I have displayed grid boxes over an image. I want to count number of grid boxes which cover an object in that image
for example http://snag.gy/geFIZ.jpg. In this image I have displayed grid on image but i need to count how many girds have been taken to cover that object completely.? Kindly help me regarding this
Regards
Dams
Slow, but easy to implement way:
1) Use this topic to add lines to image.
2) Make something like this:
Make a cycle to check every box. In each box check pixels. If you found first white pixel in box, add 1 to number of covering boxes and go for next one.
No code from you - no code from me, sorry :) Good luck!
Related
For Example, I have the below image used for demo purpose only
Fill close portion with pattern
if user tap on any part of T-Shirt, than T-Shirt should be filled with selected pattern image.
I have used to find an array of the point contains close area it takes time as well to find close region points and try to draw color at that points, but it takes too much time to draw because there are many points for the close region.
I have used code from below link
https://github.com/Chintan-Dave/UIImageScanlineFloodfill
This algorithm is actually for flood fill, but I have added one more method to collect all points to one NSSet.
A help is too much appreciated.
Thanks in advance.
I am trying to setup a style based on bootstrap3.
Basically I want to try and reduce the size of the input elements which I have done, getting a decent proportion of 'box' vs 'text'.
However if I use the same font-size in a select box with the same size then I get a situation where the text is masked along the bottom edge...
I think there is a tiny bit more margin at the top of the select box, but for the life of me I cant find where that is set in BootStrap to change it (if at all).
I think all I need to do is move the text in the 'select' element up by a couple of pixels and it will align with those bits of text in standard text boxes....
Can anyone point me in the right direct please?
Found the associated CSS in the bootstrap, with a bit of trial and error....
Mainly in the 'form-control' section.
but now also using Bootstrap 4, with a couple of additional styles.
I have an image (represented as green) overlaying a box (represented as blue), and the image is going to be transform: scale()ing in size. When this happens I need all edges of the image to complete their transformation at the same time.
To do this I need to calculate the transform-origin based on where the image is located overtop of the bounding box, using JavaScript. Assume I know all the coordinates that getBoundingClientRect() provides, for both elements.
In the six examples below I’ve placed a red dot where the transform-origin percentages should intersect.
I just can’t figure out the math to get there. The closest I've come to finding an answer is with this question, but it's a little vague and I'm not sure I fully understand the answer itself. I would greatly appreciate help with this, and will happily provide more details if I'm missing something.
After fiddling around, I figured out the formula is:
(
(box.left - image.left) /
(image.width - box.width)
) * 100
I have scanned copies of currency notes from which I need to extract only the rectangular notes.
Although the scanned copies have a very blank background, the note itself can be rotated or aligned correctly. I'm using matlab.
Example input:
Example output:
I have tried using thresholding and canny/sobel edge detection to no avail.
I also tried the solution given here but it detects the entire image for cropping and it would not work for rotated images.
PS: My primary objective is to determine the denomination of the currency. There are a couple of methods I thought I could use:
Color based, since all currency notes have varying primary colors.
The advantage of this method is that it's independent of the
rotation or scale of the input image.
Detect the small black triangle on the lower left corner of the note. This shape is unique
for each denomination.
Calculating the difference between 2 images. Since this is a small project, all input images will be of the same dpi and resolution and hence, once aligned, the difference between the input and the true images can give a rough estimate.
Which method do you think is the most viable?
It seems you are further advanced than you looked (seeing you comments) which is good! Im going to show you more or less the way you can go to solve you problem, however im not posting the whole code, just the important parts.
You have an image quite cropped and segmented. First you need to ensure that your image is without holes. So fill them!
Iinv=I==0; % you want 1 in money, 0 in not-money;
Ifill=imfill(Iinv,8,'holes'); % Fill holes
After that, you want to get only the boundary of the image:
Iedge=edge(Ifill);
And in the end you want to get the corners of that square:
C=corner(Iedge);
Now that you have 4 corners, you should be able to know the angle of this rotated "square". Once you get it do:
Irotate=imrotate(Icroped,angle);
Once here you may want to crop it again to end up just with the money! (aaah money always as an objective!)
Hope this helps!
I want to display overlapping boxplots using Sigmaplot 12. When I choose the scale for the x-axis as linear then the boxes do indeed overlap but are much too thin. See figure below. Of course they should be much wider.
When I choose the scale of the x-axis to be "category", then the boxes have the right width, but are arranged along each single x-value.
I want the position as in figure 1 and the width as in figure 2. I tried to resize the box in figure 1 but when I choose 100% in "bar width" than it still looks like Figure 1.
many thanks!
okay, I found the answer myself. In Sigmaplot, there is often the need to prepare "style"-columns, for example if you want to color your barcharts, you need a column that holds the specific color names.
For my boxplot example I needed a column that has the values for "width". These had to be quite large (2000) in order to have an effect. Why ? I have no idea. First I thought it would be because of the latitude values and that the program interprets the point as "1.000"s, but when I changed to values without decimals, it didn´t get better.
Well, here is the result in color.
Have fun !