JPA #MappedSuperclass realisation in Grails 2.4 - jpa

I found this solution, that doesn't solve the problem. In JPA we can do this:
#MappedSuperclass
public class BasicEntity {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Column(updatable = false)
#Temporal(TemporalType.TIMESTAMP)
private Date created = new Date();
#Temporal(TemporalType.TIMESTAMP)
private Date modified = new Date();
}
#Entity
public class User extends BasicEntity {
private String username;
private String password;
}
Then, hibernate.hbm2ddl.auto generates one table with all inherited columns and this is exactly what I want:
user (
id,
created,
modified,
username,
password,
)
In Grails I do this
abstract class BasicEntity {
static mapping = {
tablePerSubclass true
}
Date dateCreated
Date lastUpdated
}
class User extends BasicEntity {
String username
String password
}
And it generates me two tables with no inheritance
basic_entity (
id,
version,
date_created,
last_updated,
)
user (
id,
username,
password,
)

Related

JPARepository - delete using date comparison with derived query

I'm trying to use JPARepository in Spring Boot to delete records that are less than a certain date, for for a given userid
Should be something like this Delete * from [table] where expiration_date < [date] and userid = [userid]
I thought I should be able to use one of the automatically generated methods
int deleteByExpiryDateBeforeAndUser(Date date, User user);
But this is generating a Select and not a Delete. What am I doing wrong?
Update
Entity class
#Getter
#Setter
#ToString
#Entity(name = "refresh_token")
public class RefreshToken {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private long id;
#OneToOne
#JoinColumn(name = "user_id", referencedColumnName = "id")
private User user;
#Column(nullable = false, unique = true)
private String token;
#Column(nullable = false)
private Date expiryDate;
public RefreshToken() {
}
}
Repository class
#Repository
public interface RefreshTokenRepository extends JpaRepository<RefreshToken, Long> {
Optional<RefreshToken> findByToken(String token);
#Modifying
void deleteByUserIdAndExpiryDateBefore(Long userId, Date expiryDate);
int deleteByUser(User user);
}
Here's how I'm calling it
#Transactional
public void deleteExpiredTokens(User user) {
refreshTokenRepository.deleteByUserIdAndExpiryDateBefore(user.getId(), new Date());
}
You see a select statement because Spring Data first loads entities by condition.
Then once entities became 'managed' Spring Data issues a delete query for each entity that was found.
If you want to avoid redundant SQL query - you have to consider #Query annotation.
Then your code will look like this:
#Repository
public interface RefreshTokenRepository extends JpaRepository<RefreshToken, Long> {
// ...
#Query(value = "DELETE FROM refresh_token WHERE user_id =:userId AND expiry_date < :expiryDate", nativeQuery = true)
#Modifying
void deleteByUserIdAndExpiryDateBefore(Long userId, Date expiryDate);
//...
}

JPA how to set foreign id - in Embeddable id - that is generated

My use case is: I have a Product with multi language name. To have at most one name per language a translation should be identified by locale + productId.
My problem is to get it working with a generated productId. This are the entities:
e.g. in oracle i get: "ORA-01400: cannot insert null into ."PRODUCT_NAME"."FOREIGN_ID""
Product:
#Entity
#Data
public class Product {
#Id
#GeneratedValue
private Long id;
#Column(unique = true)
private String articleNumber;
/**
* Localized name of the product.
*/
#OneToMany(cascade = CascadeType.ALL, orphanRemoval = true)
#MapKey(name = "nameId.locale")
private Map<Locale, ProductName> names = new HashMap<>();
}
ProductName:
#Entity
#Data
public class ProductName {
#EmbeddedId
private TranslationId nameId;
private String name;
}
TranslationId:
#Embeddable
#Data
public class TranslationId implements Serializable {
private static final long serialVersionUID = 3709634245257481449L;
#Convert(converter = LocaleConverter.class)
private Locale locale;
private Long foreignId; //<-- this is null, should reference product
}
Is there a way to get this working without having to save the product first without the name? Without a generated id it is working of course - i just set same id for both.
I would like to re-use the translation id for other translated fields of other entities.

#Transactional in spring JPA

I have a spring boot application where I need to update a migratedCustomer db table based on userId and phoneNumber.
Since I have to use for loop in the service layer for every update, it is creating a
new transaction and performance is hampered.
how could I make sure only one transaction is created and hence to improve the performance. code is like below
#Entity
#Table(name = "MigratedCustomer")
public class MigratedCustomer {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String userId;
private String phoneNumber;
#Temporal(TemporalType.TIMESTAMP)
private Date createdTimestamp;
private int batchNumber;
private String comment;
}
public class MigratedCustomerService {
#Autowired
private UserRepository userRepository;
public void updateMsisdn(List<MigratedCustomer> savedCustomers) {
for (MigratedCustomer savedCustomer : savedCustomers) {
userRepository.updateStatus(savedCustomer.getUserId(),
savedCustomer.getPhoneNumber());
}
}
}
public interface MsisdnRepository extends JpaRepository<Msisdn, Long> {
#Modifying
#Query(value = "UPDATE Msisdn SET status=INACTIVE where userId=:userId and phoneNumber=:phoneNumber",
nativeQuery = true)
void updateStatus(#Param("userId") String userId, #Param("phoneNumber") String phoneNumber);
}

Spring JPA using primary key within #Embeddable class

In my application i have a scenario to fetch data from entity based on give input code and date.
The combination of code and date will be unique and will return a single record.
Below is my entity
class JpaEntity
{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private id ;
private String code;
private Date date;
private title;
//Getters and Setters
}
I have tried below approcah by changing the entity.
class JpaEntity
{
private String title;
//Getters and setters
#EmbededId
private EntityId entityID
#Embedable
public static class EntityId implements Serializable{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private id ;
private String code;
private Date date;
//Getters and Setters
}
}
I am using the entity to search based on code and date
public interface PersistentDAO extends JpaRepository<JpaEntity,String> {
{
#Query("SELECT cal FROM JpaCalendar cal" + " WHERE cal.calendarId.currencyCode=:currencyCode "
+ " AND cal.calendarId.date=:date")
Optional<JpaCalendar> findById(String currencyCode, Date date);
JpaEntity findByID(String code,Date date)
}
But the JPA is throwing error saying Component Id is not found.
is it mandatory all the field in #Embedable are primary?
is it possible #Embedable class (composite id) contain the both primary and non-primay keys.
Since i am not supposed to change the structure of the table is there any way to achieve following:
Fetch record based on give code and date.
Insert new record where in id the primary key should be auto incremented
Please suggest.
Use #Embedded & #Embeddable and don't use static class inside class
class JpaEntity
{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private id ;
#Embedded
private CodeDate codeDate;
private title;
}
#Embeddable
class CodeDate {
private String code;
private Date date;
}
You can use Jpa method naming query and create a CodeDate object call like this
public interface PersistentDAO extends JpaRepository<JpaEntity,String> {
{
JpaEntity findByCodeDate(CodeDate codeDate);
}

JPA repository retrieve custom primary key value after save

I have an entity class pointing to postgresql table. Below is table structure. The paymentreferencenumber is the PK which is populated by a trigger. id field is the sequence generated field. When i try to save in this table using JPARepository save method it inserts the first record. But after that it fails due to the primary key constraint. Since PK is a string type and generated using trigger I am specifying generator strategy as 'select'. Can anyone help me with this blocker and point me in the right direction. Thanks
Table structure --
custId serial not null,
paymentreferencenumber varchar(32) not null
constraint customers1_pkey
primary key,
firstname varchar(255),
lastname varchar(255)
Entity class --
#Entity
#Table(name = "customersnew")
public class Customer implements Serializable {
private static final long serialVersionUID = -1L;
#GeneratedValue(generator = "seq")
#GenericGenerator(name="seq", strategy="sequence", parameters = { #Parameter(name="key", value = "customersnew_custid_seq")})
#Column(name = "custid")
private long id;
#Id
#GeneratedValue(generator = "trigger_generated")
#GenericGenerator(name="trigger_generated", strategy="select", parameters = { #Parameter(name="key", value = "id")})
#Column(name = "paymentreferencenumber")
private String refNum;
#Column(name = "firstname")
private String firstName;
#Column(name = "lastname")
private String lastName;
}
--- Controller using JPA save
#RestController
public class CustomerController {
#Autowired
CustomerRepository repository;
EntityManagerFactory emf;
public CustomerController(CustomerRepository repository, EntityManagerFactory emf) {
this.repository = repository;
this.emf = emf;
}
#PostMapping("/create")
public String create(#RequestBody CustomerUI customer){
// save a single Customer
Customer returnObj = repository.saveAndFlush(new Customer(customer.getFirstName(), customer.getLastName()));
PersistenceUnitUtil util = emf.getPersistenceUnitUtil();
Object retObj = util.getIdentifier(returnObj);
return "Customer is created";
}
If you don't specify an id generation strategy, Hibernate will use GenerationType.AUTO. This will result in any of
AUTO - either identity column, sequence or table depending on the
underlying DB.
If you look here, you'll notice all of those generate ids of type long, short or int, not of type String.
Say you wanted a String UUID as an id, you could use
#Id
#GeneratedValue(generator = "uuid")
#GenericGenerator(name = "uuid", strategy = "uuid2")
#Column(name = "paymentreferencenumber")
private String refNum;