I'm wondering how to make mass rename (using rename or sed/awk), for files like this:
Name 1 - Name 2 - Name 3.doc
Name 1- Name 2 - Name 3.doc
Name 1 -Name 2 - Name 3.doc
the problem is that i want to have all files in the same schema, for example
Name 1-Name 2-Name 3.doc
without spaces at all. I'm reading rename documentation but can't find way to do this.
Try doing this :
rename 's/\s*-\s*/-/g' *.doc
You need the Perl's rename, see this post
How about:
for file in *.doc; do
mv "$file" "$(sed 's# *- *#-#g' <<< "$file")"
done
Related
I need help to rename multiple files in a directory based on the delimeter.
Sample:
From
R01235-XYZ-TRAIL.PDF
TO
R01234-TRAIL.PDF
and
From
XYZ-C12345-TRAIL.PDF
TO
C12345-TRAIL.PDF
is it possible to delete based on - delimeter?
I am not specifically removing XYZ but rather remove anything before the first - and the middle occurence between two -.. XYZ is just a representation of the characters in that field.
Thanks!
I tried SED, LS, MV, I also tried RENAME but it seems not working for me.
This might work for you:
rename -n 's/XYZ-//' file
This removes XYZ- from the file name.
If this meets your requirements, remove the -n option for the renaming to take place.
On retrospect, perhaps:
rename -n 's/([A-Z][0-9]{5}-).*-/$1/;s/^.*-([A-Z][0-9]{5}-)/$1/' file
With sed:
sed -E 's/^([A-Z][0-9]{5}-).*-|^.*([A-Z][0-9]{5}-.*)/mv & \1\2/' file
Check the results and then:
sed -E 's/^([A-Z][0-9]{5}-).*-|^.*([A-Z][0-9]{5}-.*)/mv & \1\2/' file | sh
This question already has answers here:
How to rename multiple files in a folder with a specific format?
(2 answers)
Closed 2 years ago.
I asked a similar question previously, but need help to understand the Perl commands that achieve the renaming process. I have many files in a folder with format '{galaxyID}-psf-calexp-pdr2_wide-HSC-I-{#}-{#}-{#}.fits'. Here are some examples:
7-psf-calexp-pdr2_wide-HSC-I-9608-7,2-205.41092-0.41487.fits
50-psf-calexp-pdr2_wide-HSC-I-9332-6,8-156.64674--0.03277.fits
124-psf-calexp-pdr2_wide-HSC-I-9323-4,3-143.73514--0.84442.fits
I want to rename all .fits files in the directory to match the following format:
7-HSC-I-psf.fits
50-HSC-I-psf.fits
124-HSC-I-psf.fits
namely, I want to remove "psf-calexp-pdr2_wide", all of the numbers after "HSC-I", and add "-psf" to the end of each file after HSC-I. I have tried the following command:
rename -n -e 's/-/-\d+-calexp-/-\d+pdr2_wide; /-/-//' *.fits
which gave me the error message: Argument list too long. You can probably tell I don't understand the Perl syntax. Thanks in advance!
First of all, Argument list too long doesn't come from perl; it comes from the shell because you have so many files that *.fits expanded to something too long.
To fix this, use
# GNU
find . -maxdepth 1 -name '*.fits' -exec rename ... {} +
# Non-GNU
find . -maxdepth 1 -name '*.fits' -print0 | xargs -0 rename ...
But your Perl code is also incorrect. All you need is
s/^(\d+).*/$1-HSC-I-psf.fits/
which can also be written as
s/^\d+\K.*/-HSC-I-psf.fits/
Okay so I want to know how I would go about doing this, using grep to locate .txt files named "cocacola1", "cocacola2", "cocacola3" & then copying them to another directory. So searching for files named "cocacola" &/even if it contains other characters within the file name to then copy them to another directory/location.
You can just use unix find. Assuming the files you're searching for are in 'source' and you want to copy to 'destination':
find source -name '*cocacola*' -exec cp {} destination \;
I put the wildcard '*' before and after cocacola since you said other characters might exist in the file name.
I want to loop files in one directory and then remove the specific prefix in batch, how can i do that using fish shell?
Assumed you have a directory like this:
mkdir /tmp/example
touch /tmp/example/prefix-file(seq 9)
Then you can do the following:
for i in /tmp/example/prefix-*
mv $i (echo $i | sed 's/prefix-//')
end
There are many different ways to do this, but I think this is the most straight forward way.
I am back with a second no-brainer question, but I would like to get this straight in my head.
I have an assignment in which I am charged with providing a command to find a file named test in my home directory (one command using find, and one using grep). I understand that using find is just 'find ~/test', but using grep, wouldn't I have to search out a pattern within the file 'test'? Or is there a way to search for the file (using grep), even if the file is empty?
ls ~ | grep test
I understand that using find is just 'find ~/test'
No. find ~/test will also have a match for every file or directory under the directory $HOME/test/. Rather use find ~ -type f -name test.
The assignment sounds unclear. But yes, if you give any filenames to grep, it will look at the contents of the files and ignore the names of the files. Perhaps you can grep the output of another command? Maybe ls as #Reese suggested, or maybe a different find command.
ls -R ~ | grep test
Explanation: ls -R ~ will recursively list all files and directories in your home folder. grep test will narrow down that list to files (and directories) that have "test" in their name.