I'm attempting to pull some information out of text file that is updated after I query a piece of equipment. The text file contains lines such as shown here (abbreviated):
05-Nov-13 11:11:54.3496 ( -1 7020 10244) scpeng.exe:Automation Server...
05-Nov-13 14:10:54.3496 ( -1 7020 10244) scpeng.exe:Automation Server...
05-Nov-13 14:10:54.3496 ( -1 7020 10244) scpeng.exe:Automation Server...
05-Nov-13 14:10:56.3496 ( -1 7020 10244) scpeng.exe:CServer.cpp,....
The text file can contain up to several weeks of information. I have a subroutine that will run a few seconds after I query the equipment which should allow for the reply and the applicable line to be present in the text file. In the routine, I am trying to scroll through the lines examining the date to arrive at the date of the subroutine call followed by the time (or a time ~10 seconds prior the the current time) to arrive at the lines pertinent to where the information could be found.
do
msg = msgstream.ReadLine
logdate = mide(msg,1,9)
logday = Cdate(logdate)
loop while logday < date
do
msg = msgstream.Readline
logtime = mid(msg,12,8)
'logtime = CDate(logtime) This mod is not working
loop while logtime < time
The date loop appears to work however the time is giving me problems. It does not error out but I can't get it to run beyond one line of text. Can anyone suggest a fix or better option? I have read that the built-in Date function can include the time but I do not believe this version I'm using does. Also, the text file contains times in a 24 hour format where I believe the time function returns values in a 12 hr format ie "12:43:27 PM ST".
You're making this way too complicated. Simply parse the whole date string into a datetime value:
refdate = Now
Do
msg = msgstream.ReadLine
logdate = CDate(Mid(msg, 1, 19))
Loop While logdate < refdate
You can extract date and time portions from the value later, e.g. like this:
WScript.Echo DateValue(logdate)
WScript.Echo TimeValue(logdate)
Also, Time returns the current (unformatted) system time. Whether it's displayed in 12 hour or 24 hour format depends on your system's region settings. However, you can always get the hour (0-23) by using the Hour function.
Parse each line with a regex to get the correct date and time part. I prefer a regexp above string manipulation functions because you can separate format and code.
Reassemble the date from the two parts and see if the date is smaller than yesterday at this time.
Option Explicit
dim strTest, re, matches, myDatePart, myTimePart, logDate
' teststring
strTest = "08-Nov-13 14:10:56.3496 ( -1 7020 10244) scpeng.exe:CServer.cpp,...."
Set re = new regexp
' This pattern extracts two part, the date as (dd-www-dd) and the time as (hh:mm:ss)
re.pattern = "(\d{2}-\w{3}-\d{2}) +(\d{2}:\d{2}:\d{2})"
Set matches = re.Execute(strTest)
' Get the first and second submatch to define the date and time
myDatePart = matches(0).submatches(0)
myTimePart = matches(0).submatches(1)
' datevalue and timevalue automatically tranforms to Date type
logDate = datevalue(myDatePart) + timevalue(myTimePart)
' See if the date is smaller than yesterday exactly this time
msgbox (logDate < (DateAdd("d", -1, now))) ' Returns True, because 08 Nov is earlier than yesterday.
Related
I was wondering if someone could help me.
I'm very new at ASP I want to format the current date and time as follows:
yyyy-mm-dd hh:mm:ss
But all i can do is the following
Response.Write Date
Can someone help me out please.
Date formatting options are limited in Classic ASP by default, there is a function FormatDateTime() which can format your date is various ways based on the servers regional settings.
For more control over date formatting though there are built in date time functions
Year(date) - Returns a whole number representing the year. Passing Date() will give back the current year.
Month(date) - Returns a whole number between 1 and 12, inclusive, representing the month of the year. Passing Date() will return the current month of the year.
MonthName(month[, abbv]) - Returns a string indicating the specified month. Passing in Month(Date()) as the month will give back the current Month string. As suggested by #Martha
Day(date) - Returns a whole number between 1 and 31, inclusive, representing the day of the month. Passing Date() will return the current day of the month.
Hour(time) - Returns a whole number between 0 and 23, inclusive, representing the hour of the day. Passing Time() will return the current hour.
Minute(time) - Returns a whole number between 0 and 59, inclusive, representing the minute of the hour. Passing Time() will return the current minute.
Second(time) - Returns a whole number between 0 and 59, inclusive, representing the second of the minute. Passing Time() will return the current second.
IMPORTANT:
When formatting date / time values, always store the date / time value first. Also, any needed calculations (DateAdd() etc.) should be applied before attempting to format or you will get unexpected results.
The functions Month(), Day(), Hour(), Minute() and Second() all return whole numbers. Luckily there is an easy workaround that lets you pad these values quickly Right("00" & value, 2) what it does is append 00 to the front of the value then from the right take the first two characters. This ensures that all single digit values return prefixed with a 0.
Dim dd, mm, yy, hh, nn, ss
Dim datevalue, timevalue, dtsnow, dtsvalue
'Store DateTimeStamp once.
dtsnow = Now()
'Individual date components
dd = Right("00" & Day(dtsnow), 2)
mm = Right("00" & Month(dtsnow), 2)
yy = Year(dtsnow)
hh = Right("00" & Hour(dtsnow), 2)
nn = Right("00" & Minute(dtsnow), 2)
ss = Right("00" & Second(dtsnow), 2)
'Build the date string in the format yyyy-mm-dd
datevalue = yy & "-" & mm & "-" & dd
'Build the time string in the format hh:mm:ss
timevalue = hh & ":" & nn & ":" & ss
'Concatenate both together to build the timestamp yyyy-mm-dd hh:mm:ss
dtsvalue = datevalue & " " & timevalue
Call Response.Write(dtsvalue)
Note: You can build the date string in one call but decided to break it down into the three variables to make it easier to read.
How Can I Format Date
Example of Parsing a Date String (Answers provide approaches to taking a date string format and parsing it to a valid Date variable).
Format the date of the previous day format yyyymmdd with VBScript (Example of why storing date / time before performing formatting is important)
VBScript ISO8601 (Example of functions to construct an ISO 8601 compliant date string)
Hi I am a newbie and have a problem I have been trying to solve for weeks. I have a table imported from excel with dates in text format (because dates go back to 1700s) Most are in the format "mmmyyyy", so it is relatively easy to add "1" to the date, convert to date format, and sort in correct date order. The problem I have is that some of the dates in the table are simply "yyyy", and some are empty. I cannot find an expression that works to convert these last two to eg 1 Jan yyyy and 1 Jan 1000 within the same expression. Is this possible, or would I need to do this in two queries? Sorry if this question is very basic - I cannot find an answer anywhere.
TIA
You can do something like:
Public Function ConvertDate(Byval Expression As Variant) As Date
Dim Result As Date
If IsNull(Expression) Then
Result = DateSerial(1000, 1, 1)
ElseIf Len(Expression) = 4 Then
Result = DateSerial(Expression, 1, 1)
Else
Result = DateValue(Right(Expression, 4) & "/" & Left(Expression, 3) & "/1")
End If
ConvertDate = Result
End Function
Using os.time how can I get how many months have passed since the unix epoch (Unix Timestamp)
I just need it for a month ID, so any kind of number would be fine, as long as it changes every month, and it can be reversed to get the actual month.
local function GetMonth(seconds)
local dayduration,year = 3600*24
local days={31,0,31,30,31,30,31,31,30,31,30,31}
for i=1970,10000 do -- For some reason too lazy to use while
local yeardays = i%4 == 0 and i%100 ~= 0 and 366 or 365
local yearduration = dayduration * yeardays
if yearduration < seconds then
seconds = seconds - yearduration
else
year = i break
end
end
days[2]=(year%4==0) and 29 or 28
seconds = seconds%(365*24*3600)
for i=1,12 do
if seconds>days[i]*dayduration then
seconds=seconds-days[i]*dayduration
else
return --i + year*12 <-- If you want a unique ID
end
end
end
Currently, it'll give the number 2, since it's February. If you uncomment the code at the end for the unique ID, you'll get 554 instead, meaning we're currently at the 554th month since the epoch.
As Jean-Baptiste Yunès said in his answer's comments, I'm not sure if your sentence:
NOTE: This is for Lua, but I'm unable to use os.date
meant you have no os.date, or that you don't know how to use it. You have an answer for both cases, you can use the one you need.
This may do the trick:
print (os.date("*t",os.time())["month"])
os.time() gives you the current date as a number. os.date("*t",...) converts it into a table in which the month equals to the number of the month corresponding to the date.
I'm trying to compare a file's modified date with a specific date.
What I have is this:
If FormatDateTime(objFile.DateLastModified,vbShortDate) = specificDate Then
'Do something
End if
I've tried using IsDate and a variable with a value of #11/9/2015# but always returns false. I can't figure out how to set the variable "specificDate" to 11/9/2015.
If you are comparing the date only (but not the time), then you have to cut off the fractional part of the last modified value, since integer part represents days, and fractional part - hours, minutes and seconds. After any changes convert the values back to Date type with CDate(), as well as date containing string before the comparison.
Sub Test()
dtSpecificDate = CDate("11/9/2015")
With CreateObject("Scripting.FileSystemObject").GetFile("C:\Test\tmp.txt")
dtLastModified = CDate(Int(.DateLastModified))
End With
If dtLastModified = dtSpecificDate Then
' Do something
End If
End Sub
I have to develop a system, where user will specify a starting range and an ending range (By Range, I mean to say a particular period, where PERIOD is given as a concatenation of YEAR AND MONTH). For example, PERIOD = 201304, where 2013 is the user entered Year and 04 is the MONTH. The user can specify a maximum range of upto 2 years only.
Data needs to be selected on the basis of the user entered range. The problem is whenever I try to loop through the period, the PERIOD changes after 201312 to 201313. I have separate variables for user selected year and month (start_year, start_month, end_year, end_month)
I did a IF loop there in which I tried to do the following
FOR p_tmpyear = p_tempfrom TO p_tempto
IF (p_monthfrm < 12) THEN
LET p_yearfrm = p_yearfrm + 1
LET p_monthfrm = 01
LET p_fromperiod = p_yearfrm + 1,p_monthfrm >p_fromperiod is an integer storing concatenated Month and Year, to achieve the desired PERIOD format as mentioned above.
LET p_tempfrom = p_fromperiod
END IF
DISPLAY p_tmpyear
END FOR
I even tried thsi one :
IF (p_fromperiod MOD p_yearfrm = 13) THEN
LET p_yearfrm = p_yearfrm + 1
LET p_monthfrm = 01
LET p_fromperiod = p_yearfrm + 1,p_monthfrm
Still the period changes after reaching 201212 to 201213. I want this to be 201301. Please help.
As you have probably guessed, you have some flaws in your logic. The first example is too hard to decipher, whilst the second shows you don't understand what the MOD operator does. If used correctly, in this context, it would be of the form IF variable MOD 12 = 0 i.e. every 12th value do something.
I think where you are going wrong is trying to do it all in one loop. I would keep it simple and break the problem into two nested loops, one for year, one for month
DEFINE start_year, end_year, start_month, end_month INTEGER -- sample values 2012, 2013,7,6
DEFINE loop_year, loop_month INTEGER -- values used to loop through year and month respectively
DEFINE loop_first_month, loop_last_month INTEGER -- for each year, calc first month and last month
DEFINE period CHAR(6)
-- First loop over year
FOR loop_year = start_year TO end_year
-- Calculate first and last month for the given year
-- If first year, use passed in start month else use 1
IF loop_year = start_year THEN
LET loop_first_month = start_month
ELSE
LET loop_first_month = 1
END IF
-- If last year, use passed in end month else use 12
IF loop_year = end_year THEN
LET loop_last_month = end_month
ELSE
LET loop_last_month = 12
END IF
-- Second loop over month
FOR loop_month = loop_first_month TO loop_last_month
LET period = loop_year USING "&&&&",loop_month USING "&&"
DISPLAY period
END FOR
END FOR
I would also encourage you to also post questions like this in the dedicated 4Js Genero developers forum at the 4Js website http://www.4js.com/fjs_forum/ as well as here. Most Genero developers should be aware of that forum and have access.