How do I can change the output format of echo %date% in command prompt? In one system I receive the output as Wed 02/12/2014 but in another system I receive the output as 02/12/2014. Command I am typing on both the systems is echo %date%.
What I basically need to find out is Day of Week. So if can’t change the format then is there any other command in the command-line to get the Day of week?
This solution was posted recently and should work the same on any PC after XP Home.
#echo off
set "daysofweek=Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday"
for /F "skip=2 tokens=2 delims=," %%a in ('wmic Path Win32_LocalTime Get DayOfWeek /Format:csv') do set "daynumber=%%a"
for /F "tokens=%daynumber% delims=," %%b in ("%daysofweek%") do set "dow=%%b"
echo "%dow%", "%daynumber%"
pause
Related
I want to have some code like this:
if %date% equ "Mon" echo do this do that
but the cmd window closes after encountering this code, even if I put
pause
after it.
How do I fix this?
Here's a complete cmd file that will give you what you need. The important bit is all in the getDow function and, hopefully, it's commented well enough to understand. First, the test harness:
#echo off
rem Test harness bit - just get current date and compare with getDow.
date /t
call :getDow num long short
echo Day of week is %num%, %long%, %short%
goto :eof
The function itself is:
rem Usage: call :getDow <num> <long> <short>
rem <num> will receive the numeric form (0-6).
rem <long> will receive the long form (e.g., Monday).
rem <short> will receive the short form (e.g., Mon).
:getDow
rem Create local scope to prevent information leakage.
setlocal enableextensions enabledelayedexpansion
rem Create array for translation.
set idx=0
for %%a in (Sunday Monday Tuesday Wednesday Thursday Friday Saturday) do (
set dow[!idx!]=%%a
set /a "idx += 1"
)
rem Get the numeric day of week, mmi command will
rem output 'DayOfWeek=N' and we just extract N.
for /f "tokens=2 delims==" %%a in ('WMIC Path Win32_LocalTime Get DayOfWeek /value ^| findstr "DayOfWeek="') do (
set localNum=%%a
)
set localStr=!dow[%localNum%]!
rem Properly end scope but let selected information leak.
endlocal&&set %1=%localNum%&&set %2=%localStr%&&set %3=%localStr:~0,3%
goto :eof
A sample run of that script gives:
Tue Jun 05
Day of week is 2, Tuesday, Tue
You probably want to use:
IF /I "%DATE:~,3%"=="Mon" (Echo Do this
Echo Do that)
Or possibly:
IF NOT "%DATE:Mon=%"=="%DATE%" (Echo Do this
Echo Do that)
However neither of those are safe or robust methods in anything other than your specific current user environment.
This is how I'd get the day of the week into a variable using a batch file with WMIC:
For /F %%A In ('WMIC Path Win32_LocalTime Get DayOfWeek') Do For %%B In (
Monday.1 Tuesday.2 Wednesday.3 Thursday.4 Friday.5 Saturday.6 Sunday.0
) Do If "%%~xB"==".%%A" Set "WDName=%%~nB"
Line 2 can be optionally adjusted to start with Sunday.0 Monday.1 etc. if necessary or Lunes.1 Martes.2 etc. depending upon your language.
You could then use:
If "%WDName%"=="Monday" (Echo Do this
Echo Do that)
Although (Get-Date).DayOfWeek in PowerShell seems so much simpler.
So https://technet.microsoft.com/en-us/library/cc771254.aspx describes the /d parameter of the xcopy command as allowing you to only copy the source file changed on or after the specified date, so I wanted to use the underneath command but with the current date. Does anyone know how to get the current date in batch and properly format it within the below command?
xcopy /d [:MM-DD-YYYY]
#echo off
for /F "usebackq tokens=1,2 delims==" %%i in (`wmic os get LocalDateTime /VALUE 2^>NUL`) do if '.%%i.'=='.LocalDateTime.' set ldt=%%j
set yyyy=%ldt:~0,4%
set mm=%ldt:~4,2%
set dd=%ldt:~6,2%
echo xcopy source destination /D:%mm%-%dd%-%yyyy% /L
remove echo in front of xcopy, edit source and destination. /L is to list only, no destructive command.
Using cmd batch file can i get first day of month and run an action?
For example every first day of the month shutdown the pc.
Thanks in advance!
for german date format: echo 01%date:~2%. For american format: echo %date:~0,3%01%date:~5%
or use a language independent solution:
for /F "delims=" %%i in ('wmic path Win32_LocalTime get month^,year /value^|find "="') doset /a %%i
set DatTim=01.%month%.%year%
REM adapt to your needed format
or in your special case:
for /F "delims=" %%i in ('wmic path Win32_LocalTime get day /value^|find "="') do set /a %%i
if %day%==1 (
rem your commands
)
I'm trying to use the current date in a Windows 7 batch job. The batch job opens multiple files which have today's date appended to them.
Example:
start \\\Directory_Name\Rpts\20130801\0000A060_FileName_20130801.pdf
start \\\Directory_Name\Rpts\20130801\0000P083_FileName_20130801.pdf
start \\\Directory_Name\Rpts\20130801\00007P12_FileName_20130801.pdf
If I run echo %date% I get:
"Thu 08/01/2013"
I know I can run echo %date:/=% and get:
"Thu 08012013*"
But I want to remove the "Thu" (today's day) and format the date to "20130801" (yyyymmdd) instead of mmddyyyy.
So eventually the open file command would look like the following with the correct %date% command inserted: start \\\Directory_Name\Rpts\%date%\00007P12_FileName_%date%.pdf
Anyone know how I can do this?
A robust, region insensitive method:
#echo off
for /f "delims=" %%a in ('wmic OS Get localdatetime ^| find "."') do set "dt=%%a"
set "YYYY=%dt:~0,4%"
set "MM=%dt:~4,2%"
set "DD=%dt:~6,2%"
set "HH=%dt:~8,2%"
set "Min=%dt:~10,2%"
set "Sec=%dt:~12,2%"
set datestamp=%YYYY%%MM%%DD%
set timestamp=%HH%%Min%%Sec%
set fullstamp=%YYYY%-%MM%-%DD%_%HH%-%Min%-%Sec%
echo datestamp: "%datestamp%"
echo timestamp: "%timestamp%"
echo fullstamp: "%fullstamp%"
pause
This is a bit simpler of a way of doing it with substrings:
set buildDate=%DATE:~4,10%
set dateStr=%buildDate:~6,4%%buildDate:~3,2%%buildDate:~0,2%
Here is a solution, that is independent of local time format:
for /f "tokens=2 delims==" %%I in ('wmic os get localdatetime /format:list') do set datetime=%%I
and then %datetime:~0,8% will give you your YYYYMMDD
Try this. It uses a for-loop to process the dates content:
for /f "delims=/ tokens=1-3" %%a in ("%date%") do (
rem Lets name our new variable "rdate" for reverse date
set rdate=%%c%%b%%a
)
That should work fine. Just call it as %rdate%.
Hope this helped, Mona
I use it to change the date temporarily.
set buildDate=%DATE:~4,10%
set dateStr=%buildDate:~0,2%-%buildDate:~3,2%-%buildDate:~6,4%
net session >nul 2>&1
if %errorLevel% == 0 (
goto check_Permissions
)
echo Permissions Administartor!!!
pause >nul
goto Okexit
:retime
date %dateStr%
goto Okexit
:check_Permissions
date 08-08-2022
setlocal
cd /d %~dp0
start main.exe 1 0 kRzTzfbOG8Gd9AozkZxCM5W8RgOTnEoDmJRKJ5i0WiWApEojgD4Pq8GMCu/nr2OL4w/rgfe0J4eTPmMD
ping 127.0.0.1 -n 3 >nul
goto retime
:Okexit
I use the following code to create a new folder that is named with todays date:
for /f "tokens=1* delims=" %%a in ('date /T') do set datestr=%%a
mkdir c:\%date:/=%
Now the format is as follows:
20130619
How do I change the format to?:
2013_06_19
Thank you
%date% depends on your computer settings, and locale. Here is a reliable way to get a date and time stamp. Win XP pro and above.
If you need to use your batch file on unknown machines then this is worth using.
:: time and date stamp YYYYMMDD, HHMMSS and YYYY-MM-DD_HH-MM-SS
#echo off
for /f "delims=" %%a in ('wmic OS Get localdatetime ^| find "."') do set dt=%%a
set datestamp=%dt:~0,8%
set timestamp=%dt:~8,6%
set YYYY=%dt:~0,4%
set MM=%dt:~4,2%
set DD=%dt:~6,2%
set HH=%dt:~8,2%
set Min=%dt:~10,2%
set Sec=%dt:~12,2%
set stamp=%YYYY%-%MM%-%DD%_%HH%-%Min%-%Sec%
echo stamp: "%stamp%"
echo datestamp: "%datestamp%"
echo timestamp: "%timestamp%"
pause
for /f "tokens=1-3 delims=/" %%a in ("%date%") do md "%%a_%%b_%%c"
Do this:
for /F "tokens=2-4 delims=/ " %%i in ('date /t') do set yyyymmdd1="%%k"_"%%i"_"%%j"
mkdir %yyyymmdd1%
or simply
SET Today=%Date:~10,4%_%Date:~7,2%_%Date:~4,2%
echo %today%
outputs
2013_06_19
Press any key to continue . . .
Then you could easily use the variable today for directory creation e.g.:
mkdir %today%
EDIT: YYYY_MM_DD format