How to accumulate errors in Either? - scala

Question

Suppose I have few case classes and functions to test them:
case class PersonName(...)
case class Address(...)
case class Phone(...)
def testPersonName(pn: PersonName): Either[String, PersonName] = ...
def testAddress(a: Address): Either[String, Address] = ...
def testPhone(p: Phone): Either[String, Phone] = ...
Now I define a new case class Person and a test function, which fails fast.
case class Person(name: PersonName, address: Address, phone: Phone)
def testPerson(person: Person): Either[String, Person] = for {
pn <- testPersonName(person.name).right
a <- testAddress(person.address).right
p <- testPhone(person.phone).right
} yield person;
Now I would like function testPerson to accumulate the errors rather than just fail fast.
I would like testPerson to always execute all those test* functions and return Either[List[String], Person]. How can I do that ?

Answer 1

You want to isolate the test* methods and stop using a comprehension!
Assuming (for whatever reason) that scalaz isn't an option for you... it can be done without having to add the dependency.
Unlike a lot of scalaz examples, this is one where the library doesn't reduce verbosity much more than "regular" scala can:
def testPerson(person: Person): Either[List[String], Person] = {
val name = testPersonName(person.name)
val addr = testAddress(person.address)
val phone = testPhone(person.phone)
val errors = List(name, addr, phone) collect { case Left(err) => err }
if(errors.isEmpty) Right(person) else Left(errors)
}

Answer 2

Scala's for-comprehensions (which desugar to a combination of calls to flatMap and map) are designed to allow you to sequence monadic computations in such a way that you have access to the result of earlier computations in subsequent steps. Consider the following:
def parseInt(s: String) = try Right(s.toInt) catch {
case _: Throwable => Left("Not an integer!")
}
def checkNonzero(i: Int) = if (i == 0) Left("Zero!") else Right(i)
def inverse(s: String): Either[String, Double] = for {
i <- parseInt(s).right
v <- checkNonzero(i).right
} yield 1.0 / v
This won't accumulate errors, and in fact there's no reasonable way that it could. Suppose we call inverse("foo"). Then parseInt will obviously fail, which means there's no way we can have a value for i, which means there's no way we could move on to the checkNonzero(i) step in the sequence.
In your case your computations don't have this kind of dependency, but the abstraction you're using (monadic sequencing) doesn't know that. What you want is an Either-like type that isn't monadic, but that is applicative. See my answer here for some details about the difference.
For example, you could write the following with Scalaz's Validation without changing any of your individual validation methods:
import scalaz._, syntax.apply._, syntax.std.either._
def testPerson(person: Person): Either[List[String], Person] = (
testPersonName(person.name).validation.toValidationNel |#|
testAddress(person.address).validation.toValidationNel |#|
testPhone(person.phone).validation.toValidationNel
)(Person).leftMap(_.list).toEither
Although of course this is more verbose than necessary and is throwing away some information, and using Validation throughout would be a little cleaner.

Answer 3

As #TravisBrown is telling you, for comprehensions don't really mix with error accumulations. In fact, you generally use them when you don't want fine grained error control.
A for comprehension will "short-circuit" itself on the first error found, and this is almost always what you want.
The bad thing you are doing is using String to do flow control of exceptions. You should at all times use Either[Exception, Whatever] and fine tune logging with scala.util.control.NoStackTrace and scala.util.NonFatal.
There are much better alternatives, specifically:
scalaz.EitherT and scalaz.ValidationNel.
Update:(this is incomplete, I don't know exactly what you want). You have better options than matching, such as getOrElse and recover.
def testPerson(person: Person): Person = {
val attempt = Try {
val pn = testPersonName(person.name)
val a = testAddress(person.address)
testPhone(person.phone)
}
attempt match {
case Success(person) => //..
case Failure(exception) => //..
}
}

Answer 4

Starting in Scala 2.13, we can partitionMap a List of Eithers in order to partition elements based on their Either's side.
// def testName(pn: Name): Either[String, Name] = ???
// def testAddress(a: Address): Either[String, Address] = ???
// def testPhone(p: Phone): Either[String, Phone] = ???
List(testName(Name("name")), testAddress(Address("address")), testPhone(Phone("phone")))
.partitionMap(identity) match {
case (Nil, List(name: Name, address: Address, phone: Phone)) =>
Right(Person(name, address, phone))
case (left, _) =>
Left(left)
}
// Either[List[String], Person] = Left(List("wrong name", "wrong phone"))
// or
// Either[List[String], Person] = Right(Person(Name("name"), Address("address"), Phone("phone")))
If the left side is empty, then no elements were Left and thus we can build a Person out of the Right elements.
Otherwise, we return a Left List of the Left values.
Details of the intermediate step (partitionMap):
List(Left("bad name"), Right(Address("addr")), Left("bad phone"))
.partitionMap(identity)
// (List[String], List[Any]) = (List("bad name", "bad phone"), List[Any](Address("addr")))