In my application i have a scenario to fetch data from entity based on give input code and date.
The combination of code and date will be unique and will return a single record.
Below is my entity
class JpaEntity
{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private id ;
private String code;
private Date date;
private title;
//Getters and Setters
}
I have tried below approcah by changing the entity.
class JpaEntity
{
private String title;
//Getters and setters
#EmbededId
private EntityId entityID
#Embedable
public static class EntityId implements Serializable{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private id ;
private String code;
private Date date;
//Getters and Setters
}
}
I am using the entity to search based on code and date
public interface PersistentDAO extends JpaRepository<JpaEntity,String> {
{
#Query("SELECT cal FROM JpaCalendar cal" + " WHERE cal.calendarId.currencyCode=:currencyCode "
+ " AND cal.calendarId.date=:date")
Optional<JpaCalendar> findById(String currencyCode, Date date);
JpaEntity findByID(String code,Date date)
}
But the JPA is throwing error saying Component Id is not found.
is it mandatory all the field in #Embedable are primary?
is it possible #Embedable class (composite id) contain the both primary and non-primay keys.
Since i am not supposed to change the structure of the table is there any way to achieve following:
Fetch record based on give code and date.
Insert new record where in id the primary key should be auto incremented
Please suggest.
Use #Embedded & #Embeddable and don't use static class inside class
class JpaEntity
{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private id ;
#Embedded
private CodeDate codeDate;
private title;
}
#Embeddable
class CodeDate {
private String code;
private Date date;
}
You can use Jpa method naming query and create a CodeDate object call like this
public interface PersistentDAO extends JpaRepository<JpaEntity,String> {
{
JpaEntity findByCodeDate(CodeDate codeDate);
}
Related
My use case is: I have a Product with multi language name. To have at most one name per language a translation should be identified by locale + productId.
My problem is to get it working with a generated productId. This are the entities:
e.g. in oracle i get: "ORA-01400: cannot insert null into ."PRODUCT_NAME"."FOREIGN_ID""
Product:
#Entity
#Data
public class Product {
#Id
#GeneratedValue
private Long id;
#Column(unique = true)
private String articleNumber;
/**
* Localized name of the product.
*/
#OneToMany(cascade = CascadeType.ALL, orphanRemoval = true)
#MapKey(name = "nameId.locale")
private Map<Locale, ProductName> names = new HashMap<>();
}
ProductName:
#Entity
#Data
public class ProductName {
#EmbeddedId
private TranslationId nameId;
private String name;
}
TranslationId:
#Embeddable
#Data
public class TranslationId implements Serializable {
private static final long serialVersionUID = 3709634245257481449L;
#Convert(converter = LocaleConverter.class)
private Locale locale;
private Long foreignId; //<-- this is null, should reference product
}
Is there a way to get this working without having to save the product first without the name? Without a generated id it is working of course - i just set same id for both.
I would like to re-use the translation id for other translated fields of other entities.
I have the below entities
#Entity
#Getter
#Setter
public class Aggregate {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#OneToMany(mappedBy = "aggregate")
private Set<Single> singleSet;
}
#Entity
#Getter
#Setter
public class Single {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private String id;
private Integer number;
#ManyToOne
#JoinColumn(name = "agg_id")
private Aggregate aggregate;
}
I also have the below repository
public interface AggregateRepo extends CrudRepository<Aggregate, Long> {
}
I want to return all associated Single records where number in object Single is equal to some random number
I am assuming that the query will be something like this
public interface AggregateRepo extends CrudRepository<Aggregate, Long> {
public List<Single> findBySingleSet_Number(Integer number);
}
However when I try to use Intellij to complete my named query it always populates like this
public interface AggregateRepo extends CrudRepository<Aggregate, Long> {
public List<Single> findBySingleSet_Empty_Number(Integer number);
}
I am wondering what the Empty stands for ?
Also should I create another Single repository since the query is related to returning Single records.
I am trying to migrate a Seam 2 app to CDI and use PicketLink for security. After all the reading and researching, it seems like all the examples are having one to one mapping between PicketLink model and the backend entity. e.g. Account to AccountEntity, Partition to PartitionEntity. Since I already have entities in place representing identity model, I am stuck on trying to map them to PicketLink. Here is what I have:
#MappedSuperClass
public class ModelEntityBase implement Serializable {
#Id #Generated
Long id;
Date creationDate;
}
#Entity
public Account extends ModelEntityBase {
String username;
String passwordHash;
#OneToOne(mappedBy = "account")
Person person;
}
#Entity
public Person extends ModelEntityBase {
String name;
String email;
#OneToOne
#JoinColumn(name = "account_id")
Account account;
}
Two entities (plus a super class) representing a single identity model in PicketLink, e.g. stereo type User.
Based on this why IdentityType id is String not Long, I tried to add a new Entity in:
#Entity
#IdentityManaged(BaseIdentityType.class);
public class IdentityTypeEntity implement Serializble {
#Id #Identifier
private String id;
#OneToOne(optional = false, mappedBy = "identityType")
#OwnerReference
private Account account;
#IdentityClass
private String typeName;
#ManyToOne #OwnerReference
private PartitionEntity partition;
}
I've tried a few different ways with the annotation and model classes. But when using IdentityManager.add(myUserModel), I just can't get it to populate all the entities. Is this even possible?
Got help from Pedro (PicketLink Dev). Post the answer here to help others.
This is the model class I ended up using.
#IdentityStereotype(USER)
public class User extends AbstractAttributedType implements Account {
#AttributeProperty
private Account accountEntity;
#AttributeProperty
#StereotypeProperty(IDENTITY_USER_NAME)
#Unique
private String username;
#AttributeProperty
private boolean enabled;
#AttributeProperty
private Date createdDate;
#AttributeProperty
private Date expiryDate;
#AttributeProperty
private Partition partition;
// getter and setter omitted
}
And created a new entity to map to this model:
public class IdentityTypeEntity implements Serializable {
#Id
#Identifier
private String id;
#OneToOne(optional = false, mappedBy = "identityType",
cascade = CascadeType.ALL, fetch = FetchType.EAGER)
#AttributeValue
// #NotNull
private HAccount accountEntity;
#IdentityClass
private String typeName;
#ManyToOne
#OwnerReference
private PartitionEntity partition;
#AttributeValue
private String username;
#AttributeValue
// #Transient
private boolean enabled;
#AttributeValue
private Date createdDate;
#AttributeValue
private Date expiryDate;
}
PL can map property with #AttributeProperty to entity property with #AttributeValue. But it can only map to one entity. Therefore there is no way to map, say User and its properties over to Account and Person. But you can have the entity (in my case accountEntity) in the model. I also have to duplicate a few fields in the new IdentityTypeEntity and my existing Account entity (username, eanbled, createdDate) because PL requires these. Use a #PrePersist and similar to sync them.
I have a problem to handle mapping object relationship for mysql tables.
I have 2 tables shown below:
Device
-----------
deviceId PK
deviceName
ApkInfo
--------
id PK
packageName
appName
deviceId FK
And then here are my classes:
#Entity
#Table(name="Device")
public class Device implements Serializable {
#Column
#Id
private String deviceId;
#Column
private String deviceName;
//getters and setters
}
#Entity
#Table(name="ApkInfos")
public class ApkInfo implements Serializable {
#Column
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private int id;
#Column
#Id
private String packageName;
#Column
private String appName;
#Column
#Temporal(TemporalType.TIMSTAMP)
private Date installDate;
#ManyToOne
#JoinColumn(name="deviceId" referencedColumnName="deviceId")
private Device device;
//getters and setters
}
This works for me, but I want to use compound key, deviceId and packageName, in ApkInfos table.
#Entity
#Table(name="ApkInfos")
public class ApkInfo implements Serializable {
#Colum(instable=false, updatable=false)
#Id
private String deviceId;
#Column
private String packageName;
#Column
private String appName;
#ManyToOne
#JoinColumn(name="deviceId" referencedColumnName="deviceId")
private Device device;
//getters and setters
}
But when I tried to save an entity using Spring Data JPA repository, I got an error:
org.springframework.dao.InvalidAccessApiUsageException: Class must not
be null, nested exception is java.lang.IllegalArgumentException: Class
must not be null
ApkInfo apkInfo = new ApkInfo();
apkInfo.setDeviceId("1234");
apkInfo.setPackageName("aaa");
apkInfo.setAppName("myapp");
apkInfo.setInstallDate(new Date());
apkInfo.setDevice(new Device("1234"));
repository.save(apkInfo);
And device has the deviceID '1234' already exists in the Device table.
I created a separate primary key class added #IdClass in the ApkInfo class. It works fine now, thanks. I am going to have a look at EmbeddedId more later.
I added #IdClass at the entity class and #Id for the packageName property. Also I made insert, update false for the One-to-many column.
#Entity
#Table(name="ApkInfos")
#IdClass(ApkInfo.class)
public class ApkInfo implements Serializable {
#Column #Id private String deviceId;
#Column #Id private String packageName;
#ManyToOne
#JoinColumn(name="deviceId" referencedColumnName="deviceId", insetable=false, updatable=false)
private Device device;
//getters and setters missing
}
Primary key class has only setters and overrides equals and hasCode methods.
public class ApkInfo implements Serializable {
private String deviceId;
private String packageName;
public ApkInfo(){}
public ApkInfo (String deviceId, String packageName){
this.deviceId = deviceId;
this.packageName = packageName;
}
public String getDeviceId(){
return this.deviceId;
}
public String getPackageName(){
return this.packageName;
}
#Override
public boolean equals(Object obj){
return (obj!=null &&
obj instanceof ApkInfoPk &&
deviceId.equals(((ApkInfoPk)obj).getDeviceId()) &&
packageNames.equals(((ApkInfoPk)obj).getPackageName()) );
}
#Override
public int hashCode(){
super.hashCode();
}
}
I am using Hibernate-search for searching data in my Jboss application. I have 3 JPA entity classes that all extend BaseEntity class and each are indexed by Lucene. For example:
#MappedSuperclass
public abstract class BaseEntity implements Serializable {
#Temporal(TemporalType.TIMESTAMP)
private Date created;
public abstract Long getId();
}
#Entity
#Table(name = "DVD")
public class Dvd extends BaseEntity {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Field
private String title;
}
#Entity
#Table(name = "BOOK")
public class Book extends BaseEntity {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Field
private String author;
}
Now I would like to search for either DVD title or Book author by wildcard search query and get the result list as List. This is what I have this far:
public List<BaseEntity> search(String query, int firstResult, int maxResults) {
List<BaseEntity> results = null;
FullTextEntityManager fullTextEntityManager = Search.getFullTextEntityManager(em);
Query luceneQuery = new WildcardQuery(new Term("*", "*" + query + "*"));
FullTextQuery fullTextQuery = fullTextEntityManager.createFullTextQuery(luceneQuery, BaseEntity.class);
fullTextQuery.setFirstResult(firstResult);
fullTextQuery.setMaxResults(maxResults);
results = fullTextQuery.getResultList();
return results;
}
But with this I am not getting any results. How is it possible to get this to work or is there even way without using buildQueryBuilder for each entity? Thanks!
You'll want to use the varargs-style method for the classes, like so:
FullTextQuery fullTextQuery = fullTextEntityManager.createFullTextQuery(luceneQuery, DVD.class, Book.class);
This is because when Hibernate Search creates the search query, it adds the class name(s) to the query (for the _hibernate_class field, which is the indexed class' name).