MongoDB reducing db filesize - mongodb

I have a replica-set.
And I run out of disk space on my secondary instances.
There is no space on disk to run db.repairDatabase()
Is there any other way to free some disk space?
I was thinking:
bring secondary down
Delete all data
run db.repairDatabase() if deleting data will allow it
Bring it back up.
WIll this work?
UPDATE
Worth to mention that I can't currently SSH to servers. Only using mongo client now.

No that won't work - there has to be a database there to run db.repairDatabase() on. However, what works just as well is to bring the secondary down, delete the database files and then bring it back it up. This will force a re-sync with the primary which will in effect do the same thing as a db.repairDatabase() as it will recreate the data files from scratch.
However, in order to delete the datafiles you'll need to ssh in to the instance. If you cannot ssh in you have fairly significant issues that will interfere with any attempt to recover the secondary.

Related

How to Backup from mongoDB without locking tables

There is a Replica set (primary, secondary, arbiter) with 300GB data. i want to make daily backup without lock. The Replica is placedWe use Windows 2008R2, so seems not possible to use lvm tools.
If i want to make folder copy on secondary, it needed to shut down mongod first (because its not possible copy mongod.lock while mongod is running).
What is the best solution to make fastest daily backup
I don't know if it is feasible for you, but you can add another member to replica set. This member would be hidden, so it would not be used for queries or writing operations. You can stop this server every day for make your database backups.
because it is a replicate cluster i use mongodump with the --oplog option. runs pretty quick on linux. and i think it may have some advantages in a multi tenant server over over tar or snap. disadvange is that the indexes are built when you do the mongorestore

Why and what case to issue mongodb repair command

I am using Mongodb 2.4.8 on a 64 bit machiene with 3 servers as replicaSet, for which i have currently disbaled journaling on my development box .
Durabilty is not so important for our Application , so the reason i have disabled Journaling Option .
I see that there is only one advantage of journaling , that is in case of an unclean shutdown we dont have to issue a repair command as journaling will take care of it .
To produce this unclean shutdown i killed mongo replica process using kill -9 Mongo process Id , i just removed mongo locks and restarted the mongo primary , secondary and the arbitery servers , everything started fine .
My question is that , when i should we issue the repair command actually (as removing locks and restart works )
Please excuse if the question is too dumb , as i wanted to know the risk of disbaling journaling under production .
The repairDatabase command checks your whole database for corrupted data and discards that data so the rest becomes usable again.
This can become necessary after an unclear shutdown. In your case the shutdown didn't appear to corrupt any data (or maybe it did, but it didn't become apparent yet because the data in question wasn't accessed yet). But that doesn't mean that this will always be the case. Was your database actually doing anything at that moment? When the database is idle or only performing read-operations, there is usually not much to worry about. But when it is currently in the middle of a large write-operation, a sudden shutdown without journaling can be much more troublesome.
Another scenario where a database could be corrupted and repairDatabase could help is a physical malfunction of the storage medium or a corruption of the underlying filesystem.
Important note regarding replica-sets: When you have a replica-set, and only one node is corrupted, then you should rather remove that node and rebuild it from the other members of the replica-set. RepairDatabase will destroy any corrupted data. Restoring from a replica-set will not.

Mongodb EC2 EBS Backups

I have confusion on what I need to do here. I am new to Mongo. I have set up a small Mongo server on Amazon EC2, with EBS volumes, one for data, one for logs. I need to do a backup. It's okay to take the DB down in the middle of the night, at least currently.
Using the boto library, EBS snapshots and python to do the backup, I built a simple script that does the following:
sudo service mongodb stop
run backup of data
run backup of logs
sudo service mongodb start
The script ran through and restarted, but I noted in the AWS console that the snapshots are still being created, even through boto has come back, but Mongo has restarted. Certainly not ideal.
I checked the Mongo docs, and found this explanation on what to do for backups:
http://docs.mongodb.org/ecosystem/tutorial/backup-and-restore-mongodb-on-amazon-ec2/#ec2-backup-database-files
This is good info, but a bit unclear. If you are using journaling, which we are, it says:
If the dbpath is mapped to a single EBS volume then proceed to Backup the Database Files.
We have a single volume for data. So, I'm assuming that means to bypass the steps on flushing and locking. But at the end of Backup the Database Files, it discusses removing the locks.
So, I'm a bit confused. As I read it originally, then I don't actually need to do anything - I can just run the backup, and not worry about flushing/locking period. I probably don't need to take the DB down. But the paranoid part of me says no, that sounds suspicious.
Any thoughts from anyone on this, or experience, or good old fashioned knowledge?
Since you are using journaling, you can just run the snapshot without taking the DB down. This will be fine as long as the journal files are on the same EBS volume, which they would be unless you symlink them elsewhere.
We run a lot of mongodb servers on Amazon and this is how we do it too.

Auto compact the deleted space in mongodb?

The mongodb document says that
To compact this space, run db.repairDatabase() from the mongo shell (note this operation will block and is slow).
in http://www.mongodb.org/display/DOCS/Excessive+Disk+Space
I wonder how to make the mongodb free deleted disk space automatically ?
p.s. We stored many downloading task in mongodb, up to 20GB, and finished these in half an hour.
In general if you don't need to shrink your datafiles you shouldn't shrink them at all. This is because "growing" your datafiles on disk is a fairly expensive operation and the more space that MongoDB can allocate in datafiles the less fragmentation you will have.
So, you should try to provide as much disk-space as possible for the database.
However if you must shrink the database you should keep two things in mind.
MongoDB grows it's data files by
doubling so the datafiles may be
64MB, then 128MB, etc up to 2GB (at
which point it stops doubling to
keep files until 2GB.)
As with most any database ... to
do operations like shrinking you'll
need to schedule a separate job to
do so, there is no "autoshrink" in
MongoDB. In fact of the major noSQL databases
(hate that name) only Riak
will autoshrink. So, you'll need to
create a job using your OS's
scheduler to run a shrink. You could use an bash script, or have a job run a php script, etc.
Serverside Javascript
You can use server side Javascript to do the shrink and run that JS via mongo's shell on a regular bases via a job (like cron or the windows scheduling service) ...
Assuming a collection called foo you would save the javascript below into a file called bar.js and run ...
$ mongo foo bar.js
The javascript file would look something like ...
// Get a the current collection size.
var storage = db.foo.storageSize();
var total = db.foo.totalSize();
print('Storage Size: ' + tojson(storage));
print('TotalSize: ' + tojson(total));
print('-----------------------');
print('Running db.repairDatabase()');
print('-----------------------');
// Run repair
db.repairDatabase()
// Get new collection sizes.
var storage_a = db.foo.storageSize();
var total_a = db.foo.totalSize();
print('Storage Size: ' + tojson(storage_a));
print('TotalSize: ' + tojson(total_a));
This will run and return something like ...
MongoDB shell version: 1.6.4
connecting to: foo
Storage Size: 51351
TotalSize: 79152
-----------------------
Running db.repairDatabase()
-----------------------
Storage Size: 40960
TotalSize: 65153
Run this on a schedule (during none peak hours) and you are good to go.
Capped Collections
However there is one other option, capped collections.
Capped collections are fixed sized
collections that have a very high
performance auto-FIFO age-out feature
(age out is based on insertion order).
They are a bit like the "RRD" concept
if you are familiar with that.
In addition, capped collections
automatically, with high performance,
maintain insertion order for the
objects in the collection; this is
very powerful for certain use cases
such as logging.
Basically you can limit the size of (or number of documents in ) a collection to say .. 20GB and once that limit is reached MongoDB will start to throw out the oldest records and replace them with newer entries as they come in.
This is a great way to keep a large amount of data, discarding the older data as time goes by and keeping the same amount of disk-space used.
I have another solution that might work better than doing db.repairDatabase() if you can't afford for the system to be locked, or don't have double the storage.
You must be using a replica set.
My thought is once you've removed all of the excess data that's gobbling your disk, stop a secondary replica, wipe its data directory, start it up and let it resynchronize with the master.
The process is time consuming, but it should only cost a few seconds of down time, when you do the rs.stepDown().
Also this can not be automated. Well it could, but I don't think I'm willing to try.
Running db.repairDatabase() will require that you have space equal to the current size of the database available on the file system. This can be bothersome when you know that the collections left or data you need to retain in the database would currently use much less space than what is allocated and you do not have enough space to make the repair.
As an alternative if you have few collections you actually need to retain or only want a subset of the data, then you can move the data you need to keep into a new database and drop the old one. If you need the same database name you can then move them back into a fresh db by the same name. Just make sure you recreate any indexes.
use cleanup_database
db.dropDatabase();
use oversize_database
db.collection.find({},{}).forEach(function(doc){
db = db.getSiblingDB("cleanup_database");
db.collection_subset.insert(doc);
});
use oversize_database
db.dropDatabase();
use cleanup_database
db.collection_subset.find({},{}).forEach(function(doc){
db = db.getSiblingDB("oversize_database");
db.collection.insert(doc);
});
use oversize_database
<add indexes>
db.collection.ensureIndex({field:1});
use cleanup_database
db.dropDatabase();
An export/drop/import operation for databases with many collections would likely achieve the same result but I have not tested.
Also as a policy you can keep permanent collections in a separate database from your transient/processing data and simply drop the processing database once your jobs complete. Since MongoDB is schema-less, nothing except indexes would be lost and your db and collections will be recreated when the inserts for the processes run next. Just make sure your jobs include creating any nessecary indexes at an appropriate time.
If you are using replica sets, which were not available when this question was originally written, then you can set up a process to automatically reclaim space without incurring significant disruption or performance issues.
To do so, you take advantage of the automatic initial sync capabilities of a secondary in a replica set. To explain: if you shut down a secondary, wipe its data files and restart it, the secondary will re-sync from scratch from one of the other nodes in the set (by default it picks the node closest to it by looking at ping response times). When this resync occurs, all data is rewritten from scratch (including indexes), effectively do the same thing as a repair, and disk space it reclaimed.
By running this on secondaries (and then stepping down the primary and repeating the process) you can effectively reclaim disk space on the whole set with minimal disruption. You do need to be careful if you are reading from secondaries, since this will take a secondary out of rotation for a potentially long time. You also want to make sure your oplog window is sufficient to do a successful resync, but that is generally something you would want to make sure of whether you do this or not.
To automate this process you would simply need to have a script run to perform this action on separate days (or similar) for each member of your set, preferably during your quiet time or maintenance window. A very naive version of this script would look like this in bash:
NOTE: THIS IS BASICALLY PSEUDO CODE - FOR ILLUSTRATIVE PURPOSES ONLY - DO NOT USE FOR PRODUCTION SYSTEMS WITHOUT SIGNIFICANT CHANGES
#!/bin/bash
# First arg is host MongoDB is running on, second arg is the MongoDB port
MONGO=/path/to/mongo
MONGOHOST=$1
MONGOPORT=$2
DBPATH = /path/to/dbpath
# make sure the node we are connecting to is not the primary
while (`$MONGO --quiet --host $MONGOHOST --port $MONGOPORT --eval 'db.isMaster().ismaster'`)
do
`$MONGO --quiet --host $MONGOHOST --port $MONGOPORT --eval 'rs.stepDown()'`
sleep 2
done
echo "Node is no longer primary!\n"
# Now shut down that server
# something like (assuming user is set up for key based auth and has password-less sudo access a la ec2-user in EC2)
ssh -t user#$MONGOHOST sudo service mongodb stop
# Wipe the data files for that server
ssh -t user#$MONGOHOST sudo rm -rf $DBPATH
ssh -t user#$MONGOHOST sudo mkdir $DBPATH
ssh -t user#$MONGOHOST sudo chown mongodb:mongodb $DBPATH
# Start up server again
# similar to shutdown something like
ssh -t user#$MONGOHOST sudo service mongodb start

Reducing MongoDB database file size

I've got a MongoDB database that was once large (>3GB). Since then, documents have been deleted and I was expecting the size of the database files to decrease accordingly.
But since MongoDB keeps allocated space, the files are still large.
I read here and there that the admin command mongod --repair is used to free the unused space, but I don't have enough space on the disk to run this command.
Do you know a way I can freed up unused space?
UPDATE: with the compact command and WiredTiger it looks like the extra disk space will actually be released to the OS.
UPDATE: as of v1.9+ there is a compact command.
This command will perform a compaction "in-line". It will still need some extra space, but not as much.
MongoDB compresses the files by:
copying the files to a new location
looping through the documents and re-ordering / re-solving them
replacing the original files with the new files
You can do this "compression" by running mongod --repair or by connecting directly and running db.repairDatabase().
In either case you need the space somewhere to copy the files. Now I don't know why you don't have enough space to perform a compress, however, you do have some options if you have another computer with more space.
Export the database to another computer with Mongo installed (using mongoexport) and then you can Import that same database (using mongoimport). This will result in a new database that is more compressed. Now you can stop the original mongod replace with the new database files and you're good to go.
Stop the current mongod and copy the database files to a bigger computer and run the repair on that computer. You can then move the new database files back to the original computer.
There is not currently a good way to "compact in place" using Mongo. And Mongo can definitely suck up a lot of space.
The best strategy right now for compaction is to run a Master-Slave setup. You can then compact the Slave, let it catch up and switch them over. I know still a little hairy. Maybe the Mongo team will come up with better in place compaction, but I don't think it's high on their list. Drive space is currently assumed to be cheap (and it usually is).
It looks like Mongo v1.9+ has support for the compact in place!
> db.runCommand( { compact : 'mycollectionname' } )
See the docs here: http://docs.mongodb.org/manual/reference/command/compact/
"Unlike repairDatabase, the compact command does not require double disk space to do its work. It does require a small amount of additional space while working. Additionally, compact is faster."
I had the same problem, and solved by simply doing this at the command line:
mongodump -d databasename
echo 'db.dropDatabase()' | mongo databasename
mongorestore dump/databasename
Compact all collections in current database
db.getCollectionNames().forEach(function (collectionName) {
print('Compacting: ' + collectionName);
db.runCommand({ compact: collectionName });
});
If you need to run a full repair, use the repairpath option. Point it to a disk with more available space.
For example, on my Mac I've used:
mongod --config /usr/local/etc/mongod.conf --repair --repairpath /Volumes/X/mongo_repair
Update: Per MongoDB Core Server Ticket 4266, you may need to add --nojournal to avoid an error:
mongod --config /usr/local/etc/mongod.conf --repair --repairpath /Volumes/X/mongo_repair --nojournal
Starting with 2.8 version of Mongo, you can use compression. You will have 3 levels of compression with WiredTiger engine, mmap (which is default in 2.6 does not provide compression):
None
snappy (by default)
zlib
Here is an example of how much space will you be able to save for 16 GB of data:
data is taken from this article.
We need solve 2 ways, based on StorageEngine.
1. MMAP() engine:
command: db.repairDatabase()
NOTE: repairDatabase requires free disk space equal to the size of your current data set plus 2 gigabytes. If the volume that holds dbpath lacks sufficient space, you can mount a separate volume and use that for the repair. When mounting a separate volume for repairDatabase you must run repairDatabase from the command line and use the --repairpath switch to specify the folder in which to store temporary repair files.
eg: Imagine DB size is 120 GB means, (120*2)+2 = 242 GB Hard Disk space required.
another way you do collection wise,
command: db.runCommand({compact: 'collectionName'})
2. WiredTiger:
Its automatically resolved it-self.
There has been some considerable confusion over space reclamation in MongoDB, and some recommended practice are downright dangerous to do in certain deployment types. More details below:
TL;DR repairDatabase attempts to salvage data from a standalone MongoDB deployments that is trying to recover from a disk corruption. If it recovers space, it is purely a side effect. Recovering space should never be the primary consideration of running repairDatabase.
Recover space in a standalone node
WiredTiger: For a standalone node with WiredTiger, running compact will release space to the OS, with one caveat: The compact command on WiredTiger on MongoDB 3.0.x was affected by this bug: SERVER-21833 which was fixed in MongoDB 3.2.3. Prior to this version, compact on WiredTiger could silently fail.
MMAPv1: Due to the way MMAPv1 works, there is no safe and supported method to recover space using the MMAPv1 storage engine. compact in MMAPv1 will defragment the data files, potentially making more space available for new documents, but it will not release space back to the OS.
You may be able to run repairDatabase if you fully understand the consequences of this potentially dangerous command (see below), since repairDatabase essentially rewrites the whole database by discarding corrupt documents. As a side effect, this will create new MMAPv1 data files without any fragmentation on it and release space back to the OS.
For a less adventurous method, running mongodump and mongorestore may be possible as well in an MMAPv1 deployment, subject to the size of your deployment.
Recover space in a replica set
For replica set configurations, the best and the safest method to recover space is to perform an initial sync, for both WiredTiger and MMAPv1.
If you need to recover space from all nodes in the set, you can perform a rolling initial sync. That is, perform initial sync on each of the secondaries, before finally stepping down the primary and perform initial sync on it. Rolling initial sync method is the safest method to perform replica set maintenance, and it also involves no downtime as a bonus.
Please note that the feasibility of doing a rolling initial sync also depends on the size of your deployment. For extremely large deployments, it may not be feasible to do an initial sync, and thus your options are somewhat more limited. If WiredTiger is used, you may be able to take one secondary out of the set, start it as a standalone, run compact on it, and rejoin it to the set.
Regarding repairDatabase
Please don't run repairDatabase on replica set nodes. This is very dangerous, as mentioned in the repairDatabase page and described in more details below.
The name repairDatabase is a bit misleading, since the command doesn't attempt to repair anything. The command was intended to be used when there's disk corruption on a standalone node, which could lead to corrupt documents.
The repairDatabase command could be more accurately described as "salvage database". That is, it recreates the databases by discarding corrupt documents in an attempt to get the database into a state where you can start it and salvage intact document from it.
In MMAPv1 deployments, this rebuilding of the database files releases space to the OS as a side effect. Releasing space to the OS was never the purpose.
Consequences of repairDatabase on a replica set
In a replica set, MongoDB expects all nodes in the set to contain identical data. If you run repairDatabase on a replica set node, there is a chance that the node contains undetected corruption, and repairDatabase will dutifully remove the corrupt documents for you.
Predictably, this makes that node contains a different dataset from the rest of the set. If an update happens to hit that single document, the whole set could crash.
To make matters worse, it is entirely possible that this situation could stay dormant for a long time, only to strike suddenly with no apparent reason.
In case a large chunk of data is deleted from a collection and the collection never uses the deleted space for new documents, this space needs to be returned to the operating system so that it can be used by other databases or collections. You will need to run a compact or repair operation in order to defragment the disk space and regain the usable free space.
Behavior of compaction process is dependent on MongoDB engine as follows
db.runCommand({compact: collection-name })
MMAPv1
Compaction operation defragments data files & indexes. However, it does not release space to the operating system. The operation is still useful to defragment and create more contiguous space for reuse by MongoDB. However, it is of no use though when the free disk space is very low.
An additional disk space up to 2GB is required during the compaction operation.
A database level lock is held during the compaction operation.
WiredTiger
The WiredTiger engine provides compression by default which consumes less disk space than MMAPv1.
The compact process releases the free space to the operating system.
Minimal disk space is required to run the compact operation.
WiredTiger also blocks all operations on the database as it needs database level lock.
For MMAPv1 engine, compact doest not return the space to operating system. You require to run repair operation to release the unused space.
db.runCommand({repairDatabase: 1})
Mongodb 3.0 and higher has a new storage engine - WiredTiger.
In my case switching engine reduced disk usage from 100 Gb to 25Gb.
Database files cannot be reduced in size. While "repairing" database, it is only possible for mongo server to delete some of its files. If large amount of data has been deleted, mongo server will "release" (delete), during repair, some of its existing files.
In general compact is preferable to repairDatabase. But one advantage of repair over compact is you can issue repair to the whole cluster. compact you have to log into each shard, which is kind of annoying.
When i had the same problem, i stoped my mongo server and started it again with command
mongod --repair
Before running repair operation you should check do you have enough free space on your HDD (min - is the size of your database)
For standalone mode you could use compact or repair,
For sharded cluster or replica set, in my experience, after you running compact on the primary, followed by compact the secondary, the size of primary database reduced, but not the secondary.
You might want to do resync member to reduce the size of secondary database. and by doing this you might find that the size of secondary database is even more reduced than the primary, i guess the compact command not really compacting the collection.
So, i ended up switching the primary and secondary of the replica set and doing resync member again.
my conclusion is, the best way to reduce the size of sharded/replica set is by doing resync member, switch primary secondary, and resync again.
mongoDB -repair is not recommended in case of sharded cluster.
If using replica set sharded cluster, use compact command, it will rewrites and defragments all data and index files of all collections.
syntax:
db.runCommand( { compact : "collection_name" } )
when used with force:true, compact runs on primary of replica set.
e.g. db.runCommand ( { command : "collection_name", force : true } )
Other points to consider:
-It blocks the operations. so recommended to execute in maintenance window.
-If replica sets running on different servers, needs to be execute on each member separately
- In case of sharded cluster, compact needs to execute on each shard member separately. Cannot execute against mongos instance.
Just one way that I was able to do it. No guarantee on the safety of your existing data. Try with your own risk.
Delete the data files directly and restart mongod.
For example, with ubuntu (default path to data: /var/lib/mongodb), I had couple files with name like: collection.#. I keep the collection.0 and deleted all others.
Seems an easier way if you don't have serious data in database.