Preg_match one word followed with double quotes - preg-replace

I searched all the web but did not solve my problem.
I need a regular expression to match or replace a word folowed with a double quote.
Example :
uniquehereuniqueyouunique"can"uniquegetuniquefoounique"bar"
I need to replace all unique" by something (ex notunique). I tried :
preg_replace("/unique\"/", 'notunique', $contents);
but that don't match.
thanks for your help

I found it !
preg_replace('/unique."/', 'notunique', $contents);

Related

Microsoft graph Mail Search Strict value

I have an issue with the search parameters. I want to pass a phrase in my query. For exemple i'm looking for emails where the subject is "Test 1".
For this i'm doing a get on this ressource.
https://graph.microsoft.com/v1.0/me/messages?$search="subject:Test 1"
But the behaviour of this query is : Looking for mails that contains "Test" in the subject OR 1 in any other fields.
Refering to the KQL Syntax
A phrase (includes two or more words together, separated by spaces; however, the words must be enclosed in double quotation marks)
So, to do what i want i have to put double quotes (") around my phrase to do a strict value search. Like below
subject:"Test 1"
The problem it's at this point. Microsoft graph api already use double quotes (") after the parameters $search.
?$search="Key words"
So I can't do what is mentioned in the KQL doc.
https://graph.microsoft.com/v1.0/me/messages?$search="subject:"Test 1""
It's throwing an error :
"Syntax error: character '1' is not valid at position 15 in '\"subject:\"test 1\"\"'.",
It's an expected behaviour. I was pretty sure it will not work.
If someone has any suggestions for a solution or a workaround, I'm a buyer.
What I've already tried so far :
Use simple quote
Remove the quotes right after $select=
Remove the subject part $select="Test 1", same behaviour as the first request mentioned in this post. It will looks for emails that contain "test" or "1".
Best regards.
EDIT :
After sasfrog's anwser :
I used $filter : It works well with simple operator AND, OR.I have some errors by using the Not Operator. And btw you have to use the orderby parameter to show the result by date and add the field in filter parameters.
Exemple 1 (working, what I asked for first) :
https://graph.microsoft.com/v1.0/me/messages/?$orderby=receivedDateTime desc &$filter=receivedDateTime ge 1900-01-01T00:00:00Z AND contains(subject,'test 1')
Exemple 2 (not working)
https://graph.microsoft.com/v1.0/me/messages/?$orderby=receivedDateTime desc &$filter=(receivedDateTime ge 1900-01-01T00:00:00Z AND contains(subject,'test 1')) NOT(contains(from/EmailAddress/address,[specific address]))
EDIT 2
After some test with the filter parameters.
The NOT operator is still not working so to workaround use "ne" (non-equals)
the example 2 becomes :
https://graph.microsoft.com/v1.0/me/messages/?$orderby=receivedDateTime desc&$filter=(receivedDateTime ge 1900-01-01T00:00:00Z AND contains(subject,'test 1')) AND (from/EmailAddress/address ne [specific address])
UPDATE : OTHER SOLUTION WITH $search
Using $filter is great but it looks like it was sometimes pretty slow. So I found a workaround aboutmy issue.
It's to use AND operator between all terms.
Exemple 4 :
I'm looking for the mails where the subject is test 1;
Let value = "test 1". So you have to splice it by using space separator. And after write some code to manipulate this array, to obtain something like below.
$search="(subject:test AND subject:1)"
The brackets can be important if you use a multiple fields search. And Voilà.
Not sure if it's sufficient for what you're doing, but how about using the contains function within a filter query instead:
https://graph.microsoft.com/v1.0/me/messages?$filter=contains(subject,'Test 1')
Sounds like you're already looking at the doco but here it is just in case.
Update also, this worked for me using the search method:
https://graph.microsoft.com/v1.0/me/messages?$search="subject:'Test 1'"

How to replace content within quotes via a file

Why I cannot use str_replace() to replace content between the ""? While I replace links within a file they get skipped since they are within quotes.
Example.
href="/path/to/file/is/here"
should be
href="/New/Path/To/File/Goes/Here"
If the paths/urls were not in quotes, str_replace() would work.
I'm assuming this is PHP. So, from the examples here:
http://php.net/manual/en/function.str-replace.php
You can see that you should not intercalate the same type of quotes.
So try changing the quotes in your code to single quotes or, change, the double quotes in your html to single quotes.
If that's not it, I hope at least that doc reference helps you.
This might help I usually code in java but php is pretty similar. Next time input part of your code so that the community can see your logic.
In your if statement on line 67 the 3rd variable $stringToSearch should be regex not the string your assigning it to. The purpose of regex as you know is to replace characters you don't want in your code as you already know
What you had that was not working:
// replacing string from files
//$stringToSearch = str_replace('"', "!!", $stringToSearch);
$stringToSearch = str_replace($toBeReplaced, $toBeReplacedWith, $stringToSearch);
//$stringToSearch = str_replace("!!", '"', $stringToSearch);
What I am thinking it should be:
$stringToRegex = str_replace('"', "!!", $stringToSearch);
$stringToSearch = str_replace($toBeReplaced, $toBeReplacedWith, $stringToRegex );
If anyone else has any suggestion it would be appreciated as i don't code in php.

Variable substitution of multiline list of strings in PostgreSQL

I'm trying to substitute the list in the following code:
kategori NOT IN ('Fors',
'Vattenfall',
'Markerad vinterled',
'Fångstarm till led',
'Ruskmarkering',
'Tält- och eldningsförbud, tidsbegränsat',
'Skidspår')
I found this question for the multiline part. However
SELECT ('Fors',
'Vattenfall',
'Markerad vinterled',
'Fångstarm till led',
'Ruskmarkering',
'Tält- och eldningsförbud, tidsbegränsat',
'Skidspår') exclude_fell \gset
gives
ERROR: column "fors" does not exist
LINE 1: SELECT (Fors,
^
, so I tried using triple quotes, dollar quotation and escape sequenses. Nothing has worked to satisfaction. This is true even if I use a single line variable and \set, so I must have misunderstood something about variable substitution. What is the best way of doing this?

What does `y` stand for in Perl

I have found the following piece of Perl code online:
y/a-z//s
I looked in the docs to see what it does, but I didn't find anything about it. What does the y stand for here?
The full code:
($_='jjjuuusssttt annootthheer
pppeeerrrlll haaaccckkeer')=~y/a-z//s;print;
According to perlop:
tr/SEARCHLIST/REPLACEMENTLIST/cdsr
y/SEARCHLIST/REPLACEMENTLIST/cdsr
Transliterates all occurrences of the characters found in the search list with the corresponding character in the replacement list.
For sed devotees, y is provided as a synonym for tr.
Options:
c Complement the SEARCHLIST.
d Delete found but unreplaced characters.
s Squash duplicate replaced characters.
r Return the modified string and leave the original string untouched.
If the REPLACEMENTLIST is empty, the SEARCHLIST is replicated.

regexkitlite match?

i would like to get everything inbetween &v= and "> using a regex expression,
NSString *YouTubeRegex = #"/amp;v=([^(\">)]+)/";
But that regex is not returning any matches ? i know the coding is correct just not the regex expression any help ?
Thanks
Try this :
/amp;v=(.+?)">/
http://www.rubular.com/r/Lqb63CsN2p
Assuming the regex engine is Perl-like:
"/&v=(.*)>/"
should do the trick.