Sort query in luamongo - mongodb

I'm using luamongo to query mongodb. I'm quite inexperienced with mongodb, and I'm having trouble figuring out how to specify the sorting/order for the query. I don't see anything specifically about sorting on the project's wiki, but I might be missing something.
Is there a way to do this, or do I need to manually sort the returned results?
Thanks!

From https://github.com/moai/luamongo/issues/14:
To sort a query: mongodb:query("database.collection", {query = {field=value}, orderby = {field = 1}})

Related

Pymongo - find multiple different documents

my question is very similar to how-to-get-multiple-document-using-array-of-mongodb-id, however, I would like to find multiple documents without using the _id.
That is, consider that I have documents such as
the
document = { _id: _id, key_1: val_1, key_2: val_2, key_3: val_3}
I need to be able to .find() by multiple parameters, as for example,
query_1 = {key_1: foo, key_2: bar}
query_2 = {key_1: foofoo, key_2: barbar}
Right now, I am running a query for query_1, followed by a query for query_2.
As it turns out, this method is extremely inefficient.
I tried to add concurrency as to make it faster, but the speedup was not even 2x.
Is it possible to query multiple documents at once?,
I am looking for a method that returns the union of the matches for query_1 AND query_2.
If this is not possible, do you have any suggestions that might speed a query of this type?
Thank you for your help.

How do I make a mongo query for something that is not in a subdocument array of heterodox size?

I have a mongodb collection full of 65k+ documents, each one with a properties named site_histories. The value of it is an array that might be empty, or might not be. If it is not empty, it will have one or more objects similar to this:
"site_histories" : "[{\"site_id\":\"129373\",\"accepted\":\"1\",\"rejected\":\"0\",\"pending\":\"0\",\"user_id\":\"12743\"}]"
I need to make a query that will look for every instance in the collection of a document that does not have a given user_id.
I'm pretty new to Mongo, so I was trying to make a query that would find every instance that does have the given user_id, which I was then planning on adding a "$ne" to, but even that didn't work. This is the query I was using that didn't work:
db.test.find({site_histories: { $elemMatch: {user_id: '12743\' }}})
So can anyone tell me why this query didn't work? And can anyone help me format a query that will do what I need the final query to do?
If your site_histories really is an array, it should be as simple as doing:
db.test.find({"site_histories.user_id": "12743"})
That looks in all the elements of the array.
However, I'm a bit scared of all those backslashes. If site_histories is a string, that won't work. It would mean that the schema is poorly designed, you'd maybe try with $regex

How can i exclude a mongo index from a query?

Does anyone know of a way to run a query in MongoDB, and specify that a named index NOT be used?
We have multiple indexes on our data and there are situations where mongo is making a poor choice about which index to use to satisfy some types of queries. But we don't necessarily want to declare that a specific index be used. Only that we know which one is definitely a poor choice.
Using a named index is easy:
db.users.find({....}).hint( "index_name" )
Excluding a named index might look something like this:
db.users.find({....}).hint( "index_name", false)
Any insight is appreciated.
You can't exclude indexes, you can only specify the use of one.
However, MongoDB empirically tests indexes with your query by checking the search speed of the query against all indexes. It then determines what index to use based on these results. Can you please run the query with .explain(true) to show all the query plans.
Regards,
Charlie

Spring data mongoDB GeoNear query with excluding fields

I don't know if I am doing something wrong or it is a bug.
I have the following code:
Query criteria = new Query(Criteria.where("locationTime").gte(
"date-time"));
criteria.fields().exclude("friends");
NearQuery query = NearQuery.near(point).maxDistance(maxDistance)
.num(limit).query(criteria);
GeoResults<Profile> result = mongoTemplate
.geoNear(query, Profile.class);
I am executing the query and profiles near by retrieved correctly according to distance and the "locationTime" criteria but it seems to ignore the excluded field and retrieving the profiles with their friends.
When I use simple query the exclude/include fields works perfectly.
I looked every where and could not find any resemble use-case, please let me know if i am doing something wrong.
Thanks.
There's no way to limit the fields with a geoNear command, as far as I know.
I looked into calling executeCommand to try to work around the limitations of Spring Data, but it looks like they don't even have a way to do it from the raw command.

pymongo sort grouped results

I need to group and sort by date_published some documents stored on mongodb using pymongo.
the group part went just fine :) but when I'm addding .sort() to the query it keeps failing no matter what I tried :(
here is my query:
db.activities.group(keyf_code,cond,{},reduce_code)
I want to sort by a field called "published" (timestamp)
tried to do
db.activities.group(keyf_code,cond,{},reduce_code).sort({"published": -1})
and many more variations without any success
ideas anyone?
You can't currently do sort with group in MongoDB. You can use MapReduce instead which does support a sort option. There is also an enhancement request to support group with sort here.
Although MongoDB doesn't do what you want, you can always use Python to do the sorting:
result = db.activities.group(keyf_code,cond,{},reduce_code)
result = sorted(result, key=itemgetter("published"), reverse=True)