I have added one index.html page at the root of asset folder in moovweb.
And on click of button I am trying to open the html page.
Whereas I am getting page cannot be loaded message.
How to access the local html page in moovweb?
In order to use the asset folder you need to define the static path on the config.json file
{
"host_map": [
"my mapping => www.mymapping"
],
"static_paths": {
"/newpage" : "index.html"
}}
With the mapping you can reference the page via mlocal.mysite.com/newpage.
Also, I'd recommend you to read the following content about static assets:
http://developer.moovweb.com/docs/cloud/static_asset_delivery
Cheers,
JC
Related
I generated the json file and gave the path /bin//filename.json . I am able to see the json file in author mode but not in publish. Our aem ops team says they cannot make bin as public. Tried to change the path, using js generated the json path file now at path /content//***/filename.json which I am able to see in author mode but not in publish.
My question is is there any other way that I can try . Please if any other ideas do comment.
Thank you.
Or just simple: Angular get content of page by call .infinity.json
Examp:
Your page is: /mysite/en/home.html
We change to : /mysite/en/home.infinity.json
For more detail: https://forums.adobe.com/thread/2337725
Good luck
We open using url under /bin/.. for SlingServlet
First create a slingSevlet
#SlingServlet(paths="/bin/filename.json", methods = "GET", metatype=true)
Then check the filter and make sure that /bin/filename.json accepts GET requests:
curl 'http://localhost:4502/system/console/configMgr'
Search for 'Apache Sling Referrer Filter'
Check the configuration
I used yo keystone to generate a keystone webpage and basically what I want is to sort of feature galleries on the homepage. I added the line
view.query('galleries', keystone.list('Gallery').model.find().sort('sortOrder'));
to my index.js file in the routes/views folder and basically copied the gallery.jade file into index.jade so that I could make sure the page could find "galleries" but when i try to open the page, i get the error that "galleries" is undefined.
I have also tried adding this bit of code to the same index.js
locals.data = {
galleries: keystone.list('Gallery').model.find().sort('sortOrder');
};
and calling data.galleries in index.jade but it didn't work either.
How do I get this gallery list on my jade file?
Turns out that my original change with view.query was correct. I just needed to restart my database.
I have a JSON which returns a list of URLs of images to access the JSON that is already placed in a field in this domain whitelist manifest.json, however when I try to view the pictures it complains that it can not access the images.
1 - How to Perm can display images that are not within the package App
2 - How can I download the images to download the APP and then display
to this second question I used the RAL, a lib trial google and it worked, however I could not make a test using this publication lib he claims an error, follow the link to the image lib and complaining about the error:
lib: https://github.com/GoogleChrome/apps-resource-loader
Error: http://twitter.yfrog.com/oe24998653p
You can request external images using XMLHttpRequest and transform them into ObjectURLs. Then set the src attribute in the <img> tag to each ObjectURL and it should work.
Since this is a very common use case, we created a library to simplify it. Just drop the apps-resource-loader ral.min.js to your project and then:
var remoteImage,
container = document.querySelector('.imageContainer'),
toLoad = { 'images': [
'http://myserver.com/image1.png',
'http://myserver.com/image2.png' ] }; // list of image URLs
toLoad.images.forEach(function(imageToLoad) {
remoteImage = new RAL.RemoteImage(imageToLoad);
container.appendChild(remoteImage.element);
RAL.Queue.add(remoteImage);
});
RAL.Queue.setMaxConnections(4);
RAL.Queue.start();
Remember that you need permission in the manifest.json to all domains you will be XHR'ing to. If you don't know beforehand where those images will be hosted, you can ask permission for any url:
permissions: ['<all_urls>'],
For other usages and to get the full library, please see the project page:
https://github.com/GoogleChrome/apps-resource-loader
and a simple demo at:
https://github.com/GoogleChrome/apps-resource-loader/tree/master/demo
Google has added a browser tag that allows you to include images, but so far I haven't been able to get it to work.
Here is what they show as an example
<browser src="http://i.stack.imgur.com/dmHl0.png">
I am using Zend Framework to develop some application. I develop on my localhost and then I upload it to some subdomain like abc.mydomain.com. When I upload my layout index.phtml, I get the following for all URLs:
abc.mydomain.com/css/base.css 404 (Not Found)
on the web browser console but my CSS is in the public folder.
my code to link this css is :
<?php echo $this->headLink()->appendStylesheet('/css/base.css') ?>
What should i do to make these addresses work ?
To complete my question : How does the framework distinguish between a folder and a controller or How could i tell the framework to don't act on these URL ass action , they are folders ?
Sounds like a mapping issue associated to the hosting the subdomain. Often on shared hosting you cannot map the project's public folder to the subdomain. So a variety of rewrite tricks are required to map requests for pages and assets into the right directories without confusing ZF about the requested URL.
Check out:
http://www.papayasoft.com/2010/05/08/zend-framework-shared-hosting/
for a description of the problem and various approaches to solving it.
Usually, the baseUrl() view-helper detects (internally, using the Zend_Controller_Front::getBaseUrl() method) what your app's base-url is.
But sometimes, depending upon your vhost setup and the location of your public folder within the doc root - you need to tell the app explicitly what your base-url is.
In application/configs/applicatiom.ini, you can set:
resources.frontController.baseUrl = "http://abc.mydomain.com"
Then in a view-script, you can access public assets using the baseUrl() view-helper and a relative url (relative to the base you set), as follows:
<?php echo $this->headLink()->appendStylesheet($this->baseUrl('css/base.css')) ?>
though I see many people use it as a prefix-only:
<?php echo $this->headLink()->appendStylesheet($this->baseUrl() . '/css/base.css') ?>
Well, say I have a number of html pages in my web. The case is that I´m doing changes sometimes in the directory structure, so when anybody try to access to a determinated URL, it's possible that such URL does not exit. The files names don't change but so do the paths.
As far as I now, the server takes the user to a "404" page that can be customized. Is possible to customize the page in this way?:
The user tries oneweb.com/oldpath/page.html; which does not exist.
A 404 customized page is launched
404 page runs an script IS THIS POSSIBLE?
The script is given the name of the file WHERE IS STORED SUCH NAME?
The script search the entire directory structure to find page.html HOW TO ACCESS TO THE STRUCTURE
The file is found and the new URL is stored: oneweb.com/newpath/page.html
a link appears showing the new URL
Maybe this process is relatively common and I can find some related code or tutorial?
Are you using Apache? Linux?
Add a 404 handler
ErrorDocument 404 /404.php
Then use 404.php to parse the url. This simple example just grabs everything after the last / in the URI so http://example.com/foo/bar/page.html would put page.html in $url:
$url = end(explode('/', $_SERVER['REQUEST_URI']));
Then use one of the comment example functions in http://php.net/manual/en/function.readdir.php to search your directory and find the file.
Then do a header 301 redirect
header ('HTTP/1.1 301 Moved Permanently');
header ('Location: http://example.com/' . $file_path);