Can we get user zip code using facebook sdk? - iphone

Question

I am using facebook sdk 3.0
At facebook i have added users full address as
Address- 1, Infinite loop
city/town - Cupertino, CA
UPDATE
As per the answer I tried to use FBGraphLocation protocol like this
NSDictionary<FBGraphUser> *user
id<FBGraphPlace> objPlace = user.location;
id<FBGraphLocation> objLocation = objPlace.location;
NSLog(#"place.location : %# location.street : %#",objPlace.location,objLocation.street);
It is giving (null) for both. also I am getting objLocation object as (null)
In facebook sdk response, I am getting location as only this
location = {
id = 123456789123456;
name = "Cupertino, California";
}
This is not the enough information from where i can get the zipcode of the use.
If facebook does not allow to provide zip code information then any way to get zipcode from only "Cupertino, California" information ?
I have used this url
http://maps.googleapis.com/maps/api/geocode/json?address=Cupertino,%20California&sensor=true
which give me result as
{
"long_name" = Cupertino;
"short_name" = Cupertino;
types = (
locality,
political
);
},
{
"long_name" = "Santa Clara";
"short_name" = "Santa Clara";
types = (
"administrative_area_level_2",
political
);
},
{
"long_name" = California;
"short_name" = CA;
types = (
"administrative_area_level_1",
political
);
},
{
"long_name" = "United States";
"short_name" = US;
types = (
country,
political
);
}
If I statically put that address into the URL as
http://maps.googleapis.com/maps/api/geocode/json?address=1%20Infinite%20Loop,%20Cupertino,%20CA&sensor=true
Then It gives me Zip code also.
{
"long_name" = 1;
"short_name" = 1;
types = (
"street_number"
);
},
{
"long_name" = "Apple Inc.";
"short_name" = "Apple Inc.";
types = (
establishment
);
},
{
"long_name" = "Infinite Loop";
"short_name" = "Infinite Loop";
types = (
route
);
},
{
"long_name" = Cupertino;
"short_name" = Cupertino;
types = (
locality,
political
);
},
{
"long_name" = "Santa Clara";
"short_name" = "Santa Clara";
types = (
"administrative_area_level_2",
political
);
},
{
"long_name" = California;
"short_name" = CA;
types = (
"administrative_area_level_1",
political
);
},
{
"long_name" = "United States";
"short_name" = US;
types = (
country,
political
);
},
{
"long_name" = 95014;
"short_name" = 95014;
types = (
"postal_code"
);
}
But from the Facebook sdk, I am only getting the City/Town (as stated above), added in contact Information at Facebook.com
How can I do this?

Answer 1

After digging into the SDK I found out, that you can access a user's zipcode and street using the FBGraphLocation API, which is part of the FBGraph API.
To get a FBGraphLocation you'll acess the location property of a FBGraphUser
/*!
#property
#abstract Typed access to the user's current city.
*/
#property (retain, nonatomic) id<FBGraphLocation> location;
The FBGraphLocation API has those properties available:
/*!
#property
#abstract Typed access to a location's street.
*/
#property (retain, nonatomic) NSString *street;
/*!
#property
#abstract Typed access to a location's zip code.
*/
#property (retain, nonatomic) NSString *zip;
That's what you need, right?

Answer 2

Finally I used google API to get the latitude and longitude from the address I get from the facebook and using those coordinates I find the zip code.
- (CLLocation *) getGeoCoordinatesUsingAddress: (NSString *) aStrAddres
{
NSString *esc_addr = [aStrAddres stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat:BaseURLForLocation, esc_addr];
NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
NSDictionary *googleResponse =
[NSJSONSerialization JSONObjectWithData: [result dataUsingEncoding:NSUTF8StringEncoding]
options: NSJSONReadingMutableContainers
error: nil];
NSDictionary *resultsDict = [googleResponse valueForKey:#"results"];
NSDictionary *geometryDict = [resultsDict valueForKey:#"geometry"];
NSDictionary *locationDict = [geometryDict valueForKey:#"location"];
NSArray *latArray = [locationDict valueForKey: #"lat"]; NSString *latString = [latArray lastObject];
NSArray *lngArray = [locationDict valueForKey: #"lng"]; NSString *lngString = [lngArray lastObject];
CLLocation *locationFound = [[CLLocation alloc] initWithLatitude:[latString doubleValue] longitude:[lngString doubleValue]];
NSLog(#"%s lat: %f\tlon:%f ",__FUNCTION__, [latString doubleValue], [lngString doubleValue]);
return locationFound;
}
Then I used CLGeocoder class
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
[geocoder reverseGeocodeLocation:location completionHandler:^(NSArray *placemarks, NSError *error) {
for(CLPlacemark *aPlacemark in placemarks){
NSString *strZipCode = [aPlacemark.addressDictionary objectForKey:(NSString *)kABPersonAddressZIPKey];
}
}];
Hope this help..