We're having a hierarchy of entity classes where all inherit from a BaseEntity #MappedSuperclass. Is there a way to have a spring-data "base repository" that allows you to query for any BaseEntity without having to know it's type and use a specific repository?
#MappedSuperclass
public class BaseEntity {
#Id
private Long id;
private String owner;
// setter/getter etc...
}
#Entity
public class FooEntity extends BaseEntity {
private String foo;
}
#Entity
public class BarEntity extends BaseEntity {
private String bar;
}
/**
* How to declare this base repository....
*/
public interface BaseRepository extends JpaRepository<BaseEntity, ActionPK> {
List<BaseEntity> findByOwner(String owner);
}
#Component
public class MyService {
#Autowired
private BaseRepository baseRepository;
public void doSomething() {
// ... so that is can be used like this:
List<BaseEntity> entities = baseRepository.findByOwner("john");
doSomethingWith(entities);
}
}
I think the only way you could achieve this is to create a Service class that will orchestrate all the calls to your Repository classes that have an owner property. That service call would return your list of BaseEntity objects.
Related
This is my entity with composite key:
#Entity
#Table(name = "course_ratings")
public class CourseRating {
#EmbeddedId
private CourseRatingKey id;
}
Where CourseRatingKey looks like this:
#Embeddable
public class CourseRatingKey implements Serializable {
#Column(name = "user_id")
private int userId;
#Column(name = "course_id")
private int courseId;
public CourseRatingKey() {
}
// getters, setters, equals(), hashCode()
}
And my JPA repository
#Repository
public interface CourseRatingRepository extends JpaRepository<CourseRating, CourseRatingKey> {
}
I am trying to build method that will return list of all CourseRating with given courseId property of CourseRatingKey. Below method doesn't work because JPA doesn't recognize it:
repository.findAllByIdCourseId(int id);
How can I build my method name to achieve my goal?
I have solved my problem by declaring this method in repository. I'm a bit confused as the other methods work without declaring.
#Repository
public interface CourseRatingRepository extends JpaRepository<CourseRating, CourseRatingKey> {
List<CourseRating> findAllByIdCourseId(Integer id);
}
I have a existing Model and want to use it with Picketlink. But I am using Long as #Id field. But Picketlink expect this to be a String field. I have found some hints to use another entity which maps to the corresponding entity of my model. But actually I don't now how to do it.
I have a base class, which all entities derive from:
#MappedSuperclass
public abstract class AbstractEntity implements Serializable, Cloneable {
#Id
#Identifier
#Column(name = "SID")
private Long sid;
#Column(name = "INSERT_TIME")
private Date insertTime;
#Column(name = "UPDATE_TIME")
private Date updateTime;
// getters and setters
}
And a derived realm entity:
#Entity
#IdentityManaged(Realm.class)
public class RealmEntity extends AbstractEntity {
#AttributeValue
private String name;
#PartitionClass
private String typeName;
#ConfigurationName
private String configurationName;
#AttributeValue
private boolean enforceSSL;
#AttributeValue
private int numberFailedLoginAttempts;
// getters and setters
}
And the mapping class for Picketlink looks as follows:
#IdentityPartition(supportedTypes = {
Application.class,
User.class,
Role.class
})
public class Realm extends AbstractPartition {
#AttributeProperty
private boolean enforceSSL;
#AttributeProperty
private int numberFailedLoginAttempts;
private Realm() {
this(null);
}
public Realm(String name) {
super(name);
}
}
The PartitionManager is defined as follows:
builder
.named("default.config")
.stores()
.jpa()
.supportType(User.class, Role.class, Application.class, Realm.class)
.supportGlobalRelationship(Grant.class, ApplicationAccess.class)
.mappedEntity(App.class, AppUserRole.class, AppRole.class, AppUser.class, UserEntity.class, RelationshipIdentityTypeEntity.class, RealmEntity.class)
.addContextInitializer((context, store) -> {
if (store instanceof JPAIdentityStore) {
if (!context.isParameterSet(JPAIdentityStore.INVOCATION_CTX_ENTITY_MANAGER)) {
context.setParameter(JPAIdentityStore.INVOCATION_CTX_ENTITY_MANAGER, entityManager);
}
}
});
When I try to create a new Realm Hibernate throws an error while trying to load the Realm because the #Id is defined as Long but the #Identifier of the Picketlink model is a String.
this.shsRealm = new Realm(REALM_SHS_NAME);
this.shsRealm.setEnforceSSL(true);
this.shsRealm.setNumberFailedLoginAttempts(3);
this.partitionManager.add(this.shsRealm);
java.lang.IllegalArgumentException: Provided id of the wrong type for class de.logsolut.common.picketlink.model.RealmEntity. Expected: class java.lang.Long, got class java.lang.String
How can I map the JPA model correctly to Picketlink?
I'm trying to access a property defined in #MappedSuperclass in a Criteria Query with JPA meta-model (Hibernate 4.2.8):
#MappedSuperclass
public class BaseEntity {
private DateTime createdOn;
}
My Entity:
#Entity
#Table(name = "HISTORY")
public class History extends BaseEntity implements Serializable {
private Long id;
}
How to access createdOn?
CriteriaBuilder cb = getEntityManager().getCriteriaBuilder();
CriteriaQuery<History> c = cb.createQuery(History.class);
Root<History> h = c.from(History.class);
h.orderBy(cb.asc(a.get(History_.createdOn)));
History_:
#Generated(value = "org.hibernate.jpamodelgen.JPAMetaModelEntityProcessor")
#StaticMetamodel(History.class)
public abstract class History_ extends com.test.BaseEntity_ {
public static volatile SingularAttribute<History, Long> id;
}
Is there a way to access base class' properties?
Of course there is a way. As I see in your code, you already access it: History_.createdOn is a property of the MappedSuperclass. If by "to access" you mean to select, than you simply do:
query.select(History_.createdOn)
I have have two classes that inherit from an abstract class and have a parent-children relation.
So I use annotation OneToMany and ManyToOne but the parent entity in child class is always null.
Can Someone help me please, I have spend several hours to googling and test many conf without success.
These are code from my classes :
public #Table(name="flowentity") #Entity abstract class FlowEntity {
final static Logger log = LoggerFactory.getLogger(FlowEntity.class);
//Globals informations concerning the flow state
private #Id #GeneratedValue(strategy = GenerationType.IDENTITY) Integer flowId = 0;
private String flowName;
private #OneToMany(fetch=FetchType.EAGER, cascade=CascadeType.ALL)
Set<PeopleEntity> actorSet = new HashSet<>();
//Global parameters for most of flows
//Organizational parameters
private #OneToOne(fetch=FetchType.EAGER, cascade=CascadeType.ALL)
#JoinColumn(name="organisationalEntity_Id")
OrganisationalEntity organisationalEntity;
...
public #Table(name="ams_newCPEntity") #Entity class NewMultiCPEntity extends FlowEntity {
private #OneToMany(targetEntity=NewCPEntity.class, fetch=FetchType.EAGER, cascade=CascadeType.ALL,mappedBy="parent")
Set<NewCPEntity> cpList = new HashSet<NewCPEntity>();
//Constructor
public NewMultiCPEntity(){
setFlowName(EnumFlow.N_CP_M.getFlowAcronym());
}
...
public #Table(name="ams_newCPEntity") #Entity class NewCPEntity extends FlowEntity {
final static Logger log = LoggerFactory.getLogger(NewCPEntity.class);
private boolean formNCPValidated;
private #ManyToOne #JoinColumn(name="parent_Id", nullable=false)
NewMultiCPEntity parent;
public NewCPEntity(){
log.debug("Instanciation of a new CP");
setFlowName(EnumFlow.N_CP.getFlowAcronym());
}
public #Override OrganisationalEntity getOrganisationalEntity(){
return parent.getOrganisationalEntity();
}
...
If I don't add the #JoinColumn annotation, JPA create an association table but is not able to retrieve the parent whereas the association can be done directly by requesting in database.
Thankyou very much to help.
Regards,
Thank you Chris for your comment, you are right, I forget to change the name of the table. I don't think it was the problem because the inheritance mapping is in one table flowentity with a DTYPE discriminator column.
Finally I resolve my problem by setting parent attributs when adding a new child like this :
public #Table #Entity class NewMultiCPEntity extends FlowEntity {
private #OneToMany(targetEntity=NewCPEntity.class, fetch=FetchType.EAGER, cascade=CascadeType.ALL)
List<NewCPEntity> cpList = new ArrayList<>();
//Constructor
public NewMultiCPEntity(){
setOrganisationalEntity(new OrganisationalEntity());
setFlowName(EnumFlow.N_CP_M.getFlowAcronym());
}
public List<NewCPEntity> getNCPList(){
if(cpList == null){
cpList = new ArrayList<>();
}
if(cpList.isEmpty()){
addCPEntity(new NewCPEntity());
}
return Collections.unmodifiableList(cpList);}
public boolean removeCPEntity(NewCPEntity entity){
return cpList.remove(entity);
}
public boolean addCPEntity(NewCPEntity entity){
entity.setParent(this);
entity.setOrganisationalEntity(this.getOrganisationalEntity());
return cpList.add(entity);
}
And I remove the override of getOrganizationalEntity in the child :
public #Table #Entity class NewCPEntity extends FlowEntity {
final static Logger log = LoggerFactory.getLogger(NewCPEntity.class);
private #ManyToOne(targetEntity=NewMultiCPEntity.class,cascade=CascadeType.ALL)
NewMultiCPEntity parent;
public NewCPEntity(){
log.debug("Instanciation of a new CP");
setFlowName(EnumFlow.N_CP.getFlowAcronym());
}
public NewMultiCPEntity getParent() {
return parent;
}
public void setParent(NewMultiCPEntity parent){
this.parent = parent;
}
Regards,
This works:
#MappedSuperclass
public class ExtendableTranslation extends Model {
public String label;
}
#Entity
public class LeagueT extends ExtendableTranslation {
#Id
public Integer id;
}
but if I move id field to the superclass:
#MappedSuperclass
public class ExtendableTranslation extends Model {
public String label;
#Id
public Integer id;
}
#Entity
public class LeagueT extends ExtendableTranslation {
}
I have an error:
[RuntimeException: java.lang.NoSuchMethodError: models.translations.LeagueT._ebean_setni_id(Ljava/lang/Integer;)V]
It's the same for all other annotated fields (#ManyToOne, #OneToMany). Is it a bug or I'm doing something wrong?