Just wondering if there is a way to schedule a timer for the first business day of every month?
Basically the first day of every month which is not a weekend.
I am trying to avoid creating a wrapper script if possible
[Timer]
OnCalendar=Mon..Fri *-*-1..3 00:00:00
This executes the service
only if it is a business day
only the first 3 days of the month
The intersection of these directives leads to the first business day (Monday to Friday) of every month.
Examples:
Day 1 is Saturday, day 2 is Sunday, day 3 is Monday. Script runs the 3rd
Day 1 is Sunday, day 2 is Monday. Script runs the 2nd
Day 1 is Thursday. Script runs the 1st
Source: ArchWiki
Related
I need a Pipeline to trigger on the Monthend week (Tues, Wed, Thurs and Friday) of a month.
Monthend is defined as,
"Last but one" Friday Or
Second Friday from the end of the month.
For Example, For month of June 2021, 18th is the Monthend (Orange color as shown in the image)
Calendar Image
If its just on Monthend i.e. Second Friday from the end of calendar month, its easy. Just use Occurrance as -2 and day as Friday in the Scheduled trigger and add to a pipeline to trigger,
"schedule": {
"monthlyOccurrences": [
{
"day": "Friday",
"occurrence": -2
}
]
}
but I also need to run on the Tues, Wed and Thurs of the same week, which I find it difficult as these weekdays can be second or third from the end of the calendar month. For example: For June 2021, as shown in the image, I also need to run on 15th (Third Tuesday from the end of calendar month), 16th (Third Wednesday from the end of calendar month), 17th (Second Thursday from the end of calendar month).
Can you let me know if this can be implemented using triggers of Azure data factory? If not, any otherways of implementing? Thank You!
The scheduled trigger alone is not capable of that logic (as of 2021-05-04). Easiest solution would be to use some other scheduling application.
For a purely Data-Factory solution, schedule the trigger for all the days the desired days could possibly occur on. Then modify the pipeline to do logic to determine whether the current day is actually one of the desired days.
Implementation details and sample code
The logic:
Find the last day of the month (First of the next month less 1 day).
Subtract a week so you are in the second-to-last week
Loop over [0,-1,-2,-3,-4,-5,-6] as number of days to add to the date. This produces the dates of each day of the week.
Use the dayOfWeek function to change the date into which day of the week it is
Filter to get the Friday date
Ask whether today is between the Friday date and Friday date - 3 days
We have a event every year on the weekend (Fr-Su) that includes the first Sunday of June. How would I create a iCalendar Event that expresses these three days (whole day events)?
Creating a rule for the first Sunday is easy. But for the Saturday and Friday, I did not succeed to create a rule that counts backwards (RFC 5545 says INTERVAL, COUNT must be positive]. Moreover I could not think of a different expression that would start from the Friday - it could be the last Friday of May, but also the first in June.
The RRRULE specification in RFC 5545 is lacking in this regard. The INTERVAL and COUNT values are for the repeating events, not the event itself. I've come across a similar issue when trying to define the USA day "Black Friday", the day after the 4th Thursday in November (Friday after Thanksgiving). The 4th Friday in November could occur the day after the 4th Thursday, or the prior week. There is not a way that I have found to make a RRULE for this situation.
I believe you will need to code the events individually instead of using a recurring rule.
RRULE:FREQ=YEARLY;BYDAY=FR;BYMONTH=5,6;BYSETPOS=2;BYMONTHDAY=-2,-1,1,2,3,4,5,6,7' seems to do the trick.
How can I write an ICS file for the Friday before the first Saturday of the month? led me to the right track: with 'BYMONTHDAY' I can count backwards from the end of the month.
The Friday before the first Sunday of the next month can be the last or the second to last day of the previous month, or up to the 5th day of the month. If I include May and June, I will get a set that includes the day. 'BYSETPOS' allows me to choose the second of the found Fridays. To always have the second in the set being my desired day, I include the 6th and 7th day of the month, which gives me a stable first Friday in May. Possibly matched additional Fridays in June are discarded by 'BYSETPOS' anyway.
Extending this to Saturday is simple, and the first Sunday of June is trivial.
I developed the rule with rrule.js
https://jakubroztocil.github.io/rrule/#/rfc/RRULE:BYDAY=FR;BYMONTH=5,6;BYSETPOS=2;BYMONTHDAY=-2,-1,1,2,3,4,5,6,7
I have a recurring calendar event on 1st of each month, when 1st falls on Sat/Sun is it possible for iCal to schedule it for last working day Fri?
If I understood you correctly the following RRULE should do the trick:
FREQ=MONTHLY;BYDAY=1MO,1TU,1WE,1TH,1FR,-1FR;BYMONTHDAY=1,-1,-2
See the next 100 instances
It basically does two things:
Iterate the first weekday that falls on the 1st day of the month
Iterate the last Friday of each month that falls on the last or 2nd last day of the month (in which cases the 1st of the next month falls on Saturday or Sunday).
A slightly shorter version that should yield the same results is
FREQ=MONTHLY;BYDAY=1MO,1TU,1WE,1TH,FR;BYMONTHDAY=1,-1,-2
This just iterates every Friday, but only keeps the ones that fall on the first, last and 2nd last day of each month. Though it looks like the recurrence expansion service above disagrees. That's probably a bug.
I'm assuming you mean "the last working day Friday of the previous month", in which case I don't think it possible. It would mean that some months have 2 occurrences when others have 0, which doesn't really work.
You could easily do the first working day of the month (the 1st, or the first Monday):
FREQ=MONTHLY;BYDAY=MO,TU,WE,TH,FR;BYSETPOS=1
Or, you could do always the last working day of the month:
FREQ=MONTHLY;BYDAY=MO,TU,WE,TH,FR;BYSETPOS=-1
What ical RRULE lets me choose the second (not necessarily full) week of January (for example)?
More specifically, the Sunday that starts the second week of January?
Usually, "1SU" would work, but if the month starts with Sunday itself, it would be "2SU", so I don't see an obvious solution here?
If you want the Sunday that starts the second week in January, you have to say that that Sunday can be any month day except the first (and obviously, only can be below the 8th day of the month).
The way to do this is to specify a RRULE with FREQ=YEARLY;BYMONTH=1 to specify January, BYDAY=SU to specify Sundays, BYMONTHDAY=2,3,4,5,6,7,8 to specify that your Sunday cannot be the 1st of the month and that you are only interested in the one starting the 2nd week of the month.
To summarize:
RRULE:FREQ=YEARLY;BYMONTH=1;BYDAY=SU;BYMONTHDAY=2,3,4,5,6,7,8
I am having trouble understanding how dates and days work together in a cron job.
Say I have the following command:
0 23 5 1 3 COMMAND
This translates to 23:00, on 5th of January, on Wednesday.
The problem is, that January 5th is a Sunday. How exactly will this command work out? Is the command going to be executed for both January 5th AND for every Wednesday on the month January? Or will it execute just the '5 1' bit?
I am really sorry if it is a really basic question and possibly stupid but to me it really does not make any sense.
Thank you in advance!
Commands are executed by cron when the minute, hour, and month of year fields match the current time, and at least one of the two day fields (day of month, or day of week) match
Ref: Man Page