How to apply different styles on characters X1 (bold and center/left position) and show asdasd (rightposition) in Y-axis of a table??
reality
edit in paint :)
You can use a multi-level axis for the category axis.
If Excel does not recognize the multi-levels, then you can fix that in the data source dialog.
There is, however, no way to format the axis labels to have different fonts and font sizes for the different levels. Excel simply does not support that.
Edit: there is also no setting to turn the outer level label around. Excel will determine how to show it and there is nothing the user can do to change that.
Don't shoot the messenger.
I was visualizing my vorticity vector field and notice that I am not able to see the pattern without zooming in as there are too many glyphs and are too packed.
Currently, I am using a calculator to combine X,Y,Z vorticity field into a single vector field using the calculator. Take a slice of it and do a glyph filter visualizing all points on the plane.
I notice that one possible way is to visualize a curved glyphs and scale up a little bit to make it more noticeable, but not sure how to do that. Does anyone know whats the steps to do that? Or any other suggestions?
TIA
Have you tried reducing the Maximum Number of Sample Points property in the Properties Panel when the Glyph filter is selected in the Pipeline Browser? You may also want to change the Scale Factor property to change the length of the glyphs.
I have created a chart with 2 axes that acts as a panel chart (see image)
As a panel chart I only want to show the portions of the relevant y-axes to the chart next to them. For example, for the right-most y-axis I used a custom number format to exclude anything less than 0:
_(* #,##0_);_("";_(* 0??_);_(#_)
But for the left most y-axis, I'm stuck. I want to show -400 to positive 400. I've tried 2 different options, but neither is producing the desired effect.
[<0](#,##0);[>500000000]"";#,##0_)
[<0](#,##0);[<500000000]#,##0_);""
Here is the result I'm looking for:
I learned something new today (and a bit weird) regarding formats and chart axes
After some experimenting, this is what I ended up using:
[White][>500]_(#,##0_);(#,##0);0;
The odd part: When you change the Display Units of the axis (for me, millions), then the formatting no longer recognizes the original amount (500,000,000).
Once I figured that out, I was able to work out the solution.
I have created a sparkline in SSRS. Since the values are small i get a straight line graph How do i improve the sensitivity of the graph.
the difference is like for every month
60.06
60.40
60.14
You need to look at the Sparkline Vertical Axis Properties.
Testing with data like yours and a simple Tablix/Sparkline I get results similar to yours:
Opening the Vertical Axis Properties I can see Always include zero is checked by default:
Unchecking this option has a major effect on the sparkline:
So this is one way of doing it. Other than that changing the Minimum and Maximum values here will also have an effect - you just need to play around and find the right combination for you.
I want to create a vertical bar plot. This is my code:
bar (x, sensiv);
title ('Promedio X')
xlabel('Nm')
ylabel('Refl.')
The problem is it looks like a stair plot. I've tried to add (x,sensiv, 'stacked') but it doesn't work. It looks grouped, as you can see in the next image:
graph http://imageshack.us/a/img689/9449/capturawv.jpg
I think it's because of x-axis but I couldn't change it. How can I do it? Does somebody knows how can I do it?
EDIT
Thanks Colin! I've tried to zoom and I understand what you mean and I've tried with different values, as slayton and you said.
I think that maybe it's the way I've code the plot, it is possible?
abc=0;
for p=(61:201)
abc(p)=out1_c;
end
for p=(151:301)
abc(p)=out2_c;
end
for p=(231:380)
abc(p)=out3_c;
end
for p=(381:596)
abc(p)=out4_c;
end
for p=(1152:1531)
abc(p)=out5_c;
end
for p=(1651:2051)
abc(p)=out7_c;
end
for p=(2052:2151)
abc(p)= 0;
end
The default value for the width of the bars in a bar plot is 0.8, so given that you're not currently specifying the width, you should have gaps in between each bar. This is going to sound really obvious, but have you tried zooming in on the bar plot that is created? For some datasets, the bar function will return a plot that looks like a stair plot, but in fact has gaps if you zoom in far enough. If this is the case, then you should be able to get the gaps you want by tinkering with the width parameter as suggested by slayton.
EDIT
Okay. First things first. If you want to post additional information, you should add it to your question, NOT post it as a new answer! You can do this by clicking the edit button just below where your question is on the page. To make things more readable, you might preface your edit with a capitalized bold-face heading "EDIT" as I have done here. If you are able, try now to move the additional information you've given back into your question, and then delete the answer.
Second, I have to be honest, the additional information you posted was somewhat confusing. However, I think I understand what you want now. You want 7 bars coming up to the heights out1_c, out2_c, ..., out7_c (variable names taken from your additional information) with a small gap between each bar, and the x-axis to reflect (approximately) the intervals 450-550, 550-650, etc.
Well, if you want 7 bars, then you want your input to only have seven elements. Set:
y = [out1_c; out2_c; out3_c; out4_c; out5_c; out6_c; out7_c];
y now gives you the heights your bars will come up to on the y-axis. To locate the bars on the x-axis, define a vector x that also has seven elements, where each element gives the midpoint of where you want the bar to be on the x-axis. For example:
x = [100; 200; 300; 400; 500; 600; 700];
Then just use bar(x, y). This should get you started.
A final point on the code you posted, you can actually completely avoid the loops: read up on vectorization. But if you are going to insist on loops, the first and most important rule is to preallocate your vectors/matrices. In your code abc starts out as a scalar (a 1 by 1 matrix), but then for every p, you are adding an element at index p. What is actually happening in the background is for every p, matlab is scrapping the current abc you have in memory, and building it again from scratch with the additional element. As you might expect, this will slow down your code by many orders of magnitude.
You can set the width of the individual bars by passing a value between 0 and 1 to bar. Passing 1 indicates that there should be no space between the bars
bar(x,y,1)
Passing anything less than 1 will reduce the bar sizes and introduce spacing between the individual bars
bar(x,y,.5)