I am trying to calculate the amount of days between two dates but my formula doesn't seem to be working properly. It's as is the function is ignoring the years in the dates. My function is as follows:
=IF([Today's date]>[Expiration Date],-DATEDIF([Expiration Date],[Today's date],"d"),(DATEDIF([Today's date],[Expiration Date],"d")))
I receive this error if I use the above function(Owners removed):
But then I replace -DATEDIF([Expiration Date],[Today's date],"d") with -DATEDIF([Today's date],[Expiration Date]"d") i get this result:
This is telling me that both cases are being treated as IF([Today's date]>[Expiration Date] even though 3/24/2015 is clearly larger than 11/03/2014. Can somebody please tell me what I'm doing wrong? Thanks.
=[ExpirationDate] - [TodaysDate]
Related
Does anyone know why I am encountering this error with the most basic operation in PowerBI? After a few tries myself only ending in errors I copied the syntax straight off MS site and still......error.
I created a new table and used the following:
Table = calendar(date(2000,1,1),date(2030,12,31))
Error received:
Too few arguments were passed to the DATE function. The minimum
argument count for the function is 3.
When adding the arguments its as if the DATE function does not recognize the year value at all.
Anyone else encountering this?
Also, I noticed a lot of search results advising to use the "Modelling" tab which I don't have in my desktop version. I am currently still on a free trial.
Does a free trial mean I can not use the most basic DATE() function - I truly hope this is not the case.
Here's a screenshot:
Here's a screenshot http://www.coletrumbo.com/wp-content/uploads/2015/05/dateformat-1024x575.png
I'm trying to turn the current date into July 1st of the current year using DATEFORMAT(). I learned how to do that in MySQL from this question, and I hoped it would work similarly in Jaspersoft Studio- turns out date_format( curdate(), '%Y-07-01' ) doesn't translate into
DATEFORMAT( TODAY(), '%Y-07-01' ) or DATEFORMAT( TODAY(), YY/07/01 ). Neither worked.
I could keep trying to get creative and hopefully find something that works, but I'd rather actually understand how to use DATEFORMAT().
I checked the Jaspersoft Studio User Guide, but it's not there. From the prompts on the screen, it makes a lot of sense, but I just can't figure out the "format pattern" that I'm allowed to apply, or even how to correctly write any format pattern at all. Also, this conveniently named question, DateFormat Pattern, didn't actually help at all. And community.jaspersoft.com/answers is kind of a joke in my opinion. When I checked it a couple days ago, it was filled with spam linking to live hockey games.
Thanks in advance. I'm sure this is a beginner level question, so I feel dumb asking it, and I feel like I'm wasting other people's space and time with it because I should already know. So I really appreciate your willingness to care.
I am using the following to get the todays date in a danish format
"Dato: "+new java.text.SimpleDateFormat("dd MMMM yyyy",new
Locale("da", "DK")).format(new Date())
you can find the source code for the DateTime functions directly in JR repository: https://sourceforge.net/p/jasperreports/code/ci/master/tree/jasperreports/demo/samples/functions/src/net/sf/jasperreports/functions/standard/DateTimeFunctions.java
As you can see the code is fairly simple and relies on the Joda Time library.
Therefore the second parameter you are trying to enter is a String, while the first one is a Date object.
Indeed something that could work for you is an expression like this DATEFORMAT(TODAY(), "07-01-YYYY")
Regards,
Massimo.
I have month parameter in JasperReports report which will be changed into title of month. I didn't use any query to change them. I try this code:
$P{MONTH}.intValue()==1?"JAN":
$P{MONTH}.intValue()==2?"FEB":
$P{MONTH}.intValue()==3?"MAR":
$P{MONTH}.intValue()==4?"APR":
$P{MONTH}.intValue()==5?"MAY":
$P{MONTH}.intValue()==6?"JUN":
$P{MONTH}.intValue()==7?"JUL":
$P{MONTH}.intValue()==8?"AUG":
$P{MONTH}.intValue()==9?"SEP":
$P{MONTH}.intValue()==10?"OCT":
$P{MONTH}.intValue()==11?"NOV":"DEC";
but it didn't work. Could anyone know the solution for me?
This is what I use
$F{MONTH}.intValue()==1?"JAN":
$F{MONTH}.intValue()==2?"FEB":
$F{MONTH}.intValue()==3?"MAR":
$F{MONTH}.intValue()==4?"APR":
$F{MONTH}.intValue()==5?"MAY":
$F{MONTH}.intValue()==6?"JUN":
$F{MONTH}.intValue()==7?"JUL":
$F{MONTH}.intValue()==8?"AUG":
$F{MONTH}.intValue()==9?"SEP":
$F{MONTH}.intValue()==10?"OCT":
$F{MONTH}.intValue()==11?"NOV":"DEC"
It may be the semi-colon at the end that's the problem
It may also be that you are using a Parameter - .intValue() doesn't seem valid for a Parameter
does anyone know where I can download this zip file called "businessdays.zip" which was mentioned from this link ... http://www.tek-tips.com/viewthread.cfm?qid=136159 ... I mean is there a better way of calculating business days/holidays than what is previously written here ... http://www.experts-exchange.com/Database/Reporting_/Crystal_Reports/Q_21376129.html ... I've tried this but method from experts-exchange, registered the dll but still not working for me. Can anyone help?
You could create a custom function that returns an array of holidays. See my answer to Crystal Report exclude time entries based on holiday rules.
In this post there is a function that takes a start date, and end date and return the number of working days in between. Also takes holidays into account.
I am exporting a date value from sqlite and placing it into an email. The date appears like this
279498721.322872
I am using Objective C in an Iphone App. Does anyone know how to make this export out as a regular date whether it is all number like
2009-02-10 or anything legible?
Well, if you take the number 279498721.322872 and throw it into an NSDate object using +dateWithTimeIntervalSinceReferenceDate, you get (here in the MDT timezone): 2009-11-09 15:32:01 -0700, which was just under 4 hours ago. If that's the time you're expecting, then formatting it is as simple as using an NSDateFormatter.
However, the thing to notice is that sqlite (by default) stores dates as textual representations (unless you specify differently in the sql statement). So the real question here is "where are you getting that number from?"
echo date("Y-m-d",time(279498721.322872));
Thanks for the responses. The answer came from my Guru Alex Cone. He told me to use the following:
NSTimeInterval tempInterval = (NSTimeInterval)sqlite3_column_double(statement, 4);
The tempInterval variable can then be loaded into the the NSDate method.