | |
| 1 | 3 | |
| 2 | 2 | |
I want to get the dot product of two column a and b ,the result should be equel to (3*4)+(1*2)+(1*3)+(2*2) which is 21.
I don't want use the clumsy formula (B1*B2+C1*C2+D1*D2+E1*E2) because actually I have a large table waiting to calculate.
I know emacs's Calc tool has a "vprod" function which can do those sort of things ,but I dont' know how to turn the full column to a vector.
Can anybody tell me how to achieve this task,appreciate it!
In emacs-calc, the simple product of 2 vectors calculates the dot product.
This works (I put the result in #6$3; also the parenthesis can be omitted):
| a | b | c |
|---+---+----|
| 3 | 4 | |
| 1 | 2 | |
| 1 | 3 | |
| 2 | 2 | |
|---+---+----|
| | | 21 |
#+TBLFM: #6$3=(#I$1..#II$1)*(#I$2..#II$2)
#I and #II span from the 1st hline to the second.
This can be solved using babel and R in org-mode:
#+name: mytable
| a | b | c |
|---+---+----+
| 3 | 4 | |
| 1 | 2 | |
| 1 | 3 | |
| 3 | 2 | |
#+begin_src R :var mytable=mytable
sum(mytable$a * mytable$b)
#+end_src
#+RESULTS:
: 23
I'm using Emacs org-mode to track times worked on various tasks. The last column in the table is the weekly sum for each task:
|------+-----+-----+-----+-----+-----+-------|
| Task | Mon | Tue | Wed | Thu | Fri | Total |
|------+-----+-----+-----+-----+-----+-------|
| Foo | 2 | 3 | 4 | 5 | 6 | 20 |
| Bar | 2 | 3 | 4 | 5 | 7 | 21 |
#+TBLFM: #2$7=vsum($2..$6)::#3$7=vsum($2..$6)
Currently, I have to add a formula for each new row. Is there any way to customise the formula so that it calculates the sums regardless of how many rows there are?
Column formula did the trick as suggested by fniessen. Here's what I ended up with:
|------+-----+-----+-----+-----+-----+-------|
| Task | Mon | Tue | Wed | Thu | Fri | Total |
|------+-----+-----+-----+-----+-----+-------|
| Foo | 2 | 3 | 4 | 5 | 6 | 20 |
| Bar | 2 | 3 | 4 | 5 | 7 | 21 |
#+TBLFM: $7=vsum($2..$6)
More info in the Column formulas and field formulas section from the docs.
You really should take a closer look at the documentation, and read about "column formulas" (and, even, "row formulas"). A colum formula is $7=...' and is editable viaC-c ='.
I'd like to do something like this:
How to achieve a row index column in Emacs Org Mode using a Calc column rule
but I'd like the rows to be numbered in reverse order. I suspect this should be very easy, and should have something to do with #>, but e.g. $1=#>-## doesn't work.
You can try this example
| row | data |
|-----+------|
| 8 | |
| 7 | |
|-----+------|
| 6 | |
| 5 | |
| 4 | |
| 3 | 5123 |
| 2 | |
| 1 | 4234 |
#+TBLFM: $1='(- (length org-table-dlines) ##)
I've got a table named FOO with the column ("Porc" |- 3 7 15 50 15 7 3) and I'm copying the numbers to another table, shown below. I'm doing it the hard way, cell for cell, but I was wondering if there is a way to copy that range of the remote table (A2 to the bottom) in a single command.
| Pr (%) | ROE de A | ROE de B |
|--------+----------+----------|
| 3 | -11.43 | -34.29 |
| 7 | 0. | -11.43 |
| 15 | 3.43 | 0. |
| 50 | 12. | 17.14 |
| 15 | 20.57 | 34.29 |
| 7 | 24. | 41.14 |
| 3 | 30.86 | 54.86 |
|--------+----------+----------|
| Média | 11.86 | 16.41 |
| Desvio | 8.37 | 17.61 |
#+TBLFM: #2$1=remote(FOO, A2)::#3$1=remote(FOO, A3)::#4$1=remote(FOO, A4)::etc
Thanks
It seems your answer is in the org-mode manual:
$3 = remote(FOO, ###$2)
copy column 2 from table FOO into
column 3 of the current table For the
second example, table FOO must have at
least as many rows as the current
table. Inefficient for large number of
rows.
A Kind of Corollary: Copying all fields in a given row
So just as:
$3 = remote(FOO, ###$2)
copies all the fields from a given column (col2) into column three of the new table, then:
#3 = remote(FOO, #1$$#)
copies all the fields from a given row (row1) into row 3.
There's something about how this standard reference form #r$c interacts with the ## and $# notation that makes this seem a bit abstruse. e.g. this is all the org manual has to say about this remote reference syntax:
## and $# can be used to get the row or column number of the field where the formula result goes.
Umm…?
Posting this example here because I found it all a bit mystifying and hope this helps some else save a few minutes when dealing with rows and tables in the awesome org-mode