how can I get the exit code of a 7zip's operation?
for example:
7z x filename.zip -y
how can I get it?
at now, I do some operations in bat, but I can change language.
I found something with AHK but I cannot use that language.
ps: I'm on win server 2008 r2
ErrorLevel will be populated with the error code from the last command executed. If you were to check the ErrorLevel on the line right after the 7zip command, ErrorLevel will be populated with 7zip's exit code.
7z x filename.zip -y
echo %ErrorLevel%
This above will echo 7zip's exit code
7z x filename.zip -y
set "ExitCode=%ErrorLevel%"
echo %ErrorLevel%
This above will echo set's exit code
7z x filename.zip -y
set "ExitCode=%ErrorLevel%"
echo %ExitCode%
This above will echo 7zip's exit code
You could try using the $LastExitCode variable in PowerShell to find out the exit code of your command. It returns the exit code of the last Windows based program that was run.
For example
cmd /C exit 1
Write-Host $LastExitCode # 1
Example (batch):
7z x filename.zip -y
echo(%errorlevel%
Related
Have tried different approaches to make the SSMs job working with SCP command with perl script. but the job is going into loop with out having a result.
PS : The script is working fine with running from command prompt directly.
command used in the perl script:-
$Command = "scp -i D:\File1\RS2\DataFeed\Code\PrivateKey.ppk -s $InternalFile admin#sftp.world.com:$VendorName/$DestFileName";
system command used in perl
system($command);
While running the command directly from windows cmd it is correctly placing file to the SFTP. but while running this perl script from ssms agent job it seems not working and the job is keep running without any results.
Any possible leads to the actual errors will be much appreciated
Detailed Steps :
Job in SSMS :
Step :
DataFeed.cmd
%_Debug% echo off
cd /d %0\..
pushd .
setlocal
rem -----------------------------------------------------------------
rem Localize environment
rem -----------------------------------------------------------------
if exist DataFeed_Environment.cmd (
call DataFeed_Environment.cmd
) else (
echo DataFeed_Environment.cmd not found!!!
echo
goto CmdUsage
)
rem -----------------------------------------------------------------
rem Run perl package
rem -----------------------------------------------------------------
C:\Perl\bin\perl.exe DataFeedProd1.pl
if %ERRORLEVEL% NEQ 0 goto ErrorExit
goto Exit
rem -----------------------------------------------------
rem Command Usage
rem -----------------------------------------------------
:CmdUsage
Echo ---------------------------------------------------------------------
echo.
echo DataFeed.cmd
echo Wraps the call to DataFeed.pl,
echo mails log upon errors.
echo.
echo Usage:
echo DataFeed.cmd
echo.
echo ----------------------------------
rem endlocal
rem popd
rem exit 1
rem -----------------------------------------------------------------
rem Error exit
rem -----------------------------------------------------------------
:ErrorExit
echo DataFeedProd1.pl failed !!!
echo
rem endlocal
rem popd
rem exit 1
rem -----------------------------------------------------------------
rem Exit
rem -----------------------------------------------------------------
rem endlocal
rem popd
:Exit
rem exit 0
sub CopyDataFeedFileToSftp{
my ($DataFeedFileInternal, $DataFeedVendorName,$DataFeedFileName) = #_;
my($DestFileName)=$DataFeedFileName.".zip";
my($Command);
my($RetValue) = 1;
$Command = "C:\\Users\\hprasu\\Downloads\\OpenSSH-Win64\\scp.exe -i D:\\File1\\RS2\\DataFeed\\Code\\PrivateKey.ppk -s $DataFeedFileInternal a_Tne\#nasftp\.egencia.com:$DataFeedVendorName/$DestFileName";
$RetVal = &CallSystem($Command);
if ($RetVal == 0) {
&AppendFileToLog($TempFile);
&ErrorExit("Unable to copy data feed file using SCP command:\n".$Command);
}
}
The above perl method is executing the System command
You should:
have full path to perl.exe and your perl script in job's command
escape all special characters in interpolated strings for Perl and
use full path for scp command since
operating system don't know where scp.exe is located (until it in the $PATH):
check filesystem permissions for all files in the command and perl script. Job should has access those files.
So command would be
$Command = "full_path\\scp.exe -i D:\\File1\\RS2\\DataFeed\\Code\\PrivateKey.ppk -s $InternalFile admin\#sftp.world.com:$VendorName/$DestFileName";
Read this:
https://www.geeksforgeeks.org/perl-quoted-interpolated-and-escaped-strings/
I am writing a bash script to monitor my MongoDB status. once it is crash then restart it. the script is as below:
while true
do
ret = $("mongod --config /etc/mongod.conf")
if $ret == 0
then
echo "I am out with code 0."
break
fi
echo "running again"
done
echo "I am out with code $?"
But it seems doesn't work. Return from the system:
running again
./mongo-text: line 3: mongod --config /etc/mongod.conf: No such file or directory
./mongo-text: line 3: ret: command not found
./mongo-text: line 4: ==: command not found
not sure what the problem is. Any help is appreciated.
Your loop can be made much simpler:
while ! mongod --config /etc/mongod.conf; do
echo "running again" >&2
sleep 1
done
if test -n "$VERBOSE"; then echo 'modgod successful'; fi
Note that the if keyword executes a command. So if $ret == 0 attempts to run the command $ret (assuming that variable is non-empty and contains no whitespace) with the arguments == and 0. That is almost certainly not what you intend. It is more typical to write if test "$ret" = 0 or if [ "$ret" = 0 ]. If $ret is empty, then it is attempting to execute the command == with the single argument 0.
There are several issues in your code:
$("mongod --config /etc/mongod.conf") will try to run mongod --config /etc/mongod.conf as a command, with spaces included
the if syntax is wrong
You can rewrite it this way:
while :; do
if mongod --config /etc/mongod.conf; then
echo "I am out with code 0."
break
fi
echo "running again"
# probably sleep for a few seconds here
done
echo "I am out with code $?"
For info about if statements, see:
How to check the exit status using an if statement
How to compare strings in Bash
Compound if statements with multiple expressions in Bash
In my script I need to work with the exit status of the non-last command of a pipeline:
do_real_work 2>&1 | tee real_work.log
To my surprise, $? contains the exit code of the tee. Indeed, the following command:
false 2>&1 | tee /dev/null ; echo $?
outputs 0. Surprise, because the csh's (almost) equivalent
false |& tee /dev/null ; echo $status
prints 1.
How do I get the exit code of the non-last command of the most recent pipeline?
Bash has set -o pipefail which uses the first non-zero exit code (if any) as the exit code of a pipeline.
POSIX shell doesn't have such a feature AFAIK. You could work around that with a different approach:
tail -F -n0 real_work.log &
do_real_work > real_work.log 2>&1
kill $!
That is, start following the as yet non-existing file before running the command, and kill the process after running the command.
I try to get the exitcode/errorlevel code from a bat file into the powershell script calling the bat file.
Althought the %ErrorLevel% is 1:
BAT file
call aCONFIGURATION
for %%f in (.\createData\*.g.sql) do sqlcmd -b -U %UserName% -P %Password% -S %sqlClonedServer% -d %sqlClonedDatabaseName% -i %%f -r1 1> NUL
echo %ERRORLEVEL%
When I do in the powershellscript
$lastexitcode its ALWAYS 0 but the %ErrorLevel% says 1
$build = "c:\my.bat"
$state = & $build
Write-Host $LASTEXITCODE
I am pulling my hairs of this crap powershell full with bugs.
I have read these links but they did not help as the result is different:
http://blogs.technet.com/b/heyscriptingguy/archive/2011/06/06/get-legacy-exit-codes-in-powershell.aspx
https://social.technet.microsoft.com/Forums/scriptcenter/en-US/05e37b8d-761b-4fd7-881e-977f114ad8d7/obtaining-errorlevel-return-codes-in-powershell-is-it-possible
How can I fix the $lastexitcode
echo %ERRORLEVEL% just writes the error code to stdout, after which the batch file exits normally.
If you want the batch script to actually return an error on exit, use exit /b [exitcode]:
call aCONFIGURATION
for %%f in (.\createData\*.g.sql) do sqlcmd -b -U %UserName% -P %Password% -S %sqlClonedServer% -d %sqlClonedDatabaseName% -i %%f -r1 1> NUL
exit /b %ERRORLEVEL%
I am using Psexec to run a remote batch file. I pass input to psexec and redirect it to the remote batch file which seeks a filename as its input. However while redirecting, the file name becomes a garbage as ###&#* which means actual file name is not passed to batch file which the user gives. can anyone tell what might be the reason for this.
pause
cd c:
set /P INPUT=Type input: %=%
echo Your input was: %INPUT%
copy %INPUT% \\remotemachineip\C$ && c:\psexec \\machineip cmd /k "c:\batchfile.bat arg1 < %INPUT% & del %INPUT%" -e -c -f -i
pause
pause
cd c:
set /P INPUT=Type input: %=%
echo Your input was: %INPUT%
copy %INPUT% \\remotemachineip\C$ && c:\psexec \\machineip cmd /k c:\batchfile.bat %INPUT% & del %INPUT% -c -f -i
pause
the remote batch file which seeks input from the above batch file commands on the local machine. so %1(below command) is replaced by the %INPUT%(the second argument in the cmd.exe in the above code content) which the user enters and the sqlcmd command will be executed. so the input which the user passes in the above batch file will be successfully redirected to the below batch file(content) and the command(sqlcmd below) in it will be successfully executed.
SQLCMD -Sservername -d(databasename) -iC:LINKEDSERVER.sql -v filename="%1"
for e.g if I give %INPUT% as c:\inputfile.xls it will be redirected to SQLCMD command in place of %1, so it executes it as--
SQLCMD -Sservername -d(databasename) -iC:LINKEDSERVER.sql -v filename="c:\inputfile.xls"