I'd like to compare the code contents of two syntax objects and ignore things like contexts. Is converting them to datum the only way to do so? Like:
(equal? (syntax->datum #'(x+1)) (syntax->datum #'(x+1)))
If you want to compare both objects without deconstructing them at all, then yes.
HOWEVER, the problem with this method is that it only compares the datum attached to two syntax objects, and won't actually compare their binding information.
The analogy that I've heard (from Ryan Culpepper), is this is kind of like taking two paintings, draining of them of their color, and seeing if they are identical. While they might be similar in some ways, you will miss a lot of differences from the different colors.
A better approach (although it does require some work), is to use syntax-e to destruct the syntax object into more primitive lists of syntax objects, and do this until you get identifiers (basically a syntax object whose datum is a symbol), from there, you can generally use free-identifier=? (and sometimes bound-identifier=? to see if each identifier can bind each other, and identifier-binding to compare module level identifiers.
The reason why there isn't a single simple predicate to compare two arbitrary syntax objects is because, generally, there isn't really one good definition for what makes two pieces of code equal, even if you only care about syntactic equality. For example, using the functions referenced above doesn't track internal bindings in a syntax object, so you will still get a very strict definition of what it means to be 'equal'. that is, both syntax objects have the same structure with identifiers that are either bound to the same module, or are free-identifier=?.
As such, before you use this answer, I highly recommend you take a step back and make sure this is really what you want to do. Once in a blue moon it is, but most of the time you actually are trying to solve a similar, yet simpler, problem.
Here's a concrete example of one possible way you could do the "better approach" Leif Andersen mentioned.
I have used this in multiple places for testing purposes, though if anyone wanted to use it in non-test code, they would probably want to re-visit some of the design decisions.
However, things like the equal?/recur pattern used here should be helpful no matter how you decide to define what equality means.
Some of the decisions you might want to make different choices on:
On identifiers, do you want to check that the scopes are exactly the same (bound-identifier=?), or would you want to assume that they would be bound outside of the syntax object and check that they are bound to the same thing, even if they have different scopes (free-identifier=?)? Note that if you choose the first one, then checking the results of macro expansion will sometimes return #false because of scope differences, but if you choose the second one, then if any identifier is not bound outside of the syntax object, then it would be as if you only care about symbol=? equality on names, so it will return #true in some places where it shouldn't. I chose the first one bound-identifier=? here because for testing, a "false positive" where the test fails is better than a "false negative" where the tests succeeds in cases it shouldn't.
On source locations, do you want to check that they are equal, or do you want to ignore them? This code ignores them because it's only for testing purposes, but if you want equality only for things which have the same source location, you might want to check that using functions like build-source-location-list.
On syntax properties, do you want to check that they are equal, or do you want to ignore them? This code ignores them because it's only for testing purposes, but if you want to check that you might want to use functions like syntax-property-symbol-keys.
Finally here is the code. It may not be exactly what you want depending on how you answered the questions above. However, its structure and how it uses equal?/recur might be helpful to you.
(require rackunit)
;; Works on fully wrapped, non-wrapped, and partially
;; wrapped values, and it checks that the inputs
;; are wrapped in all the same places. It checks scopes,
;; but it does not check source location.
(define-binary-check (check-stx=? stx=? actual expected))
;; Stx Stx -> Bool
(define (stx=? a b)
(cond
[(and (identifier? a) (identifier? b))
(bound-identifier=? a b)]
[(and (syntax? a) (syntax? b))
(and (bound-identifier=? (datum->syntax a '||) (datum->syntax b '||))
(stx=? (syntax-e a) (syntax-e b)))]
[else
(equal?/recur a b stx=?)]))
I've been working on some project. It should be able to do numerical and symbolic computing. But now I stuck on one problem and I don't really know how to resolve it. To be specific and short, let's say we are in package
(in-package #:brand-new-package)
Where we have symbol database
(defvar var-symbol-database (make-hash-table :test #'equal))
Reading and setting functions
(defun var-symbol (name)
(get-hash name var-symbol-database))
(defun set-var-symbol (name value)
(setf (get-hash name var-symbol-database) value))
(set-var-symbol 'temperature 300) ;K
(set-var-symbol 'f 200) ;Hz
(set-var-symbol 'k 1.3806504e-23) ;J K^-1
and now in another file (but same package) I will try to evaluate this equation
(eval '(+ 2 (var-symbol 'f)))
It won't work. Problem is that for some particular reason the value of key in hash table is.
brand-new-package::f
I though that I will solve the problem defining function like this
(set-var-symbol 1 '(var-symbol 'f)) ;Hz
But it is interpreted as
(brand-new-package::var-symbol brand-new-package::f)
The problem is that program can create many different symbols. It will compute electronic circuit equations. Program first inspect device objects like capacitors, resistors and so. It create circuit tablo by MNA.
During it many new symbols representing node voltages and currents could be created
(v1, v2, v3, i1, i2).
I needed some method to hold count and names of variables presented in equation. Because they will be passed to symbolic derivator ie (diff '(* (+ 40 v1) u2 ...) 'v1)) I came with an idea, maybe wrong, to make them reachable by index to define them as a list
'(v 1) '(v 2) '(v 3).
To make them evaluable I added to begining var-variable funcall. So list becomed
'(var-variable v 1) '(var-variable v 2) '(var-variable v 3)
But as I have written, system changes it to
'(brand-new-package::var-variable brand-new-package::v 1) '(brand-new-package::var-variable brand-new-package::v 2) '(brand-new-package::var-variable brand-new-package::v 3)
How to allow to users to acces these variables by typing (var-symbol 'v 1). I can imagine only one way. Instead of symbols use strings and export function (var-symbol). Then it will work this way
'(var-variable "v" 1)
But it is a little bit confusing.
You are duplicating what Lisp already does. Symbols are already managed in tables, called packages. A symbol can have a value. Putting it into a package is INTERN. Finding it is FIND-SYMBOL or just using the Lisp READer.
If you want your own symbol index tables, hash tables are fine. If you don't want to deal with packages of those symbols, then just use keyword symbols. They have a single colon in front. :temperature would be an example. Keyword symbols are automagically in the package KEYWORD and they evaluate to themselves.
What you state to be a "problem" is as expected. The Common Lisp notation brand-new-package::var-symbol signifies that the symbol var-symbol is in the package brand-new-package, which was the current package at the time the symbol was read by the lisp.
I'm not very familiar with Clojure/Lisp macros. I would like to write apply-recur macro which would have same meaning as (apply recur ...)
I guess there is no real need for such macro but I think it's a good exercise. So I'm asking for your solution.
Well, there really is no need for that, if only because recur cannot take varargs (a recur to the top of the function takes a single final seqable argument grouping all arguments pass the last required argument). This doesn't affect the validity of the exercise, of course.
However, there is a problem in that a "proper" apply-recur should presumably handle argument seqs returned by arbitrary expressions and not only literals:
;; this should work...
(apply-recur [1 2 3])
;; ...and this should have the same effect...
(apply-recur (vector 1 2 3))
;; ...as should this, if (foo) returns [1 2 3]
(apply-recur (foo))
However, the value of an arbitrary expression such as (foo) is simply not available, in general, at macro expansion time. (Perhaps (vector 1 2 3) might be assumed to always yield the same value, but foo might mean different things at different times (one reason eval wouldn't work), be a let-bound local rather than a Var (another reason eval wouldn't work) etc.)
Thus to write a fully general apply-recur, we would need to be able to determine how many arguments a regular recur form would expect and have (apply-recur some-expression) expand to something like
(let [seval# some-expression]
(recur (nth seval# 0)
(nth seval# 1)
...
(nth seval# n-1))) ; n-1 being the number of the final parameter
(The final nth might need to be nthnext if we're dealing with varargs, which presents a problem similar to what is described in the next paragraph. Also, it would be a good idea to add an assertion to check the length of the seqable returned by some-expression.)
I am not aware of any method to determine the proper arity of a recur at a particular spot in the code at macro-expansion time. That does not mean one isn't available -- that's something the compiler needs to know anyway, so perhaps there is a way to extract that information from its internals. Even so, any method for doing that would almost certainly need to rely on implementation details which might change in the future.
Thus the conclusion is this: even if it is at all possible to write such a macro (which might not even be the case), it is likely that any implementation would be very fragile.
As a final remark, writing an apply-recur which would only be capable of dealing with literals (actually the general structure of the arg seq would need to be given as a literal; the arguments themselves -- not necessarily, so this could work: (apply-recur [foo bar baz]) => (recur foo bar baz)) would be fairly simple. I'm not spoiling the exercise by giving away the solution, but, as a hint, consider using ~#.
apply is a function that takes another function as an argument. recur is a special form, not a function, so it cannot be passed to apply.
My problem isn't with the built-in eval procedure but how to create a simplistic version of it. Just for starters I would like to be able to take this in '(+ 1 2) and have it evaluate the expression + where the quote usually takes off the evaluation.
I have been thinking about this and found a couple things that might be useful:
Unquote: ,
(quasiquote)
(apply)
My main problem is regaining the value of + as a procedure and not a symbol. Once I get that I think I should just be able to use it with the other contents of the list.
Any tips or guidance would be much appreciated.
Firstly, if you're doing what you're doing, you can't go wrong reading at least the first chapter of the Metalinguistic Abstraction section of Structure and Interpretation of Computer Programs.
Now for a few suggestions from myself.
The usual thing to do with a symbol for a Scheme (or, indeed, any Lisp) interpreter is to look it up in some sort of "environment". If you're going to write your own eval, you will likely want to provide your own environment structures to go with it. The one thing for which you could fall back to the Scheme system you're building your eval on top of is the initial environment containing bindings for things like +, cons etc.; this can't be achieved in a 100% portable way, as far as I know, due to various Scheme systems providing different means of getting at the initial environment (including the-environment special form in MIT Scheme and interaction-environment in (Petite) Chez Scheme... and don't ask me why this is so), but the basic idea stays the same:
(define (my-eval form env)
(cond ((self-evaluating? form) form)
((symbol? form)
;; note the following calls PCS's built-in eval
(if (my-kind-of-env? env)
(my-lookup form env)
;; apparently we're dealing with an environment
;; from the underlying Scheme system, so fall back to that
;; (note we call the built-in eval here)
(eval form env)))
;; "applicative forms" follow
;; -- special forms, macro / function calls
...))
Note that you will certainly want to check whether the symbol names a special form (lambda and if are necessary -- or you could use cond in place of if -- but you're likely to want more and possibly allow for extentions to the basic set, i.e. macros). With the above skeleton eval, this would have to take place in what I called the "applicative form" handlers, but you could also handle this where you deal with symbols, or maybe put special form handlers first, followed by regular symbol lookup and function application.
Reading Paul Graham's essays on programming languages one would think that Lisp macros are the only way to go. As a busy developer, working on other platforms, I have not had the privilege of using Lisp macros. As someone who wants to understand the buzz, please explain what makes this feature so powerful.
Please also relate this to something I would understand from the worlds of Python, Java, C# or C development.
To give the short answer, macros are used for defining language syntax extensions to Common Lisp or Domain Specific Languages (DSLs). These languages are embedded right into the existing Lisp code. Now, the DSLs can have syntax similar to Lisp (like Peter Norvig's Prolog Interpreter for Common Lisp) or completely different (e.g. Infix Notation Math for Clojure).
Here is a more concrete example:Python has list comprehensions built into the language. This gives a simple syntax for a common case. The line
divisibleByTwo = [x for x in range(10) if x % 2 == 0]
yields a list containing all even numbers between 0 and 9. Back in the Python 1.5 days there was no such syntax; you'd use something more like this:
divisibleByTwo = []
for x in range( 10 ):
if x % 2 == 0:
divisibleByTwo.append( x )
These are both functionally equivalent. Let's invoke our suspension of disbelief and pretend Lisp has a very limited loop macro that just does iteration and no easy way to do the equivalent of list comprehensions.
In Lisp you could write the following. I should note this contrived example is picked to be identical to the Python code not a good example of Lisp code.
;; the following two functions just make equivalent of Python's range function
;; you can safely ignore them unless you are running this code
(defun range-helper (x)
(if (= x 0)
(list x)
(cons x (range-helper (- x 1)))))
(defun range (x)
(reverse (range-helper (- x 1))))
;; equivalent to the python example:
;; define a variable
(defvar divisibleByTwo nil)
;; loop from 0 upto and including 9
(loop for x in (range 10)
;; test for divisibility by two
if (= (mod x 2) 0)
;; append to the list
do (setq divisibleByTwo (append divisibleByTwo (list x))))
Before I go further, I should better explain what a macro is. It is a transformation performed on code by code. That is, a piece of code, read by the interpreter (or compiler), which takes in code as an argument, manipulates and the returns the result, which is then run in-place.
Of course that's a lot of typing and programmers are lazy. So we could define DSL for doing list comprehensions. In fact, we're using one macro already (the loop macro).
Lisp defines a couple of special syntax forms. The quote (') indicates the next token is a literal. The quasiquote or backtick (`) indicates the next token is a literal with escapes. Escapes are indicated by the comma operator. The literal '(1 2 3) is the equivalent of Python's [1, 2, 3]. You can assign it to another variable or use it in place. You can think of `(1 2 ,x) as the equivalent of Python's [1, 2, x] where x is a variable previously defined. This list notation is part of the magic that goes into macros. The second part is the Lisp reader which intelligently substitutes macros for code but that is best illustrated below:
So we can define a macro called lcomp (short for list comprehension). Its syntax will be exactly like the python that we used in the example [x for x in range(10) if x % 2 == 0] - (lcomp x for x in (range 10) if (= (% x 2) 0))
(defmacro lcomp (expression for var in list conditional conditional-test)
;; create a unique variable name for the result
(let ((result (gensym)))
;; the arguments are really code so we can substitute them
;; store nil in the unique variable name generated above
`(let ((,result nil))
;; var is a variable name
;; list is the list literal we are suppose to iterate over
(loop for ,var in ,list
;; conditional is if or unless
;; conditional-test is (= (mod x 2) 0) in our examples
,conditional ,conditional-test
;; and this is the action from the earlier lisp example
;; result = result + [x] in python
do (setq ,result (append ,result (list ,expression))))
;; return the result
,result)))
Now we can execute at the command line:
CL-USER> (lcomp x for x in (range 10) if (= (mod x 2) 0))
(0 2 4 6 8)
Pretty neat, huh? Now it doesn't stop there. You have a mechanism, or a paintbrush, if you like. You can have any syntax you could possibly want. Like Python or C#'s with syntax. Or .NET's LINQ syntax. In end, this is what attracts people to Lisp - ultimate flexibility.
You will find a comprehensive debate around lisp macro here.
An interesting subset of that article:
In most programming languages, syntax is complex. Macros have to take apart program syntax, analyze it, and reassemble it. They do not have access to the program's parser, so they have to depend on heuristics and best-guesses. Sometimes their cut-rate analysis is wrong, and then they break.
But Lisp is different. Lisp macros do have access to the parser, and it is a really simple parser. A Lisp macro is not handed a string, but a preparsed piece of source code in the form of a list, because the source of a Lisp program is not a string; it is a list. And Lisp programs are really good at taking apart lists and putting them back together. They do this reliably, every day.
Here is an extended example. Lisp has a macro, called "setf", that performs assignment. The simplest form of setf is
(setf x whatever)
which sets the value of the symbol "x" to the value of the expression "whatever".
Lisp also has lists; you can use the "car" and "cdr" functions to get the first element of a list or the rest of the list, respectively.
Now what if you want to replace the first element of a list with a new value? There is a standard function for doing that, and incredibly, its name is even worse than "car". It is "rplaca". But you do not have to remember "rplaca", because you can write
(setf (car somelist) whatever)
to set the car of somelist.
What is really happening here is that "setf" is a macro. At compile time, it examines its arguments, and it sees that the first one has the form (car SOMETHING). It says to itself "Oh, the programmer is trying to set the car of somthing. The function to use for that is 'rplaca'." And it quietly rewrites the code in place to:
(rplaca somelist whatever)
Common Lisp macros essentially extend the "syntactic primitives" of your code.
For example, in C, the switch/case construct only works with integral types and if you want to use it for floats or strings, you are left with nested if statements and explicit comparisons. There's also no way you can write a C macro to do the job for you.
But, since a lisp macro is (essentially) a lisp program that takes snippets of code as input and returns code to replace the "invocation" of the macro, you can extend your "primitives" repertoire as far as you want, usually ending up with a more readable program.
To do the same in C, you would have to write a custom pre-processor that eats your initial (not-quite-C) source and spits out something that a C compiler can understand. It's not a wrong way to go about it, but it's not necessarily the easiest.
Lisp macros allow you to decide when (if at all) any part or expression will be evaluated. To put a simple example, think of C's:
expr1 && expr2 && expr3 ...
What this says is: Evaluate expr1, and, should it be true, evaluate expr2, etc.
Now try to make this && into a function... thats right, you can't. Calling something like:
and(expr1, expr2, expr3)
Will evaluate all three exprs before yielding an answer regardless of whether expr1 was false!
With lisp macros you can code something like:
(defmacro && (expr1 &rest exprs)
`(if ,expr1 ;` Warning: I have not tested
(&& ,#exprs) ; this and might be wrong!
nil))
now you have an &&, which you can call just like a function and it won't evaluate any forms you pass to it unless they are all true.
To see how this is useful, contrast:
(&& (very-cheap-operation)
(very-expensive-operation)
(operation-with-serious-side-effects))
and:
and(very_cheap_operation(),
very_expensive_operation(),
operation_with_serious_side_effects());
Other things you can do with macros are creating new keywords and/or mini-languages (check out the (loop ...) macro for an example), integrating other languages into lisp, for example, you could write a macro that lets you say something like:
(setvar *rows* (sql select count(*)
from some-table
where column1 = "Yes"
and column2 like "some%string%")
And thats not even getting into Reader macros.
Hope this helps.
I don't think I've ever seen Lisp macros explained better than by this fellow: http://www.defmacro.org/ramblings/lisp.html
A lisp macro takes a program fragment as input. This program fragment is represented a data structure which can be manipulated and transformed any way you like. In the end the macro outputs another program fragment, and this fragment is what is executed at runtime.
C# does not have a macro facility, however an equivalent would be if the compiler parsed the code into a CodeDOM-tree, and passed that to a method, which transformed this into another CodeDOM, which is then compiled into IL.
This could be used to implement "sugar" syntax like the for each-statement using-clause, linq select-expressions and so on, as macros that transforms into the underlying code.
If Java had macros, you could implement Linq syntax in Java, without needing Sun to change the base language.
Here is pseudo-code for how a lisp-style macro in C# for implementing using could look:
define macro "using":
using ($type $varname = $expression) $block
into:
$type $varname;
try {
$varname = $expression;
$block;
} finally {
$varname.Dispose();
}
Since the existing answers give good concrete examples explaining what macros achieve and how, perhaps it'd help to collect together some of the thoughts on why the macro facility is a significant gain in relation to other languages; first from these answers, then a great one from elsewhere:
... in C, you would have to write a custom pre-processor [which would probably qualify as a sufficiently complicated C program] ...
—Vatine
Talk to anyone that's mastered C++ and ask them how long they spent learning all the template fudgery they need to do template metaprogramming [which is still not as powerful].
—Matt Curtis
... in Java you have to hack your way with bytecode weaving, although some frameworks like AspectJ allows you to do this using a different approach, it's fundamentally a hack.
—Miguel Ping
DOLIST is similar to Perl's foreach or Python's for. Java added a similar kind of loop construct with the "enhanced" for loop in Java 1.5, as part of JSR-201. Notice what a difference macros make. A Lisp programmer who notices a common pattern in their code can write a macro to give themselves a source-level abstraction of that pattern. A Java programmer who notices the same pattern has to convince Sun that this particular abstraction is worth adding to the language. Then Sun has to publish a JSR and convene an industry-wide "expert group" to hash everything out. That process--according to Sun--takes an average of 18 months. After that, the compiler writers all have to go upgrade their compilers to support the new feature. And even once the Java programmer's favorite compiler supports the new version of Java, they probably ''still'' can't use the new feature until they're allowed to break source compatibility with older versions of Java. So an annoyance that Common Lisp programmers can resolve for themselves within five minutes plagues Java programmers for years.
—Peter Seibel, in "Practical Common Lisp"
Think of what you can do in C or C++ with macros and templates. They're very useful tools for managing repetitive code, but they're limited in quite severe ways.
Limited macro/template syntax restricts their use. For example, you can't write a template which expands to something other than a class or a function. Macros and templates can't easily maintain internal data.
The complex, very irregular syntax of C and C++ makes it difficult to write very general macros.
Lisp and Lisp macros solve these problems.
Lisp macros are written in Lisp. You have the full power of Lisp to write the macro.
Lisp has a very regular syntax.
Talk to anyone that's mastered C++ and ask them how long they spent learning all the template fudgery they need to do template metaprogramming. Or all the crazy tricks in (excellent) books like Modern C++ Design, which are still tough to debug and (in practice) non-portable between real-world compilers even though the language has been standardised for a decade. All of that melts away if the langauge you use for metaprogramming is the same language you use for programming!
I'm not sure I can add some insight to everyone's (excellent) posts, but...
Lisp macros work great because of the Lisp syntax nature.
Lisp is an extremely regular language (think of everything is a list); macros enables you to treat data and code as the same (no string parsing or other hacks are needed to modify lisp expressions). You combine these two features and you have a very clean way to modify code.
Edit: What I was trying to say is that Lisp is homoiconic, which means that the data structure for a lisp program is written in lisp itself.
So, you end up with a way of creating your own code generator on top of the language using the language itself with all its power (eg. in Java you have to hack your way with bytecode weaving, although some frameworks like AspectJ allows you to do this using a different approach, it's fundamentally a hack).
In practice, with macros you end up building your own mini-language on top of lisp, without the need to learn additional languages or tooling, and with using the full power of the language itself.
Lisp macros represents a pattern that occurs in almost any sizeable programming project. Eventually in a large program you have a certain section of code where you realize it would be simpler and less error prone for you to write a program that outputs source code as text which you can then just paste in.
In Python objects have two methods __repr__ and __str__. __str__ is simply the human readable representation. __repr__ returns a representation that is valid Python code, which is to say, something that can be entered into the interpreter as valid Python. This way you can create little snippets of Python that generate valid code that can be pasted into your actually source.
In Lisp this whole process has been formalized by the macro system. Sure it enables you to create extensions to the syntax and do all sorts of fancy things, but it's actual usefulness is summed up by the above. Of course it helps that the Lisp macro system allows you to manipulate these "snippets" with the full power of the entire language.
In short, macros are transformations of code. They allow to introduce many new syntax constructs. E.g., consider LINQ in C#. In lisp, there are similar language extensions that are implemented by macros (e.g., built-in loop construct, iterate). Macros significantly decrease code duplication. Macros allow embedding «little languages» (e.g., where in c#/java one would use xml to configure, in lisp the same thing can be achieved with macros). Macros may hide difficulties of using libraries usage.
E.g., in lisp you can write
(iter (for (id name) in-clsql-query "select id, name from users" on-database *users-database*)
(format t "User with ID of ~A has name ~A.~%" id name))
and this hides all the database stuff (transactions, proper connection closing, fetching data, etc.) whereas in C# this requires creating SqlConnections, SqlCommands, adding SqlParameters to SqlCommands, looping on SqlDataReaders, properly closing them.
While the above all explains what macros are and even have cool examples, I think the key difference between a macro and a normal function is that LISP evaluates all the parameters first before calling the function. With a macro it's the reverse, LISP passes the parameters unevaluated to the macro. For example, if you pass (+ 1 2) to a function, the function will receive the value 3. If you pass this to a macro, it will receive a List( + 1 2). This can be used to do all kinds of incredibly useful stuff.
Adding a new control structure, e.g. loop or the deconstruction of a list
Measure the time it takes to execute a function passed in. With a function the parameter would be evaluated before control is passed to the function. With the macro, you can splice your code between the start and stop of your stopwatch. The below has the exact same code in a macro and a function and the output is very different. Note: This is a contrived example and the implementation was chosen so that it is identical to better highlight the difference.
(defmacro working-timer (b)
(let (
(start (get-universal-time))
(result (eval b))) ;; not splicing here to keep stuff simple
((- (get-universal-time) start))))
(defun my-broken-timer (b)
(let (
(start (get-universal-time))
(result (eval b))) ;; doesn't even need eval
((- (get-universal-time) start))))
(working-timer (sleep 10)) => 10
(broken-timer (sleep 10)) => 0
One-liner answer:
Minimal syntax => Macros over Expressions => Conciseness => Abstraction => Power
Lisp macros do nothing more than writing codes programmatically. That is, after expanding the macros, you got nothing more than Lisp code without macros. So, in principle, they achieve nothing new.
However, they differ from macros in other programming languages in that they write codes on the level of expressions, whereas others' macros write codes on the level of strings. This is unique to lisp thanks to their parenthesis; or put more precisely, their minimal syntax which is possible thanks to their parentheses.
As shown in many examples in this thread, and also Paul Graham's On Lisp, lisp macros can then be a tool to make your code much more concise. When conciseness reaches a point, it offers new levels of abstractions for codes to be much cleaner. Going back to the first point again, in principle they do not offer anything new, but that's like saying since paper and pencils (almost) form a Turing machine, we do not need an actual computer.
If one knows some math, think about why functors and natural transformations are useful ideas. In principle, they do not offer anything new. However by expanding what they are into lower-level math you'll see that a combination of a few simple ideas (in terms of category theory) could take 10 pages to be written down. Which one do you prefer?
I got this from the common lisp cookbook and I think it explained why lisp macros are useful.
"A macro is an ordinary piece of Lisp code that operates on another piece of putative Lisp code, translating it into (a version closer to) executable Lisp. That may sound a bit complicated, so let's give a simple example. Suppose you want a version of setq that sets two variables to the same value. So if you write
(setq2 x y (+ z 3))
when z=8 both x and y are set to 11. (I can't think of any use for this, but it's just an example.)
It should be obvious that we can't define setq2 as a function. If x=50 and y=-5, this function would receive the values 50, -5, and 11; it would have no knowledge of what variables were supposed to be set. What we really want to say is, When you (the Lisp system) see (setq2 v1 v2 e), treat it as equivalent to (progn (setq v1 e) (setq v2 e)). Actually, this isn't quite right, but it will do for now. A macro allows us to do precisely this, by specifying a program for transforming the input pattern (setq2 v1 v2 e)" into the output pattern (progn ...)."
If you thought this was nice you can keep on reading here:
http://cl-cookbook.sourceforge.net/macros.html
In python you have decorators, you basically have a function that takes another function as input. You can do what ever you want: call the function, do something else, wrap the function call in a resource acquire release, etc. but you don't get to peek inside that function. Say we wanted to make it more powerful, say your decorator received the code of the function as a list then you could not only execute the function as is but you can now execute parts of it, reorder lines of the function etc.