I have a data set with SAS date format "01JAN1980". I want to generate a variable called "quarter" with format "1980Q1" or what ever combination of year and quarter.
Here is what I my SAS codes:
quarter=QRT(date)
format quarter yyq.
but it gives me 1960Q1 instead of 1980Q1.
Does any one know where is the problem?
Thanks very much!!!
The Quarter function returns the quarter number, i.e. 1-4. SAS interprets this as a date with a value of 1, which is equivalent to 1st January 1960, then displays that date in yyq. format. So what you actually want here is just to make a copy of the original variable, without changing the value, and apply the format: quarter = date; format quarter yyq.;.
Also, in some cases you might not even need to make a copy of the variable - you can place a format statement in the middle of most procs and it will use that format for the output of the proc.
Related
I need to extract the data of the last quarter on the basis of today's date. I need to make it dynamic.
Using intnx I am able to extract the last day, not the first day.
data _null_;
a = intnx('quarter',today(),-1,'end');
format a date9.;
put a;
run;
Can anyone share the logic how to get the starting and ending date of the last quarter?
You only need a small correction to the last argument of the intnx function
data _null_;
start = intnx('quarter',today(),-1,'b');
end = intnx('quarter',today(),-1,'e');
put start= date9. end= date9.;
run;
From reliable INTNX documentation:
The fourth argument, alignment, is optional
'alignment'
controls the position of SAS dates within the interval. You must enclose alignment in quotation marks. Alignment can be one of these values:
BEGINNING
specifies that the returned date or datetime value is aligned to the beginning of the interval.
Alias B
MIDDLE
specifies that the returned date or datetime value is aligned to the midpoint of the interval, which is the average of the beginning and ending alignment values.
Alias M
END
specifies that the returned date or datetime value is aligned to the end of the interval.
Alias E
SAME
specifies that the date that is returned has the same alignment as the input date.
Aliases S, SAMEDAY See SAME Alignment for more information.
Default BEGINNING
See Aligning SAS Date Output within Its Intervals for more information.
I am trying to extract a month from a date in SAS, but so far all my new month variables are coming up as missing.
I have attempted to use some combinations of the month() function in SAS, but so far it just comes up as missing. The dates are formatted as follows: 01/31/2017 (MMDDYY10.)
I have tried
month = month(end_date)
Month =catx('/',put(month(end_date),z2
I would like the Month to show up as a number (01) or a 3 letter code (JAN), currently it is just missing (.)
Thanks in advance!
For month() to return a missing value the end_date variable must be numeric and missing. If end_date were a character variable the log would show invalid numeric data.
Use the monname3. format to convert a date value to a $3. character value mon
monthname = put (end_date, monname3.);
Other alternatives are:
keep the date value unchanged and change the format, or
map the date value to the first of the month value and also format that
For example:
end_date_copy = end_date;
format end_date_copy monname3.;
end_date_month = intnx('month', end_date, 0);
format end_date_month monname3.;
What you ultimately do depends on how the mon is to be used downstream in reporting or aggregating.
Column 1 : I have this date-time format in one column = 2018-10-08T04:30:23Z
Column 3 : I extracted date with formula = =LEFT(A11,10) and changed column format to date.
Column 32 : today(). Just to make sure both date columns match
Now when I want to compare both dates
Column 4 : =IF(C11=D11,TRUE(),FALSE())
It does not work. What did I do wrong?
One option using formulas only would be to use Excel's DATE function, which takes three parameters:
=DATE(YEAR, MONTH, DAY)
Use the following formula to extract a date from your timestamp:
=DATE(LEFT(A1,4), MID(A1,6,2), MID(A1,9,2))
This assumes that the timestamp is in cell A1, with the format in your question. Now, comparing this date value against TODAY() should work, if the original timestamp were also from today.
Should be worth trying:
=1*LEFT(A1,10)=TODAY()
May depend upon your configuration. Without format conversion (the 1*) you are trying to compare text (all string functions return Text) with a Number.
I wanted to know, how can we define date format from given date
for example, i have date 20180423 then in sas I want to define format as 'yyyymmdd'
similarly , i have date given in data as 12022018 then i want to define as 'ddmmyyyy'
Please note that, date is provided to me in proper date, but i want to define format now.
Date given may be different in future
so I need to take care all of the date format through SAS
What I thought was given date 20180422
use substr function
data test;
a=20180422;
a=substr(a,1,4);
b=substr(a,5,1);
c=substr(a,7,1);
run;
but not sure.
If anyone can provide the solution,then it really helps me in my project work.
Thanks in Advance for help.
It sounds like you want to convert various values to a date. SAS stores dates as a number, being the number of days since 1st Jan 1960. It's then usual to format this number to display as a date, in whichever format is preferred.
When importing dates that's are already in a format, it is necessary to use the input function, along with an informat, to convert the formatted value to a SAS date. If the date values being read in are all in the same format, then the specific informat can be used. In your case, where different formats are used, you can use the anydtdte. informat which will convert most of the standard date formats to a SAS date.
The example below converts 3 different date formats to a SAS date, then displays the SAS date in the date9. format. I've printed both the unformatted and formatted new values to the log, just so you can see they are stored as numbers.
data _null_;
input date_in $20.;
date_out = input(date_in, anydtdte20.);
put date_in date_out date_out :date9.;
datalines;
20180422
12022018
27apr2018
;
run;
Use the input(a,anydtdte20.); this will convert any date to SAS date, then use the functions Year(), Month(), Day() to extract the data you want.
You will find this SAS Post very useful about dates and locales.
Solution:
I created a table with two rows; each row have a different date format YYYYMMDD & DDMMYYYY to show you how the code will handles different date formats, saved them to SAS date and broke them down to Year, Month & Day:
options DATESTYLE=DMY;
data have;
input a;
datalines;
20180422
12022018
;
run;
data test;
set have;
format date_a date9.;
date_a=input(a,anydtdte20.);
Year_a=year(date_a);
month_a=month(date_a);
day_a=day(date_a);
run;
Output:
a=20180422 date_a=22APR2018 Year_a=2018 month_a=4 day_a=22
a=12022018 date_a=12FEB2018 Year_a=2018 month_a=2 day_a=12
You can use an if condition inside a data step. Using If condition, check for the condition to be true (check date value satisfies the required criteria), then format the date using a put function.Put function can take a source as first argument and format as second argument , and return the formatted value. Different values of same column, can have different formats specified that way.
Something like this,
if a = 'date1CheckCondtion' then newA = put(a , dateformat1.);
if a = 'date2' then newA = put(a , dateformat2.);
You may then choose to get all values in a common format like this:
dateA=input(newA,mmddyy6.);
I have a date that is stored as a number that is 201401. I would like to subtract 1 month, so that is 201312 and not 201400.
Also, if there is a more efficient way, please suggest as well. I also have the date stored as 01Jan2014, and would be fine converting the SAS date at that point, so that I can create two new columns (with 1 month subtracted) so that they have the value 01Dec2013 and 201312. Also, a function for incrementing the month forward or backward would be much appreciated.
Thanks in advance.
If you store the date as a SAS date, you can use the function intnx to increment it by whatever period you like.
newdate = intnx('Month',olddate,1,'s');
If you store it as an integer like your original, you're on your own to figure that out. My answer: don't.
The prior answer works.
I just wanted to add, storing as Date in SAS is not the same as storing as integer. It may display 01JAN2014 but it represents a number, so you can still perform computations.
If you store the date as a SAS date, you can use the function intnx to increment it by whatever period you like.
newdate = intnx('Month',olddate,1,'s');