iOS/Xcode - Toggle button changing position - iphone

Question

I want a button that toggles the position of an element on click.
My current code:
-(IBAction)menuTouched{
// Push menu
UITableView * sideMenu = [[UITableView alloc] initWithFrame:CGRectMake(1060, 88, 63, 661)];
sideMenu.backgroundColor = [UIColor redColor];
[self.view addSubview:sideMenu];
// Animate
[UIView animateWithDuration:1.25 animations:^{
sideMenu.frame = CGRectMake(960, 88, 63, 661);
}];
}
When clicking the button it animates the tableview in just like I want to. But now I want to animate the tableview out by pressing the exact same button. So in short I want the button to toggle in and out a tableview by changing the X position. What is the best/easiest approach?
Thanks in advance.

Answer 1

inside your .h file add
UITableView * sideMenu;
BOOL checkInOut;
inside .m file add
- (void)viewDidLoad
{
[super viewDidLoad];
checkInOut=False;
// Push menu
sideMenu = [[UITableView alloc] initWithFrame:CGRectMake(1060, 88, 63, 661)];
sideMenu.backgroundColor = [UIColor redColor];
[self.view addSubview:sideMenu];
}
-(IBAction)menuTouched
{
checkInOut=!checkInOut
if(checkInOut)
{
// Animate
[UIView animateWithDuration:1.25 animations:^{
sideMenu.frame = CGRectMake(960, 88, 63, 661);
}];
}
else
{
[UIView animateWithDuration:1.25 animations:^{
sideMenu.frame = CGRectMake(1060, 88, 63, 661);
}];
}
}

Answer 2

You will need a bool to store the state where you are, but you can just use the button.selected state for that.. Something like that:
- (IBAction)menuTouched:(id)sender
{
sender.selected = !sender.selected;
if (sender.selected)
{
// toggle on stuff
}
else
{
// toggle off stuff
}
}

Answer 3

Try it....
[UIView beginAnimations: nil context: nil];
[UIView setAnimationBeginsFromCurrentState: YES];
[UIView setAnimationDuration: 0.5];
myButton.frame = CGRectMake(0,420,320,120);
[UIView commitAnimations];
Hope i helped.

Answer 4

you can perform the same animation with different frame as you set previously
sideMenu.frame = CGRectMake(1060, 88, 63, 661);
with the check to see have you togged the table in or out to perform respective action.
Hope this helps.

Answer 5

You have to receive as UIButton reference instead of id
- (IBAction)menuTouched:(UIButton *)sender
{
sender.selected = !sender.selected;
if (sender.selected)
{
[UIView animateWithDuration:1.25 animations:^
{
UITableView * sideMenu = [[UITableView alloc] initWithFrame:CGRectMake(1060, 88, 63, 661)];
sideMenu.backgroundColor = [UIColor redColor];
[self.view addSubview:sideMenu];
sideMenu.frame = CGRectMake(960, 88, 63, 661);
}];
}
else
{
[UIView animateWithDuration:1.25 animations:^{
[sideMenu removeForSuperView];
}];
}
}

Answer 6

1.set a flag bit to represent UITableView's current state.The statement need 3 variables.
BOOL isShow;
UITableView *sideMenu;
CGFloat posX;
2.initial setting in viewDidLoad
-(void)viewDidLoad {
isShow=NO;
//to do something...
sideMenu = [[UITableView alloc] initWithFrame:CGRectMake(1060, 88, 63, 661)];
sideMenu.backgroundColor = [UIColor redColor];
[self.view addSubview:sideMenu];
}
3.What UITableView shows is just the change of X-coordinate of frame.so you can calculate posX depend on toggles 'state.and notice don't create UITableView at each time clicking.put the UITableView creat code on viewDidLoad function.
-(IBAction)menuTouched{
posX=isShow ? 1060 : 960
// Animate
[UIView animateWithDuration:1.25 animations:^{
sideMenu.frame = CGRectMake(posX, 88, 63, 661);
}];
isShow=!isShow; //boggle button
}