error in debugging the algorithm - matlab

Question

I'm trying to make an algorithm in Matlab that scans the character array from left to right and if it encounters a space, it should do nothing, but if it encounters 2 consecutive spaces, it should start printing the remaining quantities of array from next line. for example,
inpuut='a bc d';
after applying this algorithm, the final output should have to be:
a bc
d
but this algorithm is giving me the output as:
a bc
d d
Also, if someone has got a more simpler algorithm to do this task, do help me please :)
m=1; t=1;
inpuut='a bc d';
while(m<=(length(inpuut)))
if((inpuut(m)==' ')&&(inpuut(m+1)==' '))
n=m;
fprintf(inpuut(t:(n-1)));
fprintf('\n');
t=m+2;
end
fprintf(inpuut(t));
if(t<length(inpuut))
t=t+1;
elseif(t==length(inpuut))
t=t-1;
else
end
m=m+1;
end
fprintf('\n');

Answer 1

OK I gave up telling why your code doesn't work. This is a working one.
inpuut='a bc d ';
% remove trailing space
while (inpuut(end)==' ')
inpuut(end)=[];
end
str = regexp(inpuut, ' ', 'split');
for ii = 1:length(str)
fprintf('%s\n', str{ii});
end
regexp with 'split' option splits the string into a cell array, with delimiter defined in the matching expression.
fprintf is capable of handling complicated strings, much more than printing a single string.
You can remove the trailing space before printing, or do it inside the loop (check if the last cell is empty, but it's more costly).

Answer 2

You can use regexprep to replace two consecutive spaces by a line feed:
result_string = regexprep(inpuut, ' ', '\n');
If you need to remove trailing spaces: use this first:
result_string = regexprep(inpuut, ' $', '');

Answer 3

I have a solution without using regex, but I assumed you wanted to print on 2 lines maximum.
Example: with 'a b c hello':
a b
c hello
and not:
a b
c
hello
In any case, here is the code:
inpuut = 'a b c';
while(length(inpuut) > 2)
% Read the next 2 character
first2char = inpuut(1:2);
switch(first2char)
case ' ' % 2 white spaces
% we add a new line and print the rest of the input
fprintf('\n%s', inpuut(3:end));
inpuut = [];
otherwise % not 2 white spaces
% Just print one character
fprintf('%s', inpuut(1))
inpuut(1) = [];
end
end
fprintf('%s\n', inpuut);