In polymer I'm trying to manually submit a form. My form looks like this:
<form id="myForm" on-submit="{{ submitForm }}">
<input class="text" value="{{ someValue}}">
<button type="submit">Submit</button>
</form>
And in the polymer object I have:
submitForm: function(e) {
e.preventDefault();
}
Whenever I try to do the following:
document.getElementById('myForm').submit();
the form totally ignores the on-submit attribute and posts the form to a new page.
I'm building a on-screen keyboard for anyone wondering why I would want to do this. I need to submit the form whenever someone hits the enter key on the on-screen keyboard.
Does anyone know why this happens?
A JSBin example to show you the exact problem (see the alerts): http://jsbin.com/wadihija/2/
From the MDN page about submit:
The form's onsubmit event handler will not be triggered when invoking this
method ... it is not guaranteed to be invoked by HTML user agents.
However, calling click on a submit type button seems to work. See here:
http://jsbin.com/tuxac/2/edit
Here is a modification of your jsbin that I believe does what you want:
http://jsbin.com/wadihija/6/edit
Is this along the lines of what you're trying to do? This is a result of a key feature of Shadow DOM: Encapsulation. The elements in your polymer-element's template are not in the main document, and as such, are not available via document.getElementById() and the like.
You could instead call this.shadowRoot.getElementById() and it would work because this inside of your polymer-element's prototype is linked to the host element. Or even better, take advantage of the amazing features Polymer gives you for free. Polymer exposes this.$ to polymer-elements, which contains a key for every element in your template that has an ID! No method call needed, just use this.$.myForm.submit(). Here's the final jsbin.
Related
I am trying to implement a payment module in ember. I have created a form and on the form action have assigned the server address to which form will be submitted.
<form action="https://api.mondido.com/en/v1/transactions" id="payment_form">
In simple jquery I am supposed to do something like this
var onSuccess = function(transaction){
alert(transaction.id);
};
var onError = function(error){
alert(error.description);
}
$('#my_form').mondido({type:"ajax", success:onSuccess, error:onError});
But I want to wrap it around in some action in the controller. The problem is when I do something like this
<form action="https://api.mondido.com/en/v1/transactions" id="payment_form" action{{someFunction on="submit"}}>
the action is being called twice. I have to click on the submit button twice to get it going in the first attempt and then it is being submitted twice.
Any thoughts how to go around with it?
Its probably because you have two actions defined in your form. Try to remove
action="https://api.mondido.com/en/v1/transactions"
from your form tag, and handle the form submission in your controller.
I have one search form with search button and some field, when I put value in form field and click on search button then come back on form by clicking on link(modify search form) then form value does not reset...Please check it here(http://dev.viawebgroup.com/search/)
Thanks
Try this:
<script>
function test(){
var input = document.getElementById('search');
input.value = '';
};
</script>
Add onload to the body:
<button onclick="test()">Clear</button>
Add id to input field:
<input type="text" id="search">
Fatal flaw rests form befor data is sent
The simplest way I found is
onsubmit="this.reset()"
Just put this in the form tag and all's well, simple yet efective.
I someone wanted a button excluesivly for form reset I would use onclick and write the reset in a function like this.
function clform()
{
documentgetElementById('myform').reset();
}
The first is tried and true, the second I just wrote but should work.
The function works well used in a onbeforeunload event in the body.
I have been working on this problem my self because the page I wrote is dynamically updated and was keeping form data when back button of browser was used. I also used PHP to reload the page after submission and onfocus to reload the page when form is selected so input is on a fresh page and not the dynamically updated page.
I am trying to add a few "next" and "back" buttons to a form. The Idea is to divide the filling-out process into several steps and with these buttons, the div of the current step gets hidden and the next resp. previous step is displayed.
My Problem is that when I add buttons in the following way...
<button class="proceed_button" id="loan_information">Proceed</button>
<button class="cancel_button" id="loan_information">Cancel</button>
... they submit the form.
Is every button inside a form-tag considered to be a submit-button?
If so, how can I change this behavior?
If not, why are they doing it then?
Ok, the solution is that the button needs a type.
<button type="button" class="proceed_button" id="loan_information">Proceed</button>
<button type="button" class="cancel_button" id="loan_information">Cancel</button>
Like this, it won't submit the form anymore.
According to http://w3schools.com/html5/att_button_type.asp the default type is depending on the browser, so you should always specify the type.
I'm not sure that you want a button, maybe you want it to look like a button. Either way, refer to this post: rails 3: display link as button?
Once you have your button, you'll need to update your javascript to prevent anything from happening when it's clicked (assuming you have jquery). It's still nice to provide a real fallback for those dinosaurs without js, so assuming your proceed button submits for users without js, for those with js you'd do something like:
$('#proceed_button').click(function(e) { e.preventDefault(); // Show and hide your divs here });
Also note that in your posted code you should not have two buttons with the same id, your ids and classes look swapped.
I have a dynamic form that is to be displayed using an iPad.
This form has a couple of radio buttons and some text fields and one submit button.
In an iPad the virtual keyboard GO button is supposed to act ad the enter key, causing the first submit button in the form to be clicked and the form to be posted.
To avoid excessive involuntary postings before the form is complete we added an extra submit button higher up in the form, absolutely positioned outside of the visible area with onclick="return false;".
This hijacks the enter keystroke preventing accidental posting in every browser except Safari Mobile.
On an iPad we even tested Opera mobile and it works as expected.
But Safari Mobile apparently ignores the return false since event clicking the button causes a post that no other browser does, not even safari on PC.
My questions are
1: Why is safari mobile ignoring "return false" on submit, is there an other mechanism at play here?
2: How can I stop Safari mobile from posting the form when clicking GO?
I have made numerous searches on Google and Stackoverflow and found many examples but all requires a lot of javascript and event binding and the dynamic nature of the form along with user generated content makes this error prone and pretty complex since almost all required binding events to every textbox and textarea.
Any solution that works is good but the simpler the better, especially if it does not require to much customization of the form or events that might conflict with autocomplete or validation events.
Example testpage: http://lab.dnet.nu/ipad.php
I found a solution to my problem.
The base to the problem is that Safari mobile ignores onsubmit="return false" on buttons, it only works on forms.
Setting onsubmit="return false;" on the form, making a normal button (not submit) and setting onclick="form.submit()".
Ex.
<form method="post" onsubmit="return false;">
... //Other fields here
<input type="button" value="Send" onclick="form.submit();" />
</form>
The Go button does not trigger a normal button, only submit buttons.
Since the form has onsubmit="return false;" it will not post.
The button on the other hand, when clicked triggers the onclick="form.submit();" which overrides the onsubmit on the form.
This solution seems to work in any browser reliably.
Better answer is this. The other does not allow you to use a regular submit button. This attacks just the go button.
$("body").keydown(function(){
if(event.keyCode == 13) {
document.activeElement.blur();
return false;
}
});
Seems very unconventional, as this basically breaks general UX and expected device behaviour.
However, I think it also important to mention that this solution relies on the actual <form> DOM element. Meaning the onclick handler on the button should not use a jQuery object to submit but the DOM element.
jQuery object. Does not work:
<input type="button" value="Send" onclick="$("#myform").submit();" />
DOM element. Works:
<input type="button" value="Send" onclick="$("#myform").get(0).submit();" />
Without jQuery. Works:
<input type="button" value="Send" onclick="document.getElementById('myform').submit();" />
Also, here is a similar approach, using jQuery to intercept keyboard submits and only allowing clicks on a button. Credit goes to #levi: http://jsfiddle.net/RsKc7/
Here's an additional answer, in case anyone winds up chasing this issue like I did.
Provided you're using jQuery, the following snippet should prevent the "Go" button from triggering a form submission (at least it does on Nexus 7's Chrome on Android 4.2.2; YMMMV). Also, note that if you want to allow the "Enter" key to work on any of the input types below, this will prevent that from happening.
$(document.body).on('keydown', 'input:text, input[type=password], input[type=email]',
function (e) {
// Android maps the "Go" button to the Enter key => key code 13
if (e.keyCode == 13) {
return false;
}
});
Edit: It seems this bug breaks keyup/keydown in Chrome in Android > 4.3, in which case this fix will no longer work in some circumstances.
Cannot comment so i have to put a new message.
#David solution works fine if we are using an "input type button"; instead, if we are using a button tag doesn't seems to be solved by David fix.
(env: cordova, ipad mini 2)
Thanks David!
Go buttons and return buttons on mobile touch screen keyboards trigger the onclick event of your first submit button. To determine if its the user or script clicking the button, you can use the following:
$('#mybuttonId').onclick(e) {
if (e.screenX && e.screenX != 0 && e.screenY && e.screenY != 0) {
//This is the user clicking on the button.
} else {
//This is not the user, but a script , do nothing.
return false;
}
}
Hi i have a few form fields i want the on click of button a the control to be sent to action 1 but
on click of button 2 it has to be sent to action 2. Currently i am using js to change the form action dynamically on click. but is there any other solution. I cant do the checking after submit in a same method thet have to be two different methods.
The 2 buttons in this case are view(html data needs to be displayed) and download(same data as csv file). I am using cakephp 1.2 but i feel this is more of a generic problem
One form can only have one action. This is a limitation of HTML. To work around it on the client-side, you need Javascript.
It sounds like the better idea would be to give each submit button a distinctive name and value. This will be submitted like other form elements, so you can detect in the Controller which button was clicked. From there it should only be a matter of switching some View logic in the controller between normal output and download.
I found out there are few solutions
Regular JavaScript to change th form action on click of the buttons
AJAX to send the data to two separate actions on click of separate buttons
As suggested by deceze to do the processing on server side(which was not easily possible in my case)
HTML5 has a formaction attribute for this
<form action="/url" id="myForm">
<input type="submit" value="save1" formAction="/url1" />
<input type="submit" value="save2" formAction="/url2" />
</form>
Here is a fallback if you need it.
if (!('formAction' in document.createElement('input'))){
$('form').on('click', 'input[type=submit]', function (e) {
var attr = this.getAttribute('formAction');
if (attr) {
this.action = attr; //Set the form's action to formAction
}
});
}