Link to last version of stateful page - wicket

Question

I have a number of stateful pages with some state for each page. For example each page has a form that was submitted.
How can I organize a menu with links to last versions of these stateful pages? Should I store anywhere (may be in the session) reference to appropriate object for each page? If I use
onClick() { setResponsePage(MyPage.class); }
than I lose the previous state of the page. I want to link to last state of the page.

Answer 1

Each time the page is rendered store the page's id in the session.
int pageId = pageInstance.getPageId();
A list or stack data structure could be used to hold the identifiers.
You can implement the navigation menu using a repeater (RepeatingView or such) that creates a new link for each page id in the session.
In the link's click handler you can redirect the user as follows:
Page pageInstance = (Page) new PageProvider(pageId, null).getPageInstance();
setResponsePage(pageInstance);

Answer 2

pageId = this.getPageId(); // get current version of lets say a HomePage
//OnClick for Link
public void onClick()
{
WebPage homePageInstance =
(WebPage) new PageProvider(HomePage.pageId, null).getPageInstance();
setResponsePage(homePageInstance);
}
});

Answer 3

I make it passing int previousId parameter via constructor :
#MountPath(value = "editSomethingPage")
public class TestPage extends WebPage {
int previousPageId = 0;
public TestPage(int previousPage) {
super();
this.previousPageId = previousPage;
}
#Override
protected void onInitialize() {
super.onInitialize();
add(new Link("goBack") {
#Override
public void onClick() {
if (previousPageId != 0) {
setResponsePage((Page) AuthenticatedWebSession.get().getPageManager().getPage(previousPageId));
} else {
setResponsePage(PreviousPage.class);
}
}
});
}
}
It prevents creation of new page instance and keeps all states of page made by user.