Ask update and delete multiple array in MongoDb - mongodb

I have a real case in my project:
> db.foo.insert({a:'1',
... province: [{id:'1',name:'Yogyakarta',state:[{id:'1',name:'bantul'}]}]
... })
Then I find()...
> db.foo.find();
> { "_id" : ObjectId("5279ef4c6cfd9d5c0e19bbe0"),
"a" : "1",
"province" : [
{"id" : "1",
"name" : "Yogyakarta",
"state" : [
{"id" : "1","name" : "bantul" }
]
}
]
}
how to remove and update state with id='1'

REMOVE
To remove the documents that match a deletion criteria, call the remove() method with the <query> parameter.
db.foo.remove({'province.state.id': '1'})
Example
First, insert data Yogyakarta - Bantul
db.foo.insert({a:'1', province: [{id:'1',name:'Yogyakarta',state:[{id:'1',name:'bantul'}]}] })
Insert data Jakarta - Jakarta Selatan
db.foo.insert({a:'1', province: [{id:'2',name:'Jakarta',state:[{id:'2',name:'Jakarta Selatan'}]}] })
Now, you have two documents
db.foo.find();
Result
[
{ "a" : "1", "_id" : { "$oid" : "527b54c6cc937439340367f9" }, "province" : [ { "name" : "Yogyakarta", "id" : "1", "state" : [ { "name" : "bantul", "id" : "1" } ] } ] },
{ "a" : "1", "_id" : { "$oid" : "527b54d3cc937439340367fa" }, "province" : [ { "name" : "Jakarta", "id" : "2", "state" : [ { "name" : "Jakarta Selatan", "id" : "2" } ] } ] }
]
Now, delete document where the subdocument province contains a field state whose value 1.
db.foo.remove({'province.state.id': '1'})
Check
db.foo.find();
Now, you have one document
[
{ "a" : "1", "_id" : { "$oid" : "527b54d3cc937439340367fa" }, "province" : [ { "name" : "Jakarta", "id" : "2", "state" : [ { "name" : "Jakarta Selatan", "id" : "2" } ] } ] }
]
UPDATE
By default, the update() method updates a single document. If the multi option is set to true, the method updates all documents that match the query criteria.
db.foo.update({'province.state.id': '2'}, { $set: {'a': '2'} })
Check
db.foo.find();
Result
[
{ "a" : "2", "_id" : { "$oid" : "527b54d3cc937439340367fa" }, "province" : [ { "name" : "Jakarta", "id" : "2", "state" : [ { "name" : "Jakarta Selatan", "id" : "2" } ] } ] }
]

Related

All Mongo documents with duplicated objects inside array

Find documents with duplicated objects inside an array.
Some answers works just with array made of "basic type elements" (i.e. array of strings). Here I want to filter on certain objects fields
In example:
{
"name": "1",
"arr": [{ "type": "fruit", "name":"pear"},{ "type": "fruit","name":"banana"}]
},
{
"name":"2",
"arr": [{"type":"fish"}]
}
Given the above two documents, I want to retrieve just document 1, because it has 2 elements in the array that have the same type. (Of course I want all documents with such property, not just one)
The following query can get us the expected output:
db.collection.find({
$expr:{
$ne:[
{
$size:"$arr"
},
{
$size:{
$setUnion:["$arr.type"]
}
}
]
}
}).pretty()
Data set:
{
"_id" : ObjectId("5d7b8546d76ccfa3cb0f133c"),
"name" : "1",
"arr" : [
{
"type" : "fruit",
"name" : "pear"
},
{
"type" : "fruit",
"name" : "banana"
}
]
}
{
"_id" : ObjectId("5d7b8546d76ccfa3cb0f133d"),
"name" : "2",
"arr" : [
{
"type" : "fish"
}
]
}
{
"_id" : ObjectId("5d7b8546d76ccfa3cb0f133e"),
"name" : "3",
"arr" : [
{
"type" : "product",
"name" : "watch"
},
{
"type" : "product",
"name" : "Pen"
}
]
}
Output:
{
"_id" : ObjectId("5d7b8546d76ccfa3cb0f133c"),
"name" : "1",
"arr" : [
{
"type" : "fruit",
"name" : "pear"
},
{
"type" : "fruit",
"name" : "banana"
}
]
}
{
"_id" : ObjectId("5d7b8546d76ccfa3cb0f133e"),
"name" : "3",
"arr" : [
{
"type" : "product",
"name" : "watch"
},
{
"type" : "product",
"name" : "Pen"
}
]
}
Query analysis: We are filtering documents in which the size of arr is not equal to the count of unique type present in the arr

How to group nasted array in mongo db

In my mongodb collection I have next records
{ "_id" : ObjectId("5d0dfb68264b2d01a3237a3e"), "name" : "lexa", "cat" : 2, "gender" : "male", "date" : ISODate("2019-06-22T09:56:56.070Z") }
{ "_id" : ObjectId("5d0dfb6c264b2d01a3237a3f"), "name" : "dima", "cat" : 2, "gender" : "male", "date" : ISODate("2019-06-22T09:57:00.925Z") }
{ "_id" : ObjectId("5d0dfb75264b2d01a3237a40"), "name" : "lena", "cat" : 2, "gender" : "female", "date" : ISODate("2019-06-22T09:57:10.003Z") }
{ "_id" : ObjectId("5d0dfb7a264b2d01a3237a41"), "name" : "nina", "cat" : 2, "gender" : "female", "date" : ISODate("2019-06-22T09:57:14.941Z") }
{ "_id" : ObjectId("5d0dfb8f264b2d01a3237a42"), "name" : "nina", "cat" : 1, "gender" : "female", "date" : ISODate("2019-06-22T09:57:35.128Z") }
{ "_id" : ObjectId("5d0dfb93264b2d01a3237a43"), "name" : "lena", "cat" : 1, "gender" : "female", "date" : ISODate("2019-06-22T09:57:39.789Z") }
{ "_id" : ObjectId("5d0dfb9b264b2d01a3237a44"), "name" : "dima", "cat" : 1, "gender" : "male", "date" : ISODate("2019-06-22T09:57:47.150Z")
Then I use aggregation mongo framework to group that records by cat.
db.foo.aggregate([{'$group':
{
'_id': '$cat',
'users':
{'$push':
{
'name':'$name',
'gender': '$gender'
}
}
}
}])
That query returns me next result
{
"_id" : 1,
"users" : [
{
"name" : "nina",
"gender" : "female"
},
{
"name" : "lena",
"gender" : "female"
},
{
"name" : "dima",
"gender" : "male"
}
]
}
{
"_id" : 2,
"users" : [
{
"name" : "lexa",
"gender" : "male"
},
{
"name" : "dima",
"gender" : "male"
},
{
"name" : "lena",
"gender" : "female"
},
{
"name" : "nina",
"gender" : "female"
}
]
}
And the question is what I need to add to my query to group by my users array. I want to get something like this
{
"_id" : 1,
"users" : [
{
"gender": "male",
"names": ["dima"]
},
{
"gender": "female",
"names": ["lena", "nina"]
}
]
}
{
"_id" : 2,
"users" : [
{
"gender": "male",
"names": ["lexa", "dima"]
},
{
"gender": "female",
"names": ["lena", "nina"]
}
]
}
I need to have my nested array been grouped too without loosing first group result
Would be easier to first group by cat X gender and then restructure the data like so :
db.foo.aggregate([
{'$group':
{
'_id': {cat: '$cat', gender: "$gender"},
'names':
{'$push':
{
'name':'$name',
}
}
}
},
{
$group: {
'_id': "$_id.cat",
users: { $push: { gender: "$_id.gender", names: "$names" }
}
}
])

Mongodb update nested array by id

I have the following document and want to update state
Document ID: ObjectId("5a4e5a448b70d50e34d204a5")
Target ID: ObjectId("5a4e5a438b70d50e34d203ea")
I have no idea how to update the state to e.g. 4
{
"_id" : ObjectId("5a4e5a448b70d50e34d204a5"),
"name" : "Wirtschaftsdienst",
"date" : ISODate("2012-10-07T00:00:00.000Z"),
"comment" : null,
"tasks" : [
{
"name" : "Speisen und Getränke",
"sections" : [
{
"start" : 46800,
"end" : 72000,
"entirely" : true,
"assistants" : [
{
"assistant" : {
"_id" : ObjectId("5a4e5a438b70d50e34d203ea")
},
"state" : 3
},
{
"assistant" : {
"_id" : ObjectId("5a4e5a438b70d50e34d203f4")
},
"state" : 3
}
]
}
]
}
]
}
Use positional operator $[] along with arrayFilters to get your job done!
Try this query:
db.collection.update(
{"_id" : ObjectId("5a4e5a448b70d50e34d204a5")},
{$set: {"tasks.$[].sections.$[].assistants.$[element].state":4}},
{arrayFilters: [ {"element.assistant":{"_id" :
ObjectId("5a4e5a438b70d50e34d203ea")} }
], multi:true}
)
And the output is:
/* 1 */
{
"_id" : ObjectId("5a4e5a448b70d50e34d204a5"),
"name" : "Wirtschaftsdienst",
"date" : ISODate("2012-10-07T00:00:00.000Z"),
"comment" : null,
"tasks" : [
{
"name" : "Speisen und Getränke",
"sections" : [
{
"start" : 46800,
"end" : 72000,
"entirely" : true,
"assistants" : [
{
"assistant" : {
"_id" : ObjectId("5a4e5a438b70d50e34d203ea")
},
"state" : 4.0
},
{
"assistant" : {
"_id" : ObjectId("5a4e5a438b70d50e34d203f4")
},
"state" : 3.0
}
]
}
]
}
]
}

MongoDB query with multiple conditions

I have data with multiple documents :
{
"_id" : ObjectId("57b68dbbc19c0bd86d62e486"),
"empId" : "1"
"type" : "WebUser",
"city" : "Pune"
}
{
"_id" : ObjectId("57b68dbbc19c0bd86d62e487"),
"empId" : "2"
"type" : "Admin",
"city" : "Mumbai"
}
{
"_id" : ObjectId("57b68dbbc19c0bd86d62e488"),
"empId" : "3"
"type" : "Admin",
"city" : "Pune"
}
{
"_id" : ObjectId("57b68dbbc19c0bd86d62e489"),
"empId" : "4"
"type" : "User",
"city" : "Mumbai"
}
I want to get data according to my multiple conditions :
condition 1:- {"type" : "WebUser", "city" : "Pune"}
condition 2:- {"type" : "WebUser", "city" : "Pune"} & {"type" : "User", "city" : "Mumbai"}
I want below result when run condition 1 :
{
"_id" : ObjectId("57b68dbbc19c0bd86d62e486"),
"empId" : "1"
"type" : "WebUser",
"city" : "Pune"
}
When I run second condition :
{
"_id" : ObjectId("57b68dbbc19c0bd86d62e486"),
"empId" : "1"
"type" : "WebUser",
"city" : "Pune"
}
{
"_id" : ObjectId("57b68dbbc19c0bd86d62e489"),
"empId" : "4"
"type" : "User",
"city" : "Mumbai"
}
I want above result by one query,
Currently I am using below aggregate query,
db.emp.aggregate([
{ $match: { '$and': [
{"type" : "WebUser", "city" : "Pune"},
{"type" : "User", "city" : "Mumbai"}
] } },
{ $group: { _id: 1, ids: { $push: "$empId" } } }
])
Above query work for first condition & fails for other. Please help me.
For the second condition, you can use the $in operator in your query as:
db.emp.find({
"type" : { "$in": ["WebUser", "User"] },
"city" : { "$in": ["Pune", "Mumbai"] }
})
If you want to use in aggregation:
db.emp.aggregate([
{
"$match": {
"type" : { "$in": ["WebUser", "User"] },
"city" : { "$in": ["Pune", "Mumbai"] }
}
},
{ "$group": { "_id": null, "ids": { "$push": "$empId" } } }
])
or simply use the distinct() method to return an array of distinct empIds that match the above query as:
var employeeIds = db.emp.distinct("empId", {
"type" : { "$in": ["WebUser", "User"] },
"city" : { "$in": ["Pune", "Mumbai"] }
});
If you are looking for the AND operator
This example checks if a field exists AND is null
db.getCollection('TheCollection').find({
$and: [
{'the_key': { $exists: true }},
{'the_key': null}
]
})
This example checks if a field has 'value1' OR 'value2'
db.getCollection('TheCollection').find({
$or: [
{'the_key': 'value1'},
{`the_key': 'value2'}
]
})
When just checking for null, the return contains non-existing fields plus fields with value null
db.getCollection('TheCollection').find({'the_key': null})
You can use mongo db $or operator.
db.emp.find({ $or: [
{ "type": "WebUser", "city": "Pune" },
{ "type": "user", "city": "Mumbai"}
]})
You can pass conditions in the array.
For more reference see mongo docs
Display the document where in the “StudName” has value “Ajay Rathod”.
db.Student.find({name:"ajay rathod"})
{ "_id" : ObjectId("5fdd895cd2d5a20ee8cea0de"), "
Retrieve only Student Name and Grade.
db.Student.find({},{name:1,grade:1,_id:0})
{ "name" : "dhruv", "grade" : "A" }
{ "name" : "jay", "grade" : "B" }
{ "name" : "abhi", "grade" : "C" }
{ "name" : "aayush", "grade" : "A" }
{ "name" : "sukhdev", "grade" : "B" }
{ "name" : "dhruval", "grade" : "B" }
{ "name" : "ajay rathod", "grade" : "D" }

MongoDB find documents if a property array doesn't contain an object

I have a list of documents like this.
[
{
"name" : "test",
"data" : [
{ "code" : "name", "value" : "Diego" },
{ "code" : "nick", "value" : "Darko" },
{ "code" : "special", "value" : true }
]
},
{
"name" : "another",
"data" : [
{ "code" : "name", "value" : "Antonio" },
{ "code" : "nick", "value" : "Tony" }
]
}
]
now I need to find all the documents that:
a) don't contain a "data" item with code "special"
OR
b) contains a "data" item with code "special" and value false
It's like I needed the opposite of $elemMatch or I'm missing something?
I'm assuming that you're inserting each document in your list of documents as a separate member of a collection test.
For a,
db.test.find({ "data.code" : { "$ne" : "special" } })
For b.,
db.test.find({ "data" : { "$elemMatch" : { "code" : "special", "value" : false } } })
Combining the two with $or,
db.test.find({ "$or" : [
{ "data.code" : { "$ne" : "special" } },
{ "data" : { "$elemMatch" : { "code" : "special", "value" : false } } }
] })
Hope this $nin will solve your issues.
I insertd your docs into "so" collection
db.so.find({}).pretty();
{
"_id" : ObjectId("5489cd4f4cb16307b808d4b2"),
"name" : "test",
"data" : [
{ "code" : "name",
"value" : "Diego"
},
{ "code" : "nick",
"value" : "Darko"
},
{ "code" : "special",
"value" : true
}
]
}
{
"_id" : ObjectId("5489cd674cb16307b808d4b3"),
"name" : "another",
"data" : [
{"code" : "name",
"value" : "Antonio"
},
{ "code" : "nick",
"value" : "Tony"
}
]
}
don't contain a "data" item with code "special"
> db.so.find({"data.code":{$nin:["special"]}}).pretty();
{
"_id" : ObjectId("5489cd674cb16307b808d4b3"),
"name" : "another",
"data" : [
{ "code" : "name",
"value" : "Antonio"
},
{ "code" : "nick",
"value" : "Tony"
}
]
}
contains a "data" item with code "special" and value false
db.so.find({$and:[{"data.code":"special"},{"data.value":false}]}).pretty();