CTE Pivot with Group by results - tsql

Question

I have a table with Datetime column, I want to check if there's a record for each hour of the day, then to display the missing hour of the day, so I write a first script with Pivot to find if ther's a record of each hour but the result don't group the rows by the same Date,
with test as (SELECT [numero] ,[client] ,[creele] ,[montantPaye] ,[AnneeProduction] ,cast(creele as Date) as Datee ,DATEPART(HOUR, creele) as 'Heure' FROM [CLMDatabase].[dbo].[Fiches] group by creele, numero, client, montantPaye,AnneeProduction ) select Datee,
isnull([1],0) as "01h",
isnull([2],0) as "02h",
isnull([3],0) as "03h",
isnull([4],0) as "04h",
isnull([5],0) as "05h",
isnull([6],0) as "06h",
isnull([7],0) as "07h",
isnull([8],0) as "08h",
isnull([9],0) as "09h",
isnull([10],0) as "10h",
isnull([11],0) as "11h",
isnull([12],0) as "12h",
isnull([13],0) as "13h",
isnull([14],0) as "14h",
isnull([15],0) as "15h",
isnull([16],0) as "16h",
isnull([17],0) as "17h",
isnull([18],0) as "18h",
isnull([19],0) as "19h",
isnull([20],0) as "20h",
isnull([21],0) as "21h",
isnull([22],0) as "22h",
isnull([23],0) as "23h",
isnull([00],0) as "00h" from test pivot ( count (client)for Heure in ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12],[13],[14],[15] ,[16],[17] ,[18] ,[19] ,[20],[21],[22],[23],[00])) as pvt order by datee ;
The result is like that :
Date ¦ 01h ¦ 02h ¦03h ¦ 04h ...
03-10.2006 ¦ 1 ¦ 0 ¦ 0 ¦ 0 ...
03-10.2006 ¦ 0 ¦ 0 ¦ 1 ¦ 0 ...
13-11.2006 ¦ 0 ¦ 0 ¦ 0 ¦ 1 ...
rather than :
Date ¦ 01h ¦ 02h ¦03h ¦ 04h ...
03-10.2006 ¦ 1 ¦ 0 ¦ 1 ¦ 0 ...
13-11.2006 ¦ 0 ¦ 0 ¦ 0 ¦ 1 ...

Answer 1

you can agregate in subquery or in cte required data and then transpose it thro pivot
SELECT Datee ,
ISNULL([1], 0) AS [01h] ,
ISNULL([2], 0) AS [02h] ,
ISNULL([3], 0) AS [03h] ,
ISNULL([4], 0) AS [04h] ,
ISNULL([5], 0) AS [05h] ,
ISNULL([6], 0) AS [06h] ,
ISNULL([7], 0) AS [07h] ,
ISNULL([8], 0) AS [08h] ,
ISNULL([9], 0) AS [09h] ,
ISNULL([10], 0) AS [10h] ,
ISNULL([11], 0) AS [11h] ,
ISNULL([12], 0) AS [12h] ,
ISNULL([13], 0) AS [13h] ,
ISNULL([14], 0) AS [14h] ,
ISNULL([15], 0) AS [15h] ,
ISNULL([16], 0) AS [16h] ,
ISNULL([17], 0) AS [17h] ,
ISNULL([18], 0) AS [18h] ,
ISNULL([19], 0) AS [19h] ,
ISNULL([20], 0) AS [20h] ,
ISNULL([21], 0) AS [21h] ,
ISNULL([22], 0) AS [22h] ,
ISNULL([23], 0) AS [23h] ,
ISNULL([00], 0) AS [00h]
FROM ( SELECT COUNT([client]) AS Client ,
CONVERT(DATE, creele) AS Datee ,
DATEPART(HOUR, creele) AS [Heure]
FROM #t
GROUP BY CONVERT(DATE, creele) ,
DATEPART(HOUR, creele)
) AS newtest PIVOT ( SUM(Client) FOR Heure IN ( [1], [2], [3], [4],
[5], [6], [7], [8],
[9], [10], [11],
[12], [13], [14],
[15], [16], [17],
[18], [19], [20],
[21], [22], [23],
[00] ) ) AS pvt
ORDER BY Datee;