I want to scan the curve in matlab for a specified area suppose 0-10 in X axis and 50-150 in y-axis and get the co-ordinates of the points of the line.
I am very new in this. I am starting from scratch. so any help is appreciated.
regards
Borad
Related
How to find out distance between point along the surface from one point to all other point on the cylinder surface.
XYZ coordinates of points are known
e.g
suppose 4 points are there on the surface of the cylinder here i want to find out following data i.e distance between point(1-2),point(1-3),point(1-4),point(2-3),point(2-4),point(3,4) along the surface.H
What you are looking for is the geodesic of a cylinder. Since you mentioned Matlab in the tag, you can use this tool
I have a set of data whose points I have plotted and fitted using a power of 2 fit in MATLAB. I'm trying to draw 3 lines to that curve as tangential lines. Each of these lines start from the co-ordinates of say, (x,y): (2,0) (4,0) (9,0).
Is it possible for MATLAB to draw lines from the curve to the first known point until the line has only one solution (tangent to the curve) with the curve?
I feel that this requires some sort of specified interval which tells MATLAB to step the co-ordinates until it finds the closest point. Does anyone know if this has been done or can be done at all?
From a point not lying on the curve, you want to draw a line that is tangent to it. In case of a convex function like y=2^x this is only possible from a point under the curve (not over it).
Since you already have the point (call it (a,b)), you need the slope of such a line. The slope is determined by the values (y-b)/(x-a) where (x,y) runs over the curve. Specifically, the "forward-looking" tangent has the slope equal to the minimum of (y-b)/(x-a) over all x>a. And the "backward-looking " tangent has the slope equal to the maximum of (y-b)/(x-a) over all x
Here is a very straightforward implementation of the above: I used find to restrict the search to either x>a or x<a and took min and max to find the slopes.
x = 0:0.01:4;
y = 2.^x;
a = 2;
b = 3;
k = min((y(find(x>a))-b)./(x(find(x>a))-a));
plot(x,y)
hold on
plot(x,k*(x-a)+b,'r')
k = max((y(find(x<a))-b)./(x(find(x<a))-a));
plot(x,k*(x-a)+b,'g')
I'm trying to calculate the angle between 2 geographic (Latitude,Longitude) points in MATLAB. The points are:
(-65.226,125.5) and (-65.236,125.433).
I used the MATLAB function, azimuth, as:
azimuth(-65.226,125.5,-65.236,125.433)
I convert the result to radians, and plotting this using quiver, I get the following plot:
I want the red vector to point from the top right dot to the bottom left dot.
The points are at fairly high latitude (~65S), and the separation of the points is low (about 0.1 degrees). Thus, I can't really understand how the curvature of the earth could affect the azimuth prediction that much..
Does anyone have any experience with azimuth in MATLAB, or have a better suggestion to calculating the angle between the coordinate pairs?
Thanks!
Here you can detailed information and formulae on how to find angle between two latitude-longitude points.
I want to plot 3D cube of size 2x2x5 (x,y,z) around an interest point to get the nearest points to it and inside the cube. The interest point may be at the center of cube.
How can I get the nearest points to the interest point?
There are several techniques for drawing cubes here. You will need to choose one that lets you specify size and origin. The sizes will be 2,2,5, and the origin will be the coordinates of the interest point.
If I explain why, this might make more sense
I have a logical matrix (103x3488) output of a photo of a measuring staff having been run through edge detect (1=edge, 0=noedge). Aim- to calculate the distance in pixels between the graduations on the staff. Problem, staff sags in the middle.
Idea: User inputs co-ordinates (using ginput or something) of each end of staff and the midpoint of the sag, then if the edges between these points can be extracted into arrays I can easily find the locations of the edges.
Any way of extracting an array from a matrix in this manner?
Also open to other ideas, only been using matlab for a month, so most functions are unknown to me.
edit:
Link to image
It shows a small area of the matrix, so in this example 1 and 2 are the points I want to sample between, and I'd want to return the points that occur along the red line.
Cheers
Try this
dat=imread('83zlP.png');
figure(1)
pcolor(double(dat))
shading flat
axis equal
% get the line ends
gi=floor(ginput(2))
x=gi(:,1);
y=gi(:,2);
xl=min(x):max(x); % line pixel x coords
yl=floor(interp1(x,y,xl)); % line pixel y coords
pdat=nan(length(xl),1);
for i=1:length(xl)
pdat(i)=dat(yl(i),xl(i));
end
figure(2)
plot(1:length(xl),pdat)
peaks=find(pdat>40); % threshhold for peak detection
bigpeak=peaks(diff(peaks)>10); % threshold for selecting only edge of peak
hold all
plot(xl(bigpeak),pdat(bigpeak),'x')
meanspacex=mean(diff(xl(bigpeak)));
meanspacey=mean(diff(yl(bigpeak)));
meanspace=sqrt(meanspacex^2+meanspacey^2);
The matrix pdat gives the pixels along the line you have selected. The meanspace is edge spacing in pixel units. The thresholds might need fiddling with, depending on the image.
After seeing the image, I'm not sure where the "sagging" you're referring to is taking place. The image is rotated, but you can fix that using imrotate. The degree to which it needs to be rotated should be easy enough; just input the coordinates A and B and use the inverse tangent to find the angle offset from 0 degrees.
Regarding the points, once it's aligned straight, all you need to do is specify a row in the image matrix (it would be a 1 x 3448 vector) and use find to get non-zero vector indexes. As the rotate function may have interpolated the pixels somewhat, you may get more than one index per "line", but they'll be identifiable as being consecutive numbers, and you can just average them to get an approximate value.