I am trying to filter workgroup name that only contains BL or CL so I used the formula...
STARTSWITH([wrkgrp_shrt_nm], "BL") or STARTSWITH([wrkgrp_shrt_nm], "CL" )
I get the little green check, but when I hit apply it is blank and nothing pulls through
I tried another formula...
if right([wrkgrp_shrt_nm],2) = 'BL' then 1 elseif
right([wrkgrp_shrt_nm],2) = 'CL' then 1 elseif
right([wrkgrp_shrt_nm],2) then 0
end
but I am only getting an error
any suggestions?
If you want "contains", you can just call contains()
contains(wrkgrp_shrt_nm, 'BL') or contains(wrkgrp_shrt_nm, 'CL')
Does the same thing as the find() solution Fred posted, just a little easier to read in this case. I'm not sure why Fred says you cannot use IF. I use IF all the time without problems.
BTW, in case you were wondering, the square brackets around field names are optional if the field name does not include spaces or punctuation, and function names are not case sensitive.
To clarify, you're asking for "contains BL or CL", but your formula specify STARTSWITH which will be true is your field [wrkgrp_shrt_nm] starts with the string "BL" or the string "CL".
If you want "contains", you could use FIND:
FIND([wrkgrp_shrt_nm], 'BL' ) > 0 OR FIND([wrkgrp_shrt_nm], 'CL' ) > 0
You cannot use IF in a condition field, but you can use inline IF (IIF), however it's not necessary in your case.
Edit:
I can totally be wrong with my comment on IF (because I'm still new in Tableau) but I tried IF in a condition field of a filter (as the OP asked) and I can't make it work. I use IF all the time in Calculated Fields however. I'll try again...
Related
I am trying to create a regular expression to determine if a string contains a number for an SQL statement. If the value is numeric, then I want to add 1 to it. If the number is not numeric, I want to return a 1. More or less. Here is the SQL:
SELECT
field,
CASE
WHEN regexp_like(field, '^ *\d*\.?\d* *$') THEN dec(field) + 1
ELSE 1
END nextnumber
FROM mytable
This actually works, and returns something like this:
INVALID 1
00000 1
00001E 1
00379 380
00013 14
99904 99905
But to push the envelope of understanding, what if I wanted to cover negative numbers, or those with a positive sign. The sign would have to immediately precede or follow the number, but not both, and I would not want to allow white space between the sign and the number.
I came up with a conditional expression with a capture group to capture the sign on the front of the number to determine if a sign was allowed on the end, but it seems a little awkward to handle given I don't really need a yes-pattern.
Here is the modified regex: ^ ([+-]?)*\d*\.?\d*(?(1) *|[+-]? *)$
This works at regex101.com, but in order for it to work I need to have something before the pipe, so I have to duplicate the next pattern in both the yes-pattern and the no-pattern.
All that background for this question: How can I avoid that duplication?
EDIT: DB2 for i uses International Components for Unicode to provide regular expression processing. It turns out that this library does not support conditionals like PRCE, so I changed the tags on this question. The answer given by Wiktor Stribiżew provides a working alternative to the conditional by using a negative lookahead.
You do not have to duplicate the end pattern, just move it outside the conditional:
^ *([+-])?\d*\.?\d*(?(1)|[+-]?) *$
See the regex demo. So, the yes-part is empty, and the no-part has an optional pattern.
You may also solve it with a mere negative lookahead:
^ *([+-](?!.*[-+]))?\d*\.?\d*[+-]? *$
See another regex demo. Here, ([+-](?!.*[-+]))? matches (optionally) a + or - that are not followed with any 0+ char followed with another + or -.
I need a regrex query to match any string having given character. So i tried for example
SELECT wt.CHGUSER FROM "CDB"."WTBALL" wt where REGEXP_LIKE (wt.CHGUSER, '^\d*115*$');
So i am expecting to fetch all the strings having 115 somewhere in between each string. I tried many combinations but i am getting empty column or weird combination.
Are you sure You need a regex? You write "all the strings having 115 somewhere in between each string", but test for a all-digit string with "115" somewhere...
Btw. this could be done also without regex:
WHERE LOCATE('115', wt.CHGUSER) > 0
AND TRANSLATE(wt.CHGUSER, '', '0123456789') --if You really want to test all-digit string
why not use the native "LIKE" expression?
where wt.CHGUSER like '%115%'
This will give different results than your regexp because your expression is looking for '115' so long as there is a digit immediate before and after it. A more generic regexp, which matches your question, would be '.*115.*'
What about -
REGEXP_LIKE (wt.CHGUSER, '^*\d115\d*$');
Using LIKE '%[0-9]%' to find "yellow 2 x 4 plate".
This is a simplified example that isn't working as I believe it should.
Table (command) with single column (commandtext, varchar).
Single entry in commandtext: yellow 2 x 4 plate.
SELECT
*
FROM command
WHERE commandtext LIKE '%[0-9]%'
Results = Empty set.
I expect that all this should be looking for is a digit between 0-9 surrounded by anythings else.
I am CLEARLY not getting something here...
As you have found out, you can use SQL standard SIMILAR TO:
... WHERE col SIMILAR TO '%[[:digit:]]%'
You could also use POSIX regular expressions:
... WHERE col ~ '[[:digit:]]'
I have an issue with the search parameters. I want to pass a phrase in my query. For exemple i'm looking for emails where the subject is "Test 1".
For this i'm doing a get on this ressource.
https://graph.microsoft.com/v1.0/me/messages?$search="subject:Test 1"
But the behaviour of this query is : Looking for mails that contains "Test" in the subject OR 1 in any other fields.
Refering to the KQL Syntax
A phrase (includes two or more words together, separated by spaces; however, the words must be enclosed in double quotation marks)
So, to do what i want i have to put double quotes (") around my phrase to do a strict value search. Like below
subject:"Test 1"
The problem it's at this point. Microsoft graph api already use double quotes (") after the parameters $search.
?$search="Key words"
So I can't do what is mentioned in the KQL doc.
https://graph.microsoft.com/v1.0/me/messages?$search="subject:"Test 1""
It's throwing an error :
"Syntax error: character '1' is not valid at position 15 in '\"subject:\"test 1\"\"'.",
It's an expected behaviour. I was pretty sure it will not work.
If someone has any suggestions for a solution or a workaround, I'm a buyer.
What I've already tried so far :
Use simple quote
Remove the quotes right after $select=
Remove the subject part $select="Test 1", same behaviour as the first request mentioned in this post. It will looks for emails that contain "test" or "1".
Best regards.
EDIT :
After sasfrog's anwser :
I used $filter : It works well with simple operator AND, OR.I have some errors by using the Not Operator. And btw you have to use the orderby parameter to show the result by date and add the field in filter parameters.
Exemple 1 (working, what I asked for first) :
https://graph.microsoft.com/v1.0/me/messages/?$orderby=receivedDateTime desc &$filter=receivedDateTime ge 1900-01-01T00:00:00Z AND contains(subject,'test 1')
Exemple 2 (not working)
https://graph.microsoft.com/v1.0/me/messages/?$orderby=receivedDateTime desc &$filter=(receivedDateTime ge 1900-01-01T00:00:00Z AND contains(subject,'test 1')) NOT(contains(from/EmailAddress/address,[specific address]))
EDIT 2
After some test with the filter parameters.
The NOT operator is still not working so to workaround use "ne" (non-equals)
the example 2 becomes :
https://graph.microsoft.com/v1.0/me/messages/?$orderby=receivedDateTime desc&$filter=(receivedDateTime ge 1900-01-01T00:00:00Z AND contains(subject,'test 1')) AND (from/EmailAddress/address ne [specific address])
UPDATE : OTHER SOLUTION WITH $search
Using $filter is great but it looks like it was sometimes pretty slow. So I found a workaround aboutmy issue.
It's to use AND operator between all terms.
Exemple 4 :
I'm looking for the mails where the subject is test 1;
Let value = "test 1". So you have to splice it by using space separator. And after write some code to manipulate this array, to obtain something like below.
$search="(subject:test AND subject:1)"
The brackets can be important if you use a multiple fields search. And Voilà.
Not sure if it's sufficient for what you're doing, but how about using the contains function within a filter query instead:
https://graph.microsoft.com/v1.0/me/messages?$filter=contains(subject,'Test 1')
Sounds like you're already looking at the doco but here it is just in case.
Update also, this worked for me using the search method:
https://graph.microsoft.com/v1.0/me/messages?$search="subject:'Test 1'"
I have a DB2 v7r3 SQL SELECT statement with three instances of REGEXP_SUBSTR(), all with the same regex pattern string, each of which extract one of three groups.
I'd like to change the first SUBSTR to REGEXP_REPLACE() to do a conditional replacement if there's no match, to insert a default value similarly to the ELSE section of a CASE...END. But I can't make it work. I could easily use a CASE, but it seems more compact & efficient to use RegEx.
For example, I have descriptions of food containers sizes, in various states of completeness:
12X125
6X350
1X1500
1500ML
1000
The last two don't have the 'nnX' part at the beginning, in which case '1X' is assumed and needs to be inserted.
This is my current working pattern string:
^(?:(\d{1,3})(?:X))?((?:\d{1,4})(?:\.\d{1,3})?)(L|ML|PK|Z|)$
The groups returned are: quantity, size, and unit.
But only the first group needs the conditional replacement:
(?:(\d{1,3})(?:X))?
This RexEgg webpage describes the (?=...) operator, and it seems to be what I need, but I'm not sure. It's in the list of operators for my version of DB2, but I can't make it work. Frankly, it's a bit deeper than my regex knowledge, and I can't even make it work in my favorite online regex tester, Regex101.
So...does anyone have any idea or suggestions..? Thanks.
Try this (replace "digits not followed by X_or_digit"):
with t(s) as (values
'12X125'
, '6X350'
, '1X1500'
, '1500'
, '1125'
)
select regexp_replace(s, '^([\d]+(?![X\d]))', '1X\1')
from t;