I need to convert currency from string format to number format.
For example my string variable value is #"10 lakh". The string value for this converted into number format would be 1000000. How can one make this type of conversion?
(Converting 10 lakh to 1000000, this is the issue)
Try
- (NSNumber *)multiplierForKey:(NSString *)key
{
NSDictionary *dict = #{#"thousand":#1000, #"lakh":#100000, #"million":#1000000, #"crore":#100000000};
NSNumber *value = dict[[key lowercaseString]];
return value?value:#1;
}
- (void)findMultiplier{
NSString *string = #"10 lakh";
NSArray *components = [string componentsSeparatedByString:#" "];
if ([components count]==2) {
NSNumber *value = components[0];
NSString *key = components[1];
NSNumber *multiplier = [self multiplierForKey:key];
NSDecimalNumber *decimalValue = [NSDecimalNumber decimalNumberWithDecimal:[value decimalValue]];
NSDecimalNumber *multiplierValue = [NSDecimalNumber decimalNumberWithDecimal:[multiplier decimalValue]];
NSDecimalNumber *finalValue = [decimalValue decimalNumberByMultiplyingBy:multiplierValue];
NSLog(#"Value : %#",finalValue);
}
}
You can make switch cases according to your denominations. By choosing particular switch case you can choose the desired value. I don't think there is predefined method to accomplish this.
hope this helps.
Related
I have a string like: "mocktail, wine, beer"
How can I convert this into: "mocktail", "wine", "beer"?
the following gives you the desired result:
NSString *_inputString = #"\"mocktail, wine, beer\"";
NSLog(#"input string : %#", _inputString);
NSLog(#"output string : %#", [_inputString stringByReplacingOccurrencesOfString:#", " withString:#"\", \""]);
the result is:
input string : "mocktail, wine, beer"
output string : "mocktail", "wine", "beer"
You need to use:
NSArray * components = [myString componentsSeparatedByString: #", "];
NSString *string = #"mocktail, wine, beer";
//remove whitespaces
NSString *trimmedString = [string stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
//get array of string
NSArray *array = [trimmedString componentsSeparatedByString:#","];
NSMutableArray *newArray = [[NSMutableArray alloc] init];
for (NSString *trimmedString in array) {
NSString *newString = [NSMutableString stringWithFormat:#"'%#'", trimmedString];
[newArray addObject:newString];
}
//merge new strings
NSString *finalString = [NSString stringWithFormat:#"%#", [newArray objectAtIndex:0]];
for (NSInteger i = 1; i < [newArray count]; i++) {
finalString = [NSString stringWithFormat:#"%#, %#", finalString, [newArray objectAtIndex:i]];
}
Without knowing spesifically about iOS or objective-c, I assume you could use a split function.
In almost any higher level programming language there is such a function.
Try:
Objective-C split
This gets you an array of Strings. You can then practically do with those what you want to do, e.g. surrounding them with single quotes and appending them back together. :D
I have NSString like this #"0,0,0,0,0,0,1,2012-03-08,2012-03-17". I want values separated by comma. I want values before comma and neglect comma.
I am new in iPhone, I know how to do in Java but not getting how to do in Objective-C.
NSString *string = #"0,0,0,0,0,0,1,2012-03-08,2012-03-17";
NSArray *componentArray = [string componentSeperatedByString:#","];
Use the componentsSeparatedByString: method of NSString.
NSString *str = #"0,0,0,0,0,0,1,2012-03-08,2012-03-17";
NSArray *components = [str componentsSeparatedByString:#","];
for (NSString *comp in components)
{
NSLog(#"%#", comp);
}
for (NSString *s in [yourstring componentsSeparatedByString:#","])
{
int thisval = [s intValue];
}
NSString * str=[zoneDict objectForKey:#"name"];
NSLog(#"==========string zone::==========%#",str);
// str="(GMT +3:00) Baghdad, Riyadh, Moscow, St. Petersbur";
How can I get the 3:00 value from the above string?
NSString *str = #"(GMT -3:00) Baghdad, Riyadh, Moscow, St. Petersbur";
NSRange endRange = [str rangeOfString:#")"];
NSString *timeString = [str substringWithRange:NSMakeRange(5, endRange.location-5)];
NSRange separatorRange = [timeString rangeOfString:#":"];
NSInteger hourInt = [[timeString substringWithRange:NSMakeRange(0, separatorRange.location)] intValue];
NSLog(#"Hour:%d",hourInt);
Rather than trying to extract the time offset from the string, is there any way you could store actual time zone data in your zoneDict? For example you could store NSTimeZone instances instead.
If all you have is the string, you could use an NSRegularExpression object and extract the relevant information using a regular expression instead.
If you could explain further what you're trying to do then there may be an alternative way to achieve what you want.
I like to use -[NSString componentsSeparatedByString]:
NSString *str = #"(GMT -3:00) Baghdad, Riyadh, Moscow, St. Petersbur";
NSArray *myWords = [myString componentsSeparatedByString:#")"];
NSString *temp1 = [myWords objectAtIndex:0];
if ([temp1 rangeOfString:#"-"].location == NSNotFound) {
NSArray *temp2 = [temp1 componentsSeparatedByString:#"+"];
NSString *temp3 = [temp2 objectAtIndex:1];
NSLog(#"Your String - %#", temp3);
}
else {
NSArray *temp2 = [temp1 componentsSeparatedByString:#"-"];
NSString *temp3 = [temp2 objectAtIndex:1];
NSLog(#"Your String - %#", temp3);
}
Output:
Your String - 3:00
Using regular expressions is the better option in my view (if you are forced to extract the '3' only). The regular expression string would contain something like "\d?" but don't quote me on that, you'll have to look up the exact string. Perhaps someone on here could provide the exact string.
I want to convert string data to NSInteger.
If the string is a human readable representation of a number, you can do this:
NSInteger myInt = [myString intValue];
[myString intValue] returns a cType "int"
[myString integerValue] returns a NSInteger.
In most cases I do find these simple functions by looking at apples class references, quickest way to get there is click [option] button and double-click on the class declarations (in this case NSString ).
I've found this to be the proper answer.
NSInteger myInt = [someString integerValue];
NSNumber *tempVal2=[[[NSNumberFormatter alloc] init] numberFromString:#"your text here"];
returns NULL if string or returns NSNumber
NSInteger intValue=[tempVal2 integerValue];
returns integer of NSNumber
this is safer than integerValue:
-(NSInteger)integerFromString:(NSString *)string
{
NSNumberFormatter *formatter=[[NSNumberFormatter alloc]init];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
NSNumber *numberObj = [formatter numberFromString:string];
return [numberObj integerValue];
}
int myInt = [myString intValue];
NSLog(#"Display Int Value:%i",myInt);
NSString *string = [NSString stringWithFormat:#"%d", theinteger];
I am trying to build a small table using NSString. I cannot seem to format the strings properly.
Here is what I have
[NSString stringWithFormat:#"%8#: %.6f",e,v]
where e is an NSString from somewhere else, and v is a float.
What I want is output something like this:
Grapes: 20.3
Pomegranates: 2.5
Oranges: 15.1
What I get is
Grapes:20.3
Pomegranates:2.5
Oranges:15.1
How can I fix my format to do something like this?
you could try using - stringByPaddingToLength:withString:startingAtIndex:
NSDictionary* fruits = [NSDictionary dictionaryWithObjectsAndKeys:
[NSNumber numberWithFloat:20.3], #"Grapes",
[NSNumber numberWithFloat:2.5], #"Pomegranates",
[NSNumber numberWithFloat:15.1], #"Oranges",
nil];
NSUInteger longestNameLength = 0;
for (NSString* key in [fruits allKeys])
{
NSUInteger keyLength = [key length];
if (keyLength > longestNameLength)
{
longestNameLength = keyLength;
}
}
for (NSString* key in [fruits allKeys])
{
NSUInteger keyLength = [key length];
NSNumber* object = [fruits objectForKey:key];
NSUInteger padding = longestNameLength - keyLength + 1;
NSLog(#"%#", [NSString stringWithFormat:#"%#:%*s%5.2f", key, padding, " ", [object floatValue]]);
}
Output:
Oranges: 15.10
Pomegranates: 2.50
Grapes: 20.30
The NSNumberFormatter class is the way to go!
Example:
NSNumberFormatter *numFormatter = [[NSNumberFormatter alloc] init];
[numFormatter setPaddingCharacter:#"0"];
[numFormatter setFormatWidth:2];
NSString *paddedString = [numFormatter stringFromNumber:[NSNumber numberWithInteger:integer]];
[numFormatter release];
I think you want something like
[NSString stringWithFormat:#"%-9# %6.1f",[e stringByAppendingString:#":"],v]
since you want padding in front of the float to make it fit the column, though if the NSString is longer than 8, it will break the columns.
%-8f left-aligns the string in a 9-character-wide column (9-wide since the : is appended to the string beforehand, which is done so the : is at the end of the string, not after padding spaces); %6.1f right-aligns the float in a 6-char field with 1 decimal place.
edit: also, if you're viewing the output as if it were HTML (through some sort of web view, for instance), that may be reducing any instances of more than one space to a single space.