How to get currentPagePath in Slingservlet? - aem

Question

From some javascript I call the following Slingservlet with ("/bin/fooServlet?"+params);
#SlingServlet(paths = "/bin/fooServlet", methods = "GET", metatype = true)
public class FooServlet extends SlingAllMethodsServlet {
..
protected void doGet(SlingHttpServletRequest request, SlingHttpServletResponse response) {
Session session = resourceResolver.adaptTo(Session.class);
Page currentPage = pageManager.getPage(request.getPathInfo());
String currentPagePath = currentPage.getPath();
...
}
My Question is: How to get the currentPagePath of the current Page in FooServlet? currentPagePath in the code is null.

Answer 1

As Thomas mentioned, if you define a servlet with fixed paths property, you wouldn't have reference to a Resource.
One way of achieving this is by passing your page path along with the request to the servlet. Also CQ.WCM.getPagePath() returns only /libs/wcm/core/content/siteadmin, as the current page is siteadmin and you may need to tweak your script a bit in order to access the selected page within siteadmin.
To get your page path either from siteadmin or from the page itself, you can use the following script and then pass the value to your servlet for further processing.
var currentPagePath = null;
/* if accessed via siteadmin */
if(CQ.wcm.SiteAdmin.hasListSelection()) {
var grid = CQ.wcm.SiteAdmin.getActiveGrid();
var selections = grid.getSelectionModel().getSelections();
/*Assuming that you are selecting only one page at a time. */
currentPagePath = selections[0].id;
} else { /* accessed via page */
currentPagePath = CQ.WCM.getPagePath();
}
And then you can call the servlet with the currentPagePath as one of the parameters.
GET /bin/fooServlet?currentPagePath=' + currentPagePath + '&foo=bar';
UPDATE
The above code works fine for CQ 5.5 + , for older versions you can use this.
var currentPagePath = null;
/* if accessed via siteadmin */
if(CQ.wcm.SiteAdmin.hasListSelection()) {
var grid = CQ.Ext.getCmp(window.CQ_SiteAdmin_id + "-grid");
if (grid) {
var selections = grid.getSelectionModel().getSelections();
currentPagePath = selections[0].id;
}
} else { /* accessed via page */
currentPagePath = CQ.WCM.getPagePath();
}

Answer 2

If you define the servlet with a fixed paths property you don't have any reference to a Resource or Page
You either need to define resourceTypes that matches to a page component or use cq:Page, but this will then be active for every request to a page and is not recommended without at least some selectors
Then you can get the Resource with request.getResource(). To get a Page you'll need to adapt the ResourceResolver to a PageManager and use getContainingPage(Resource resource).
Have a look at the documentation:
http://sling.apache.org/documentation/the-sling-engine/servlets.html

Answer 3

request.getPathInfo() in this case presumably is /bin/fooServlet?[parameterString], which is why PageManager is returning null for its path — from the PageManager's point of view, no resource exists at this location.
One simple option would be to send an additional callingPage parameter when hitting the Servlet. This way you could just read it from the parameter map:
GET /bin/fooServlet?foo=bar&callingPage=/en/home.html
void doGet() {
PageManager pageManager = resourceResolver.adaptTo(PageManager.class);
String callingPage = request.getParameter("callingPage");
String callingPagePath = pageManager.getPage(callingPage).getPath();
}

Answer 4

I don't know if it's a good pratice, but perhaps you could use the referer.
import java.net.URI;
import java.net.URISyntaxException;
try {
String currentPagePath = new URI(request.getHeader("referer")).getPath();
} catch (java.net.URISyntaxException e) {
}