I have a decimal date field (TDDATR) that is in the YYYYMMDD format.
I would like to create a field that is TDDATR + 30 days but I am unable to.
Using 'Define Results Field' I have tried a few things;
Simply doing this;
TDDATR + 30 DAYS
But it returned this error: Labeled duration not used correctly.
I tried using the DIGITS and SUBSTR commands to create a field in the DDMMYYYY format and then +30 days but got the same error.
Same as above but in the DD/MM/YYYY format - same error.
Using DATE(TDDATR) but all I see is +'s in the field.
Using DATE( ) on the fields created in step 2 and 3 - still get +'s
I've ran out of ideas - any help would be greatly appreciated.
Query/400 lacks a lot of the features that an SQL based interface has.
I'd urge you to consider switching to Query Manager (STRQM) which is a fully SQL based product. You can even convert Query/400 queries to Query Manager queries with the RTVQMQRY command by having the ALWQRYDFN parm set to *YES.
The other option that IBM is pushing is Web Query. Again, fully SQL based and you can convert Query/400 queries into it.
Having said that, the problem is that FLD + 30 DAYS only works when FLD is a DATE data type. Query/400 includes a DATE() function to convert non-date types into date. But it's very limited in that it only works with character fields formatted according to your job defaults. Assuming you're in the US, it'd only work with a character value of '07/01/15'.
You could do a lot of manipulation in Query/400 and end up with a result field that meets DATE()'s requirements. But a better solution would be to create an SQL view over your table and have your numeric date converted into a date data type in the view.
You can find code examples that show how to convert a numeric YYYYMMDD to a actual date data type in the view. However, I'd recommend create a user defined function (UDF) that will do the conversion for you. That will make it much easier to use in the view and to reuse in other places.
If you'd like, there's an open source package called iDate, that includes all the code required for convert to/from date data types.
Download that, install/compile it and your SQL view becomes
select ... idate(TDDATR,'*CCYMD') as TD_DATE
from myfile
The use of days is as follow
Field Expression
CURDATE_30 days(current(date)) + 30
The solution to your problem is: given the field A dec(8,0)
Field Expression
YYYYMMDD_ date(substr(digits(a),5,2)||'/'||
substr(digits(a),7,2)||'/'||
substr(digits(a),3,2))
NEXT_MONTH DAYS(YYYYMMDD_) + 30
Remember to check the date format in your job description. In the example the format is MDY or MM/DD/YY.
More info here
Based on the information here, I created the below 2 fields;
TDDIGI DIGITS(TDDATR)
TDDAT1 SUBSTR(TDDIGI,7,2)||'/'||
SUBSTR(TDDIGI,5,2)||'/'||
SUBSTR(TDDIGI,3,2)
From here I was able to create a date field;
TDDAT2 DATE(TDDAT1)
Which allowed me to perform the necessary calculations.
The format of TDDAT1 is based on your job description which can be found by;
WRKJOB
Option 2
Page down
Date format..: X
Mine was *DMY, so TDDAT1 was formatted based on this.
Related
I am very new to Azure Data Factory. I have created a simple Pipeline using the same source and target table. The pipeline is supposed to take the date column from the source table, apply an expression to the column date (datatype date as shown in the schema below) in the source table, and it is supposed to either load 1 if the date is within the last 7 days or 0 otherwise in the column last_7_days (as in schema).
The schema for both source and target tables look like this:
Now, I am facing a challenge to write an expression in the component DerivedColumn. I have managed to find out the date which is 7 days ago with the expression: .
In summary, the idea is to load last_7_days column in target Table with value '1' if date >= current date - interval 7 day and date <= current date like in SQL.I would be very grateful, if anyone could help me with any tips and suggestions. If you require further information, please let me know.
Just for more information: source/target table column date is static with 10 years of date from 2020 till 2030 in yyyy-mm-dd format. ETL should run everyday and only put value 1 to the last 7 days: column last_7_days looking back from current date. Other entries must recieve value 0.
You currently use the expression bellow:
case ( date == currentDate(),1, date >= subDays(currentDate(),7),1, date <subDays(currentDate(),7,0, date > currentDate(),0)
If we were you, we will also choose case() function to build the expression.
About you question in comment, I'm afraid no, there isn't an another elegant way for. To achieve our request, Data Flow expression can be complex. It may be comprised with many functions. case() function is the best one for you.
It's very clear and easy to understand.
I've pulled in data in Qlik Sense (cloud) from the Google Analytics connector. I'm trying to convert the standard date [ga_dateHourMinute] field to a more eligible date format.
The current format is YearMonthDayhHourMinute, for instance: 201810250004, I would like to convert this to the standard date format 2018-10-25 00:04:00. How do I do this? Answers concerning methods in the data load script or master formula's or variables are all welcome.
Click to see screenshot: left = current date format and right = desired date format
This is one approach:
DateAlter:
LOAD * INLINE [
Date
201810250004
];
DateAlter2:
LOAD
Date(Date#([Date], 'YYYYMMDDhhmm') ,'YYYY-MM-DD hh:mm') AS [MyDateField]
Resident
DateAlter;
If you haven't played around with the data manager, it will allow you to edit fields and handle dates in a fairly easy manner:
Qlik Sense Data Manager
I ended up creating a text fields that combined the different digits from the one field into a new order, then pushed the data format into a date/time. Quite a bit of work, but fairly solid.
I am using cognos version 10 and I need my dates to display in this format 'yyyy-mm' but it is showing dates like '2014-04' as '2014-4' so it is reading the dates out of order by producing '2014-11' first because it starts with a one. I need to add a zero to those double digit integers that way the months(specifically) will display in order.
here's an the code I've created in attempt:
_year( start_date ) ||'-'|| _month( start_date )
IF(_month(start_date) > 10)
THEN('0' +_month(start_date))
Short answer: Use yyyy-MM.
Your question lacks a lot of detail, so my response is based on considerable guess-work.
Are you asking about formatting, or do you want to transform the values? Formatting can be done without code. The code for your data item should be start_date.
Is this for a List column body? Where do you enter your format (yyyy-mm)? Are you using the Data format property?
In the Data format dialog, if you can't find another setting that will do what you want, you can enter a pattern into the Pattern property. If you look at the tips at the bottom of the Data format dialog, you'll notice that using yyyy-mm would give you a four digit year, a hyphen, and a two-digit minute. Perhaps you should try yyyy-MM. It works for me.
As for sorting: Even if you used yyyy-M for the pattern, 2014-04-22 (displayed as 2014-4), should sort before 2014-11-01 (displayed as 2014-11). The only reason the sort would be wrong is if it is using some other data besides the dates.
I am building a map in CartoDB which uses Postgres. I'm simply trying to display my dates as: 10-16-2014 but, haven't been able to because Postgres includes an unneeded timestamp in every date column.
Should I alter the column to remove the timestamp or, is it simply a matter of a (correct) SELECT query? I can SELECT records from a date range no problem with:
SELECT * FROM mytable
WHERE myTableDate >= '2014-01-01' AND myTableDate < '2014-12-31'
However, my dates appear in my CartoDB maps as: 2014-10-16T00:00:00Z and I'm just trying to get the popups on my maps to read: 10-16-2014.
Any help would be appreciated - Thank you!
You are confusing storage with display.
Store a timestamp or date, depending on whethether you need time or not.
If you want formatted output, ask the database for formatted output with to_char, e.g.
SELECT col1, col2, to_char(col3, 'DD-MM-YY'), ... FROM ...;
See the PostgreSQL manual.
There is no way to set a user-specified date output format. Dates are always output in ISO format. If PostgreSQL let you specify other formats without changing the SQL query text it'd really confuse client drivers and applications that expect the date format the protocol specifies and get something entirely different.
You have two basic options.
1 Change the column from a timestamp to a date column.
2 Cast to date in your SQL query (i.e. mytimestamp::date works).
In general if this is a presentation issue, I don't usually think that is a good reason to muck around with the database structure. That's better handled by client-side processing or casting in an SQL query. On the other hand if the issue is a semantic one, then you may want to revisit your database structure.
I have imported some data into SAS from some Excel spreadsheets sent to me. When I view the output from the imported table, the date appears as "01APR2014" and maintains chronological order. When I view the column properties the type is "Date" and the length is 8. Both the format and informat are DATE9.
I need to be able to convert this date to week-year and month-year, but no matter what I try I always get Jan, 1960.
Using proc sql, I used the below to get the week-year,
"(put(datepart(a.fnlz_date),weeku3.))|| "-" ||(put(datepart(a.fnlz_date),year.)) as FNLZD_WK_YR,"
but all I got was "W00-1960". I've used the formula above successfully many times before with SAS datetime values.
For month-yr, using proc sql, I tried
"datepart(a.fnlz_date) as DT_FNLZD format=monyy.,"
but the only value returned is "JAN60".
I also tried using SUBSTR, but got an error saying it requires a character argument, so SAS must see it as a number at least.
My question; does anyone know a way to get the week-yr and/or month-yr from this format? If so, how? I'm not opposed to using a data step, but I haven't been able to get that to work either.
Thanks in advance for any help or insight provided.
datepart converts datetimes to dates. Not helpful here.
If you're just displaying this, then you have a few options, particularly for month. You can just change the format of the variable (This changes what's displayed, but not the underlying value; consider this a value label).
When you use this like this (again, it looks like you got most of the way there):
proc sql;
select datevar format=monyy5. from table;
quit;
Just don't include that datepart function call as that's not appropriate unless you have a datetime. (Date=# of days since 1/1/1960, Datetime = # of seconds since 1/1/1960:00:00:00).
That will display it with MONYY5. format, which would be MAY10 for May, 2010. You have some other format options, see the documentation on formats by category for more details.
I can't think of a Week format that matches what you want (there are week formats, like WEEKW., as you clearly found, but I don't know that they do exactly what you want. So, if you want to build one yourself, you can either build a custom picture format, or you can make a string.
Building a custom picture format isn't too hard; see the documentation on Picture formats or google SAS Date Picture Format.
proc format;
picture weekyear (default=8)
low-high = 'W%0U-%Y' (datatype=date) ;
quit;
Now you can use that as a normal format.
To get at the week/etc. to build values, you can also use functions week(), month(), etc., if that's easier.
Since the data was already in a date format, I only needed to drop the DATEPART function that only works with datetime values. So, for month-yr,
"a.fnlz_date as fnlz_mnth format=monyy.,"
gives me the results I'm looking for.
Cheers!