How to format date in SQLite to get like 10-Jan-2014. What formatting string I need.
I have seen this SQLite date formatting and other questions but did not find my answer.
The given link formats the date to only numeric like 2014-01-10 etc.
Any one know?
Month names are not supported in SQLite.
You can use a lookup table to make and get your desired format with month names directly from query.
You can also write your own formatting function in your programming language.
Related
I'm using previously written scripts that have the date format in the WHERE clause as 'DD-MMM-YY', however, in the table it is formatted as 'DD-MMM-YY HH.MM.SS.000000000 AM/PM. Does it matter that these formats do not match up? After comparing results it doesn't seem like any data is missing using non-matching formats. Wasn't sure if efficiency would be different if they matched or didn't match? Just let me know your thoughts and opinions. Thanks all!
Your where clause is fine. The table formatting is just a representation of the date. You can change this if it helps you view the results more easily (see link below), but it will make no difference to the efficiency of the query.
How can I set a custom date time format in Oracle SQL Developer?
I have a decimal date field (TDDATR) that is in the YYYYMMDD format.
I would like to create a field that is TDDATR + 30 days but I am unable to.
Using 'Define Results Field' I have tried a few things;
Simply doing this;
TDDATR + 30 DAYS
But it returned this error: Labeled duration not used correctly.
I tried using the DIGITS and SUBSTR commands to create a field in the DDMMYYYY format and then +30 days but got the same error.
Same as above but in the DD/MM/YYYY format - same error.
Using DATE(TDDATR) but all I see is +'s in the field.
Using DATE( ) on the fields created in step 2 and 3 - still get +'s
I've ran out of ideas - any help would be greatly appreciated.
Query/400 lacks a lot of the features that an SQL based interface has.
I'd urge you to consider switching to Query Manager (STRQM) which is a fully SQL based product. You can even convert Query/400 queries to Query Manager queries with the RTVQMQRY command by having the ALWQRYDFN parm set to *YES.
The other option that IBM is pushing is Web Query. Again, fully SQL based and you can convert Query/400 queries into it.
Having said that, the problem is that FLD + 30 DAYS only works when FLD is a DATE data type. Query/400 includes a DATE() function to convert non-date types into date. But it's very limited in that it only works with character fields formatted according to your job defaults. Assuming you're in the US, it'd only work with a character value of '07/01/15'.
You could do a lot of manipulation in Query/400 and end up with a result field that meets DATE()'s requirements. But a better solution would be to create an SQL view over your table and have your numeric date converted into a date data type in the view.
You can find code examples that show how to convert a numeric YYYYMMDD to a actual date data type in the view. However, I'd recommend create a user defined function (UDF) that will do the conversion for you. That will make it much easier to use in the view and to reuse in other places.
If you'd like, there's an open source package called iDate, that includes all the code required for convert to/from date data types.
Download that, install/compile it and your SQL view becomes
select ... idate(TDDATR,'*CCYMD') as TD_DATE
from myfile
The use of days is as follow
Field Expression
CURDATE_30 days(current(date)) + 30
The solution to your problem is: given the field A dec(8,0)
Field Expression
YYYYMMDD_ date(substr(digits(a),5,2)||'/'||
substr(digits(a),7,2)||'/'||
substr(digits(a),3,2))
NEXT_MONTH DAYS(YYYYMMDD_) + 30
Remember to check the date format in your job description. In the example the format is MDY or MM/DD/YY.
More info here
Based on the information here, I created the below 2 fields;
TDDIGI DIGITS(TDDATR)
TDDAT1 SUBSTR(TDDIGI,7,2)||'/'||
SUBSTR(TDDIGI,5,2)||'/'||
SUBSTR(TDDIGI,3,2)
From here I was able to create a date field;
TDDAT2 DATE(TDDAT1)
Which allowed me to perform the necessary calculations.
The format of TDDAT1 is based on your job description which can be found by;
WRKJOB
Option 2
Page down
Date format..: X
Mine was *DMY, so TDDAT1 was formatted based on this.
I have imported some data into SAS from some Excel spreadsheets sent to me. When I view the output from the imported table, the date appears as "01APR2014" and maintains chronological order. When I view the column properties the type is "Date" and the length is 8. Both the format and informat are DATE9.
I need to be able to convert this date to week-year and month-year, but no matter what I try I always get Jan, 1960.
Using proc sql, I used the below to get the week-year,
"(put(datepart(a.fnlz_date),weeku3.))|| "-" ||(put(datepart(a.fnlz_date),year.)) as FNLZD_WK_YR,"
but all I got was "W00-1960". I've used the formula above successfully many times before with SAS datetime values.
For month-yr, using proc sql, I tried
"datepart(a.fnlz_date) as DT_FNLZD format=monyy.,"
but the only value returned is "JAN60".
I also tried using SUBSTR, but got an error saying it requires a character argument, so SAS must see it as a number at least.
My question; does anyone know a way to get the week-yr and/or month-yr from this format? If so, how? I'm not opposed to using a data step, but I haven't been able to get that to work either.
Thanks in advance for any help or insight provided.
datepart converts datetimes to dates. Not helpful here.
If you're just displaying this, then you have a few options, particularly for month. You can just change the format of the variable (This changes what's displayed, but not the underlying value; consider this a value label).
When you use this like this (again, it looks like you got most of the way there):
proc sql;
select datevar format=monyy5. from table;
quit;
Just don't include that datepart function call as that's not appropriate unless you have a datetime. (Date=# of days since 1/1/1960, Datetime = # of seconds since 1/1/1960:00:00:00).
That will display it with MONYY5. format, which would be MAY10 for May, 2010. You have some other format options, see the documentation on formats by category for more details.
I can't think of a Week format that matches what you want (there are week formats, like WEEKW., as you clearly found, but I don't know that they do exactly what you want. So, if you want to build one yourself, you can either build a custom picture format, or you can make a string.
Building a custom picture format isn't too hard; see the documentation on Picture formats or google SAS Date Picture Format.
proc format;
picture weekyear (default=8)
low-high = 'W%0U-%Y' (datatype=date) ;
quit;
Now you can use that as a normal format.
To get at the week/etc. to build values, you can also use functions week(), month(), etc., if that's easier.
Since the data was already in a date format, I only needed to drop the DATEPART function that only works with datetime values. So, for month-yr,
"a.fnlz_date as fnlz_mnth format=monyy.,"
gives me the results I'm looking for.
Cheers!
When importing a text file into Access 2007 with date/time values like
2014-07-02T16:09:49-07:00
Access is unable to convert to date and shows the same as text. How do I convert the same in to date/time in Access?
You will probably need to import the ISO 8601 date/time values into a Text field, then use an Update query to convert those string values and write them to a Date/Time field. The question
Parsing an ISO8601 date/time (including TimeZone) in Excel
has several answers that include VBA functions you might be able to adapt depending on your specific requirements (and possibly some slight differences in date handling between Excel and Access).
I've found several questions regarding SAS dates in this forum, but i haven't been able to find the answer to this one. I think it is rather simple, but i can't get it right.
I have a data set with a date (DD-MM-YYYY) which for some reason has a Character format. I would like it to be translated into a date format (YYYY-MM-DD). I can get it to 'look' right by by separating and concatenating the parts, but, then i can't get the format right.
Use the input() function with an appropriate informat:
datevariable=input(textvariable,ddmmyy10.);