I have a mongodb with a table named Patient. When I display the content with MongoVUE I see my Patients in this format:
/* 0 */
{
"_id" : ObjectId("547c4aa9dbe9665042dddf76"),
"Patient" : {
"Maidenname" : { },
"Phone" : {
"Type" : { },
"Number" : { }
},
"Citizenship" : { },
"SSN" : 1234567,
"Profession" : { },
"systemUID" : { },
"lid" : 111,
"system" : "abc",
"Address" : {
"Street" : { },
"State" : { },
"Zip" : { },
"Country" : { },
"City" : { }
},
"Lastname" : "asdf",
"Firstname" : "Test",
"Birthdate" : 19000101,
"Identifier" : {
"id" : 123,
"system" : "abc",
"UID" : { }
}
}
}
I would like to make a find on the field Firstname with value Test, this is my query:
db.Patient.find({Firstname:"Test"})
But it returns 0 rows.
I also tried this one:
db.Patient.find({Patient : {Firstname:"Test"}})
Also 0 rows returned.
When I do a find like this:
db.Patient.find()
I get all data. (also the one with "Firstname" : "Test")
Can anyone help me with that find query?
Should try this it work well
db.patiens.find({"Patient.Firstname":"Test"})
Since Firstname is in Patient object, it is its property you need to select is as
db.Patient.find({"Patient.Firstname":"Test"})
Related
Hi this is an example of my structure.
"_id" : ObjectId("12312341234cf123cc123456"),
"internetMessageId" : "<1234#1234asdfasc.COM>",
"ccRecipients" : [
{
"emailAddress" : {
"name" : "Joe"
"address" : "joe#gmail.com"
}
},
{
"emailAddress" : {
"name" : "Marc",
"address" : "marc#gmail.com"
}
}
],
"toRecipients" : [
{
"emailAddress" : {
"name" : "Mary"
"address" : "mary#gmail.com"
}
},
{
"emailAddress" : {
"name" : "Frank",
"address" : "frank#gmail.com"
}
}
],
"bccRecipients" : [],
"from" : {
"emailAddress" : {
"name" : "Juan",
"address" : "juan#gmail.com"
}
}
}
I have several duplicated documents as above and I want to keep only one of them. I understand that I should create a unique combination of columns from, internetMessadeId, toRecipients, ccRecipients, and bccRecipients but I'm struggling to put it all together.
Thanks for any help.
I have one scenario like need to sort the result of group() in mongoDB
For Example:
Suppose you have documents in Student collection like below
{
"id":"kjdkfdjkljflkd73847",
"DepartementID":123,
"parties":[
{
"idNumber" : "103",
"studentName" : {
"suffix" : "Mr",
"firstName" : "ram",
"middleName" : "",
"lastName" : "gorli"
}
},
{
"idNumber" : "99",
"studentName" : {
"suffix" : "Mr",
"firstName" : "ramesh",
"middleName" : "",
"lastName" : "vogue"
}
},
]
},
{
"id":"kjdkfdjkljflkd73847",
"DepartementID":123,
"parties":[
{
"idNumber" : "101",
"studentName" : {
"suffix" : "Mr",
"firstName" : "Mike",
"middleName" : "",
"lastName" : "john"
}
},
{
"idNumber" : "102",
"studentName" : {
"suffix" : "Mr",
"firstName" : "ram",
"middleName" : " ",
"lastName" : "gorli"
}
},
]
}
I'm grouping the details by using DepartmentID in student collection, In group() itself I need to sort by using last name in parties. how can we achieve this in one query it self?
please help me out. I really appreciate your efforts.
This will work for you :
db.getCollection('quotes').aggregate([
{
$unwind:"$parties"
},
{
$sort:{
"parties.studentName.lastName": 1
}
},
{
$group:{
_id:"$DepartementID",
parties:{
$push:"$parties"
}
}
}
])
I'm still new to MongoDB and non-relational databases in general so if the answer to my question is "Dude, you're thinking about your data in the wrong way", please let me know.
That being said, here's what I'm after. I have the following data:
{
"_id" : ObjectId("549b26b370b452eeb6acecd3"),
"user" : "54530e03c575dc86d61d22f8",
"workHistory" : [
{
"description" : "",
"endDate" : null,
"name" : "My Company",
"skills" : [
{
"_id" : ObjectId("549b29c970b452eeb6acecd4")
},
{
"_id" : ObjectId("549b29c970b452eeb6acecd5")
},
{
"_id" : ObjectId("549b29c970b452eeb6acecda")
},
{
"_id" : ObjectId("549b29c970b452eeb6acecdb")
},
{
"_id" : ObjectId("549b29c970b452eeb6acecdd")
},
{
"_id" : ObjectId("549b29c970b452eeb6acece9")
},
{
"_id" : ObjectId("549b29c970b452eeb6acecea")
},
{
"_id" : ObjectId("549b995b70b452eeb6acecf9")
},
{
"_id" : ObjectId("549b999470b452eeb6acecfa")
},
{
"_id" : ObjectId("549b9ab670b452eeb6acecfb")
}
],
"startDate" : "2013-10-01"
},
{
"description" : "",
"endDate" : "2013-10-01",
"name" : "Another Company",
"skills" : [
{
"_id" : ObjectId("549b29c970b452eeb6acecd4")
},
{
"_id" : ObjectId("549b29c970b452eeb6acecd5")
},
{
"_id" : ObjectId("549b29c970b452eeb6acecdb")
},
{
"_id" : ObjectId("549b29c970b452eeb6acecdd")
},
{
"_id" : ObjectId("549b29c970b452eeb6acece1")
},
{
"_id" : ObjectId("549b29c970b452eeb6acece9")
},
{
"_id" : ObjectId("549b995b70b452eeb6acecf9")
}
],
"startDate" : "2012-04-01"
},
.....
What I am trying to do is resolve that data I can list the actual skill names under "skills" instead of just object ID's. For reference here's the skills collection:
/* 0 */
{
"_id" : ObjectId("549b29c970b452eeb6acecd4"),
"name" : "CSS",
"description" : ""
}
/* 1 */
{
"_id" : ObjectId("549b29c970b452eeb6acecd5"),
"name" : "HTML5",
"description" : ""
}
/* 2 */
{
"_id" : ObjectId("549b29c970b452eeb6acecd6"),
"name" : "Ruby",
"description" : ""
}
/* 3 */
{
"_id" : ObjectId("549b29c970b452eeb6acecd7"),
"name" : "Ruby on Rails",
"description" : ""
}
I've tried looking into using MapReduce to do some kind of join, but I can barely wrap my head around it and all the examples I'm finding don't have data this complex.
What's the best approach for getting my desired result? Side note: I'm not 100% sure that simply embedding the skills in the "skills" property is the right approach. I'm trying to keep them separate because the skills may be listed in other areas of my application separate from work history.
I have a collection ,this is one of it's docs :
{
"_id" : 1 ,
"first_name" : "john",
"phone" : [
{
"type" : "mobile",
"number" : "9151112233"
},
{
"type" : "home",
"city_code" : 51,
"number" : "55251544"
},
{
"type" : "mobile",
"number" : "9152425125"
}
]
}
I'm searching for "phones" that contain type "mobile" and show them.
I need something like this :
{
"number" : "9151112233",
"number" : "9152425125"
}
I write this query for that :
db.main.find({ _id : 1 , 'phone.type' : "mobile" },{'phone.number' : true , _id : false}).forEach(printjson)
I want to show only numbers that their types are mobile but this query show all to numbers because this single doc contain others too.
How can I fix it?
I'd use the aggregation framework along with the $unwind, $match and $project commands. This:
db.main.aggregate({$unwind:"$phone"},{$match:{"phone.type":"mobile"}},{$project:{"phone.number":1,"_id":0}})
produces this output:
{ "phone" : { "number" : "9151112233" } }
{ "phone" : { "number" : "9152425125" } }
which only matches the mobile numbers.
http://docs.mongodb.org/manual/aggregation/
I need a way to find inside nested array documents.
I want to find value matching inside street_1.
this is my query:
db.phonebook.find({'address.home.street_1' : 'street 1 result'});
and my document:
{
"_id" : ObjectId("53788c0c74d3ead0098b4568"),
"first_name" : "jarod",
"last_name" : "petters",
"company" : "nostromos",
"phone_numbers" : [
{
"cell" : "0752203337"
},
{
"home" : "0850819201"
},
{
"home" : "0499955550"
}
],
"website" : "http://www.mywebsite.com",
"email" : [
{
"home" : "email.first.com"
},
{
"office" : "email.second.com"
}
],
"address" : [
{
"home" : {
"stree_1" : "street 1 result",
"stree_2" : "",
"postal_code" : "66502",
"city" : "my littre city",
"country" : "usa"
}
}
],
"nationality" : "mars",
"date_of_birth" : "1978-01-01"
}
Your query is the good one. But your document is not good, you have done a mistake in your document, you write stree_1 instead of street_1. If your document is right, change your query to :
db.phonebook.find({'address.home.stree_1' : 'street 1 result'});