I am having trouble understanding how dates and days work together in a cron job.
Say I have the following command:
0 23 5 1 3 COMMAND
This translates to 23:00, on 5th of January, on Wednesday.
The problem is, that January 5th is a Sunday. How exactly will this command work out? Is the command going to be executed for both January 5th AND for every Wednesday on the month January? Or will it execute just the '5 1' bit?
I am really sorry if it is a really basic question and possibly stupid but to me it really does not make any sense.
Thank you in advance!
Commands are executed by cron when the minute, hour, and month of year fields match the current time, and at least one of the two day fields (day of month, or day of week) match
Ref: Man Page
Related
I need an RRULE for every other Saturday except the last week of the month. I tried to create one with a weekly frequency, but didn't know how to apply an exception for the last week of the month:
RRULE:FREQ=MONTHLY;INTERVAL=1;BYDAY=SA
I also tried creating a rule with a monthly frequency, which allowed me to skip the last week of the month, but I didn't know how to make it every other week:
RRULE:FREQ=MONTHLY;INTERVAL=1;BYDAY=SA;BYSETPOS=-2,-3,-4,-5
I looked through the specification, but I'm not seeing anything that makes this possible.
The secret to the solution here is that BYMONTHDAY can be negative like BYSETPOS. This allows one to exclude the last 7 days of each month even though the number of days in the month varies. Your DTSTART should be on a SATURDAY, so one doesn't really need the BYDAY=SA
This rrule works in google calendar (if DTSTART is on Saturday and generally for any every 2nd week but not the last week rule for any day of week specified by the DTSTART):
RRULE:FREQ=WEEKLY;INTERVAL=2;BYMONTHDAY=-8,-9,-10,-11,-12,-13,-14,-15,-16,-17,-18,-19,-20,-21,-22,-23,-24,-25,-26,-27,-28,-29,-30,-31
See test calendar:
https://calendar.google.com/calendar/u/0?cid=ZXBwdWE4N2RwZm5xODVic3JydDJzaXFsY3NAZ3JvdXAuY2FsZW5kYXIuZ29vZ2xlLmNvbQ
Spec: https://datatracker.ietf.org/doc/html/rfc2445#page-43
and
https://icalevents.com/2447-need-to-know-the-possible-combinations-for-repeating-dates-an-ical-cheatsheet/ for the expansion & contraction (limiting) rules & combinations
Just wondering if there is a way to schedule a timer for the first business day of every month?
Basically the first day of every month which is not a weekend.
I am trying to avoid creating a wrapper script if possible
[Timer]
OnCalendar=Mon..Fri *-*-1..3 00:00:00
This executes the service
only if it is a business day
only the first 3 days of the month
The intersection of these directives leads to the first business day (Monday to Friday) of every month.
Examples:
Day 1 is Saturday, day 2 is Sunday, day 3 is Monday. Script runs the 3rd
Day 1 is Sunday, day 2 is Monday. Script runs the 2nd
Day 1 is Thursday. Script runs the 1st
Source: ArchWiki
I need help on calculating my start date for my report date parameters.
The end date will always be the last Sunday, here: =DateAdd("d", 1 - WeekDay(Today(), 1), Today())
What I need help with is how to write a formula to go back 6 months from today and pick the 1st Saturday in that range..
Thanks in advance.
Assuming your start day is a Sunday then you can use this...
=DATEADD(
DateInterval.Day,
7 - WEEKEDAY( DATEADD(DateInterval.Month,-6,Today()), FirstDayOfWeek.Sunday),
DATEADD(DateInterval.Month,-6,Today())
)
This works as follows
WEEKEDAY( DATEADD(DateInterval.Month,-6,Today()), FirstDayOfWeek.Sunday)
Takes today's date, subtracts 6 months and then finds out what daynumber that is. Running that today (2018-11-08) gives use (2018-05-10) which is a Thursday, this is day number 5
Saturdays are day number 7 (if your first day of week is a Sunday). As there can be no higher number than 7 we can do a simple subtraction of 7 minus the day number we landed on (from above) which gives us a required adjustment of 2 days.
Finally the outer DATEADD function simply says add our calculated 2 days to the date 6 months ago.
Hope that makes sense!?
If the first day of the week is not a Sunday for you then you may have to do some Mod% calc on the second argument to calculate the correct number of days to adjust by.
I have a recurring calendar event on 1st of each month, when 1st falls on Sat/Sun is it possible for iCal to schedule it for last working day Fri?
If I understood you correctly the following RRULE should do the trick:
FREQ=MONTHLY;BYDAY=1MO,1TU,1WE,1TH,1FR,-1FR;BYMONTHDAY=1,-1,-2
See the next 100 instances
It basically does two things:
Iterate the first weekday that falls on the 1st day of the month
Iterate the last Friday of each month that falls on the last or 2nd last day of the month (in which cases the 1st of the next month falls on Saturday or Sunday).
A slightly shorter version that should yield the same results is
FREQ=MONTHLY;BYDAY=1MO,1TU,1WE,1TH,FR;BYMONTHDAY=1,-1,-2
This just iterates every Friday, but only keeps the ones that fall on the first, last and 2nd last day of each month. Though it looks like the recurrence expansion service above disagrees. That's probably a bug.
I'm assuming you mean "the last working day Friday of the previous month", in which case I don't think it possible. It would mean that some months have 2 occurrences when others have 0, which doesn't really work.
You could easily do the first working day of the month (the 1st, or the first Monday):
FREQ=MONTHLY;BYDAY=MO,TU,WE,TH,FR;BYSETPOS=1
Or, you could do always the last working day of the month:
FREQ=MONTHLY;BYDAY=MO,TU,WE,TH,FR;BYSETPOS=-1
Is there a function in Haskell that will allow me to enter component of a date (like a string representation or day month year components) that I can get information from (like day of week, days in a month, etc.)?
I've looked online and it looks like there are a lot of custom libraries, but I'm hoping there's one in the standard prelude library of ghci 10.6.4 that's just not well documented?
Are Data.Time.Calendar and Data.Time.Format in the time library sufficient?
You can parse a string representation of a date and get the length of a month using gregorianMonthLength. Not sure about day of the week, though you could format the date as a string using a format that just displays the week day.
A quick Google search turns up this, which may be what you want. It lets you parse strings representing dates and extract information from them.
You can find the day of the week with mondayStartWeek or sundayStartWeek, depending on whether you think a week starts on Monday, or on Sunday. Both functions are in Data.Time.Calendar.OrdinalDate.
λ> snd $ mondayStartWeek $ fromGregorian 2017 10 3
2
In the above example, the return value is 2, which indicates the second day of the week. Since the function is called mondayStartWeek, Monday is the first day, so 2 corresponds to Tuesday. This is true of October 3, 2017.
A warning regarding week numbers
Both functions return a tuple, where the second element is the week day. As far as I can tell, that should be trustworthy.
The first element, however, is the week number of the year. Be careful with that, because the rules for week numbering are political. If I remember correctly, in USA, week 1 is the week that contains January 1. That's not the case in Denmark, where I live. Here, week 1 is the first week where Thursday falls in the new year. This can mean that December 31 can fall in week 1 of the next year. IIRC, this is the rule for many other European countries. Some years, the American and the European week numbers align, but some years, they don't.